Can someone please help me with this question (there are more questions like this that I will post later, if your answer is correct I will give you brainliest)

Answer:

Um

Step-by-step explanation:

Answer:

Step-by-step explanation:

60-10=50

they washed 50 cars.

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step explanation:

Answer:

x=14

Step-by-step explanation:

3+1.50x=24

24-3=21

21/1.50=14

Answer is C which is 14

Answer:

Step-by-step explanation:

From the information given;

We are to take a look at a 2⁵ factorial design.

The factorial design consists of carrying out the design of equipment by testing it by modifying not the parameters one by one but by modifying several simultaneous parameters.

An experiment is termed to be a 2⁵ factorial experiment if in the experiment 5 factors are studied consecutively with each at two-level.

Thus, there are five factors and 2 levels in the experiment.

Answer:

Someone text me on sc queenalyssa_05

Step-by-step explanation:

Answer:5

Step-by-step explanation:

Answer:

its c

Step-by-step explanation:

trust and dont vote me out! its not me i sware its cyan he sus!

Answer:

It's C

Step-by-step explanation:

Answer:

-3.21

Step-by-step explanation:

If you pay close attention the numbers are 5 points away from each other, so after -3.2 is -3.21! Hope that helped love :)

Answer:

x = 39

Step-by-step explanation:

A circle is made up of 360 degrees

235+ 54+ x+32 = 360

Combine like terms

x+321=360

Subtract 321 from each side

x+321-321 = 360-321

x = 39

Answer:

x is equal to -1/3

hope this helps

Answer: I'm pretty sure x = 3

Step-by-step explanation: 3 times 3 = 9. 9 + 15 = 24. And when I solve for x it equals 3.

Answer:

-4( 3a+4)

Step-by-step explanation:

-12a - 16

-4*3a -4*4

Factor out a -4

-4( 3a+4)

Answer:

L = 20

W = 10

Step-by-step explanation:

L = (w + 10)

NL = (w + 13)

Divide 299 by 13:

299 ÷ 13 = 23

So, 23 x 13 = 299

L = 23

W = 13

Subtract 3 from both to get the original length and width

Answer:

Jiao sent out 18,920 beads.

Step-by-step explanation:

All I did was add.

</3 hope this helps.

Since Kyle invested $500 and received $650 after three years, the value of Kyles's interest rate is 43.3%.

Given the following data:

To calculate the value of Kyles's interest rate:

Mathematically, simple interest is given by the formula:

[tex]S.I = \frac{PRT}{100}[/tex]

Where:

Making R the subject of formula, we have:

[tex]R = \frac{100S.I}{PT}[/tex]

Substituting the given parameters into the formula, we have;

[tex]R = \frac{100 \times 650}{500 \times 3}\\\\R = \frac{65000}{1500}[/tex]

Interest rate, R = 43.3%

Read more: https://brainly.com/question/22621039?referrer=searchResults

Answer:

8.49 per pair/pack of gloves

Step-by-step explanation:

i got this by taking 33.96 divided by 4 so i could find out how much for one pair

Answer:

70 is the answer to the question

Answer:

[tex]70^{o}[/tex]

Step-by-step explanation:

Opposite angles in a parallelogram are equal. The opposite angle to A is C and we are trying to find angle C. Therefore, <C = <A, therefore, <c= 70 degrees

Answer:

Not 100% sure on this make sure you double check

Step-by-step explanation:

X- 10          

Y- 10

Slope- (-1)

like I said this could be wrong  

Answer:

11.8% Decrease

Step-by-step explanation:

I googles it i am sorry if it's not right

Answer:

this is what i did i apologize if i’m late and u no longer need the answer or if i’m wrong

Step-by-step explanation:

Answer:

-

Step-by-step explanation:

I took the test

The correct operator that enters a circle is a subtraction sign.

Given the expressions

[tex](4x^5-8x) ()(3x^2-8x+9)[/tex]

We need to know which sign goes into the bracket that will give a trinomial when simplified.

A trinomial is a function containing 3-terms.

Using the subtraction sign.

[tex](4x^5-8x) - (3x^2-8x+9)[/tex]

Expand

[tex]= 4x^5-8x - 3x^2+8x-9\\= 4x^5-3x^2-8x+8x-9\\=4x^5-3x^2+0-9\\=4x^5-3x^2-9[/tex]

Since the resulting term is a trinomial (3 terms), hence the correct operator that enters a circle is a subtraction sign.

Learn more here: https://brainly.com/question/1320408

Answer:

270 miles and 180 minutes

Step-by-step explanation:

There are 4 living fish, but unless the dead one was taken from the tank, there are still 5 fish in the tank.

Answer: graph b

Step-by-step explanation:

Answer:

its line fjfjfjjejjdjdj

As per the given condition, the required one dimensional object with no end point is a line.

"In geometry, a ray can be defined as a part of a line that has a fixed starting point but no end point. It can extend infinitely in one direction.

On its way to infinity, a ray may pass through more than one point. When naming a ray, it is denoted by drawing a small ray on top of the name of the ray. "

"A line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints."

"A line is a one-dimensional object, which has length but no width. A line is made of a set of points which is extended in opposite directions infinitely. It is determined by two points in a two-dimensional plane. "

"A point is a primitive notion that models an exact location in the space, and has no length, width, or thickness. In modern mathematics, a point refers more generally to an element of some set called a space."

Given, a one dimensional object with no endpoint.

Therefore, the require object is a line.

Learn more about a line here: https://brainly.com/question/27560536

#SPJ2

Answer:

bout 7

Step-by-step explanation:

Answer:3.049533e+44 to be exact

Step-by-step explanation:

Answer: Images of Graphs are listed below. I am unsure on how to conduct the second part. but there is the first part

Step-by-step explanation:

Answer:

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Step-by-step explanation:

The objective of this question is to solve:

[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]

Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:

Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:

i.e.

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]

To Replace:

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]

[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]

[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]

Thus;

[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0

[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]

∴

In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:

[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]

By Factorization:

[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]

[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]

However;

The root [tex]\lambda = -6 \pm i[/tex] yield;

[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]

[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]

The root [tex]\lambda = 3[/tex] yield;

[tex]y_3(x) = c_3 e^{3x}[/tex]

∴

The general solution is:

[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]

Using Euler's Identity ;

[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]

[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]