a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.

A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder
A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder

Answers

Answer 1

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity

Answer 2

A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column  having length 0.19m which is given by,

(p₀+pm)×0.190 = nRT÷A.

What is Pressure?

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area.  its SI unit is Pascal (Pa) which is equal to N/m².  is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.

We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.

i.e.  (p₀+pm) = pressure on the air column

this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.

i.e. (p₀+pm) = back pressure inside the gas column......1)

according to ideal gas equation, PV=nRT

pressure inside the air column is P = nRT÷V

where V is volume of gas that is A×0.190.

P = nRT÷(A×0.190).....( back pressure inside the gas column).

equation 1 becomes

(p₀+pm) = nRT÷(A×0.190).

Hence we get

(p₀+pm) ×0.190= nRT÷(A).

Hence proved.

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6.25÷6.94                 5.40÷12.01                    21.60÷16.00

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0.9006÷0.4496        0.4496÷0.4496            1.35÷0.4496

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Hi there!

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Answers

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Answers

Answer:

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Explanation:

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Answers

Answer:

a) Gradient = rise/run = mass/volume

since the graph is mass against volume we know mass is on the y-axis and volume is on the x-axis

in physics it’s best to use a larger part of the graph to find the gradient, so imma use the biggest values.

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I got this graph (the image)

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