A turtle is moving at a speed of 1.5 m/s for a time of 120 s. What is the distance the turtle travels?

Answer:

She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing

Explanation:

The given parameters are;

The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km

The initial elevation of the plane Ashley is flying = Sea level = 0 m

The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance

∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance

We have;

The gradient  = Rate of change of elevation/(Horizontal distance)

Therefore;

The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km

The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

→Acceleration of block

→Tension in strings

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

Answer & Explanation:

Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.

Explanation:

distance

speed =_________

time

distance = speed × time

= 2.5 × 5.0

distance = 12.5 m

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

Answer: IT IS TRUE

Explanation:

Hope this helps

Plyometrics can help a person maintain cardiorespiratory fitness T

It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness

Plyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.

Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.

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Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]

Substituting the known values, gives;

[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]

The horizontal range ≈ 141.25 m.

Answer: An independent variable is the variable which is changed. Experiments are usually published to communicate findings to the scientific community.

Disproving a hypothesis means it cannot be tested again.

Explanation: i hoped that helped.

Answer:

Velocity = 15.87m/s

Explanation:

Given the following data;

Distance, d = 200000m

Time, t = 12600secs

*To find the velocity*

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

[tex]Velocity = \frac{distance}{time}[/tex]

Substituting into the equation, we have;

[tex]V = \frac{200000}{12600}[/tex]

Velocity = 15.87m/s

Therefore, the velocity of the car is 15.87 meters per seconds due west.

Answer:

Explanation:

The time taken can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{20}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

Explanation:

A bar chart also known as a bar graph can be defined as the graphical representation of data (informations) by using vertical columns or rectangular bars. When a data set is observed, a bar chart can be used to graphically represent or record the total or overall amount of information contained therein. Generally, bar charts are used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

The bar graph has a x-axis and a y-axis used to represent the various categories of data collected.

In this scenario, the x-axis is used to denote the points earned by the teams while the y-axis is used to denote the seasons as seen in the image attached.

Hence, point scores by team (Team A, B and C) per seasons (2002, 2003, 2004 and 2005) can best be compared through the use of a bar chart (graph).

Answer:

Answer above is correct i only put this:

Explanation:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{147}{9.8} \\ [/tex]

We have the final answer as

Hope this helps you

Answer is c, they are equal:

Explanation:

Answer:

correction of farsightedness uses a converging lenses that compensates for the under convergence by the eye. the converging lens produces an image farther from the eye than the object so that farsighted can see it clearly.

Answer:

1. The subduction zone serves as the meeting point for two tectonic plates.

2. At the Mid- Ocean ridge, decompression melting occurs.

3 What causes the magma to rise is the increase in pressure caused by collection of gases by the magma.

Explanation:

Subduction zone is define as a zone where tectonic plates ( an oceanic plate slides beneath a continental plate) meets and contributes to the rise of magma to the surface in geological sciences.

At the Mid - Oceanic ridge, decompression melting occurs. As mantle ascends beneath the mid-ocean ridge, less and less rock lies above it, so large pressure changes occur, which leads to melting. The melt is less dense than the solid, and rises to the surface to form the oceanic crust.

At the subduction zone the magma that is formed is usually made up of silica rich lava. Thick silica rich magma does not release the gasses very easily so they build up inside the magma chamber. As the gasses collect in the chamber, the pressure rises. It is possible for the pressure to rise so much that the chamber cannot contain the magma and it erupts explosively.

Answer:

because nono gravity

Explanation:

no gravity

Answer : 16 m/s east

Explanation: Trust the process!!

From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east

The relative velocity is defined as the velocity of an object with respect to another observer

When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .

From the frame of reference of runner 1, the velocity of runner 2 will be

v (relative) = v1 + v1

v1 = velocity of runner 1  = 11m/s west

v2 = velocity of runner 2 = 5m/s

v = 11 + 5 = 16 m/s

correct answer will be O D. 16 m/s east as runner 2 is running in east direction

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Answer:

B

Explanation:

This is a balanced force. In a balanced force, nothing happens.

-- The distance the force moved through

-- How long the force lasted

The other thing we need to calculate the power is the "Velocity".

The relation can be shown as:

→ [tex]P= Fv[/tex]

where,

Thus the above is the right response.

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Answer:

40.1m/s

Explanation:

This is a kinematics problem

x = 82m

a = -9.8m/s^2

v(initial) = 0

Find: v(final)

Using kinematics equation:

vf^2 = vi^2 + 2a(delta)x

vf^2 = 0 + 2*(-9.8)*(82)

vf = sqrt(1607.2) = 40.09m/s

The is traveling with a velocity of 40.1m/s when it hits the ground.

Answer:

V₀ = 5.47 m/s

Explanation:

The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 3.04 m

θ = Launch Angle = 41.7°

V₀ = Minimum Launch Speed = ?

g = 9.81 m/s²

Therefore,

3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)

V₀² = 3.04 m/(0.10126 s²/m)

V₀ = √30.02 m²/s²

V₀ = 5.47 m/s

Answer:

Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.

Explanation:

Decreasing the temperature of the copper made the final temperature decrease. But the mass remains constant.

Heat is energy that is transmitted from one body to another as a result of a temperature differential. When two bodies of different temperatures come into contact,

Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.

Thermal expansion is caused by heating. The mass remains constant. The loudness rises. As a result, the density drops.

To learn more about heat energy refer to the  link;

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Answer:

There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.

Explanation:

If the data consistently do not support the hypothesis, then CLEARLY, the hypothesis is NOT a reasonable explanation of what you are investigating. The hypothesis is rejected, and we search for a new interpretation, an new hypothesis that supports the experimental data

Respiratory and circulatory systems are the two systems within the human body that work together during exercise.

The respiratory system:

The circulatory system:

During exercise:

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Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

Answer:

100km/hr

Explanation:

From the problem statement we know that distance of the trip is 115km

Expected time for the trip = 1.2hrs

→ If she spends the first half-hour going 90km/hr,

    Here  time  = 0.5hr

              speed  = 90km/hr

 The distance covered;

    Distance covered   =  Speed x time

    Distance covered  = 90 x 0.5  = 45km

→The remaining distance will be:

        Total distance - distance covered

              115km  - 45km  = 70km

→ The remaining time;

      1.2hr - 0.5hr  = 0.7hr

 Speed  = [tex]\frac{distance}{time}[/tex]  

  Insert the parameters and solve;

  Speed  = [tex]\frac{70}{0.7}[/tex]   = 100km/hr

For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.