Answer:
Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these
Explanation:
Hey im super sorry if i get this wrong :)
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.
Answer:
4.2s
Explanation:
Given parameters:
Power = 2190W
Mass of box = 1.47 x 10⁴g
distance = 6.34 x 10⁴mm
Unknown:
Time = ?
Solution:
Power is the rate at which work is done;
Mathematically;
Power = [tex]\frac{work done}{time}[/tex]
Time = [tex]\frac{work done}{power}[/tex]
Work done = weight x height
convert mass to kg;
100g = 1kg;
1.47 x 10⁴g = 14.7kg
convert the height to m;
1000mm = 1m
6.34 x 10⁴mm gives 63.4m
Work done = 14.7 x 9.8 x 63.4 = 9133.4J
Time taken = [tex]\frac{9133.4}{2190}[/tex] = 4.2s
What is the magnitude of the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 3.80 s
Answer:
The correct solution will be "12.48 in/s²".
Explanation:
The given values are:
Angular speed
= 79.0 rev/min
Time
= 3.80 seconds
Now,
⇒ [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]
[tex]=\frac{8.2}{3.8}[/tex]
[tex]=2.1 \ rad/s^2[/tex]
Tangential acceleration will be:
= [tex]Angular acc.\times radius[/tex]
= [tex]2.1\times 6.5\times 0.0254[/tex]
= [tex]0.3467 \ m/s^2[/tex]
= [tex]12.48 \ in/s^2[/tex]
Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.
Answer:
v₃ = 1.625 [m/s]
Explanation:
To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.
Since the collision is inelastic, the two bodies are joined after the collision.
P = m*v [kg*m/s]
m = mass [kg]
v = velocity [m/s]
where:
P = lineal momentum [kg*m/s]
Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.
Pbefore = Pafter
(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃
where:
m₁ = mass one = 5 [kg]
v₁ = velocity of the mass one = 2 [m/s]
m₂ = mass two = 3 [kg]
v₂ = velocity of the mass two = 1 [m/s]
v₃ = velocity of the combined masses after the collision [m/s]
Now replacing we have:
(5*2) + (3*1) = (5 + 3)*v₃
10 + 3 = 8*v₃
v₃ = 13/8
v₃ = 1.625 [m/s]
for a solar eclipse to occur which of the following alignments must be necessary
carter found the rock shown in the picture below near a river
Answer:
there's no picture
Explanation:
and what would the question be anyways?
Answer:
what is the question
Explanation:
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
A current of 15 Amps flows through a circuit with a resistance of 0.10 Ohms. What is the voltage?
A. 0.006 Volts
OB. 1.5 Volts
O C. 15 Volts
D. 150 Volts
Voltage = (current) x (resistance) (Ohm's law)
Voltage = (15 A) x (0.10 ohm)
Voltage = 1.5 volts (B)
A 1,200 kg roller coaster car starts rolling up a slope at a speed of 15 m/s. What is the highest point it could reach?
Answer:
11.48 m
Explanation:
The following data were obtained from the question:
Mass (m) of the roller coaster = 1200 Kg
Initial velocity (u) = 15 m/s.
Final velocity (v) = 0 m/s (at highest point)
Acceleration due to gravity (g) = 9.8 m/s²
Highest point (h) =?
The highest point reached by the roller coaster can be obtained as illustrated below:
h = u²/2g
h = 15² / 2 × 9.8
h = 225/19.6
h = 11.48 m
Therefore, the highest point reached by the roller-coaster is 11.48 m
A solid keeps its shape due to which of the following factors?
Space between particles
Attractive forces between particles
The type of element in the solid
The container it is placed in
Answer:
c
Explanation:
because whatever elements are used like gas uses water evaporation so yeah
Answer:
(A) Space between particles!
Explanation:
Solids can hold their shape because their molecules are tightly packed together!
✞ Bye Have A Nice Day! ✞
QUESTION 13
Marci would describe almost a perfect person whenever her friends would ask her who she thought was
her ideal life partner. This "perfect" person would be ain)
O a prototype
b.reinforcer
oc. anagram
d. heuristic
If the brakes are applied and the speed of the car is reduced to 13 m/s in 14 s, determine the constant deceleration of the car.Express your answer to three significant figures and include the appropriate units. Assume ais negative if it acts in the opposite sense to the positive velocity.
Answer:
Explanation:
v = u + at
v is final velocity , u is initial velocity , a is acceleration and t is time .
here v = 0 , u = 13 m /s , t = 14 s
putting the values
0 = 13 + 14 a
a = 13 / 14 m /s²
= - .9286
= - 0.929 m /s²
A 16-V battery powers a series circuit that contains two lightbulbs The
voltage across the first lightbulb is 12-V
Complete question:
A 16-V battery powers a series circuit that contains two lightbulbs. The voltage across the first lightbulb is 12-V.
a. What fractional part of the circuit's total energy is transformed in the first lightbulb? Simply your answer.
b. What fractional part of the circuit's total energy is transformed in the second lightbulb? Simply your answer.
Answer:
(a) Fraction of energy of the first bulb in the total energy of circuit is 3/4
(b) Fraction of energy of the second bulb in the total energy of circuit is 1/4
Explanation:
Given;
total voltage across the series circuit, [tex]V_T[/tex] = 16 V
voltage across the first light bulb, V₁ = 12 V
The voltage across the second light bulb is given by;
V₂ = [tex]V_T[/tex] - V₁
V₂ = 16 V - 12 V
V₂ = 4 V
The total power across the circuit is given by;
P = I[tex]V_T[/tex]
P = 16I
Where;
I is the constant current in the circuit
(a)
power in the first light bulb is given by;
P₁ = 12I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_1}{P} = \frac{12I}{16I} = \frac{3}{4}[/tex]
(b)
power in the second light bulb is given by;
P₂ = 4I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_2}{P} = \frac{4I}{16I} = \frac{1}{4}[/tex]
What is the momentum of a 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway
Answer:
486,750 kg*m/s
Explanation:
Momentum is mass*velocity
M = m*v
M = 8850kg*55m/s
M = 486,750 kg*m/s
The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
Given:
The mass of the truck is, m = 8850 kg,
The velocity of the truck is, v = 55 m/s,
Calculate the momentum of the truck as shown below,
Momentum = m × v
Momentum = 8850 × 55
Momentum = 486750 kg m / s
Thus, the Momentum of the truck is 486750 kg m / s.
To know more about momentum:
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The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.
The subject is science just to let you know.
Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
Nine, Brazil, Venezuela
Explanation:
yes or no
1.the ink of a pen that is used for writing is not a colloid
2.the blood consists of solid particles and plasma are considered a kind of colloid.
Answer:
1. No, it is a colloid
2. Yes
Explanation:
At which temperature are the particles in a pencil moving faster: 20°C or 50°C?
Answer:
movement generates energy=heat so 50c should be it
What holds the metal ions together in a lattice?
A. covalent bonds
B. metallic bonds
C. hydrogen bonds
D. ionic bonds
Answer:
B. Metallic bonds.
A 60-kg woman runs up a staircase 15 m high (vertically) in 20 s.
Required:
a. How much power does she expend?
b. What is her horsepowerrating.
Answer:
(a) 441 W (b) 0.59 hP
Explanation:
Given that,
Mass of a woman, m = 60 kg
Height of a staircase, h = 15 m
Time, t = 20 s
(a) We need to find the power she expend. Work done per unit time is called power. It is given by :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\P=441\ W[/tex]
( b) Since, 1 hP = 745.7 W
P = 0.59 hP
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity of the object?
V = at + V0
where v0 is the initial speed, a is the acceleration and t is the time.
So:
v = 5m/s^2*5s + 25m/s = 50 m/s
Full moon is located______
a. farthest from the Sun
b. at a 90 degree angle with the Sun and Earth
c. closest to the Sun
Answer:
Im going to take an educated guess and say its B.
Explanation:
A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
What is a Full moon?A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.
When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.
Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
To learn more about the Full moon, refer to the link:
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Explain the procedures used and data recorded to identify a crystalline mineral based on its properties.
Answer:
By examining its external shape, color, hardness, etc.
Explanation:
what is a factor that scientists use to classify orders of soil?
If a car traveled 50 meters in 2 seconds, what will the velocity be? (Write the answer with a number, on decimal if needed, then a space and the units, for example 5.7 m/s)
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{50}{2} \\ [/tex]
We have the final answer as
25 m/sHope this helps you
Based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart ?
Answer:
F' = 100 F/r²
Explanation:
The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:
F = Gm₁m₂/r²
where,
F = Force between objects
G = Universal Gravitational Constant
m₁ = mass of first object
m₂ = mass of second object
r = distance between objects = 10 m
Therefore,
F = Gm₁m₂/10²
Gm₁m₂ = 100F --------------------- equation (1)
Now, we consider these objects at any distance r apart. So, the force becomes:
F' = Gm₁m₂/r²
using equation (1), we get:
F' = 100 F/r²
So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.
The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,
[tex]P=\frac{GMm}{r^2}[/tex]
M and m are the masses
r is the distance between the masses
If the force between objects that are 10 meters apart, hence;
[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]
To find the force between objects that are any distance apart, we will use the same formula above to have;
[tex]P'=\frac{GMm}{r^2}\\[/tex]
Substitute the result above into the expression to have:
[tex]P'=\frac{100P}{r^2}[/tex]
Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
Learn more on gravitational law here: https://brainly.com/question/11760568
Calculate the velocity of an object moved around a circle with a radius of 1.65 m and an
acceleration of 3.5 m/s2.
Answer:
2.4m
Explanation:
Given parameters:
Radius of circle = 1.65m
Acceleration = 3.5m/s²
Unknown:
Velocity of the object = ?
Solution:
To solve this problem, we have to apply the formula of centripetal acceleration;
Centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r is the radius
v² = centripetal acceleration x radius
Insert parameters and solve;
v² = 3.5 x 1.65
v = √5.775 = 2.4m
The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Given the data in the question;
Radius; [tex]r = 1.65m[/tex]Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]Velocity; [tex]v = \ ?[/tex]
From the centripetal force equation, we use the expression for centripetal acceleration:
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.
We substitute our given values into the equation
[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]
Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Learn more: https://brainly.com/question/17689540
When the wooden block is placed in the water and allowed to float to the top, what percentage of it is submerged
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, what is described in the question is known as upthrust. Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.
The percentage of the submerged wooden block can be calculated as
length (in height) of the wood block submerged in water/total length (in height) of the wood × 100
The first group of planets that are made of rock and closest to the sun
Answer:
A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun
things that affects the demand for electricity
a bowling ball hits two standing bowling pins at the same time. which of the following is true. assume that all collisions are elastic
Answer:
b?
Explanation:
The peripheral speed of the tooth of a 10-in.-diameter circular saw blade is 230 ft/s when the power to the saw is turned off. The speed of the tooth decreases at a constant rate, and the blade comes to rest in 17 s. Determine the time at which the total acceleration of the tooth is 130 ft/s2.
Answer:
The time is [tex]t_r =21.58 \ s[/tex]
Explanation:
From the question we are told that
The diameter of the circular saw is [tex]d = 10 \ in = \frac{10}{12} = 0.833 \ feet[/tex]
The peripheral speed is [tex]u = 230 \ ft/s[/tex]
The time taken for the blade to come to rest is t = 17 s
The total acceleration of the tooth considered is [tex]a = 130 \ ft/s^2[/tex]
Generally the radius of the blade is mathematically represented as
[tex]r = \frac{0.833}{2}= 0. 4165 \ feet[/tex]
Generally the tangential acceleration of the blade is mathematically represented as
[tex]a__{t}} = \frac{v - u}{t}[/tex]
Here v is the final velocity of the tooth of the blade which is zero since the blade came to rest
so
[tex]a__{t}} = \frac{0 - 230}{ 17}[/tex]
=> [tex]a__{t}} = - 13.53 \ ft/s^2[/tex]
Generally the total acceleration of the tooth of the blade is mathematically represented as
[tex]a = \sqrt{a_t^2 + a_r^2}[/tex]
Here [tex]a_r[/tex] is the radial acceleration , now making [tex]a_r[/tex] the subject of the formula we have that
[tex]130= \sqrt{13.56 ^2 + a_r^2}[/tex]
=> [tex]a_r = \sqrt{130^2 -(- 13.56)^2}[/tex]
=> [tex]a_r = 129.3 \ m/s^2[/tex]
Generally radial acceleration is mathematically represented as
[tex]a_r = \frac{v_r^2}{r}[/tex]
Here [tex]v_r[/tex] is the velocity at which the total acceleration is 130 ft/s2.
=> [tex]v_r = \sqrt{a_r * r }[/tex]
=> [tex]v_r = \sqrt{129.3 * 0.4165 }[/tex]
=> [tex]v_r = 7.34 \ m/s[/tex]
Generally the time at which the total acceleration is 130 ft/s2. is mathematically represented as
[tex]t_r = \frac{7.34 - 300}{a_t}[/tex]
=> [tex]t_r = \frac{7.34 - 300}{-13.56}[/tex]
=> [tex]t_r =21.58 \ s[/tex]