completely factor: 4t + 2rt + 8st

Answer:

14824

Step-by-step explanation:

the product is 14824

Answer:

3-6 I think

Step-by-step explanation:

m = 36

Work

45 + 2.50m = 3.75m

       -3.75m    -3.75m

45 - 1.25m = 0

- 45             - 45

-1.25m = -45

-1.25     -1.25

    m = 36

Answer:

Step-by-step explanation:

Using the formula for calculating confidence interval

CI = xbar±z×S/√n

xbar is the mean of the sample

z is the z score at 90% = 1.645

S is the standard deviation of the score

n is the sample size = 26

Since we are not given the scores, we can assume the values of our mean and standard Deviation

Let xbar = 38

S = 3.0

Substitute the given values into the formula

CI = 38±(1.645×3.0/√26)

CI = 38±(1.645×3.0/5.099)

CI = 38±(1.645×0.5884)

CI = 38±0.9678

CI = (38-0.9678, 38+0.9678)

CI = (38.0322, 38.9678)

CI = (38.0, 38.9)

Hence the 90% confidence interval for the true mean of statistics exam scores is 38.0≤p≤38.9

Note that the we will need to generate the mean and standard deviation from the data but since we are not given the required data, we had to assume the value we used in calculation.

Answer:

Neither Dom or Riley is correct

Step-by-step explanation:

The change in temperature between 12PM and 6AM can be obtained by subtracting the 12PM temperature from the 6AM temperature because temperature increases as the hours of the day go by.

To carry out this subtraction on the number line, the following steps should be taken;

(i) Mark the numbers corresponding to 6AM and 12PM temperatures on same number line.

(ii) From the number corresponding to the 12 PM temperature, find out how many steps that are needed to reach the position of the number corresponding to the 6AM temperature.

This number of steps represents the temperature change between the 12PM temperature and the 6 AM temperature.

Answer:

8333333333/100000000000 i think

Answer:

83/100

Step-by-step explanation:

SP of a machine = Rs. 990

Profit% = 10 %

SP of other machine = Rs. 1960

loss% = 2 %

his gain or loss percentage​

We know that,

CP * (100 + profit%)/100 = SP

So,

First machine :

CP * (100 + 10)/100 = 990

⟹ CP = 990 * 100/110

⟹ CP = Rs. 900

Second machine :

We know that,

CP * (100 - loss%)/100 = SP

⟹ CP * (100 - 2)/100 = 1960

⟹ CP = 1960 * 100/98

⟹ CP = Rs. 2000

Now,

We have to find the total loss or profit percentage.

We observe that,

SP > CP.

so, a gain is occured.

gain % = gain/CP * 100

gain = SP - CP

So,

gain% = (2950 - 2900)/2900 * 100

⟹ gain% = 50/29

⟹ gain% = 1.72 %

∴ A gain of 1.72% is occured in the whole transaction.

I hope it will help you.

Regards.

Answer:

HELLO SISO❤

IT'S ME YIREN

Step-by-step explanation:

→ CP of machine = (SP * 100) / (100 + Profit%) = (990 * 100) / (100 + 10) = (990 * 100) / 110 = Rs. 900 . Case 2) :- shopkeeper sells another machine for Rs. 1960 at a loss of 2%

Answer:

L = [tex]5 \frac{1}{6} cm = \frac{31}{6} [/tex] cm

B = [tex]2 \frac{2}{7}cm = \frac{16}{7} [/tex]cm

Area = [tex] \frac{31}{6} cm \times \frac{16}{7}cm = \frac{496}{42}cm^{2} [/tex]

[tex]11 \frac{34}{42}cm^{2} [/tex]

[tex] = 11\frac{17}{21}cm^{2} [/tex]

Answer:

1. Add 4 to both sides. 3x-4+4=8+4

2. Divide 3 from both sides. 3x/3=12/3

3. Solution. x=4.

Step-by-step explanation:

Answer:

9 R 1

Step-by-step explanation:

73/8 = 9 R 1

we know 8x 9 = 72 so we know we have a remainder of 1

=========================================================

Work Shown:

A = 1+sqrt(2)

B = 1-sqrt(2)

-------------------

Using A and B, let's add and subtract those values

A+B = (1+sqrt(2))+(1-sqrt(2))

A+B = 1+sqrt(2)+1-sqrt(2)

A+B = 1+1+sqrt(2)-sqrt(2)

A+B = 2

and

A-B = (1+sqrt(2))-(1-sqrt(2))

A-B = 1+sqrt(2)-1+sqrt(2)

A-B = 1-1+sqrt(2)+sqrt(2)

A-B = 2sqrt(2)

-------------------

Next, square both sides of the A equation

A^2 = (1+sqrt(2))^2

A^2 = (1+sqrt(2))(1+sqrt(2))

A^2 = 1(1+sqrt(2))+sqrt(2)(1+sqrt(2))

A^2 = 1+sqrt(2)+sqrt(2)+sqrt(2)*sqrt(2)

A^2 = 1+2sqrt(2)+2

A^2 = 3+2sqrt(2)

-------------------

Do the same for B

B^2 = (1-sqrt(2))^2

B^2 = (1-sqrt(2))(1-sqrt(2))

B^2 = 1(1-sqrt(2))-sqrt(2)(1-sqrt(2))

B^2 = 1-sqrt(2)-sqrt(2)-sqrt(2)*(-sqrt(2))

B^2 = 1-2sqrt(2)+2

B^2 = 3-2sqrt(2)

There's a bit of nice symmetry going on with A^2 and B^2, due to A and B having similar symmetric structures themselves.

-------------------

Lets add A^2 to B^2

A^2+B^2 = (3+2sqrt(2)) + (3-2sqrt(2))

A^2+B^2 = 3+2sqrt(2) + 3-2sqrt(2)

A^2+B^2 = 3+3+2sqrt(2)-2sqrt(2)

A^2+B^2 = 6

-------------------

Now onto the final event

We'll use the difference of squares rule twice

Afterward, apply substitution using the previous sections above.

A^4 - B^4 = (A^2)^2 - (B^2)^2

A^4 - B^4 = (A^2-B^2)(A^2+B^2)

A^4 - B^4 = (A-B)(A+B)(A^2+B^2)

A^4 - B^4 = (2sqrt(2))(2)(6)

A^4 - B^4 = 2*6*2*sqrt(2)

A^4 - B^4 = 24*sqrt(2)

(1+sqrt(2))^4 - (1-sqrt(2))^4 = 24*sqrt(2)

-------------------

To check this with your calculator, you can type in the following

(1+sqrt(2))^4 - (1-sqrt(2))^4 - 24*sqrt(2)

The result you should get should be 0, or very close to it

I'm using the property that if x = y, then x-y = 0.

Answer:

A (-7,0)

Step-by-step explanation:

I just drew it cause it's way easier than typing out :)

Answer: 320 grams

Step-by-step explanation:

Let the mas of the teapot be denoted by a

Let the mass of the cups be denoted by c

The question can be turned into an equation which will be:

a + 4c = 1280 ......... equation i

a + 10c = 2720 ........ equation ii

Subtract equation i from ii

6c = 1440

c = 1440/6

c = 240 grams

The mas of the cup is 240 grams

From equation i

a + 4c = 1280

a + 4(240) = 1280

a + 960 = 1280

a = 1280 - 960

a = 320 grams

The mass of the teapot is 320 grams

Step-by-step explanation:

Original formula: T^2 = 2p + as

T^2 - 2p = as

s = (T^2 - 2p) / a

Answer:

C

Step-by-step explanation:

Apex

The value of function of g (x) is,

⇒ g (x) = 2∛z

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The function g(x) is a transformation of the cube root parent function,

The function is,

⇒ f (x) = ∛z

Now, After translation we get;

The value of function of g (x) is,

⇒ g (x) = 2∛z

Thus, The value of function of g (x) is,

⇒ g (x) = 2∛z

Learn more about the function visit:

https://brainly.com/question/11624077

#SPJ7

Answer:

Step-by-step explanation:

m + $37.07 = $55.29

$55.29 - $37.07 = $18.22

Hope this helps and pls do mark me brainliest if you can:)

Answer:

3x^2-x-2 or (x+1) (3x-2) (x-2)

Step-by-step explanation:

I'm assuming you have to divide:

(x-2)[tex]\sqrt{3x^3-5x^2-4x+4}[/tex]

Hope this helps.

Answer:

p(x)=(x+1)(3x-2)(x-2)

Step-by-step explanation:

Answer: B) The value of s(x) depends on the value of x, since s is a function of x.

It's similar to f(x) or g(x) function notation, but now we're using the letter s.

The x is the input of the function. The output is s(x). So that's why s(x) depends on x.

Answer:

D i'm pretty sure

Step-by-step explanation:

Answer: $2.19

Step-by-step explanation: you have to find the surface area. Add 10*7*2 and 7*1.25*2 and 1.25*10*2 and then multiply by 0.012! Then you can get your answer. (17.5 + 140 + 25)*0.012. I think this is right. Sorry if itś not.

Answer:

[tex]\frac{4a-2}{2a+1}[/tex]

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

[tex]\frac{8a^2-2}{4a^2+4a+1}[/tex]

= [tex]\frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)}[/tex] ← cancel (2a + 1) on numerator/ denominator

= [tex]\frac{2(2a-1)}{2a+1}[/tex]

= [tex]\frac{4a-2}{2a+1}[/tex]

Answer:

I'm sorry but I don't know how to do function notation. I'm so sorry that I couldn't help you with this.

Answer:

x = undefined

Step-by-step explanation:

Expand brackets

4x - 1 = 4x + 4

Rearrange and make like terms next to each other

4x - 4x = 4 + 1

0x = 5

x = 5/0

when 0 is the denominator the answer is undefined

Answer: from what i calculated there is no solution

Step-by-step explanation:

Answer:

I cant see

Step-by-step explanation:

Answer:

dont have an answer yet...question too small to see...

Step-by-step explanation:

Answer:

10,500.93 feet

Step-by-step explanation:

From the question, we are told that Tom walks 3.2km every morning.

1 mile = 1.609km

1 mile = 5280 feet

Step 1

1.609km = 1 mile

3.2km = x mile

Cross Multiply

x mile × 1.609km = 3.2km × 1 mile

x mile = 3.2km × 1 mile/1.609.

= 1.9888129273 miles

1 mile = 5280 feet

1.9888129273miles = y

Cross Multiply

y = 1.9888129273 × 5280 feet/1 mile

= 10500.932256 feet

Approximately = 10,500.93 feet

Therefore, Tom walks for 10,500.93 feet

10560

Answer:

10,500.93 feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

A quadratic equation has equal/repeated solutions when a discriminant (Δ) is equal 0.

The formula of a discriminant (Δ) of equation

[tex]ax^2+bx+c=0\\\\\Delta=b^2-4ac[/tex]

We have the equation

[tex]4x^2+8x+p=0\to a=4;\ b=8;\ c=p[/tex]

substitute

[tex]\Delta=8^2-4\cdot4\cdot p=64-16p\\\\\Delta=0\iff64-16p=0[/tex]

subtract 64 from both sides

[tex]-16p=-64[/tex]

divide both sides by (-16)

[tex]\dfrac{-16p}{-16}=\dfrac{-64}{-16}\\\\p=4[/tex]

Answer:

f(5)=225 and f(10)=250

Step-by-step explanation:

Answer:

Step-by-step explanation:

23.74, .43, .2734, .0347, .0043