Bender Electronics buys keyboards for its computers from another company. The keyboards are received in shipments of 100 boxes, each box containing 20 keyboards. The quality control department at Bender Electronics first randomly selects one box from each shipment and then randomly selects 5 key boards from that box. The shipment is accepted if not more than 1 of the 5 keyboards is defective. The quality control inspector at Bender Electronics selected a box from a recently received shipment of keyboards. Unknown to the inspector, this box contains 6 defective keyboards.
Round your answers to four decimal places.
a. What is the probability that this shipment will be accepted?
P(shipment accepted)=
b. What is the probability that this shipment will not be accepted?
P(shipment not accepted)=

Answers

Answer 1

Answer:

a

  [tex]P(shipment\ accepted) =0.6337 [/tex]\

b

   [tex]P(shipment\ not\ accepted)= 0.3663 [/tex]  

Step-by-step explanation:

from the question we are told that

   The number of boxes N  =  100

     The  number of keyboard in each box is  k =  20  

     The sample size is  n =  5

Generally the number of ways of selecting 1 keyboard from the 5 selected keyboard is mathematically represented as

     [tex]G  =  \ ^{5}C_1[/tex]

Here  C stands for  combination (Hence in the question we will be making use of the combination functionality in our calculator )

Generally the number of ways of selecting 0 keyboard from the 5 selected keyboard is mathematically represented as

       [tex]H  =  \ ^{5}C_0[/tex]

Generally the number of ways of selecting 5 keyboard from the 20 keyboards is mathematically represented as

          [tex]F  =  \ ^{20}C_5[/tex]

Generally the number of ways of selecting 5 keyboard from the  15 keyboards is mathematically represented as

        [tex]W  =  \ ^{15}C_5[/tex]

Generally the number of ways of selecting 5 keyboard from the  15 keyboards is mathematically represented as

        [tex]V  =  \ ^{15}C_4 [/tex]

Generally the probability that a shipment will be accepted is mathematically represented as

 Probability of  0 defect out of  5 + Probability of  1 defect out of 5

Now  

  Probability of  0 defect out of  5 is mathematically represented  as

        [tex]P(A_1) =  \frac{H*W }{ F}[/tex]

=>      [tex]P(A_1) =  \frac{1 *3003 }{ 15504}[/tex]

=>      [tex]P(A_1) =  0.1937[/tex]

And  Probability of  1 defect out of 5 is mathematically represented as

     [tex]P(A_2) =  \frac{ G * V}{ F}[/tex]

 => [tex]P(A_2) =  \frac{ 5 * 1365}{15504}[/tex]  

 =>   [tex]P(A_2) =  0.440[/tex]  

Generally the probability that a shipment will be accepted is mathematically represented as

     [tex]P(shipment\ accepted) =0.1937 +  0.440[/tex]

=>    [tex]P(shipment\ accepted) =0.6337 [/tex]

Generally the probability that this shipment will not be accepted is mathematically represented as

    [tex]P(shipment\ not\ accepted)= 1 -P(shipment \ accepted)[/tex]

     [tex]P(shipment\ not\ accepted)= 1 - 0.6337 [/tex]  

     [tex]P(shipment\ not\ accepted)= 0.3663 [/tex]  


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x = 40°
y = 6

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[tex]For \: x = -1 , y = 2(-1) + 3 = 1 [/tex]

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the function is graphed below. On which interval of X is the average rate of change of the function the greatest?

Answers

Answer:

Between x = 48 and x = 45.

Step-by-step explanation:

Average rate of change of a function in the given interval is represented by,

Average rate of change = [tex]\frac{\triangle y}{\triangle x}[/tex]

From the table attached,

Average rate of change of the function between x = 3 and x = 9

= [tex]\frac{16-7}{9-3}[/tex]

= 3

Average rate of change in the interval x = 9 and x = 22

= [tex]\frac{32-16}{22-9}[/tex]

= [tex]\frac{16}{13}[/tex]

= 1.23

Average rate of change in the interval x = 9 and x = 22,

= [tex]\frac{45-32}{45-22}[/tex]

= [tex]\frac{13}{23}[/tex]

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Average rate of change in the interval x = 45 and x = 48,

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Option given in bottom right will be the answer.

determine the range of the following graph:

Answers

Answer:

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Step-by-step explanation:

(-7) - 8 = (-15) (Range is the difference between Max and Min Value)

please follow me and mark as brainliest

A researcher wants to compare the heights of males between generations to see if they differ. To do this, he samples random pairs of males who are at least 18 years old and their fathers. He then splits them into a sample of fathers and a sample of sons. Suppose that data were collected for a random sample of 11 pairs, where each difference is calculated by subtracting the height of the son from the height of the father. Assume that the heights are normally distributed. The test statistic is t≈1.971, α=0.05, the corresponding rejection regions are t<−2.228 and t>2.228, the null hypothesis is H0:μd=0, and the alternative hypothesis is Ha:μd≠0.

Select all that apply:
a. Reject the null hypothesis.
b. Fail to reject the null hypothesis.
c. The conclusion of the hypothesis test is that there is sufficient evidence to suggest that the heights of males between generations are different.
d. The conclusion of the hypothesis test is that there is insufficient evidence to suggest that the heights of males between generations are different.

Answers

Answer:

The correct option is  

Option A and Option C

Step-by-step explanation:

From the question we are told that

   The sample size of paired men is  [tex]n_p   =  11[/tex]

   The test statistics is  t≈1.971

    The  significance level is  α=0.05

    The rejection region is  t<−2.228 and t>2.228

    The null hypothesis is  [tex]H_o :\mu_ d=0[/tex]

     The alternative hypothesis  is  [tex]H_a :\mu_ d \ne 0[/tex]

Generally the degree of freedom is mathematically represented as

        [tex]df  =  n_1 +  n_2 - 2[/tex]

Here [tex]n_1[/tex] is the sample size of  father which is  [tex]n_1 =  11[/tex]

        [tex]n_2[/tex] is the sample size of males who are at least 18 years old  which is  [tex]n_2 =  11[/tex]

So

     [tex]df  =  11 +  11 - 2[/tex]

=>   [tex]df  =  20[/tex]

Generally the critical values of  α=0.05 from the  t- distribution table at a degree of freedom of  [tex]df  =  20[/tex]  for a two -tailed test  is  

     [tex]t_{0.05 , 20 } =  \pm 2.08596345  [/tex]

From the value  obtained we see that the critical value  is within the region of rejection hence

 The decision rule is

Reject the null hypothesis

The conclusion is  

  The conclusion of the hypothesis test is that there is sufficient evidence to suggest that the heights of males between generations are different.

     

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BLO
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Lo siento, no sé español, quizá alguien más te ayudaría

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

Complete question :

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