Answers
Answer:
447.64 grams
Explanation:
To find the mass when given moles, it is a pretty simple process.
I start by finding the molar mass of chloric acid, which comes out to 84.46 grams/mol. To find the MM (molar mass), you just take the mass of each element in the molecule from the periodic table and add them all together.
After this, you set up the equation by taking the moles given and multiplying it by the molar mass. This gives you the new value in grams (since we cancelled out the moles). I have attached my work below.
I hope this helps! :^)
The mass of 5.3 moles chloric acid has been 447.85 g.
The mass of 1 mole of a compound has been equivalent to the molar mass of the compound. The molar mass of a compound has been the sum of the constituent atoms in a formula unit.
The molar mass (mwt) of chloric acid has been given as:
[tex]mwt=m_H\;+\;m_C_l\;+\;(m_O\;\times\;3)[/tex]
By substituting the values for the mass of constituent atoms, the molar mass has been given as:
[tex]mwt=1\;+\;35.5\;+\;16\;\times\;3\\mwt=36.5\;+\;48\\mwt=84.5[/tex]
The molar mass of chloric acid has been 84.5 g/mol.
The mass of 1 mole of chloric acid has been 84.5 g/mol. The mass of 5.3 moles chloric acid has been:
[tex]\rm 1\;mol=84.5\;g\\5.3\;mol=5.3\;\times\;84.5\;g\\5.3\;mol=447.85\;g[/tex]
The mass of 5.3 moles chloric acid has been 447.85 g.
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Related Questions
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Answers
Answer:
CH4(g)+2O2(g)→CO2(g)+2H2O(g)
Explanation:
For a complete combustion reaction of a hydrocarbon, oxygen is always one of the reactants, and the products are always carbon dioxide and water.
help me. correct answer will be marked as brnlst
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How many aluminum ions are present in 65.5 mL of 0.210 M All3solution?
Answers
Answer:
Aluminium ions present's in 65.5mL of 0.210
M All 3solution is Given below-:
Answer and Explanation: 1
The first step is to determine the moles of aluminum ions. This utilizes the volume, molar concentration, and subscripts from the chemical formula of aluminum (III) fluoride as shown.
65.5 mL×1 L1000 mL×0.210 mol AlF31 L×1 mol Al3+1 mol AlF3=0.013755 mol Al3+65.5 mL×1 L1000 mL×0.210 mol AlF31 L×1 mol Al3+1 mol AlF3=0.013755 mol Al3+
To calculate for the number of aluminum ions, we use Avogadro's number as shown.
0.013755 mol Al3+×6.022×1023 ions1 mol Al3+=8.28×1021 ions Al3+.
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Answer:
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Explanation:
The first step is to determine the moles of aluminum ions. This utilizes the volume, molar concentration, and subscripts from the chemical formula of aluminum (III) fluoride as shown.
65.5. To calculate for the number of aluminum ions, we use Avogadro's number as shown.
What is the concentration of chloride ions in solution after the reaction of 5.8 mL 0.12 M ammonium chloride with 3.2 mL 0.21 M silver nitrate
Answers
Answer:
ok
Explanation:
Find the volume of 0.160 M sulfuric acid necessary to react completely with 75.0 g sodium hydroxide.
Answers
The volume of 0.160 M sulfuric acid necessary to react completely with 75.0 g sodium hydroxide is 0.15L
The reaction of sulphuric acid and sodium hydroxide is expressed as:
[tex]2NaOH + H_2SO_4 ==> Na_2SO_4 + 2H_2O[/tex]
Determine the moles of NaOH present
Molar mass of NaOH = 23 + 16 + 1 = 40g/mole
Given that mass of NaOH is 75.0g
Mole of NaOH = 75/40 = 1.875moles
Determine the number of moles [tex]H_2SO_4[/tex] needed to react with 1.875 moles NaOH
Moles of [tex]H_2SO_4[/tex] = [tex]\frac{1.875}{2} = 0.9375moles of H_2SO_4[/tex]
Recall that volume = Molar mass * number of moles
Volume of [tex]H_2SO_4[/tex] = 0.160 * 0.9375
Volume of [tex]H_2SO_4[/tex] = 0.15L
Hence the volume of 0.160 M sulfuric acid necessary to react completely with 75.0 g sodium hydroxide is 0.15L
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Describe two or three ways in which the measurements you made could lead to errors in the results. Explain how each error would affect the answer of molar mass. In other words, would the molar mass go up or down and why
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Explanation:
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Be sure to answer all parts. Select the anti periplanar geometry for the E2 reaction of (CH3)2CHCH2Br with base. mc2x mc2xd1 mc2xans mc2xd2 Then draw the product that results after elimination of HBr. draw structure ...
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The anti periplanar geometry for the E2 reaction of (CH3)2CHCH2Br with base is shown in the image attached as well as the structure of the product formed in the reaction.
In organic chemistry, an antiperiplanar conformation is one in which the groups point up and down at a dihedral angle of 180° away from one another. In the image attached, the antiperiplanar conformation of (CH3)2CHCH2Br is shown.
Recall that an E2 reaction is a synchronous elimination reaction where to atoms leave at the same time. The product of this reaction is also shown in the image attached.
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the role of haemoglobin in the transport of oxygen and carbon dioxide
Answers
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Airflow through a long 0.2m square air conditioning duct maintained the outer duct surface temperature at 10degree.if the horizontal duct is uninsulated and exposed to air at 35degree in the crawl space beneath at home.
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Answers
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Explanation:
The difference in temperature will be:
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If you're American, this will be °F I believe, so the answer will be:
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HELP PLEASE I WILL GIVE BRAINLIEST PLEASE HELP ME
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Answer:
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Answers
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Answers
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Explanation:
A piece of potato had an original mass of 3.2g and after being left in a sugar solution for 24 hours it then had a mass of 2.8g. Calculate the percentage mass decrease of the potato.
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May kwento po ba yan o yan na talaga
Wyndirbu lie the following best describes the role played by
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С
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Hope that helps you out.
What is the molarity of Ca(NO3)2 in a solution resulting from mixing 150.0 mL of 0.200 M HNO3 with 150.0 mL of 0.0100 M Ca(OH)2
Answers
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Answer:
translation to English please
What is measurement??
0000000000
Answers
measurement is the process of finding the value of any Unknown physical quantities in standard value.
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Measurement has been defined as the concept widely used in math and science to quantify an object. It is used to denote the quantification of the event or the object with respect to other or individually.
Hence, the definition of measurement is the process of determining the size or smallness of a physical amount by comparing it to a reference quantity of the same kind as the object.
It has been used to determine the quantity to be small or large based on some predetermined standard or values. It compares the physical quantity like mass can be estimated using kilograms or grams.
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