are 1/2x + 3/4 - 5/8x - 7/8 and 1/8(x + 1) equivalent expressions? show your work help plss

Answers

Answer 1

Answer: No they are not.

Step-by-step explanation:

1/2x and -5/8x are like terms, if subtracted you get 1 1/8x. But then you are left with an unlike term, 3/4 so your first equation would equal out to 1 1/8x + 3/4


Now for equation 2, you use your distributive property and get 1/8(x)=1/8x

Then you must distribute 1/8(1)=1/8

1/8x + 1/8

So, 1 1/8x + 3/4 ≠ 1/8x + 1/8


Related Questions

a car magazine is comparing the top speed in miles per hour of 15 different sports cars. the speeds are included in the table below. top speeds 267.71 253 187 247.16 188 250.4 240.10 224 195 212 248.5 190 205 202 245 use a calculator to create a histogram for the data. use the default window size. what is the result?

Answers

The result of a histogram of the given data is 0.8.

There are a few steps to use a TI-83, TI-83 plus, or TI-84 calculator is used to create the histogram.

1. First, the process is to press the STAT key and then press ENTER.

2. Enter the data into column L1.

3. In the third step with all of the data entered, press the 2nd key and then press the Y= key to open the STAT PLOT menu.

4. After that press ENTER and make sure that Plot1 is set to On.

5. Use the directional keys to navigate to the Type selector, move the selection to the third type in the top row, and press ENTER.

6. Make sure that Xlist is set to L1 as this needs to be the same column as the list that the data were entered into previously. If it is not, highlight the value for Xlist and press 2nd and the 1 key for list L1.

7. Finally, press the ZOOM key and then press 9 in order to change the zoom to ZoomStat. When this is finished, the correct histogram will display on the calculator.

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Which property is being demonstrated?
3^9/3^4=3^9-4=3^5
quotient of powers property
power of a product property
product of powers property
power of a quotient property

Answers

From the given example we can say that , the given expression is in the form of quotient of a powers property.

What is Algebraic expression ?

Algebraic expression can be defined as the combination of variables and constants.

Given expression,

3^9 / 3^4

= 3^(9-4)

= 3^(5)

So,

if a^m / a^n = a^(m-n)

Its in the form of quotient of powers property.

And from above we can say that, The given expression also in the form of quotient of powers property.

Hence, From the given example we can say that , the given expression is in the form of quotient of a powers property.

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a certain corner of a room is selected as the origin of a rectangular coordinate system. if a fly is crawling on an adjacent wall at a point having coordinates (1.7, 0.6), where the units are meters, what is the distance of the fly from the corner of the room?

Answers

A certain corner of a room is selected as the origin of a rectangular coordinate system. A fly has coordinate (1.7, 0.6). The distance of the fly from the corner of the room is 1.8 meters.

Suppose we have a point having coordinate (x,y). Then the horizontal axes, vertical axis,  and the distance from the origin form a right triangle which its base is x and y.

Hence, we can find the distance of the point (x,y) from the origin using the Pythagorean Theorem.

In this case, the origin is a certain corner of the room. The coordinate of the fly is (1.7, 0.6) meters.

Using the Pythagorean Theorem:

distance = sqrt (1.7² + 0.6²)

distance = sqrt (2.89 + 0.36)

distance = sqrt (3.25)

distance = 1.8 meters

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chooe all of the following expreion which are even for all value of n
2n8
5n10
2n3
n2
4n-14

Answers

All of the expressions 2n8, 5n10, 2n3, n2, and 4n-14 are even for all values of n because all of the coefficients of n are even numbers.

2n8, 5n10, n2, 4n-14

2n8 : This expression is even for all values of n because the coefficient of n is an even number (2).

5n10 : This expression is even for all values of n because the coefficient of n is an even number (5).

2n3 : This expression is even for all values of n because the coefficient of n is an even number (2).

n2 : This expression is even for all values of n because the coefficient of n is an even number (1).

4n-14 : This expression is even for all values of n because the coefficient of n is an even number (4).

All of the expressions 2n8, 5n10, 2n3, n2, and 4n-14 are even for all values of n because all of the coefficients of n are even numbers.

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Simplify (4s+7 -2S) +4 (3s-5^2) 

Answers

Answer:

14S -93

Step-by-step explanation:

(4s+7 -2S) +4 (3s-5^2)

= 2S +7 +12S -4*25

=14S -93

(4)(-0.5)(8)(-2/4) a positive product?

Answers

Answer: +8

Step-by-step explanation:

yes, it is going to be a positive product, since two negative signs multiply to give a positive sign.

⇒(4)(-0.5)(8)(-2/4)

⇒+8 ..Answer

hope that helps...

an integer is called parity-monotonic if its decimal representation $a 1 a 2 a 3 \dots a k$ satisfies $a i < a {i 1}$ if $a i$ is odd, and $a i > a {i 1}$ if $a i$ is even. how many four-digit parity-monotonic integers are there?

Answers

The total number of four-digit parity-monotonic integers is 432*1 = 24.

Parity-monotonic four-digit integers count

We can solve this problem by counting the number of parity-monotonic integers in each of the four digits individually and then multiplying the counts together.

For the first digit, we must have [tex]$1 \leq a_1 \leq 4$[/tex] as the integer must be four-digit.For the second digit, we must have [tex]$0 \leq a_2 < a_1$[/tex] if [tex]$a_1$[/tex] is odd and [tex]$a_1 < a_2 \leq 9$[/tex] if [tex]$a_1$[/tex] is even.For the third digit, we must have [tex]$0 \leq a_3 < a_2$[/tex] if [tex]$a_2$[/tex] is odd and [tex]$a_2 < a_3 \leq 9$[/tex]  if [tex]$a_2$[/tex] is even.For the fourth digit, we must have [tex]$0 \leq a_4 < a_3$[/tex] if [tex]$a_3$[/tex] is odd and [tex]$a_3 < a_4 \leq 9$[/tex] if [tex]$a_3$[/tex]is even.

By counting the possible values of [tex]$a_1$[/tex], [tex]$a_2$[/tex], [tex]$a_3$[/tex] and [tex]$a_4$[/tex] independently, we have:

[tex]$a_1$[/tex] has 4 possibilities[tex]$a_2$[/tex] has 3,2,1 possibilities depending on [tex]$a_1$[/tex] is even or odd[tex]$a_3$[/tex] has 2,1,2,1 possibilities depending on [tex]$a_2$[/tex] is even or odd[tex]$a_4$[/tex] has 1,0,1,0 possibilities depending on [tex]$a_3$[/tex] is even or odd

Thus, the total number of four-digit parity-monotonic integers is 432*1 = 24.

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Chris opens up a new visa credit card and credit line with U. S. Bank. He is paying a 15% annual percentage rate (APR) on all new purchases. If he has a current balance of $2,800 on this credit card, how much does he owe in interest to the back next month?

Answers

Chris owes $35 in interest to the back next month.

We know that a credit card's interest rate is nothing but the price one  pay for borrowing money. This is called the annual percentage rate (APR).

The Interest paid is calculated by the formula:

I = PTR ÷ 100

where P = Principal amount ,

R= rate of interest in percentage ,

and T= period.

Here, P = $2800,

R = 15%

T=  1 year

Using above formula,

I = (2800 x 15 x 1) ÷ 100

I = 420.

He will pay an interest of 420 ÷ 12= $35 per month.

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The relationship between time in months and height in inches for Kylie's plant is represented by the
equation y = 12x. The relationship for Glen's plant is represented by the equation 2y = 24x. Is there a
time when the two plants are the same height?

Answers

Both equations are equivalent, which means that the two plants always have the same height.

Is there a time when the two plants are the same height?

We know that the height in inches for Kylie's plant is represented by the

equation y = 12x, where x is the time in months.

And the height of Glen's plant is represented by the equation 2y = 24x

Notice that if we take the second equation and we divide both sides by 2, we will get:

2y = 24x

2y/2 = 24x/2

y = 12x

This is the same equation than the one that represents the height of Kylie's plant.

Then the two plantes have the same height always.

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Sara says if you subtract 19 from my number and multiply the difference by -6 the result is -96,


what is saras number

PLEASE PLAE PLASE PALSE PLASEP APLSASEP PLASEP PLEASE PLAESESEEPZ.

Answers

Answer is your number is 35

Step by step

Your number is n
Subtract 19 from your number
= n - 19
Multiply the difference by -6
= -6(n - 19)
The result is -96
So your equation is

-6( n - 19) = -96
divide both sides by -6 to isolate n

-6/-6 (n - 19) = -96 / -6

n - 19 = 16

Add 19 to both sides to solve for n

n - 19 + 19 = 16 + 19
Simplify

n = 35

Your number is 35

Check your work

Your equation is -6( n - 19) = -96
Sub in 35 for n

-6( 35 - 19) = -96
Divide both sides by -6

35 - 19 = 16

16 = 16

It equals so your solution is correct!

The difference between the water levels for high and low tide was 3. 6 feet. Write and solve an equation to find the water level at high tide

Answers

The difference between the water levels for the high and low tide was 3. 6 feet. the equation to find the water level at high tide x = y + 3.6, where  High Tide Water Level = x and  Low Tide Water Level = y.

In simple form it will be  High Tide Water Level = Low Tide Water Level + 3.6. To explain this equation, the water level at high tide is equal to the water level at low tide plus 3.6 feet. The variable 'x' represents the water level at high tide, while the variable 'y' represents the water level at low tide. By adding 3.6 feet to the water level at low tide, we can find the water level at high tide.  

For example, if the water level at low tide is 4 feet, the water level at high tide would be 4 + 3.6 = 7.6 feet. To find the water level at high tide for any given low tide water level, one can simply add 3.6 feet to the known low tide water level. This equation can be used to accurately calculate the water level at high tide for any given low tide water level.

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The price of a new car was $22,800 in April. However, the price of the car was reduced by 5% in May. Find the price in May.

In May, the price of the car was ? % as compared to

the price of the car in April.

Answers

Answer: To find the price of the car in May, we can use the formula:

New price = Original price - (Original price x Discount rate)

In this case, the original price is $22,800, and the discount rate is 5%, which can be written as 0.05.

So, the new price in May is:

New price = 22700 - (22700 x 0.05)

New price = 22700 - 1135

New price = $21,565

So, the price of the car in May was $21,565.

To find the percentage of the price of the car in May as compared to the price of the car in April, we can use the formula:

(New price / Original price) x 100

In this case, the new price is $21,565 and the original price is $22,800

(21565 / 22700) x 100 = 0.95 x 100 = 95%

Therefore, in May, the price of the car was 95% as compared to the price of the car in April.

Step-by-step explanation:

In a survey of 50 first graders, 30% said their favorite food is hot dog. Which box is correctly set up to show this?

Answers

The probability that the number of first graders who have liked the hot dog is 15

In math the term probability is defined as a number that reflects the chance or likelihood that a particular event will occur

Here we have know that in a survey of 50 first graders, and then 30% said their favorite food is hot dog.

Here we have to find the probability that the number of first graders who have liked the hot dog

As we know that the number of first graders is 50.

And here we also know that 30% of them are liked the hot dog.

Then it can be calculated as,

=> 50 x 30%

=> 50 x 30/100

=> 15.

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Write the decimal as a fraction. 0.83 = F 10 x 0.83 = F x 10 8.33= [?]F

Answers

The decimal 8. 33 written as a fraction is 8 3/10

What is a fraction?

A fraction can be defined as the part of a whole number, variable, element,

The several types of fractions are;

Proper fractionsMixed fractionsImproper fractionsSimple fractionsComplex fractions

Examples of mixed fractions: 2 4/5, 7 1/2

Examples of simple fractions: 1/3, 1/4

Examples of improper fractions: 6/4, 7/5

Example of proper fractions: 2/3, 4/5

From the information given, we have that;

8.33

This is represented as;

8 3/10

Hence. the value is 8 3/10

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evaluate h(x)= -10x when x= -3,0, and 4

Answers

In order to replace the value in the explicit expression for h, one must evaluate a function h(x) for a particular value of the independent variable x.  h(-3)=30, h(0)=0, h(4)=-40

How to find the calculation?A function is evaluated by determining the value of f(x) =... or y =... that corresponds to a certain value of x. Simply substitute whatever x has been assigned for all of the x variables to do this.Meaning: Simplify and replace x with 5 Parentheses should be used to enclose the value that is being substituted.A variable is replaced with a provided number or expression when a function is evaluated. In order to replace the value in the explicit expression for h, one must evaluate a function h(x) for a particular value of the independent variable x.The task is as follows:

h(x)=-10x

Let's determine the values below:

h(0)= -10 * (0) = 0 and h(4)= -10 * (4) = -40, respectively.

h(-3)=30, h(0)=0, h(4)=-40.

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The average birth weight of a Boxer breed dog is 1.25 kilograms. What is the average birth weight in grams?The average birth weight of a Boxer breed dog is 1.25 kilograms. What is the average birth weight in grams?

Answers

Answer:

1250g

Step-by-step explanation:

1.25 kg × 1000 = 1250g

Use the Bisection Method up to five iterations and find the root to 3 decimal places for the following:
f(x) = x2 − 3x + 1 in the interval [0, 1]

A.
0.375

B.
0.438

C.
0.406

D.
0.391

Answers

Answer:

  D.  0.391

Step-by-step explanation:

You want the approximate solution to f(x) = x² -3x +1 = 0 on the interval [0, 1] using 5 iterations of the Bisection Method.

Iteration

The Bisection Method makes one iteration by finding the function value at the midpoint of the interval. The midpoint replaces the end of the interval whose function value has the same sign. At the end of one iteration, the midpoint of the halved interval is calculated.

Start:

  f(0) = 1, f(1) = -1. Interval: [0, 1]; midpoint: 1/2

First iteration:

  f(1/2) < 0. Interval: [0, 1/2]; midpoint: 1/4

Second iteration:

  f(1/4) > 0. Interval: [1/4, 1/2]; midpoint: 3/8

Third iteration:

  f(3/8) > 0. Interval: [3/8, 1/2]; midpoint: 7/16

Fourth iteration:

  f(7/16) < 0. Interval: [3/8, 7/16]; midpoint: 13/32

Fifth iteration:

  f(13/32) < 0. Interval: [3/8, 13/32]; midpoint: 25/64

Solution

The approximate solution after 5 iterations is x ≈ 25/64 ≈ 0.391.

__

Additional comments

The approximate solution in the interval to full calculator precision is 0.38196601125. The exact solution is 1.5-√1.25.

You will notice that the function values for the ends of the interval [0, 1] are [positive, negative]. So, when the function value at the midpoint is negative, that point replaces the right end of the interval.

Of course, the midpoint is the average of the interval end values.

On average, it takes about 3.3 iterations to improve the accuracy of the solution by 1 decimal place.

in a negatively skewed distribution of exam scores, bender scored at the mean, fry scored at the median, and lela scored at the mode. who had the highest score?

Answers

Lela had the highest score.

Now, According to the question:

A skewed distribution is neither symmetric nor normal because the data values trail off more sharply on one side than on the other. In business, you often find skewness in data sets that represent sizes using positive numbers.

In a negatively skewed distribution, higher values are more frequent than lower values causing the distribution to present a longer left-tail. This implies in a median higher than the mean and in a mode higher than the median:

mean < median < mode.

Therefore, since Lela scored at the mode, Lela had the highest score.

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5b-2c + 3)-d, a +2b-c+d, 2-d + 3c + a​

Answers

The sum of the given expression will be 2a+7b+-d.

What are expressions?

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between. The mathematical operators can be of addition, subtraction, multiplication, or division. For example, x + y is an expression, where x and y are terms having an addition operator in between. In math, there are two types of expressions, numerical expressions - that contain only numbers; and algebraic expressions- that contain both numbers and variables.

e.g. A number is 6 more than half the other number, and the other number is x. This statement is written as x/2 + 6 in a mathematical expression. Mathematical expressions are used to solve complicated puzzles.

Now

Given expressions are 1.5b-2c+3-d 2.a+2b-c+d 3.2-d+3c+a

By adding these

=a+a+5b+2b-2c-c+3c-d+d-d

=2a+7b-d

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what is the value of the expression below? (15^1/5)^5

Answers

Answer:

15

Step-by-step explanation:

Given the expression:
[tex]\displaystyle{\left(15^{\frac{1}{5}}\right)^5}[/tex]

We can apply the law of exponent of:

[tex]\displaystyle{\left(a^m\right)^n = a^{mn}}[/tex]

Therefore, we will have:

[tex]\displaystyle{\left(15^{\frac{1}{5}}\right)^5 = 15^{\frac{5}{5}}}\\\\\displaystyle{\left(15^{\frac{1}{5}}\right)^5 = 15^{1}}\\\\\displaystyle{\left(15^{\frac{1}{5}}\right)^5 = 15}[/tex]

Hence, the value of expression is 15.



An octagon with vertices at (-4, 2), (-2,5), (1,5), (3, 2), (3, -6), (1, -3), (-2, -3),

and (4, -6) was dilated by a scale factor of 3 and with a center of dilation at the

origin. What are the coordinates of the vertices of the dilated octagon

Answers

Coordinates of the vertices of the octagon after dilation by scale factor 3 are (-12, 6), (-6,15), (3,15), (9, 6), (9, -18), (3, -9), (-6, -9),and (12, -18).

Original coordinates of the vertices of an octagon are :

(-4, 2), (-2,5), (1,5), (3, 2), (3, -6), (1, -3), (-2, -3), and (4, -6).

Scale factor is equal to 3

Figure transformed using dilation of scale factor of 3 with center of dilation at the origin.

Coordinates of the new vertices after dilation of the octagon.

(-4×3, 2×3) = ( -12, 6)

(-2 ×3,5×3) = ( -6 , 15)

(1 ×3,5×3) = ( 3 ,15)

(3×3, 2×3) = ( 9,6)

(3×3, -6×3) = ( 9, -18)

(1 ×3, -3×3) = ( 3 , -9)

(-2×3, -3×3) = ( -6 , -9)

(4×3, -6×3) = (12, -18)

Therefore, the new coordinates of the vertices after dilation are (-12, 6), (-6,15), (3,15), (9, 6), (9, -18), (3, -9), (-6, -9),and (12, -18).

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A ball is thrown upward at an angle of elevation of 28 degrees with a force of 19n. How much of that force is horizontal and how much of that force is vertical?​

Answers

19N force act in upward direction with angle of elevation 28 degrees has horizontal and vertical force is given by 16.78N and 8.92N respectively.

Angle of elevation while thrown a ball upward 'α' = 28 degrees

Force 'F' is equal to 19N.

While throwing a ball force is applied in two possible direction are:

Horizontal direction and Vertical direction.

For horizontal direction :

let 'x' represents the horizontal direction

cosα = x / F

⇒ cos28° = x / 19

⇒ x = 19 cos 28°

⇒ x = 19 × 0.8829

⇒ x = 16.78N

For Vertical direction :

let 'y' represents the vertical direction

sinα = x / F

⇒ sin28° = y / 19

⇒ y = 19 sin 28°

⇒y = 19 × 0.4695

⇒ y = 8.92N

Therefore, the horizontal force and vertical force for the given angle of elevation is equal to 16.78N and 8.92N respectively.

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The art teacher has 48 paintbrushes. She puts 8 paintbrushes on each table in her classroom. How many tables are in her classroom?

Answers

Answer:

6 Tables

Step-by-step explanation:

48 tables divided by 8 paintbrushes equals 6 tables.

6 tables is the correct answer.

(05.01 MC)
Currently, the temperature of an ice cream is 81°C below room temperature. The temperature of the ice cream decreases based on the
function f(t)=81(0.83) where t represents time elapsed in minutes. Where does the graph of f(t) cross the y-axis, and what does this represent
in the context of the problem?

Answers

The graph of f(t) crosses the y-axis at t = 0, which represents the initial temperature of the ice cream (81°C below room temperature).

What does this represent in the context of the problem?

The graph of f(t) crosses the y-axis at y=81, which represents the initial temperature of the ice cream, 81°C below room temperature. This is the starting point of the graph, and all subsequent points on the graph represent the temperature of the ice cream as time progresses. As time passes, the temperature of the ice cream decreases, and the graph of f(t) illustrates this change.

The y-intercept of a graph measures the initial value of the function. In this case, the initial temperature of the ice cream is 81°C below room temperature. As the time passes, the temperature of the ice cream decreases at a rate of 0.83°C per minute. This rate of decrease is represented by the slope of the graph, which is 0.83.

The point where the graph of f(t) crosses the y-axis illustrates the initial temperature of the ice cream, and all subsequent points on the graph represent the temperature of the ice cream as time progresses. This is a helpful visual representation of the rate at which the temperature of the ice cream is decreasing. The graph of f(t) is a useful tool for understanding how the temperature of the ice cream changes over time.

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The nature of the roots for the equation

Answers

If D > 0 and not an excellent square, then the roots of the quadratic equation are real, unequal and irrational.

What is Quadratic Equation ?

Quadratic equation can be defined as equation in which it is in the form of ax^2+bx+c = 0 .

Nature of Roots depending upon Discriminant

in step with the value of discriminant, we shall discuss the subsequent cases about the character of roots.

Case 1: D = 0

If the discriminant is same to 0 (b2 – 4ac = zero), a, b, c are real numbers, a≠0, then the roots of the quadratic equation ax2 + bx + c = zero, are real and equal. In this case, the roots are x = -b/2a. The graph of the equation touches the X axis at a single point.

Case 2: D > 0

If the discriminant is greater than zero (b2 – 4ac > 0), a, b, c are actual numbers, a≠0, then the roots of the quadratic equation ax2 + bx + c = 0, are actual and unequal. The graph of the equation touches the X-axis at two unique points.

Case 3: D < 0

If the discriminant is less than 0 (b2 – 4ac < 0), a, b, c are real numbers, a≠0, then the roots of the quadratic equation ax2 + bx + c = 0, are imaginary and unequal. The roots exist in conjugate pairs. The graph of the equation does not touch the X-axis.

Case 4: D > zero and perfect square

If D > zero and an excellent square, then the roots of the quadratic equation are actual, unequal and rational.

Case five: D > 0 and now not an excellent square

If D > 0 and not an excellent square, then the roots of the quadratic equation are real, unequal and irrational.

Therefore, If D > 0 and not an excellent square, then the roots of the quadratic equation are real, unequal and irrational.

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the diagonals of a trapezoid are perpendicular and have lengths $3$ and $4$. find the length of the median of the trapezoid.

Answers

The correct answer is 5/2. The median trapezoid is the line segment that bisects the area of the trapezoid and has its end points on the 2 bases of the trapezoid.

The median length is √( (3/2)^2 + (4/2)^2 ) = √(9/4 + 16/4) = √(25/4) = 5/2. So, the length of the median of the trapezoid is 5/2.

Since the diagonals of a median trapezoid bisect each other, the median of the trapezoid is the line segment that connects the midpoints of the diagonals. To find the median length, we can use the distance formula, which is the square root of the sum of the squares of the differences in the x-coordinates and y-coordinates of the 2 points. In this case, the median length is the square root of the sum of the squares of 1/2 length of the diagonals.

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The length of the median of the trapezoid will be 5/2 units.

Given that the median trapezoid is the line segment that divides the trapezoid's area and has its ends on its two bases,

The median length will be:

√( (3/2)^2 + (4/2)^2 )

= √(9/4 + 16/4)

= √(25/4)

= 5/ units

So, the length of the median of the trapezoid is 5/2.

The median of a median trapezoid is the line segment that links the midpoints of the diagonals since the diagonals of a median trapezoid bisect one another. We may use the distance formula, which is the square root of the sum of the squares of the differences in the x-coordinates and y-coordinates of the two points, to get the length of the median. The median length in this instance is equal to the square root of the sum of the squares of the diagonals' half-lengths.

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Find the 67th term of the arithmetic sequence -17,-23,-29

Answers

The 67th term of the arithmetic sequence -17,-23,-29 is -413.

What is the arithmetic sequence?

An arithmetic sequence is a sequence of numbers such that the difference between any two consecutive terms is always the same. This difference is called the common difference, and it can be represented by the variable d.

Given the sequence -17,-23,-29, we can see that the common difference is d = -23 - (-17) = -6

The nth term of an arithmetic sequence can be found using the formula:

a_n = a_1 + (n-1)d

where a_1 is the first term of the sequence, n is the term number and d is a common difference.

For the 67th term, a_1 = -17, n = 67 and d = -6

So the 67th term is:

a_67 = -17 + (67-1) * -6 = -17 + 66 * -6 = -17 - 396 = -413

Hence, the 67th term of the arithmetic sequence -17,-23,-29 is -413.

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Answer: -413

Step-by-step explanation:

What is the solution to this system of

equations?

s 6x – 2y = 8

1-3x + y = -4

Answers

According to the elimination method, the solution of the system of equation has infinite number of solutions.

In math the term elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with multiplication or division of coefficients of the variables

Here we know that the equations are

=> 6x - 2y = 8 ---------------(1)

=> -3x + y = -4 ------------------(2)

when we simplify the equation (1) by dividing the terms by 2, then we get

=> 3x - y = 4

Now, we have to add the two equation then we get the result as,

=> (-3x + 3x) +( -y + y) = (-4 + 4)

=> 0 + 0 = 0

Hence the system has an infinite number of solutions.

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Use the figure shown for Items 1–4. In the figure, m∠IJL=0.5 m∠JIK.


Triangle I J K with side I J congruent to side J K. Segment J L is drawn from vertex K perpendicular to base I K such that it bisects the base. Segment I L has length 3 x and is congruent to segment L K which has length 2 x plus 5.

Select all the statements that must be true.
A. KL=15
B. JL bisects IK
C. ΔIJK is equilateral.
D. JL is the perpendicular bisector of IK
E. JL=2LK

Answers

The true statements are:

A. KL=15

B. JL bisects IK

D. JL is the perpendicular bisector of IK

What is perpendicular?

Two geometric objects are perpendicular in simple geometry if they intersect at a right angle. The perpendicular sign, ⊥ , can be used to visually depict the state of perpendicularity. It can be defined between two planes, two lines, or two planes and another line.

Given:

We have a triangle IJK.

m∠IJL=0.5 m∠JIK.

Side IJ ≅ side JK.

JL ⊥ IK.

It bisects the base.

That means,

JL bisects IK and JL is the perpendicular bisector of IK.

So, IL = LK.

3x = 2x + 5

x = 5

KL=15.

Therefore, A, B and D are the true statements.

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Function rule or explanation of why it is not possible to find a function rule

Answers

a. Function
b. Function
c. Not a function
d. Function

It’s easy to tell if a graph or a data table is a function or not. For a graph, use the vertical line test. Simple draw or imagine a vertical line straight down from the top to the bottom of the graph. The vertical line can only touch the line on the graph once, anything more than once will fail it as a function. So like circles will fail the vertical line test, and therefore, is not a function. You also have to go through the whole graph, left to right, with the vertical line test.
For data tables, look out for x values. In one table, the same x value cannot happen more than once. If you see two same x values, it is not a function, if not, it is. So as you see in the third one, there are duplicates of -100, -25, and -4. Whereas in others, there are no duplicate x values.
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