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the diagram shows two cells found in human blood.
a. the actual diagram of
red blood cell is 0.007mm ( 7 um) in diameter.
Calculate the magnification of the diagram. show your working.
side note: I measured it in a ruler and it's 2.3 cm = 23 mm (drawn to scale)
Answers
a)
Actual diameter = 0.007 mm
Diameter of scaled diagram = 2.3 cm = 23 mm
Formula to use:
Magnification = scaled dimension/actual dimension
Magnification = 23/0.007
Magnification = 3285.714... → x3286
b)
Red blood cells (RBCs), otherwise known as erythrocytes, don't have nuclei and organelles such as mitochondria, are smaller than WBCs and have a biconcave disc shape ideal for purpose
c)
i.
RBCs transport oxygen inhaled into the lungs around the body to all tissues and organs
ii.
RBCs are void of organelles so they are maximally packed with haemoglobin to bind and transport oxygen;
The biconcave disc shape is ideal for flowing through the blood vessels, particularly the capillaries, optimising them for transporting oxygen;
The small size also helps in being able to circulate the vasculature effectively and successfully
a)Actual diameter = 0.007 mm
Diameter of scaled diagram = 2.3 cm = 23 mm
Formula to use:
Magnification = scaled dimension/actual dimension
Magnification = 23/0.007
Magnification = 3285.714... → x3286
b)Red blood cells (RBCs), otherwise known as erythrocytes, don't have nuclei and organelles such as mitochondria, are smaller than WBCs and have a biconcave disc shape ideal for the purpose.
c)i.RBCs transport oxygen inhaled into the lungs around the body to all tissues and organs
ii.RBCs are void of organelles so they are maximally packed with haemoglobin to bind and transport oxygen;
What are RBCs?The biconcave disc shape is ideal for flowing through the blood vessels, particularly the capillaries, optimising them for transporting oxygen;The small size also helps in being able to circulate the vasculature effectively and successfully.
Thus, these are the answer.
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I hope this helps! :)
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Note: This question is incomplete because the map is missing. Here is the map.
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Explanation: Someone in the comments was helpful enough to say it but couldn't post it so yea, just passing it on but its right so thanks to them
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Hope this helps you!
Answer:
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Answer:
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GIVE BRAINLIEST PLZ! :)
The difference between bacterial and eukaryotic transcription is that in bacteria, transcription and translation can occur simultaneously in the cytoplasm of the cell, whereas in eukaryotes transcription occurs in the nucleus and translation occurs in the cytoplasm.
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now you’ll examine an operon that undergoes negative and positive control. the ara operon in e. coli codes for enzymes that metabolize the sugar arabinose, which e. coli can use for energy. as you can see in the diagram, the regulatory protein arac can act as both an activator and a repressor of the ara operon.
Answers
The lac operon is known to be able to undergoes negative and positive control.
The diagram based on the 4 table arrangement is filled up below (Right to left);
In the presence of arabinose: initiator, activator, yes, yes.In the absence of arabinose: initiator and operator, repressor, no, no.
If a mutation prevents arabinose from biding to AraC: initiator and operator, repressor, no, no.
If arabinose is present but a mutation and AraD enzyme renders it non-functional: initiator, activator, yes, no.
The metabolism of the sugar arabinose is known to be influenced by an operon that is said to undergo both positive control and negative control.
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When arabinose is absent, one part of the AraC dimer is often bounded to the initiator, while the other part is bounded to the operator, thereby hindering transcription.
See full question below
Now you'll examine an operon that undergoes negative and positive control. The ara operon in E. coli codes for enzymes that metabolize the sugar arabinose, which E. coli can use for energy. As you can see in the diagram, the regulatory protein AraC can act as both an activator and a repressor of the ara operon.
Use the diagram above to fill in the table.
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