Find the area of the rhombus below.​

The class that contains the 80 th percentile is d) 32-34.

First, find the total frequency of the income :

Total frequency = 2 + 11 + 8 + 5 + 4 = 30

The position of the number at the 80 th percentile would then be :

= 30 x 80 %

= 24 th position

The cumulative frequency of :

26 - 28 =  2

28  - 30 : 2 + 11 = 13

30 - 32 : 13 + 8 = 21

This then means that the 24 th position is in the next interval of 32 - 34.

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The value of the radius is 13.04

Pythagoras theorem states that: The sum of square of the two legs of a right triangle is equal to the square of the other side.

Therefore c² = a² + b²

Since MN is perpendicular to JK , this means MK = JM = JK/2

= 14/2 = 7

HI = JK, therefore LI is also 7

and MN = LN = 11

Therefore,

NI =√ LN)² + LI)²

NI = √ 11² + 7²

NI = √121+49

NI = √ 170

NI = 13.04( nearest hundredth)

therefore the radius of the circle is 13.04

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The breadth and error margin of the confidence interval will rise when the confidence level is raised from 95% to 98%.

We are more certain that the genuine population mean falls inside the interval if the confidence level is larger. The range of feasible values for the population means will be broader since we need to widen the interval in order to reach this higher degree of confidence.

Since the margin of error equals half of the interval's breadth, it is directly proportional to the interval's width. The margin of error will therefore expand as the confidence level does as well.

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Answer:

√(6 + 9 +12) = √27 = 3√3

√(-6 + 9 + 12) = √15 = √3√5

√(6 - 9 + 12) = √9 = 3

√(6 + 9 - 12) = √3

(1/4)(3√3)(√3√5)(3)(√3)

= (1/4)(27√3)(√5) = (27√15)/4 = 26.1

Answer:correct answer is 26.1

Step-by-step explanation:

Heron's formula states that the area (A) of a triangle with side lengths a, b, and c is given by:

A = √(s(s-a)(s-b)(s-c))

where s is the semiperimeter, which is half the perimeter of the triangle:

s = (a + b + c) / 2

In this case, the side lengths are a = 6, b = 9, and c = 12. Therefore, the semiperimeter is:

s = (6 + 9 + 12) / 2 = 27 / 2

Using Heron's formula, we can now calculate the area of the triangle:

1. The width of the pen must be greater than or equal to the sum of the diameters of the two circular food containers, which is equal to 2x + 2x = 4x:

2. The width of the pen must also be less than or equal to the length of the pen, which is 10 feet:

3. The radii of the gravel bases must be greater than or equal to the radii of the food containers, which is equal to x:

4. The radii of the gravel bases must also be less than or equal to half the width of the pen, which is equal to y/2:

System of inequalities that can be used to determine the width of the pen, y, and the radii of the gravel bases, x, is:

Answer:

Step-by-step explanation:

The sum of the diameters of the gravel bases cannot exceed the width of the pen, so 2⁢x+2⁢x≤y. Rewrite this to get y≥4⁢x as the first inequality in the system.Next, to write the expression for the cost of the fencing, find the perimeter of the rectangle and multiply the perimeter by the cost per foot of fencing. The pen is a rectangle, so the perimeter is 2⁢(10)+2⁢(y), or 20+2⁢y. Multiply the cost ($4.00 per foot) by the perimeter to get 4⁢(20+2⁢y).Now write an expression for the gravel bases for the circular food containers. Because A=π⁢r2 and the cost of the gravel is $2.00 per square foot, multiply the cost of the material by the sum of these areas to get 2⁢(π⁢x2)+2⁢(π⁢x2).The total cost must be less than or equal to $150, so we can say that 4⁢(20+2⁢y)+2⁢(π⁢x2)+2⁢(π⁢x2)≤150. Finally, simplify and solve for y.80+8⁢y+2⁢π⁢x2+2⁢π⁢x2≤15080+8⁢y+4⁢π⁢x2≤1508⁢y≤70−4⁢π⁢x2y≤8.75−0.5⁢π⁢x2So, this is the system.

y≥4⁢x

y≤8.75−0.5⁢π⁢x2

Answer:

Step-by-step explanation:

1. Get mileage per gallon by dividing miles traveled by gallons used

[tex]\frac{125}{5} = 25 mpg\\[/tex]

2. Divide miles you want to travel by the mileage per gallon you got on the first step

[tex]\frac{400}{25} = 16 gallons[/tex]

Answer:

x is 25

Step-by-step explanation:

There is a common ratio between the sides. In this case, 35/28 is 1.25. This is the number you have to multiply to 20. 1.25 * 20 = 25.

The length of the third side of the triangle is 10.7 feet.

Patricia is building a garden in her backyard that is shaped like a triangle. She has already built two sides of the garden  and they have length of 6 feet and 7 feet.

She wants to find the length of the third side. The angles between the the built sides is 110 degrees.

Therefore, let's find the third sides using the included angle and the two known sides.

using cosine rules,

c² = a² + b² - 2ab cos C

c² = 6² + 7² - 2(6)(7) cos 110

c² = 36 + 49 - 84 cos 110°

c² = 85 - 84(-0.34202014332)

c² = 85 + 28.7296920394

c = √113.729

c = 10.6643799632

c = 10.7 feet

Therefore,

third side of the triangle = 10.7 feet

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The graph of the function y = 2x⁴ - 5x³ + x² - 2x + 4 is plotted and attached.

We have the 4 functions as shown in the image attached.

The y - intercept is the point where the graph intercepts the y - axis.

Function [1] -

y = 4 + 2x

y - intercept is 4

Function [2] -

y = 5ˣ + 1

y - intercept is 2.

Function [3] -

the y-intercept is 1.

Function [4] -

the y - intercept is at -1.

Therefore, the greatest y-intercept is of function -

f(x) = 2x + 4

and the least y-intercept is of the function shown in graph [4] or function [4].

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Answer:

Carlos puts $3 into his bank account and it grows by 50% each year

f(x)=4^x+1

(The Table)

(The Graph)

The two inequalities of the graph are:

y ≥ 3x - 1

y < -¹/₂x + 4

The general form of the equation of a line in slope intercept form is:

y = mx + c

where:

m is slope

c is y-intercept

An inequality can be represented graphically as a region on one side of a line. Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region. Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region.

The first inequality with a solid line has a y-intercept of -1 and since it is shaded above the line, we will use ≥.

Two coordinates on the line are: (0, -1) and (1, 2)

The slope = (2 + 1)/(1 - 0) = 3

Thus, inequality is:

y ≥ 3x - 1

The second inequality with a dashed line has a y-intercept of 4 and since it is shaded below the line, we will use <.

Two coordinates on the line are: (4, 0) and (0, 2)

The slope = (2 - 0)/(0 - 4) = -1/2

Thus, inequality is:

y < -¹/₂x + 4

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Answer:

The area of one planter is:

4 1/5 in × 1 1/3 in = (21/5) in × (4/3) in = 28/5 in²

In a 3 x 3 array, there are 3 planters in each row and 3 planters in each column, so there are a total of 9 planters.

The area covered by the planters is:

9 × (28/5) in² = 252/5 in² ≈ 50.4 in²

Therefore, the area covered by the planters is approximately 50.4 square inches.

Step-by-step explanation:

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Answer:

- angle T is congruent to angle U (given)

- NS is congruent to SH (given)

- angle TSN is congruent to USH (vertical angles are congruent)

So triangle TNS is congruent to triangle UHS by AAS.

The z-score for 71 is -1.

z-score is a measure of how many standard deviations an observation or data point is away from the mean of a distribution.

It is calculated by subtracting the mean from the observation and then dividing the result by the standard deviation: z = (x - μ) / σ

A positive z-score means that the data point is above the mean, while a negative z-score means that it is below the mean.

Applying the formula to solve our question

Here is a proven formula to use:

z = (x - μ) / σ

where:

x = the data item (x = 71)

μ = the mean of the distribution (μ = 80)

σ = the standard deviation of the distribution (σ = 9)

Substituting the values, we get:

z = (71 - 80) / 9

z = -1

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Answer:

5x + 3y = - 15

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (0, - 5) ← 2 points on the line

m = [tex]\frac{-5-0}{0-(-3)}[/tex] = [tex]\frac{-5}{0+3}[/tex] = - [tex]\frac{5}{3}[/tex]

the line crosses the y- axis at (0, - 5 ) ⇒ c = - 5

y = - [tex]\frac{5}{3}[/tex] x - 5 ← in slope- intercept form

multiply through by 3 to clear the fraction

3y = - 5x - 15 ( add 5x to both sides )

5x + 3y = - 15 ← in standard form

Answer:

A) oblique hexagonal prism

Step-by-step explanation:

Answer:

right hexagonal prism

Step-by-step explanation:

as seen on the Image below the left one is a right hexagonal prism and the right one is a oblique hexagonal prism.

Answer: 6.5

Step-by-step explanation:

26/4 = 6.5 hours

Both distributions of the total cost of attendance are skewed right

The average cost of attendance is higher for private universities.

The costs of more than 75 % of the public institutions were within the costs of the lowest 25% of private institutions.

Both the range and IQR was higher for private universities

Both distributions have outliers.

A boxplot is a standardized way of displaying the distribution of data based on a five number summary (“minimum”, first quartile [Q1], median, third quartile [Q3] and “maximum”).

It can tell you about your outliers and what their values are

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Answer:

skewed right private 75 private do have outliers

Step-by-step explanation:

[tex]\sin^2(\theta)+\cos^2(\theta)=1\hspace{9em} \begin{array}{llll} \textit{Symmetry Identities} \\\\ \sin(-\theta )=-\sin(\theta) \\\\ \cos(-\theta )=\cos(\theta ) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\cot(-x)\cos(-x)+\sin(-x)\implies \cfrac{\cos(-x)}{\sin(-x)}\cos(-x)+\sin(-x) \\\\\\ \cfrac{\cos(x)}{-\sin(x)}\cos(x)+[-\sin(x)]\implies \cfrac{-\cos^2(x)}{\sin(x)}-\sin(x) \\\\\\ \cfrac{-\cos^2(x)-\sin^2(x)}{\sin(x)}\implies \cfrac{-( ~~ \cos^2(x)+\sin^2(x) ~~ )}{\sin(x)} \\\\\\ \cfrac{-( ~~ 1 ~~ )}{\sin(x)}\implies -\cfrac{1}{\sin(x)}\implies -\csc(x)[/tex]

The coordinates of vertex B' are (76, -86).

In Mathematics and Geometry, a dilation is a type of transformation which typically changes the size of a geometric object, but not its shape.

Next, we would have to dilate the coordinates of the preimage by using a scale factor of 9 centered at the point D (-5, 5) by using this mathematical expression:

(x, y)  →  (k(x - a) + a, k(y - b) + b)

For coordinate B, we have;

Coordinate B = (4, -4)  →  (9(4 - (-5)) + (-5), 9(-4 - 5) + (-5))

Coordinate B = (4, -4)  →  (9(9) - 5, 9(-9) - 5)

Coordinate B = (4, -4)  →  (81 - 5, -81 - 5)

Coordinate B' = (76, -86).

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Complete Question:

ΔABC with vertices at A (-1, -1). B (4,-4), and C (2, -6) is dilated by a scale factor of 9 to create ΔA'B'C'. The center of dilation is the point (5, -6).

What are the coordinates of vertex B'?

Answer:

there is missing information needed to provide a solution to this problem.

Answer:

3.14 (24 square) (2.5)

Step-by-step explanation:

3.14 24 square 2.5

X radius squared X height???

Answer:

15,136 km

Step-by-step explanation:

Im not 100% sure but everyone meses up sometimes/

The likelihood that they will choose to work in an animal shelter for each of the six options they choose is around 0.2214 or 22.14%

The probability is given as,

P = (Favorable event) / (Total event)

The likelihood of choosing an opportunity at an animal shelter is 7/9. If each chance is equally likely to be chosen, the likelihood of choosing six in a row from an animal shelter may be estimated by multiplying the likelihood of choosing one opportunity by itself six times:

P = (7/9) x (7/9) x (7/9) x (7/9)

P = (7/9)⁶

P = 0.2214 or 22.14%

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[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{ \textit{we'll use this one} }{a^{log_a (x)}=x} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \log_5(x-7)=2\implies 5^{\log_5(x-7)}=5^2\implies x-7=5^2 \\\\\\ x-7=25\implies x=32[/tex]

For 3 personal training session both gym cost same.

We have,

At Silver gym, membership is $25 per month and personal training sessions are $30 each.

At Fit Factor, membership is $65 per month, the and personal training sessions are $20 each.

let the number of personal session be x.

So, 25+ 30x = 65 + 20x

30x - 20x = 65 - 25

10x = 30

x= 3 sessions

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The required vertical distance from the top of the slide to the bottom of the pool is 43.8 feet.

We can use trigonometry to solve this problem. Let's call the vertical distance from the top of the slide to the bottom of the pool "h" (in feet). We can use the angle of depression (45°) to find the horizontal distance from the top of the slide to the bottom of the pool. Since the slide has a constant slope, the angle between the slide and the ground is also 45°. It implies that the vertical height is equal to the horizontal projection of the slide.

Apply Pythagorean theorem,
45² = h² + h²
h = 45/√2
h = 31.8

Now, as mentioned that depth of the pool is 12 feet so, the total vertical height is given as,
= h + 12
= 31.8 + 12
= 43.8 feet

Thus, the required vertical distance from the top of the slide to the bottom of the pool is 43.8 feet.

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The  null hypothesis and the alterative hypothesis are [tex]H_0[/tex] : [tex]\mu[/tex] > 1220

[tex]H_\alpha[/tex]: [tex]\mu[/tex] ≤ 1220.

The standardized test statistic is 1.725.

We have,

[tex]\mu[/tex] > 1220,

α = 0.03

[tex]\sigma[/tex] = 202.17

X = 1249.88

n= 300

a) According to the claim and the sample statistics, the null hypothesis and the alterative hypothesis are given by:

[tex]H_0[/tex] : [tex]\mu[/tex] > 1220

[tex]H_\alpha[/tex]: [tex]\mu[/tex] ≤ 1220

b) The standardized test statistic is

=| [tex](\mu[/tex] - X) / ([tex]\sigma[/tex] / √n)|

= |( 1220 - 1249.88) / (202.17/√300)|

= |(-29.88)/ 17.320|

= |-1.725|

= 1.725

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The total weight of all the cantaloupes that weigh more than 2 1 / 2 pounds is 8 2 / 4 lb ​.

As shown on the line plot, the number of cantaloupes with a higher mass than 2 1 / 2 pounds are those which have a weight of 2 3 / 4 pounds.

There are enough of them that when they are added up, we get the sum of 8 2 / 4 lb​ as the total mass of the cantaloupes. This can also be written in decimals as 8. 5 lb.

In conclusion, option D. is correct.

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Answer:

32

Step-by-step explanation:

in the word problem “256 chairs in the cafeteria. this is 8 times the chairs in the library.” Which means 8 times the number of chairs in the library equals the number of chairs in the cafeteria.

L = library

8 x L = 256

to find L divided 256 by 8

256/8 = 32

L = 32

Check the answer

8 x 32 = 256