Helpppp guys plsss help !

The moon's gravitation force is determined by the mass and the size of the moon. Since the moon has significantly less mass than the Earth, it will not pull objects toward itself at the strength that Earth will.

Answer:

an acronym because it is shorted to remember like mvemjsun it's the planet

Complete Question

A block is attached to one end of a spring with the other end of the spring fixed to a wall. The block is vibrating horizontally on a frictionless surface. If the mass of the block is 4.0 kg, the spring constant is k = 100 N/m, and the maximum distance of the block from the equilibrium position is 20 cm, what is the speed of the block at an instant when it is a distance of 16 cm from the equilibrium position?

Answer:

The velocity is [tex]v = 0.6 \ m/s[/tex]

Explanation:

From the question we are told that

  The mass of the block is  m =  4.0 kg

  The spring constant is k =  100 N/m

  The maximum distance of the block from equilibrium position is  d = 20 cm =0.20 m

   The distance considered is  [tex]d_k = 16 \ cm = 0.16 \ m[/tex]

Generally the maximum energy stored in the spring is mathematically represented as

      [tex]E = \frac{1}{2} * k * d^2[/tex]

=>  [tex]E = \frac{1}{2} *100 * 0.2^2[/tex]

=>  [tex]E = 2.0 \ J[/tex]

Gnerally according to the law of energy conservation

   The energy maximum energy of  the spring = energy of  the spring at [tex]d_k[/tex] + energy of the block at [tex]d_k[/tex]

Here energy of the block at [tex]d_k[/tex] is mathematically represented as

        [tex]K_1 = \frac{1}{2} mv^2[/tex]

=>    [tex]K_1 = \frac{1}{2} * 4* v^2[/tex]

=>    [tex]K_1 = 2v^2[/tex]

Generally the energy of the spring at [tex]d_k[/tex] is mathematically represented as

      [tex]E_2 =\frac{1}{2} * k * d_k^2[/tex]

=>    [tex]E_2 =\frac{1}{2} * 100 * (0.16)^2[/tex]

=>    [tex]E_2 =1.28 \ J[/tex]

So

       [tex]2.0 = 1.28 + 2v^2[/tex]

=>    [tex]v = 0.6 \ m/s[/tex]

Answer:

The answer is c

Explanation:

Answer:

[tex]a=1.33\ m/s^2[/tex]

Explanation:

Given that,

Initialy, the jet is at rest, u = 0

Final velocity of the jet, v = 75 m/s

Distance, d = 2100 m

We need to find the acceleration of the jet. It is based on the concept of equation of kinematics. Using third equation of motion, w get :

[tex]v^2-u^2=2ad[/tex]

a is acceleration

[tex]75^2=2a\times 2100\\\\a=\dfrac{75^2}{2\times 2100}\\\\a=1.33\ m/s^2[/tex]

So, the acceleration of the jet is [tex]1.33\ m/s^2[/tex].

Answer:

they are all made of gass and they are all giants.

Explanation:

Answer:

How are the gas giants similar to one another? dont have solid surfaces and are much larger than earth. Why do all of the gas giants have thick atmospheres? Because they are so massive, the gas giants exert a much stronger gravitational force than the terrestrial planets

Explanation:

Answer:

an atom

Explanation: atom then matter

Answer:

the basic building blocks that make up matter are called atoms.

Answer:

Physical science is the study of the inorganic world. That is, it does not study living things.  The four main branches of physical science are astronomy, physics, chemistry, and the Earth sciences, which include meteorology and geology.

Answer:

Sodium and calcium

Explanation:

Answer:

Ionic bond is the name given to one of the three ways in which atoms can interact with each other. The other forms of interaction between atoms are the covalent bond, which occurs between atoms of ametals, hydrogens, or ametal and hydrogen, and the metallic bond, which occurs only between atoms of the same metal.

Explanation

:The atoms of the chemical elements that participate in the ionic bond must present, necessarily, the nature of gaining or losing electrons, thus, the ionic bond can occur between:

a metal and an ametal;

a metal and hydrogen.

Sodium: metallic element, as it has the characteristic of losing electron; belonging to the IA family, atomic number 11, with an electron in the valence shell.

Chlorine: ametalic element, as it has the characteristic of gaining electrons; belonging to the VIIA family, with atomic number 17.

Answer:

18 m/s west

Explanation:

The correct option is C. 23 m/s east

Conservation of momentum states that For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

using conservation of momentum

m1v1 + m2v2 = m1 v1' + m2 v2'

Given

m1 = 3154 kg

v1= 6m/s

m2 = 8296 kg

v2 = 23 m/s

v1' = 7m/s

v2' = ?

3154 * 6 + 8296 * 23 = 3154 * 7 + 8296 v2'

209732 - 22078 = 8296 v2'

187654 = 8296 v2'

v2' = 22.62 ≈ 23 m/s east

correct option is C. 23 m/s east

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Answer:

Approximately 17.21 seconds

Explanation:

With subtraction, we have the gazelle 18.3 km/h slower than the cheetah, which is about 5.08333 m/s. As the gazelle is 87.5 meters ahead of the cheetah, 87.5 divided by 5.083333333 is about 17.21 seconds.

Answer:

5.1 m

Explanation:

Given in the y direction:

v₀ = 10 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (10 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 5.1 m

Answer:

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

Explanation:

Answer:

Yes, the number of electrons determines the chemical properties of the atom.

Explanation:

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

THIS LAW IS TRUE AS IT ALSO HAVE A REAL LIFE EXAMPLE.

Examples of Newton's 1st Law : If you slide a hockey puck on ice, eventually it will stop, because of friction on the ice. It will also stop if it hits something, like a player's stick or a goalpost.

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 2.857m/s²

Time  = 15.5s

Unknown:

Final speed of the car = ?

Solution:

 We use one of the motion equations to solve this problem;

     V = U + at

  Where V is the final velocity

               U is the initial velocity

               a is the acceleration

                t is the time taken

    V = 0 + 2.857 x 15.5  = 44.28m/s

Answer:

For number 1 no treatment available , number 2 cochlear hearing loss

Explanation:

nerve damage is permanent

Answer:

A) sum

Explanation:

That's the answer bro

Answer:

the answer is C subtraction

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

f is the force

m is the acceleration

From the question we have

[tex]a = \frac{6.2}{3.2} \\ = 1.9375[/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]F_y=96.4N[/tex]

Explanation:

Hello.

In this case, considering the force diagram shown on the attached picture, we can see that the component of his force is directed downwards is:

[tex]F_y=F\times sin (\theta)[/tex]

Because the other component is the horizontal one:

[tex]F_x=F\times cos(\theta)[/tex]

In this case, the y-component force turns out:

[tex]F_y=150N\times sin (40\°)\\\\F_y=96.4N[/tex]

Moreover, the x-component force is also computed if required:

[tex]F_x=150N\times cos(40\°)\\\\F_x=114.9N[/tex]

Best regards.

the answer is 198.23

Force(f) = 18344 N

Acceleration(a) = 92.54 m/s²

we know that m=f/a

m=18344/92.54</p><p>

ma 198.23 kg

pls mark me brainliest thankss!

Answer:

central nervous system

peripheral nervous system

Explanation:

The nervous system has two main parts: The central nervous system is made up of the brain and spinal cord. The peripheral nervous system is made up of nerves that branch off from the spinal cord and extend to all parts of the body.Oct 1, 2018

Answer:

The central nervous system

The peripheral nervous system

Explanation:

The central nervous system (CNS) is the brain and spinal cord, and the peripheral nervous system (PNS) is everything else

Given parameters:

Force on the object = 300N

Mass of object  = 25kg

Unknown:

Acceleration  = ?

Solution:

According to Newton's second law of motion, force is a product of mass and acceleration.

   Force  = mass x acceleration

Input the parameters and solve for the acceleration;

         300  = 25 x acceleration

           Acceleration  = 12m/s²

The acceleration is  12m/s²

Answer:

1.77 m/s^2

Explanation:

since it is unbalanced there must be net force(resultant force)

[tex]net \: force \: = accleration \: \times mass[/tex]

net force = 23N

mass = 13kg

a = x

x = 23/13

= 1.769...

approximately = 1.77 m/s^2

Answer:

The second choice

Explanation:

I think the answer is the second choice because if the surface is smooth, there is less friction. With a boat, it is easier to pull it on water than on the sand, because water has less friction, and thus, the answer is the second choice because rough surfaces have more friction.

Hopefully the explanation and answer helps!

Answer:

(a) Approximately [tex]0.335\; \rm m[/tex].

(b) Approximately [tex]1.86\; \rm m\cdot s^{-1}[/tex].

(c) Approximately [tex]0.707\; \rm m[/tex].

(d) Approximately [tex]0.228\; \rm m[/tex].

Explanation:

Consider the conversion of energy in this object-spring system.

First diagram: Right before the object came into contact with the spring, the object carries kinetic energy [tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^2[/tex].

Second diagram: As the object moves towards the position in the third diagram, the spring gains elastic potential energy. At the same time, the object loses energy due to friction.

Third diagram: After the velocity of the object becomes zero, it has moved a distance of [tex]D[/tex] and compressed the spring by the same distance.

The sum of these two energies should match the initial kinetic energy of the object (before it comes into contact with the spring.) That is:

[tex]\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^{2} = (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].

Assume that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex]. In the equation above, all symbols other than [tex]D[/tex] have known values:

Substitute in the known values to obtain an equation for [tex]D[/tex] (where the unit of [tex]D\![/tex] is [tex]m[/tex].)

[tex]3.178 = 2.69775\, D + 25\, D^2[/tex].

[tex]2.69775\, D + 25\, D^2 + 3.178 = 0[/tex].

Simplify and solve for [tex]D[/tex]. Note that [tex]D > 0[/tex] because the energy lost to friction should be greater than zero.

[tex]D \approx 0.335\; \rm m[/tex].

The energy of the object-spring system in the third diagram is the same as the elastic potential energy of the spring:

[tex]\displaystyle \frac{1}{2}\,k\, D^2 \approx 2.81\; \rm J[/tex].

As the object moves to the left, part of that energy will be lost to friction:

[tex](\mu \cdot m \cdot g) \, D \approx 0.905\; \rm J[/tex].

The rest will become the kinetic energy of that block by the time the block reaches the position in the fourth diagram:

[tex]2.81\; \rm J - 0.905\; \rm J \approx 1.91\; \rm J[/tex].

Calculate the velocity corresponding to that kinetic energy:

[tex]\displaystyle v =\sqrt{\frac{2\, (\text{Kinetic Energy})}{m}} \approx 1.86\; \rm m \cdot s^{-1}[/tex].

As the object moves from the position in the fourth diagram to the position in the fifth, all its kinetic energy ([tex]1.91\; \rm J[/tex]) would be lost to friction.

How far would the object need to move on the surface to lose that much energy to friction? Again, the size of the friction force is [tex]\mu \cdot m \cdot g[/tex].

[tex]\displaystyle (\text{Distance Travelled}) = \frac{\text{(Work Done by friction)}}{\text{(Size of the Friction Force)}} \approx0.707\; \rm m[/tex].

Similar to (a), solving (d) involves another quadratic equation about [tex]D[/tex].

Left-hand side of the equation: kinetic energy of the object (as in the fourth diagram,) [tex]1.91\; \rm J[/tex].

Right-hand side of the equation: energy lost to friction, plus the gain in the elastic potential energy of the spring.

[tex]\displaystyle {1.91\; \rm J} \approx (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2[/tex].

[tex]25\, D^2 + 2.69775\, D - 1.90811\approx 0[/tex].

Again, [tex]D > 0[/tex] because the energy lost to friction is greater than zero.

[tex]D \approx 0.228\; \rm m[/tex].

The energy transferred between the object and the spring as a closed system, therefore, conserved are;

(a) The distance of compression, d ≈ 0.3354 meters

(b) The speed in the un-stretched position wen the object is sliding to the left, v ≈ 1.8623 m/s

(c) The distance where the object comes to rest, D ≈ 0.7071 m

(d) The distance the object will come to rest attached to the spring, D ≈ 0.2278 m

The reason the above values are correct are as follows;

The known parameters are;

Mass of the object, m₁ = 1.10 kg

Coefficient of friction, μ = 0.250

The initial speed of the object, [tex]v_i[/tex] = 2.60 m/s

Force constant of the spring, K = 50.0 N/m

Distance the spring is compressed by the object = d

(a) Conservation of energy principle

[tex]Kinetic \ energy = \dfrac{1}{2} \cdot m\cdot v^2[/tex]

Work done = Force × Distance

Friction force, [tex]F_f[/tex] = W × μ

Weight, W = m·g

Weight = Mass × Acceleration

Energy transferred by object = Work done by spring + Work done by friction

[tex]Energy \ transferred \ by \ object = Kinetic \ energy = \dfrac{1}{2} \times 1.10\times 2.60^2 = 3.718[/tex]

Energy transferred by object = 3.718 J

[tex]Work \ done \ by \ spring = \dfrac{1}{2} \cdot k\cdot x^2[/tex]

[tex]Work \ by \ spring \ to \ bring \ object \ to \ rest, \ W_{spring} = \dfrac{1}{2} \times 50\times d^2[/tex]

[tex]W_{spring}[/tex] = 25·d²

Work done by friction, [tex]W_{friction}[/tex] = 1.10×9.81×0.250×d = 2.69775·d

Therefore;

3.718 = 25·d² + 2.69775·d

25·d² + 2.69775·d - 3.718 = 0

Solving gives

The distance of the compression d ≈ 0.3354 m

(b) The energy given by the spring = 25·d²

The work done by friction, [tex]W_{friction}[/tex] = 2.69775·d

Kinetic energy given to object = 0.55·v²

0.55·v² = 25·d² - 2.69775·d

0.55·v² = 25×0.3354² - 2.69775×0.3354

∴ v = √(3.4682) = 1.8623

The velocity of the object at the un stretched position, v ≈ 1.8623 m/s

(c) The kinetic energy, K.E. of the object on the way left is given as follows;

K.E. = 0.5 × 1.10 kg × 3.4682 m²/s² = 1.90751 J

The work done by friction before object comes to rest = 2.69775·D

[tex]D = \dfrac{1.90751 \, J}{2.69775 \, N} \approx 0.7071 \, m[/tex]

The distance where the object comes to rest, D ≈ 0.7071 m

(d) The work done on spring, [tex]W_{spring}[/tex] = 25·D'²

Work done on friction, [tex]W_{friction}[/tex] = 2.69775·D'

Kinetic energy of object, K.E. ≈ 1.90751 J

K.E. = [tex]W_{spring}[/tex] + [tex]W_{friction}[/tex]

1.90751 ≈ 25·D'² + 2.6775·D'

25·D'² + 2.6775·D' - 1.90751 = 0

Solving with a graphing calculator gives;

D' ≈ 0.2278 m

The new value of the distance D = 0.2278 m

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Answer:

The best and most correct answer among the choices provided by the question is the third choice. What he observed on the waves is the constructive interference. I hope my answer has come to your help. God bless and have a nice day ahead!

Explanation:

Answer:

Pierce conducts an experiment in which waves collide in a way that the energy increases. What has occurred?

refraction

reflection

constructive interference <<<---CORRECT

destructive interference

Explanation:

2021 EDGE

Answer:

Four metals other than iron that can be made to exhibit magnetic properties are nickel, cobalt, manganese, and chromium.

two

neutral region

north

magnetic

Explanation:

PennFoster

The four metals other than iron that can be made to exhibit magnetic properties are:

Furthermore, the words which can be used to accurately complete the sentences below are:

The magnet has two unlike poles and in the neutral region, there is the South and North poles.

The North and South poles repel each other and a magnet can attract any material which contains iron materials.

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