Answer:
8.6 years
Step-by-step explanation:
An important problem in industry is shipment damage. A electronics distribution company ships its product by truck and determines that it cannot meet its profit expectations if, on average, the number of damaged items per truckload is greater than 12. A random sample of 12 departing truckloads is selected at the delivery point and the average number of damaged items per truckload is calculated to be 9.4 with a calculated sample of variance of 0.64. Select a 99% confidence interval for the true mean of damaged items.
a) [48.26, -30.02]
b) [10.67, 11.93]
c) [-0.6285, 0.6285]
d) [10.69, 11.91]
e) [11.37, 12.63]
f) none of the above
Answer:
the answer is b) (10.67,11.93)
Step-by-step explanation:
hope this helps
there's a width of 8 in., a length of 20 in., and a height of 12 in.
a) what is the longest poster you could fit in the box? express your answer to the nearest tenth of an inch.
b) explain why you can fit only one maximum-length poster in the box, but you can fit multiple 21.5-inch posters in the same box.
Answer:
a.
Approximately [tex]24.7\; \rm in[/tex].
b.
While there are three diagonals in a box (a rectangular prism,) all three diagonals goes through the same point- the centroid of this box.
For a maximum-length poster to fit in this box, it would have to be on one of the main diagonals of this box. Hence, any maximum-length poster that fits in this box would go through the centroid of this box.
It's not possible to force more than one posters to go through the same point (i.e., the centroid) in space. Hence, it would not be possible to fit a second maximum-length poster into this box.
This argument does not apply to [tex]21.5\; \rm in[/tex] posters. These posters are shorter than the diagonal of this box; they could fit inside the box without having to go through a particular point in space.
Step-by-step explanation:
The longest poster that could be fit into this box (a rectangular prism) would be as long as the longest line segment in this box. That line segment would be one of the three diagonals of this box.
Apply the Pythagorean theorem twice to find the length of that diagonal.
Start by finding calculating the diagonal of the base of this box. The base of this box is a rectangle with width [tex]8\; \rm in[/tex] and length [tex]10\; \rm in[/tex]. The length of its diagonal would be [tex]\sqrt{8^2 + 10^2}[/tex] inches.
Combine that with the height of this box to find the length of the diagonal of this box.
[tex]\begin{aligned}& \sqrt{{\left(\sqrt{8^2 + 10^2}\right)}^2 + 12^2 \\ &= \sqrt{8^2 + 10^2 + 12^2} \\ &\approx 24.7 \end{aligned}[/tex].
whats 7 times 8 divided by 2 i think the answer s 6 am i right or ring please tell me
Answer:
28Step-by-step explanation:
First,
7 times 8 = 7 × 8 = 56
Then,
The product divided by 2 = 56 ÷ 2 = 28
Hence,
The required answer is 28
Given the function f(x) = 4^x - 1, explain and show how to find the average rate of change between x = 1 and x = 4.
Answer:
84
Step-by-step explanation:
f(1)=4^1 - 1 = 3
f(4) = 4^4 - 1 = 255
rate of change = [tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]
(255 - 3) / (4 - 1) = 252 / 3 = 84
ANSWER IT HOW THE QUESTIONS ARE ASKED!! Thank you so much!!
Answer:
[tex](a)\ Pr = \frac{2}{5}[/tex]
[tex](b)\ Pr = \frac{9}{20}[/tex]
[tex](c)\ E(Orange) = 100[/tex]
[tex](d)\ E(Orange) = 62.5[/tex]
Step-by-step explanation:
Solving (a): Theoretical probability of green or yellow
Here, we consider the spinner itself
From the attached image, we have:
[tex]n= 5[/tex] --- i.e. 5 sections
[tex]Yellow = 1[/tex]
[tex]Green = 1[/tex]
So, the probability is:
[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]
[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]
[tex]Pr = \frac{1}{5} + \frac{1}{5}[/tex]
Take LCM
[tex]Pr = \frac{1+1}{5}[/tex]
[tex]Pr = \frac{2}{5}[/tex]
Solving (b): Experimental probability of green or yellow
Here, we consider the result of the experiment
From the attached image, we have:
[tex]n= 40[/tex] --- i.e. 40 spins
[tex]Yellow = 12[/tex]
[tex]Green = 6[/tex]
So, the probability is:
[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]
[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]
[tex]Pr = \frac{12}{40} + \frac{6}{40}[/tex]
Take LCM
[tex]Pr = \frac{12+6}{40}[/tex]
[tex]Pr = \frac{18}{40}[/tex]
Simplify
[tex]Pr = \frac{9}{20}[/tex]
Solving (c): Expectation of orange outcomes in a spin of 500 times, theoretically.
Here, we consider the spinner itself
From the attached image, we have:
[tex]n= 5[/tex] --- i.e. 5 sections
[tex]Orange = 1[/tex]
So, the probability of having an outcome of orange in 1 spin is:
[tex]Pr = P(Orange)[/tex]
[tex]Pr = \frac{Orange}{n}[/tex]
[tex]Pr = \frac{1}{5}[/tex]
In 500 spins, the expectation is:
[tex]E(Orange) = Pr * 500[/tex]
[tex]E(Orange) = \frac{1}{5} * 500[/tex]
[tex]E(Orange) = 100[/tex]
Solving (c): Expectation of orange outcomes in a spin of 500 times, base on experiments.
Here, we consider the spinner itself
From the attached image, we have:
[tex]n= 40[/tex] --- i.e. 40 spins
[tex]Orange = 5[/tex]
So, the probability of having an outcome of orange is:
[tex]Pr = P(Orange)[/tex]
[tex]Pr = \frac{Orange}{n}[/tex]
[tex]Pr = \frac{5}{40}[/tex]
[tex]Pr = \frac{1}{8}[/tex]
In 500 spins, the expectation is:
[tex]E(Orange) = Pr * 500[/tex]
[tex]E(Orange) = \frac{1}{8} * 500[/tex]
[tex]E(Orange) = 62.5[/tex]
It has been observed that some persons who suffer acute heartburn, again suffer acute heartburn within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 45 people in the first group and this group will be administered the new drug. There are 75 people in the second group and this group will be administered a placebo. After one year, 12% of the first group has a second episode and 14% of the second group has a second episode. Conduct a hypothesis test to determine, at the significance level 0.1, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is less than the true percentage of those in the second group who suffer a second episode.
A. [ z < -1.65, RHo].
B. [ z < -1.65 and z > 1.65, FRHo].
C. [z > 1.65, FRHo].
D. [z < -1.65 and z > 1.65, FRHo].
E. [z > -1.65 and z < 1.65, RHo].
F. None of the above.
Answer:
F. None of the above.
Step-by-step explanation:
Let the null and alternate hypothesis be
H0: p1 ≥ p2 against the claim Ha: p1 < p2
the significance level is 0.1
The critical region is z < z∝= 1.28
The test statistic is
Z= ( p^1-p^2)- (p1-p2)/√p1^q1^/n1 + p2^q2^/n2
Here n1= 45 , n2= 75
p1= 0.12 p2= 0.14
q1= 0.88 q2= 0.86
z= 0.12- 0.14/√0.12*0.88/45 +0.14*0.86/75
Z= 0.02/ √0.00235 + 0.00161
Z= 0.02/0.062891
z= 0.318
The calculated value of z= 0.318 lies in the critical region z < 1.28
therefore accept Ha.
All of the options are incorrect as the critical value for one tailed test for 0.1 is 1.28 .
Write an equation of a line with slope -4 and y- intercept of 0
Answer:
y=-4x
Step-by-step explanation:
I will give Brainliest
Please help me find the answer
Answer:
in the first traingle
sinC = 36/39 = 12/13
CosC= 15/39 = 5/13
TanA= 15/36=5/12
this is the values i didnt understand the question so i just find the values
in the second Triangle
SinA=2√5/5
CosA=√5/5
TanB= √5/2√5=1/2
cos 30 = √3/2
sin45=√2/2
tan60= √3
hopefully its helpful iam sorry i didnt understand what they mean in the question my engilish is bad
Sin of c. Sin'-1(36/39)=90
Cos of c cos'-1(15/39)=67.38
Tan of a tan'-1(15/36)=22.62
Sin of a sin'-1(2squarroot5/5)=63.43
Cos od a cos'-1(squareroot5/5)=63.43
Tan of b tan'-1(2squareroot5/squareroot5)=63.43
Cos30 is pie/6 or squareroot of 3 /2
Sin of 45 is pie/4 or squareroot2/2
Tan60 is pie/3 or squareroot3
Simplify.
4^3•4^-6
A. 1/4^3
B. 1/4^9
C. 1/4^18
D. 4^3
Answer:
A
Step-by-step explanation:
This can be rearranged as 4^3 * 1/(4^6)
or (4^3)/(4^6)
This can be changed to:
(4^3)/((4^3)*(4^3)
Which is equal to 1/(4^3)
or
4^(-3)
Here are some clues about my age. • Both my father’s age and mine are 2-digit numbers. • If you reverse the order of the digits of my father’s age, you get my age. • My father is 27 years older than I am. How old am I? Show your work and justify your thinking.
For the given condition the age of the son will be 69 years.
What is the equation?A mathematical equation asserts the equality of two expressions, which may or may not contain variables or integers. Equations are fundamental concerns, and efforts to rationally address them have served as the primary driving forces behind the creation of mathematics.
Suppose the two-digit number is x,
The father's and son's ages are 10x+y and 10y+x respectively.According to the given condition,
(10x+y) -(10y+x)=27
9x-9y=27
x-y=27/9
x-y=3
The value of x and y will be 4 and 1.
At x=9 and y=6, the age of the son is obtained as,
=10×6+9
=69 years
Thus, the age of the son will be 69 years.
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The sidewalk is 5 feet wide and the garden measures 20 feet across. Which measurement is closest to the area of the outer edge of the sidewalk?
A.
200 ft2
B.
400 ft2
C.
700 ft2
D.
1,000 ft2
Answer:
A (obviously)
Step-by-step explanation:
Info Given
Sidewalk is 5 ft. wideGarden is 20 ft. acrossWhat is the mean ? 50, 55, 58, 58, 90, 92, 99
sum of observations
mean =..........................no. of observations
50+55+58+90+58+92+99 502
....................................... = .........= 71.77 7
awnser is 71.7
hope this helpedDegree and Radian Measures
Convert the given radian measure to a degree measure.
1.2 /pi (π)
a. -216°
b. 108°
c. 216°
d. -108°
Please select from the best choices provided
Answer:
C. 216°
Step-by-step explanation:
I calculated it logically
Plz help find the rule 50 points
Answer:
1², 2²,3², 4², 5², 6², 7², 8², 9², 10², 11², 12², 13², 14², 15², 16², 17², 18², 19², 20²,........
Each number is multiplied by itself.
Find the surface area of the composite figure.
6 cm
5 cm
4 cm
6 cm
15 cm
3 cm
The surface area of the given composite figure will be 384 square cm.
What is surface area?The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called the surface area.
In the given image we have a composite figure one is a rectangular cuboid and the other is a triangular prism. The surface area will be equal to the sum of all the outer sides of the figure.
The surface area of the triangular shape will be calculated as:-
SA = 2( Area of triangle ) + Area of rectangular surfaces
SA = 2 ( (1/2) B x H ) + (5 x 6 ) + ( 6 x 3 )
SA = ( 3 x 4 ) + ( 30 ) + ( 18 )
SA = 12 + 30 + 18
SA = 60 square cm
The surface area of the rectangular cuboid will be calculated as:-
SA = ( 4 x 6 ) + 2 ( 158 x 4 ) + 2 ( 15 X 6 )
SA = 24 + 120 + 180
SA = 324 square cm
Total surface area will be = 324 + 60 = 384 square cm.
Therefore the surface area of the given composite figure will be 384 square cm.
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Four less than two times a number is seven times the sum of that number and 8. Which equation
could be used to solve this problem?
1. 4- 2n + 7n = 8
2. 2n - 4 = 7n + 8
3. 2n - 4 = 7(n + 8)
4. 4 - 2n = 7(n + 8)
9514 1404 393
Answer:
3. 2n - 4 = 7(n + 8)
Step-by-step explanation:
Two times a number is 2n. Four less than 2n is (2n-4). The sum of a number and 8 is (n+8). Seven times that sum is 7(n+8). The statement says these values are equal:
2n -4 = 7(n +8)
You deposit $800 in an account that pays 3.6% annual interest compounded quarterly. When does your balance first exceed $1200?
Answer:
It would take 4 years. The formula for continuously compounded interest is: where P is the principal, r is the interest rate as a decimal number, and t is the number of years.
Step-by-step explanation:
You deposit $800 in an account that pays 3.6% annual interest compounded quarterly. after 11 years your balance first exceed $1200.
How to find the compound interest?If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:
[tex]a = p(1 + \dfrac{r}{n})^{nt}[/tex]
You deposit $800 in an account that pays 3.6% annual interest compounded quarterly.
[tex]a = p(1 + \dfrac{r}{n})^{nt}[/tex]
[tex]1200 = 800(1 + \dfrac{3.6}{4})^{4t}\\\\300 = (1 + 0.9)^{4t}\\\\t = 11.4[/tex]
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round 98,376 to the nearest thousand
Answer:
98000
Step-by-step explanation:
I do need to know NOTHING.
Answer:
Thats cool man.
Step-by-step explanation:
i got yelled at for my grandma giving a coney dog at A and W and she got sick is there a way i can cut my dad out of his life
Answer:
this whole sentence confused me a lot
Step-by-step explanation:
yes there is, but it depends on how you want to do it
Answer:
I don't really get what you're implying can you please explain?
Step-by-step explanation:
haha this just really confused me :)
Between which x-values and y-values does the cluster lie?
Answer:
Here is the picture
Step-by-step explanation:
The number lies between x-values 4 and 6 and y-values 6 and 9.
What are coordinates?Coordinates are a pair of integers (Cartesian coordinates), or occasionally a letter and a number, that identify a certain place on a grid, often referred to as a coordinate plane.
Given that scatter plot lies in quadrant 1 of a coordinate plane, and the 14 points are plotted in the first quadrant.
We need to find the range of x and y values for this scatter plot.
The x values of the 14 points are given as;
2, 4, 4,1, 5, 5, 5, 5, 6, 6, 7, 8, 9.5, 9.5
The y values of the 14 points are given as;
5, 6, 9, 7.2, 6, 6.8, 8, 9, 7, 8.5, 10, 10.5, 9.5, 11.4
We can conclude that that most of the points are clustered between x-values 4 and 6 and y-values 6 and 9.
Therefore, the points are clustered between the x-values 4 and 6 and y-values 6 and 9.
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The complete question is
Select the correct answer. Scatter plot in quadrant 1 of a coordinate plane. 14 points are plotted at (2, 5), (4, 6), (4, 9), (4.1, 7.2), (5, 6), (5, 6.8), (5, 8), (5, 9), (6, 7), (6, 8.5), (7, 10), (8, 10.5), (9.5, 9.5), and (9.5, 11.4). Between which x-values and y-values does the cluster in this scatter plot lie? A. It lies between x-values 2 and 4 and y-values 4 and 6. B. It lies between x-values 4 and 6 and y-values 9 and 10. C. It lies between x-values 4 and 6 and y-values 6 and 9. D. It lies between x-values 7 and 9 and y-values 10 and 11.
Take a look at the photo and please right an explanation for your answer
The makers of MaxGrow want to ensure customers that their product will work under a wide variety of conditions such as a variety of watering conditions (no added water or watering daily) and how much fertilizer was used (no fertilizer, half fertilizer, or full fertilizer). The researchers randomly choose which group each tomato plant will be assigned to. At the end of the experiment, the number of tomatoes picked from each tomato plant is recorded.
a. Identify the subjects.
b. Explanatory variables
c. Treatments
d. Response variable
Answer:
Subject : Tomato plant
Explanatory variables : Watering condition ; Fertilizer addition
Treatment : daily watering ; half fertilizer ; full fertilizer
Response variable = Number of tomato picked
Step-by-step explanation:
Subjects are the individuals, animals or plants upon which treatment is applied. The subject here are the tomato plants
The Explanatory variables are the independent variables upon which we want base the variation of the dependent variable. The Independent variables are the watering condition a d the amount of fertilizer added.
Treatment : These are the actual changes made or applied on the subject, they include, daily watering, full or half fertilizer application.
Response variable : The number of tomatoes picked. This is also called the dependent variable, it is the outcome which may be due to the effect of the independent variable.
A right-angled triangle, with two sides adjacent to the right angle labeled 7 and 11 respectively, and the hypotenuse is labeled x.
Find the exact value of $x$ .
Answer:
170
c=a^2+b^2=7^2+11^2≈13.0384 or 170
Step-by-step explanation:
mrk me brainliest please
A b c or d?? Lmk..Brainly
Answer:
28.3 (b)
Step-by-step explanation:
To solve circumference, you will need to use the equation C = 2 *pi* r
for this, we will use 3.14 for pi and the radius is 4.5 so this is how we need to solve it
C= 2 pi (4.5) Solve 2*4.5
C= 9 pi Now we input 3.14 for pi and multiply
C= 9(3.14)
C= 28.26 Now we round to the nearest tenth to get
C=28.3
Suppose that two investors A and B have exhibited the indifference probabilities as shown in table below. Indifference probability Investor A Investor B Net return (RM) -2000 0 0 - 1000 0.70 0.10 0 0.80 0.20 1000 0.85 0.30 2000 0.90 0.50 3000 0.95 0.60 4000 1.00 1.00 a) Determine the utility value (for each monetary value) for each investor and fill it in table above. b) Graph the utility functions for both investors and categorize each investor as either a risk- averse person or a risk seeker. c) Suppose that investor A has the chance to invest in one of two ventures. Venture I can produce a net return of RM3000 with probability 0.40 or a net loss of RM1000 with probability 0.60. Venture II can produce a net return of RM2000 with probability 0.60 and no return with probability 0.40. Based on utility function in (b), use the expected utility criterion to determine the venture investor A should select. What is the expected monetary value associated with the selected venture?
Answer:
Da Answer is Suppose that two investors A and B have exhibited the indifference probabilities as shown in table below. Indifference probability Investor A Investor B Net return (RM) -2000 0 0 - 1000 0.70 0.10 0 0.80 0.20 1000 0.85 0.30 2000 0.90 0.50 3000 0.95 0.60 4000 1.00 1.00 a) Determine the utility value (for each monetary value) for each investor and fill it in table above. b) Graph the utility functions for both investors and categorize each investor as either a risk- averse person or a risk seeker. c) Suppose that investor A has the chance to invest in one of two ventures. Venture I can produce a net return of RM3000 with probability 0.40 or a net loss of RM1000 with probability 0.60. Venture II can produce a net return of RM2000 with probability 0.60 and no return with probability 0.40. Based on utility function in (b), use the expected utility criterion to determine the venture investor A should select. What is the expected monetary value associated with the selected venture?
Step-by-step explanation:
LESSSSSSS GOOOOOOOOOO
Given that the triangles shown below are similar, what is the value of x? 32 20 H 48M P A. 96 B. 10.7 C. 24 D. 20
Answer:
I DONT SEE TRIANGLES
Step-by-step explanation:
the perimeter of a square field is 880m. Find it's area in hectares
This is the answer hope it helps
The area of the square field is 4840 hectares.
What is perimeter of square?Perimeter of the square is defined as addition the lengths of the square's four sides.
Perimeter of the square equation is 4a
Where, a is length of the square
Given data as :
Perimeter of the square field = 880 m
Side of the square = Perimeter/4
Side of the square = 880/4
Side of the square = 220 m
So, length of each side of the square is 220 m
Area of square = Side × Side
Area of square = 220 m × 220 m
Area of square = 48400 square meters
Area of square = 48.4 square kilometers
As we know that 1 sq km = 100 hectares
So, 48.4 km = 48.4 × 100 = 4840 hectares
Hence, the area of the square field is 4840 hectares.
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Trying to finish this test at 3:30 am plz help
Given:
The given sum is:
[tex]\sum _{k=4}^9(5k+3)[/tex]
To find:
The expanded form and find the sum.
Solution:
We have,
[tex]\sum _{k=4}^9(5k+3)[/tex]
The expanded form of given sum is:
[tex]\sum _{k=4}^9(5k+3)=(5(4)+3)+(5(5)+3)+(5(6)+3)+(5(7)+3)+(5(8)+3)+(5(9)+3)[/tex]
[tex]\sum _{k=4}^9(5k+3)=(20+3)+(25+3)+(30+3)+(35+3)+(4+3)+(45+3)[/tex]
[tex]\sum _{k=4}^9(5k+3)=23+28+33+38+43+48[/tex]
[tex]\sum _{k=4}^9(5k+3)=213[/tex]
Therefore, the correct option is C.
Ms. Lin’s son likes to lift weights. He was lifting 125 pounds last year. This year he can lift 35 more pounds. How much weight can he lift this year?
Answer:
He can lift 160 pounds
Step-by-step explanation:
125 (from last year) + 35 (more pounds) = 160 (total pounds)
125 + 35 = 160