Calculate the correlation coefficient of the following data:
X
1
4
8
6
2
y
9
16
22
24
12

Answer:

41

Step-by-step explanation:

a^2+b^2=c^2

So...

40^2+9^2=1681

√1681=41

We can factor the polynomial as:-32a^2 - 82a + 31 = 32(a - \frac{1}{2})(a - \frac{31}{32})

.To make the polynomial 32a^2 - 82a + C factorable, we need to find an integer value for C such that the quadratic expression can be factored into two binomials.

To do this, we can use the formula for the discriminant: b^2 - 4ac. Since we want the discriminant to be a perfect square, we can set it equal to some integer k^2 and solve for C:

82^2 - 4(32)(C) = k^2

6724 - 128C = k^2

We can try different values of k and solve for C until we find an integer solution. For example, if we let k = 10, we get:

10^2 = 6724 - 128C

C = 31

To verify that this value of C works, we can factor the trinomial using the X formula:

a = 32, b = -82, c = 31

X = (-b ± sqrt(b^2 - 4ac)) / 2a

X = (82 ± sqrt(82^2 - 4(32)(31))) / 2(32)

X = (82 ± 8) / 64

So, the roots of the quadratic are:

a = 32, X1 = 1/2, X2 = 31/32

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The distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

To solve this problem, we can use the law of cosines to find the length of AC and the law of sines to find the angle at A.

First, we can use the given information to draw a diagram and label the angles and sides:

       C

      / \

     /   \

 5 /     \ 7

   /       \

  /         \

A /___θ_____\ B

From the given information, we know that:

AB = 7 km

BC = 5 km

∠ABC = 100° (since ∠ABD = 180° - 30° - 70° = 80° and ∠DBC = 180° - 280° = 100°)

Using the law of cosines, we can find the length of AC:

AC^2 = AB^2 + BC^2 - 2ABBCcos(∠ABC)

AC^2 = 7^2 + 5^2 - 2(7)(5)cos(100°)

AC^2 ≈ 41.84

AC ≈ 6.47 km

Next, we can use the law of sines to find the angle at A:

sin(∠CAB)/AC = sin(∠ABC)/AB

sin(∠CAB)/6.47 = sin(100°)/7

sin(∠CAB) ≈ 0.276

∠CAB ≈ 16.2°

To find the bearing of A from C, we can use the fact that the bearing is the angle measured clockwise from north. Since ∠CAB is acute and the bearing of B from A is 30° east of north, the bearing of A from C is:

360° - (30° + ∠CAB) ≈ 313.8°

Finally, to find the area of triangle ABC, we can use the formula:

Area = (1/2)ABBCsin(∠ABC)

Substituting the given values, we get:

Area = (1/2)(7)(5)sin(100°)

Area ≈ 14.8 km²

Therefore, the distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

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Answer:

Step-by-step explanation:

Answer:

vfejwbjelkn

Step-by-step explanation:

Answer:

[tex]\dfrac{dy}{dx}=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

Step-by-step explanation:

Note: I will provide links with descriptions/steps to each of the rules used in this differential equation at the bottom of this answer.

Given

[tex]-26x^2+4x^{39} y+y^9=-21[/tex]

Find [tex]\dfrac{dy}{dx}[/tex]

Differentiate the left side of the equation.

[tex]\dfrac{d}{dx}\left(-26x^2+4x^{39}y+y^9\right)= \dfrac{d}{dx}\left(-21\right)[/tex]

Focus the left side of the equation.                                                         Apply the Sum Rule for derivatives.

[tex]\dfrac{d}{dx} \left[-26x^2\right]+\dfrac{d}{dx} \left[4x^{39}y\right]+\dfrac{d}{dx} \left[y^9\right][/tex]

Lets evaluate each derivative.

1.   Evaluate [tex]\frac{d}{dx} \left[-26x^2\right][/tex]

Differentiate using the Power Rule for derivatives.

[tex]\dfrac{d}{dx} \left[-26x^2\right]=2*26x^{2-1}[/tex]

Simplify.

[tex]2*-26x^{2-1}\\-52x^{2-1}\\-52x[/tex]

2.   Evaluate [tex]\frac{d}{dx} \left[4x^{39}y \right][/tex]

Differentiate using the Product Rule for derivatives.

[tex]4\left(x^{39}\dfrac{d}{dx}\left[y\right]+y\dfrac{d}{dx}\left[x^{39}\right]\right)[/tex]

Rewrite  [tex]\dfrac{d}{dx}\left[y\right][/tex] as [tex]y'[/tex]

[tex]4\left(x^{39}y'+y\dfrac{d}{dx}\left[x^{39}\right]\right)[/tex]

Differentiate using the Power Rule for derivatives.

[tex]4\left(x^{39}y'+y\left(39x^{39-1} \right)\right)[/tex]

Simplify.

[tex]4\left(x^{39}y'+39yx^{38} \right)[/tex]

3.   Evaluate [tex]\frac{d}{dx} \left[y^9\right][/tex]

Differentiate using the Chain Rule for derivatives.

[tex]9y^8\dfrac{d}{dx} \left[y\right][/tex]

Rewrite  [tex]\dfrac{d}{dx}\left[y\right][/tex] as [tex]y'[/tex]

[tex]9y^8y'[/tex]

Add up all of the derivatives then simplify.

[tex]-52x+4\left(x^{39}y'+39yx^{38} \right)+9y^8y'[/tex]

[tex]-52x+4\left(x^{39}y'\right)+4\left(39yx^{38} \right)+9y^8y'[/tex]

[tex]-52x+4x^{39}y'+156yx^{38}+9y^8y'[/tex]

[tex]4x^{39}y'+156x^{38}y+9y^8y'-52x[/tex]

Focus the right side of the equation.

[tex]\dfrac{d}{dx}\left(-21\right)[/tex]

Since [tex]-21[/tex] is constant with respect to [tex]x[/tex] , the derivative of [tex]-21[/tex] with respect to [tex]x[/tex] is 0 .

Now we have

[tex]4x^{39}y'+156x^{38}y+9y^8y'-52x=0[/tex]

Finally lets solve for [tex]y'[/tex].

Subtract [tex]156x^{38}y[/tex] from both sides of the equation.

[tex]4x^{39}y'+9y^8y'-52x=-156x^{38}y[/tex]

Add [tex]52x[/tex] to both sides of the equation.

[tex]4x^{39}y'+9y^8y'=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]4x^{39}y'[/tex]

[tex]y'\left(4x^{39}\right) +9y^8y'=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]9y^8y'[/tex]

[tex]y'\left(4x^{39}\right)+y'\left(9y^8\right)=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]y'\left(4x^{39}\right)+y'\left(9y^8\right)[/tex]

[tex]y'\left(4x^{39}+9y^8\right)+=-156x^{38}y+52x[/tex]

Divide each term by [tex]4x^{39}+9y^8[/tex]

[tex]\dfrac{y'\left(4x^{39}+9y^8\right)}{4x^{39}+9y^8} =\dfrac{-156x^{38}y}{4x^{39}+9y^8} +\dfrac{52x}{4x^{39}+9y^8}[/tex]

Cancel the common factor of [tex]4x^{39}+9y^8[/tex] on the left side of the equation.

[tex]y'=\dfrac{-156x^{38}y}{4x^{39}+9y^8} +\dfrac{52x}{4x^{39}+9y^8}[/tex]

Combine the numerators over the common denominator.

[tex]y'=\dfrac{-156x^{38}y+52x}{4x^{39}+9y^8}[/tex]

Factor [tex]52x[/tex] out of [tex]-156x^{38}y+52x[/tex] and simplify.

[tex]y'=\dfrac{52x\left(-3x^{37}y\right)+52x}{4x^{39}+9y^8}[/tex]

[tex]y'=\dfrac{52x\left(-3x^{37}y\right)+52x(1)}{4x^{39}+9y^8}[/tex]

[tex]y'=\dfrac{52x\left(-3x^{37}y+1\right) }{4x^{39}+9y^8}[/tex]

[tex]y'=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

Rewrite [tex]y'[/tex] as [tex]\dfrac{dy}{dx}[/tex].

[tex]\dfrac{dy}{dx}=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

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Jacobi measured the diagonals of three TV screens as 5/84 inches, 46 inches and 46. 625 inches.

The lengths of the diagonals in ascending order are 5/84 inches, 46 inches, and 46.625 inches.

The diagonals of the three TV displays are 5/84, 46, and 46.625 inches, respectively.

To determine the ascending order of the diagonals, we first convert the fraction 5/84 to a decimal. We may accomplish this by dividing 5 by 84 with a calculator or long division, yielding:

0.05952381

We can now contrast the three diagonal lengths:

0.05952381 inches

46 inches

46.625 inches

Hence, in increasing order, the diagonals are:

0.05952381 inches

46 inches

46.625 inches

As a result, the diagonal lengths in ascending order are 0.05952381 inches, 46 inches, and 46.625 inches.

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Answer:

12

Step-by-step explanation:

p(x) = 2(-3x+5)+2(x+4)

Substitution :

p(2) = 2(-3(2) +5) + 2(2+5)
= 2(-6 + 5) + 2 (7)
= 2(-1) + 2(7)
= -2 + 14
= 12

Answer:

Yardley is approximately 5.7 miles away from the airport.

Step-by-step explanation:

Let's use the following variables:

x = distance between Yardley and the airport

Using the Pythagorean theorem:

x^2 + 7^2 = 9^2

x^2 + 49 = 81

x^2 = 32

x = sqrt(32)

x ≈ 5.7

Therefore, Yardley is approximately 5.7 miles away from the airport.

Answer:

5.7 miles

Step-by-step explanation:

To find:-

Answer:-

We are given that airport and Wildgrove are 7miles apart and the distance between Yardley and Wildgrove is 9miles . We are interested in finding out tge distance between Yardley and airport.

As you can see from the figure attached, the distance can be calculated using Pythagoras theorem ,

[tex]\rm\implies a^2+b^2 = h^2 \\[/tex]

where ,

Here the longest side is 9 miles and one other side is 7 miles . On substituting the respective values, we have;

[tex]\rm\implies a^2 + (7)^2 = 9^2 \\[/tex]

[tex]\rm\implies a^2 + 49 = 81 \\[/tex]

[tex]\rm\implies a^2 = 81 - 49 \\[/tex]

[tex]\rm\implies a^2 = 32 \\[/tex]

[tex]\rm\implies a =\sqrt{32} \\[/tex]

[tex]\rm\implies a = 5.65 \\[/tex]

[tex]\rm\implies \red{ a = 5.7 } \\[/tex]

Hence the distance between Yardley and airport is 5.7 miles .

By simplification the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form is[tex]y = (x + 1/2)^2 - 33/4[/tex], and its vertex is (-1/2, -33/4).

What is the vertex form of a quadratic equation?

The standard form of a quadratic function is:

[tex]y = ax^2 + bx + c[/tex]

where a, b, and c are constants and x is the variable.

The vertex form of a quadratic function is:

[tex]y = a(x - h)^2 + k[/tex]

where a, h, and k are constants and (h, k) is the vertex of the parabola.

To write the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form, we need to complete the square. The vertex form of a quadratic function is given by:

[tex]y = a(x - h)^2 + k[/tex]

where (h, k) is the vertex of the parabola.

So, first we need to factor out the coefficient of the x^2 term:

[tex]y = 1(x^2 + x) - 8[/tex]

Now, we need to complete the square for the expression inside the parentheses:

[tex]y = 1(x^2 + x + 1/4 - 1/4) - 8[/tex]

[tex]y = 1[(x + 1/2)^2 - 1/4] - 8[/tex]

Finally, we can simplify and write the function in vertex form:

[tex]y = (x + 1/2)^2 - 33/4[/tex]

Therefore, the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form is[tex]y = (x + 1/2)^2 - 33/4[/tex], and its vertex is (-1/2, -33/4).

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According to the question the exponential function that goes through the two points is: [tex]y = 4(9^x).[/tex]

Given,

We must first determine the values of a and b before we can build an exponential function with the form y = abx that passes through the points (0,4) and (2,324).

Using the point (0,4), we have:

4 = ab^0

4 = a(1)

a = 4

Using the point (2,324), we have:

324 = 4b^2

b^2 = 81

b = 9 (since b must be positive)

So the exponential function that goes through the two points is:

y = 4(9^x)

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The properties of the least squares line are that the intercept represents the estimated base appraised value for any house in East Meadow, and the slope represents the estimated increase in appraised value for each additional room in the house.

The properties of the least squares line, ? = 74.80 + 19.72x, are as follows:
1. The intercept, ?0, is 74.80. This represents the estimated base appraised value for any house in East Meadow, regardless of the number of rooms. However, there is no practical interpretation for this value, since a house with 0 rooms is nonsensical.

2. The slope, ?1, is 19.72. This represents the estimated increase in appraised value for each additional room in the house. For each additional room in the house, we estimate the appraised value to increase $19,720.

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The polygon has 12 sides and each angle has a measure of 30°.

The border of a Susan B. Anthony dollar is in the shape of a regular polygon. A regular polygon is a polygon with equal sides and equal angles. To calculate the number of sides and measure of the angles, the formula for finding the measure of the interior angles of a regular polygon is used. The formula is (n-2)180/n where n is the number of sides. For the Susan B. Anthony dollar, the number of sides is 12, so the measure of the interior angles is (12-2)180/12 = 30°. Therefore, the polygon has 12 sides and each angle has a measure of 30°, rounded to the nearest degree.

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The probability of rolling a 1 and spinning section A on the spinner is 1/24.

To find the probability of rolling a 1 and spinning section A on the spinner, we need to first determine the total number of possible outcomes for the experiment. The number cube has 6 possible outcomes, and the spinner has 4 possible outcomes. Therefore, the total number of possible outcomes for the experiment is 6 x 4 = 24.

Next, we need to determine the number of outcomes that meet the criteria of rolling a 1 and spinning section A. Rolling a 1 has a probability of 1/6, and spinning section A has a probability of 1/4.

The probability of both events occurring simultaneously is the product of the two probabilities, which is (1/6) x (1/4) = 1/24.

This means that out of the 24 possible outcomes, only one outcome will result in rolling a 1 and spinning section A on the spinner.

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Complete Question:

A number cube numbered (1, 2, 3, 4, 5, 6)  is rolled and a spinner with 4 sections (A, B, C, D) is spun. Find the probability of P(1 and A).

Answer:

no one can solve that because how you spelled it but good luck

Answer:

y= -2 when x is 0,y= -10 where x is 1 and y= -18 where x is 2

Step-by-step explanation:

when you equate x to 0 then you substitute to the equation give which is y+8x= -2, the same thing applies to the next numbers which is 1 and 2. to show it will look like is suppose to be in the form like when x is 0 it will be y+8(0)= -2

which will solve to get y+0=-2

which is the same as y=-2

The assumptions include:

1. The observations are normally distributed.

2 The observertions are independent.

Test hypotheses include the null hypothesis that the anxiety level is same before after the course and the alternative hypothesis that the anxiety level derveases after taking the course.

The standard deviation is 1.1475. The value of to will be:

= -1.125 / (1.1475 / √16)

= 3.9212

Based on the p value, it should be noted that the null hypothesis is rejected.

In conclusion, the anxiety level decrease after the students take the course.

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Before you took this course, you probably heard many stories about Statistics courses. Oftentimes parents of students have had bad experiences with Statistics courses and pass on their anxieties to their children. To test whether actually taking AP Statistics decreases students' anxieties about Statistics, an AP Statistics instructor gave a test to rate student anxiety at the beginning and end of his course.

Anxiety levels were measured on a scale of 0-10. Here are the data for 16 randomly chosen students from a class of 180 students:

Do the data indicate that anxiety levels about Statistics decreases after students take AP Statistics? Test an appropriate hypothesis and state your conclusion.

Step-by-step explanation:

The area with the highest inches receives most rainfall 1¼

The area with the lowest inches received lowest rainfall 1/8

1¼ location will have highest frequency using the ⅛line plot. There are 10 of ⅛ in 1¼

Add all the inches

1/8 + 3/8 +1/8 + 1/8 + 3/4+ 3/4 + 1/4 + 1¼ + 1/4 +1

6/8 + 2¼ + 1

6/8 + 3¼

6/8 + 13/4 = 32/8

Total rain = 4inches

The amount of aspirin in the bloodstream will be about 0.838 times what it was before.

The function that represents the amount of aspirin, A, present in the bloodstream x hours after taking a 325 mg pill is:

[tex]A = A_0 \times b^x[/tex]

where A_0 is the initial amount of aspirin in the bloodstream (which is 325 mg), and b is a constant that represents the rate of decay of the aspirin in the bloodstream.

We are told that after 3 hours, there is about 199.6 mg of aspirin remaining in the patient's bloodstream. Using the function above, we can set up an equation based on this information:

[tex]199.6 = 325 \times b^3[/tex]

To solve for b, we can divide both sides by 325 and then take the cube root of both sides:

[tex]b^3[/tex]= 199.6 / 325

b = [tex](199.6 / 325)^{(1/3)[/tex]

b ≈ 0.838

So the value of b is approximately 0.838. In the context of the problem, this means that the amount of aspirin in the bloodstream decreases by a factor of approximately 0.838 every hour. In other words, if we wait one hour,  If we wait two hours, it will be about (0.838)^2 times what it was before, and so on. This exponential decay model can be useful in predicting how long it will take for the aspirin to be completely eliminated from the bloodstream.

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The lines having linear equation y=4x+1 and y=2x-1 intersect at the point (-1, -3).

What is a linear equation, exactly?

A linear equation is an algebraic equation of the first degree that describes a line in a two-dimensional plane. It is an equation of the form y = mx + b, where x and y are variables, m is the slope of the line, and b is the y-intercept. The slope represents the rate of change of y with respect to x, while the y-intercept represents the point at which the line crosses the y-axis

Now,

To find the point of intersection between the lines y=4x+1 and y=2x-1, we can set the two equations equal to each other or we can graph these and find the intersection point.

1.

4x+1 = 2x-1

Simplifying this equation, we get:

2x = -2

x = -1

Now, we can substitute this value of x into either equation to find the corresponding value of y:

y = 4x+1 = 4(-1)+1 = -3

Therefore,

               the lines y=4x+1 and y=2x-1 intersect at the point (-1, -3).

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A. Yes, because the rate of change is a constant $70 per year. We can observe that the amount owed increases by $70 for every year that passes.

This is due to the simple interest rate of 7% per year, which means that the boy owes an additional 7% of the original amount ($1000) each year. Thus, the  the amount owed after one year is $1000 + 0.07($1000) = $1070, after two years it is $1000 + 2(0.07($1000)) = $1140, and so on. $70  is the change rate per year.

B. It will be no due to the change rate is $0 per year in 2nd and 3rd years.

This statement is false because, as we calculated in part A, the rate of change is constant at $70 per year. Therefore, the amount owed will increase by $70 even during the second and third years, as long as the boy has not made any payments towards the loan.

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The equation of the line shown is y = 1x + 9.

An equation is a statement of equality between two expressions. It is typically expressed in mathematical notation, with the left side of the equation equal to the right side. Equations are used to describe how two values are related, and can be used to solve problems or predict outcomes. Equations can be used in any field of study, from physics to economics.

The equation of the line shown can be found by using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is m = (10 - 9)/(10 - 0) = 1.

The y-intercept is b = 9, as this is the point at which the line crosses the y-axis. Therefore, the equation of the line shown is y = 1x + 9.

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Complete questions as follows-
this is happening do proper format and calculation
Find the equation of the line shown.
y
10
S87654321
9
0 1 2 3 4 5 6 7 8 9 10
X

= 5x = 5(12) = 60 sandwiches, the number of ham sandwiches. Tina makes 60 ham sandwiches.

First, we need to find the total number of each type of sandwich that Tina makes:

3/8 of the sandwiches are tuna, so the number of tuna sandwiches

= 3/8 x 480

= 180 sandwiches

35% of the sandwiches are beef, so the number of beef sandwiches

= 35% x 480

= 0.35 x 480

= 168 sandwiches

The remaining sandwiches must be ham and cheese sandwiches. Let's call the number of ham sandwiches "h" and the number of cheese sandwiches "c". We know that h:c = 5:6, which means that h = 5x and c = 6x for some common factor x. The total number of sandwiches is 480, so:

h + c = 480 - 180 - 168

h + c = 132

Substituting h = 5x and c = 6x, we get:

5x + 6x = 132                              

11x = 132

x = 12

Therefore, the number of ham sandwiches = 5x = 5(12) = 60 sandwiches. Tina makes 60 ham sandwiches.

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Answer: o find the maximum value of the objective function F=5x+2y and the values of x and y for which it occurs, we need to graph the constraints and determine the feasible region. Then, we can evaluate the objective function at the vertices of the feasible region to find the maximum value.

First, we will graph the constraints x+2y<6 and 2x+y<6. To do this, we can rewrite the inequalities as equations and graph the corresponding lines:

x+2y=6 (solid line)

2x+y=6 (dashed line)

Next, we need to determine which side of each line satisfies the inequality. To do this, we can choose a point on one side of each line and substitute its coordinates into the inequality. If the inequality is true, then that side of the line satisfies the inequality. If not, then the other side satisfies the inequality.

For example, let's choose the point (0,0) as a test point for the inequality x+2y<6:

0+2(0)<6

This is true, so the side of the line on which (0,0) lies satisfies the inequality. Similarly, we can choose the point (0,0) as a test point for the inequality 2x+y<6:

2(0)+0<6

This is also true, so the side of the line on which (0,0) lies satisfies the inequality.

Now, we can shade in the feasible region, which is the region of the graph that satisfies all of the constraints. It is the region bounded by the two lines and the axes, and it is shown in the figure below:

lua

   |              .

   |            .

   |          .

 3 |        .

   |      .

   |    .

 2 |  .

   |.

   ----------------

     0  1  2  3  4  5  6

The vertices of the feasible region are (0,3), (2,2), and (3,0). To find the maximum value of the objective function, we evaluate it at each vertex:

F(0,3) = 5(0) + 2(3) = 6

F(2,2) = 5(2) + 2(2) = 14

F(3,0) = 5(3) + 2(0) = 15

Therefore, the maximum value of the objective function is 15, and it occurs when x=3 and y=0.

enjoy (:

Answer:

(4,-5)

Step-by-step explanation:

(x,y)  → (-x, -y)

(-4,5) → (4,-5)

Helping in the name of Jesus.

Check the picture below.

let's notice the polygon has 6 sides, so

[tex]\underset{in~degrees}{\textit{sum of all interior angles}}\\\\ S = 180(n-2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=6 \end{cases}\implies S=180(6-2)\implies S=720 \\\\[-0.35em] ~\dotfill\\\\ 2b+110+116+112+110~~ = ~~720 \\\\\\ 2b+448=720\implies 2b=272\implies b=\cfrac{272}{2}\implies b=136[/tex]

Answer:

Step-by-step explanation:

we can replace 5 with [tex]\sqrt{5}^{2}[/tex]

then.

[tex]\sqrt{5}^{n-1+2}=\sqrt{5}^{n+1}[/tex]

The measured angle at position 1 is 63 degree. The angle which is  between the two tangents drawn from a outer side point to a circle is supplementary to  angle subtended

An angle is a geometric figure formed by two rays, or line segments that share a common endpoint, called the vertex of the angle. Angles are measured in degrees, radians, or other units, and are typically denoted using the symbol  θ

In geometry, the tangent to a circle is a line that intersects the circle at exactly one point, called the point of tangency. The tangent line is perpendicular to the radius of the circle that passes through the point of tangency.

In the given question ,

The angle which is  between the two tangents drawn from a outer side point to a circle is supplementary to  angle subtended by the line segment joining the points of contact at the center.

From the above theorem  we can write

angle at position 1 x= 360 - ((360-243)+90+90)

we get x=63

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Throughout his innings, Kohli scored 432 runs in total.. Rohit scored 422 runs and Rahul scored 427 runs. In total, they scored 442 runs.

Kohli, Rohit and Rahul are three of the greatest batsmen in Indian cricket. In a match, they scored 442 runs in total.Rohit scored the most runs (422 total),. Kohli scored 10 runs less than Rohit, making his total score 432 runs. Rahul was the third highest scorer, with 5 runs more than Rohit, making his total score 427 runs. This shows the great batting prowess of the three batsmen and how they were able to score a combined 442 runs between them. This goes to show the great talent and skill that the three players possess and how they are able to make such a great contribution to their team's total score.

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The value of x is 25 using Pythagoras theorem.

A pοint where twο lines meet prοduces an angle.

The breadth οf the "οpening" between these twο rays is referred tο as a "angle". It is depicted by the figure.

Radians, a unit οf circularity οr rοtatiοn, and degrees are twο cοmmοn units used tο describe angles.

By cοnnecting twο rays at their ends, οne can make an angle in geοmetry. The sides οr limbs οf the angle are what are meant by these rays.

The limbs and the vertex are the twο main parts οf an angle.

The cοmmοn terminal οf the twο beams is the shared vertex.

Pythagοras theοrem,

perpendicular²= hypοtenuse² + base²

Find the hypotenuse of lower triangle

c² = 15² + 9²

c = [tex]\sqrt{15^2 + 8^2}[/tex]

c = 17

Now, c is the base altitude of upper triangle

So

x² = [tex]\sqrt{20^2 + 15^2}[/tex]

x = 25

Thus, the value of x is 25 using Pythagoras theorem.

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