The value of the spring constant for the spring stretched by 35 cm is 0.000244 J/cm.
To calculate the spring constant, the equation
Work = Force x Distance. The work of the spring (0.30 J) is known, as well as the distance the spring is stretched (35 cm). Therefore, the force is calculated by dividing the work by the distance is 0.0086 erg.
Force = - spring constant x Distance
The force is then divided by the distance the spring is stretched back to its equilibrium position (35 cm) to find the spring constant. The spring constant is the amount of force required to stretch the spring 1 cm. In this example, the spring constant is 0.000244 J/cm.
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for the pulley system shown, determine the acceleration and velocity of block a after block b has fallen for 3 seconds from rest. block b accelerates at 0.5 m/s2. (0.25 m/s2, 0.75 m/s)
At the time when the Acceleration of b is 0.5 the acceleration would be 0.25 m/s2 and the velocity would be 0.75 m/s after 3 seconds of falling B.
The relation between the acceleration of 2 bodies in this situation will be as a1 = 2a2 where a1 is the acceleration of body1 and a2 is the acceleration of body2. So given the acceleration of the body at 3 seconds is 0.5 m/s2 so the acceleration of body1 would be half of the body1.
Similarly for velocity using v= u+ at ....(i). we can find the velocity of body1 as we have acceleration(a), time(t), And Initial Velocity(u).
u= 0 ................ (As the body starts from rest)
a = 0.25m/s2 .........(calculated on the basis of the acceleration of body2)
t = 3 Seconds ---(As given)
So from (i) we can say
v = 0+ 0.25*3 => v = 0.75 m/s
So the velocity of body 1 will be 0.75m/s after 3 seconds of falling down.
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I need someone to graph this for me if possible
Here is the formula for the problem
X Axis = 30°/25 DIV = 12 °C/DIV
Y Axis = 6.0cm/19 DIV = 0.3157 => 0.32 cm/DIV
NEED THIS BY 11 PM EST THIS WAS POSTED ON 1/24/2023
To make a graph with the data in the table, we must place the data in a column on the x-axis and the other data on the y-axis to organize the information correctly.
How to make a graph with the information from the chart?To make a graph with the information in the table, we must identify what type of table would serve to relate the data in the table. In this case, a line graph would be useful because it has the purpose of demonstrating the differences of an object over time or subjected to different conditions.
In this case, we want to demonstrate the influence that temperature has on the height of a plant. Therefore, we put the temperature on the y axis and the height of the plant on the x axis.
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chapter 5 - problem 6. an eccentric inventor attempts to levitate a cork ball by wrapping it with foil and placing a large negative charge on the ball and then putting a large positive charge on the ceiling of his workshop. instead, while attempting to place a large negative charge on the ball, the foil flies off. explain.
The foil flew off because of static electricity. When the inventor attempted to place a large negative charge on the ball, the negative charge caused an imbalance of electrons between the ball and the foil.
What is static electricity?Static electricity is a form of electrical energy that occurs when electric charge accumulates on the surface of an object. It is created when two objects that have a different electrical charge come into contact and then separate, causing electrons to move from one object to the other.
This caused an electric field to form between the ball and the foil, generating an electrostatic force which repelled the foil away from the ball.
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Why does heating water affect surface tension
As temperature increases, molecules of liquid become more active and they move more rapidly.
from the list below, select the ingredient that is not necessary for the national weather service to issue a blizzard warning.
Bitterly cold air with wind chill temperatures is not required for the national weather service to issue a blizzard warning.
What is weather service?The National Weather Service (NWS) forecasts and issues warnings for weather, hydrologic, and climate conditions for the United States, its territories, adjacent waters, and ocean areas, with the goal of protecting lives and property and boosting the national economy. Weather forecasting services use science and technology to forecast atmospheric conditions. Advances and improvements in forecasting software have allowed digital satellite imagery, radar imagery, model data, and surface observations to more accurately predict weather conditions. Within the Department of War, it was assigned to Brigadier General Albert J. Myer's Signal Service Corps. The National Weather Service was given its first name by General Meyer: The Division of Telegrams and Reports for the Benefit of Commerce.
Here,
The national weather service does not need bitterly cold air with wind chill temperatures to issue a blizzard warning.
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Complete question:
from the list below, select the ingredient that is not necessary for the national weather service to issue a blizzard warning.
a. Bitterly cold air with wind chill temperatures below -18F
b. Falling or blowing snow
c. Reduced visibility to 1/4 mile or less
d. 30 kt (35 mph) sustained winds
A single cylinder, double acting compressor with bore and stoke of 45 cm x 45 cm is tested at 150 rpm and found to deliver a gas from 101.3 kPa and 300 K to 675 kPa at a rate of 0.166 m^3/s when n = 1.33 for compression and expansion process? Calculate the percent clearance.Answer in %
A single cylinder, double acting compressor with bore and stroke of 45 cm x 45 cm is tested at 150 rpm. The percent clearance is 586.6%
What is a formula?An equation is a mathematical statement that uses the equals sign (=) to show that two expressions are equal. Equations can be used to find solutions to problems with unknown values and to define relationships between various variables. Equations are also used to represent natural laws and describe the behavior of physical systems.
The following equation can be used to determine the percentage of clearance:
C is equal to 100 times (Vd/Vs - 1),
where Vd is the volume displaced per cycle and
Vs is the volume swept per cycle.
The following equation can be used to determine the displaced volume per cycle: (n/n-1) x (V1/P1) x (P2 - P1) is Vd.
The following equation can be used to determine the swept volume per cycle: Vs is equal to /4 × (D2) × L, where D is the cylinder's bore and L is its stroke.
We obtain: by putting the given values into the equations:
Vs = /4 × (452) × 45 = 10302.5 cm3/cycle = 0.01031 m3/cycle
C = 100 × (6.049/0.01031 - 1) = 586.6%,
which indicates that the clearance percentage is 586.6%.
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The impulse an object experiences is the
product
of the
[ Select ]
and
[ Select ]
, and its unit is
[ Select ]
or
[ Select ]
.
Answer:
Explanation:
Impulse is the product of force and time
there for it unit will be [Newton seconds]
Your physics teacher crumples a piece of paper into a ball and releases it from rest 2.0 m from the ground. How long does the ball take to hit the ground?
When the ball is released from rest 2.0 m from the ground, it will hit the ground at 0.63 seconds.
What is the fall kinematics equation?Therefore, acceleration owing to gravity is the name given to the acceleration of falling objects in free fall.
The paper ball falls from the rest, so the initial velocity will be 0.
s = ut + 1/2 at²
S is the height
u is the initial velocity
g is the gravity (9.81 m/s²)
t the time
The height will be 2.0 m, u = 0
2 = 0 x t + 1/2 x 10 x t²
2 = 5t²
t² = 2/5
t = 0.63 seconds.
Therefore, the ball will hit the ground after 0.63 seconds of its release.
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while the penumbra of a sunspot can "grow" and become bigger. What do you think this means? What is the significance of it for us on Earth
While the penumbra of a sunspot can "grow" and become bigger.The significance is that the area around the sunspot is becoming darker and larger.
Why do sunspots appear and what are they?Sunspots are cooler, darker areas on the sun's surface that stand out from the sun's brighter surroundings. They are brought on by a blockage in the flow of heat and energy from the interior of the sun caused by intense magnetic activity. Sunspots can be anywhere from a few hundred to many thousands of kilometers in diameter and are most common near the sun's poles. Depending on their size and activity, sunspots can last for days, weeks, or even months.
Sunspots are linked to increased solar activity, which can alter Earth's magnetic fields, so this is significant for us on Earth. Geomagnetic storms and additional radiation that reaches Earth's surface as a result of this could disrupt electronic systems like power grids and radio transmissions.
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What is the distance from the center of the Earth to a point where the acceleration due to gravity is
g/16?
This same distance from the Earth's core to a location where the gravitational acceleration is g/16 is roughly 20,000 miles (32,000 kilometers).
What is the most basic meaning of acceleration?The pace at which speed changes is known as acceleration. So because direction of an object's velocity is shifting even while it follows a circular course, it continues to accelerate.
How do you determine acceleration?According to the formula a = v/t, kinetic energy (a) is the product of the change in momentum (v) and the shift in time (t).
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true/false. three particles of identical mass m are acted on only by their mutual gravitational attraction. they are initially located at the vertices of an equilateral triangle with sides of length l. consider the motion of any one particle about the com of the system, g and using g as the origin of the inertial frame, find the angular velocity required to keep l constant
True, the three particles of identical mass m are acted on only by their mutual gravitational attraction when located at the vertices of an equilateral triangle with sides of length l.
To keep l constant, the angular velocity required for the motion of any one particle about the center of mass (COM) of the system, g, needs to be calculated.
This can be calculated by using the equation
ω = √[G × m × (1/l³)].
In this equation, G represents the gravitational constant and m is the mass of the particles. Thus, the angular velocity required to keep the sides of the triangle of length l constant is equal to √[G × m × (1/l³)].
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the ionosphere (or thermosphere) is really far out there! it is home to which of the following? select all that apply.
The ionosphere is the home of all charged particles in the earth's atmosphere, as well as some of the satellites that we launch.
The ionosphere of Earth extends from the top of the atmosphere to the very edge of space. The Sun heats the gases until they lose an electron or two, resulting in a sea of electrically charged particles.
The ionosphere extends 50 to 400 miles above the Earth's surface, right on the edge of space. The ionosphere, along with the neutral upper atmosphere, forms the boundary between Earth's lower atmosphere — where we live and breathe — and space.
This space boundary is right where many of our Earth-orbiting satellites, including the International Space Station, are located. This means that these satellites can be affected by the ionosphere's constantly changing conditions, such as sudden swells of charged particles that increase drag on satellites and shorten their orbital lifetimes, or how long they can orbit Earth.
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The figure shows the angular velocity for a system as a function of time. Assume all the horizontal divisions are in seconds and all the vertical divisions are in rad/s. At t = 0 s the system is at a position of -1 rad.
What is the angular acceleration in rad/s2 at t = 4 s?
What is the change in angular position between 0 and 2 s in radians?
What is the final angular position, in degrees, after the entire 6 s interval?
If the system has a radius of 40 cm, how fast is a point on the outermost edge moving at t = 1 s in m/s?
If the system has a radius of 40 cm, what is the tangential acceleration on a point on the outermost edge at t = 0.5 s in m/s2?
The graph shows that the final angular position depends on the angular acceleration at time t = 4 s and the angular position between 0 and 2 s, which is represented by -1/4 rad/sec2 and -1/2 rad, respectively (0, 6).
In physics, angular acceleration refers to how quickly angular velocity changes over time. Since spin angular velocity and orbital angular velocity are two distinct types of angular velocity, respectively, there are also two distinct types of angular acceleration. Spin angular acceleration and orbital angular acceleration are the names for these.
The change in angle between 0 and 2 seconds is equivalent to -(1/4)*2 = -1/2 rad. Angle acceleration is equivalent to dv/dt = -1/4 rad/sec2 at 4 seconds.
The graph shows degrees as the ultimate angular position after the whole 6 s interval (0, 6).
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When a certain metal is illuminated by light, photoelectrons are observed provided that the wavelength of the light is less than 669 nm. Which one of the following values is closest to the work function of this metal? (h=6.626 x 10^-34 Js, c = 3.00 x10^8 m/s, 1 eV = 1.60 x10^-19)
A.) 1.9 eV
B.) 2.3 eV
C.) 2.0 eV
D.) 2.2 eV
The work function of this metal is 1.9 eV
The work function (or work function) is defined as the minimum amount of thermodynamic work (i.e. energy) required to remove an electron from a solid to a point in the vacuum immediately outside the solid surface.When light of suitable frequency falls on a metal surface, electrons are emitted. These photo (light) generated electrons are called photoelectrons.Due to the attraction of this positive image, the negative electron turns back to metal surface hence cannot leave the metal crystal permanently. But to overcome this attraction force an electron requires sufficient energy supplied from outside usually from external light sources. The minimum energy required just to escape an electron from a metal surface is known as work function.We know that Work function is defined by : W = hc/λ
Where, h = planck's constant = 6.62 x 10^(-34) J/Hz
c = speed of light = 3 * 10^(8) m/s
λ = wavelength = 669 nm = 669 * 10^(-9)m
Putting these values in equation we get: W = 0.030 * 10^(-17) J
To convert it in eV we divide this by 1ev = 1.60 x10^(-19)
Doing so we get W = 1.9 eV
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If you could drive a Jetson's flying car at a constant speed of 160km/hr (100 mi/hr) across oceans
and space, approximately how long would it take to drive to the nearest star, Alpha Centauri (4.4
light-years away)?
30 million years
30 trillion years
30 millenia years
30 billion years
Driving to the nearest star, Alpha Centauri, would take 26.4 million kilometers.
What is speed?Speed is the rate at which an object moves along a path in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar value. The rate at which an object's position changes in any direction. Speed is defined as the ratio of distance traveled to time spent traveling. The direction of movement of the body or object is defined by velocity. Speed is fundamentally a scalar quantity. Velocity is, in essence, a vector quantity. It is the rate at which distance changes. It is the displacement rate of change.
Here,
speed=distance/time
time=distance/speed
=4.4*9.46 trillion kilometers/160
=26.4 million kilometer
It would take 26.4 million kilometer to drive to the nearest star, Alpha Centauri.
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how can you calculate thë mechanical advantage a simple machine provides?
a. divide the output force by the output displacement
b. divide the output force by the input force
c. divide the output displacement by the input displacement
d. simple machines do not provide a mechanical advantage
The mechanical advantage a simple machine is obtained by dividing the output force by the input force.
option B.
What is mechanical advantage?
The mechanical advantage of a simple machine is the ratio of output force to input force. It is also the ratio of load overcame by a simple machine to the effort applied by the simple machine.
Mathematically, the formula for mechanical advantage of a simple machine is given as;
M.A = output force / input force
M.A = Load / effort
Thus, the mechanical advantage of a simple machine depends on the output force of the machine and the input force of the machine.
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A cart of mass m moving at 12 m/s to the right collides elastically with a cart of mass 4.0 kg that is originally at rest. After the collision, the cart of mass m moves to the left with a velocity of 6.0 m/s. Assuming an elastic collision in one dimension only, what is the velocity of the center of mass (V_cm) of the two carts before the collision? 2.0 m/s 3.0 m/s 6.0 m/s 9.0 m/s 18 m/s
The velocity of the center of mass (V_cm) of the two carts before the collision is between 3.0 m/s and 0.3 m/s.
What is collision?Collision is a term used to describe the physical impact between two or more objects. It is a phenomenon that occurs when two or more objects, such as cars, collide with each other, resulting in a transfer of energy from one to the other.
The velocity of the center of mass (V_cm) of the two carts before the collision can be calculated using the conservation of momentum equation:
V_cm = (m*V_1 + 4.0 kg*V_2) / (m + 4.0 kg)
Where V_1 is the initial velocity of the first cart (12 m/s) and V_2 is the initial velocity of the second cart (0 m/s).
Substituting values, we obtain:
V_cm = (m*12.0 m/s + 4.0 kg*0 m/s) / (m + 4.0 kg)
V_cm = 12.0 m/s / (m + 4.0 kg)
Since the mass of the first cart (m) is unknown, we cannot calculate the exact value of V_cm. However, we can calculate the maximum and minimum values of V_cm. For the minimum value, we assume m = 0, and for the maximum value, we assume m = ∞.
Minimum value: V_cm = 12.0 m/s / (0 + 4.0 kg) = 3.0 m/s
Maximum value: V_cm = 12.0 m/s / (∞ + 4.0 kg) = 0.3 m/s
Therefore, the velocity of the center of mass (V_cm) of the two carts before the collision is between 3.0 m/s and 0.3 m/s.
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Identify and draw the forces that act on the pencil. Be certain to draw each force at the correct location (the point at which the force acts on the pencil). The black dot represents the center of gravity of the pencil. Draw the vectors starting at the points where the forces act on the pencil.
A force is a push or pull upon an object resulting from the object's interaction with another object.
What is force?Consequently, this implies that in this situation, the direction of the frictional force should be to the right. Let me now just illustrate this scenario. Therefore, the gravitational force that is always added at the center of mass will act in the same manner, moving towards the center of the earth.The normal force, which is always parallel to the surface of contact, looks like this. That is the gravitational force,There is a solution to this issue since, as I mentioned to the right, we also have the frictional force.A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.To learn more about force refer to:
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Pls help need answers
The angular diameter of Mars in radians and in arc minutes and the evaluation of the capability of human eyes to resolve Mars of diameter 6.8 × 10³ km, located 5.5 × 10⁷ km away are as follows;
(d) The angular diameter of Mars is 1.23[tex]\overline{63}[/tex] × 10⁻⁴ rad
(e) The angular diameter in arc minutes is about 0.425 arc minute.
Optical aid is required for humans to resolve Mars.What is an angular diameter?The angular diameter is an apparent dimension used to describe the size of a circular object, observed from a specified point of view or location.
The diameter of Mars = 6,800 km
The closest distance between Mars and Earth when Mars gets closest to Earth = 55,000,000 km
(d) The angular diameter of Mars can be obtained by finding the vertex angle formed by the diameter of Mars and the ray from the observer on Earth to the left and right extremities of Mars using the trigonometric ratio of tangent as follows;
Angular diameter = 2 × arctan((6,800/2)/55,000,000) = 0.000123636363 radians
The angular diameter of Mars as observed from Earth is 1.23[tex]\overline{63}[/tex] × 10⁻⁴ radians
(e) 1 radians = 3437.75 arc minute
0.000123636363 radians = 0.000123636363 × 3437.75 arc minute
0.000123636363 × 3437.75 ≈ 0.425
Therefore;
0.000123636363 radians ≈ 0.425 arc minute
The specified level of detail that the human eye can resolve is one arc minute (1')
The apparent angular diameter of Mars, which is about 0.425 arc minute is lesser than the angular limit of detail of one arc minute that the eye can resolve, therefore, humans can not resolve Mars without optical aid.
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The researchers calculated a chi-square value of 29.25. If there are three degrees of freedom and the significance level is p=0.05, which of the following statements best completes the chi-square test?
The chi-square test indicates that the observed data is statistically significant, as the chi-square value of 29.25 is greater than the critical value of 7.815 at the 0.05 significance level and three degrees of freedom.
What is chi-square test?The chi-square test is a statistical test used to determine if there is a significant difference between observed frequencies and expected frequencies in one or more categories. It is commonly used in hypothesis testing to compare the observed data to expected data, and to measure how well a particular model fits the data. The chi-square statistic is calculated by subtracting the expected frequencies from the observed frequencies, squaring each of the differences, and then summing them. The result is then compared to a chi-square table to determine the probability that the observed data did not differ from the expected data.
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as the box is sliding down the ramp how are the magnitudes of the horizontal and the vertical components of the box's velocity changing
From free body diagram ma = mgsin - mgco.as the box is sliding down the ramp how are the magnitudes of the horizontal and the vertical components of the box's velocity changing.
what is magnitudes of the horizontal and the vertical components of the box's velocity changing?
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; its value is 9.8 m/s/s, down, The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.This is accomplished by taking the magnitude of the vector times the cosine of the vector's angle to find the horizontal component, and the magnitude of the vector times the sine of the vector's angle to find the vertical component.The magnitudes of the components of velocity v → v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal.To learn more about components refers to:
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A 100-g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track in Figure 7.39. Show that the final speed of the toy car is 0.687 m/s if its initial speed is 2.00 m/s and it coasts up the frictionless slope, gaining 0.180 m in altitude.
In order to solve this, we can use the conservation of mechanical energy. The total mechanical energy of an object is the sum of its kinetic energy (KE) and its potential energy (PE).
The initial mechanical energy of the toy car is the sum of its initial kinetic energy and its initial potential energy, which is zero since it starts at the same level as the track. The final mechanical energy of the toy car is the sum of its final kinetic energy and its final potential energy.
We know the initial speed of the toy car is 2.00 m/s, and it coasts up the frictionless slope, gaining 0.180 m in altitude. We can use these values to find the final mechanical energy of the toy car.
E_initial = KE_initial + PE_initial = (1/2)mv^2_initial + mgh_initial = 0
E_final = KE_final + PE_final = (1/2)mv^2_final + mgh_final
We know the mass of the toy car is 100g and we can convert it to kg by dividing it by 1000.
m = 100/1000 = 0.1 kg
We also know that the acceleration due to gravity is 9.8 m/s^2.
g = 9.8 m/s^2
Substituting these values into the equation for final mechanical energy, we get:
E_final = (1/2)mv^2_final + mgh_final = (1/2) * 0.1 * v^2_final + 0.1 * 9.8 * 0.180 = 0.05v^2_final + 0.018
Since the initial mechanical energy is zero, we can set the final mechanical energy equal to zero and solve for the final velocity of the toy car.
E_initial = E_final = 0
0.05v^2_final + 0.018 = 0
v^2_final = -0.018 / 0.05
v_final = sqrt(-0.018 / 0.05)
The final velocity/speed of the toy car is 0.687 m/s.
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The Weather Monitor. Your South American expedition splits into two groups: one that stays at home base, and yours that goes off to
set up a sensor that will monitor precipitation, temperature, and sunlight through the upcoming winter. The sensor must link up to a
central communications system at base camp that simultaneously uploads the data from numerous sensors to a satellite. In order to
set up and calibrate the sensor, you will have to communicate with base camp to give them specific location information.
Unfortunately, the group's communication and navigation equipment has dwindled to walkie-talkies and a compass due to a river-raft
mishap, which means your group must not exceed the range of the walkie-talkies (3.0 miles). However, you do have a laser rangefinder
to help you measure distances as you navigate with the compass. After a few hours of hiking, you find the perfect plateau on which to
mount the sensor. You have carefully mapped your path from base camp around lakes and other obstacles: 500 m West (W), 240 m S,
770 mW, 980 m NE, 860 m W, and 420 m 30.0° W of S. The final leg is due south, 2.00 km up a constant slope and ending at a plateau
that is h= 360 m above the level of base camp.
(a) How far are you from base camp? Will you be able to communicate with home base using the walkie-talkies?
(b) What is the geographical direction from base camp to the sensor (expressed in the form 8° south of west, etc.)?
(c) What is the angle of inclination from base camp to the detector?
(a) Number i
(b) Number
(c) Number
The total distance from base camp to the sensor is 4.23 km.
What is the angle of inclination from base camp to the detector?You are 3.8 km from base camp. The walkie-talkies have a range of 3.0 miles, which is 4.8 km, so you will be able to communicate with home base.The direction from base camp to the sensor is approximately 32° south of west.The angle of inclination from base camp to the detector is approximately 15.8°.This is well within the range of the walkie-talkies, so communication with base camp should not be a problem.The geographical direction from base camp to the sensor is 14.4° south of west.This can be calculated by adding up the angles of the course taken and then calculating the angle of the resultant vector.The angle of inclination from base camp to the detector is 43.2°.This can be calculated by taking the difference between the height of the plateau and the height of base camp, and then dividing that by the distance between them.This information is necessary for the group to be able to accurately calibrate the sensor at the correct location.To learn more about The angle of inclination refer to:
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four solid plastic cylinders all have radius 2.55 cm and length 6.24 cm. find the charge of each cylinder given the following additional information about each one
The charge with uniform density 15.9 nC/m^2 everywhere on its surface is 4.8nC, on its curved lateral surface only is 582.5nC, throughout the plastic is 1730.6nC, along the length of the plastic is 174.7nC.
Given the radius of cylinder (r) = 2.55cm = 2.55 x 10^-2m
The length of cylinder (h) = 6.24cm = 6.24 x 10^-2m
The total surface area of cylinder is calculated as: (A) = 2πr(r + h)
Then, A = 2 x 3.14 x 2.55 x 10^-2(2.55 x 10^-2 + 6.24 x 10^-2)
A = 188.8 x 10^-4m^2
The charge on cylinder = q
We know that the charge density is calculated as:
charge = charge density x total area of cylinder
(a) Given the charge density on cylinder a is = 15.9NC/m^2
The charge on cylinder = surface area x charge density
charge = 4πr^2 x 15.9 = 4 x 3.14 x (2.55 x 10^-2)^2 x 15.9 = 4.8nC
(b) the charge density on curved lateral surface only = 15.9nC/m^2
charge = 2πrhx15.9 = 2 x 3.14 x 2.55 x 10^-2 x 6.24 x 10^-2 x 15.9
= 582.5 nC
(c) the charge density throughout the plastic is = 475 nC/m^3
charge = πr^2h x 475 = 1730.6 nC
(d) along the length of the plastic is 64.2 nC/m
charge = πrh x 64.2 = 174.7 nC
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complete question: four solid plastic cylinders all have radius 2.55 cm and length 6.24 cm. find the charge of each cylinder given the following additional information about each one.
Cylinder (a) carries charge with uniform density 15.9 nC/m^2 everywhere on its surface.
Cylinder (b) carries charge with uniform density 15.9 nC/m^2 on its curved lateral surface only.
Cylinder (c) carries charge with uniform density 475 nC/m^3 throughout the plastic.
Cylinder (d) carries charge with uniform linear density 64.2 nC/m along the length of the plastic.
Which of the following wave characteristics remain unchanged when a wave crosses a boundary into a different medium?
A. frequency, B. amplitude, C. wavelength, D. velocity
E. direction
Wave characteristics that remain unchanged are A. Frequency and E. Direction.
Frequency and direction are the only Wave characteristics that don't change when a wave crosses a barrier into a new medium. No matter what medium a wave is travelling through, frequency refers to the rate of change of a wave per unit of time. The wave's direction dictates how it will interact with other materials and objects along its course, as well as how it will be oriented.
But when a wave enters another medium, its wavelength and speed do alter. The wave's length, which varies depending on the medium it is travelling through, is the space between its two successive crests or troughs. The wave's velocity, which also varies when it encounters a different medium, is its speed. This is so because the characteristics of the medium the wave is travelling through affect its speed.
The wave's amplitude, which is likewise altered when it passes a boundary into a new medium, is its largest departure from its resting point. This is so because the material the wave is going through has an effect on the energy of the wave, which determines the amplitude.
As a result, when a wave crosses a boundary and enters a new medium, its wavelength, velocity, and amplitude all vary based on the characteristics of the new medium but its frequency and direction stay the same.
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i give good amount of points
(a) The acceleration of the object when it travels 5 m is 2 m/s².
(b) The time taken for the object to travel the first 12 m is 3.46 seconds.
(c) The work done in displacing the object 12 m is 48 J.
(d) The speed of the object at a displacement of 12 m is 6.92 m/s.
(e) The speed of the object at a displacement of 12 m is zero.
What is the acceleration of the object?
The acceleration of the object is calculated as follows;
a = F / m
when the object travels 5 m, the force = 4 N
a = 4 N / 2 kg
a = 2 m/s²
The time taken for the object to travel the first 12 m is calculated as follows;
t = √ (2s / a )
where;
s is the distancet = √ (2 x 12 / 2 )
t = 3.46 seconds
The work done in displacing the object 12 m is calculated as follows;
W = Fd
W = 4 N x 12 m
W = 48 J
The speed of the object at a displacement of 12 m is calculated as;
v = at
v = 2 m/s² x 3.46 s
v = 6.92 m/s
At a displacement of 20 m, the acceleration of the object is zero, hence the velocity is zero.
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consider an application that transmits data at a steady rate (for example, the sender generates an n-bit unit of data every k time units, where k is small and fixed). also, when such an application starts, it will continue running for a relatively long period of time. answer the following questions, briefly justifying your answer:
Circuit-switched network is the more appropriate for this application that transmits data at a steady rate.
The application would perform best over a circuit-switched network since it requires lengthy sessions with steady, predictable bandwidth needs. Because the transmission rate is steady and known, it is possible to reserve bandwidth for each application session without wasting much of it. In addition, the overhead costs of setting up and tearing down connections are reduced over the lengthy duration of a typical application session.
It makes more sense to use a circuit-switched network rather than a packet-switched network, which is more practical when data shows in bursts, as the data are transmitted at a steady rate (x bits per second, for example), and they are also transmitted over a relatively long period of time rather than in short bursts.
The question is incomplete. The complete question is 'Would a packet-switched network or a circuit-switched network be more appropriate for this application? Why?'
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electric field and electric force .are synonyms referring to the same thing unselected are not the same because electric field refers to the effects of multiple electric forces unselected are unrelated to each other unselected are related quantities, but not the same thing
Electric field and electric force are related quantities, but not the same thing.
The strength of the electric field is defined as the electrostatic force experienced by a small test charge [tex]q_{0}[/tex] placed at that point divided by the charge itself. The electric field is a vector quantity, and its direction is the same as the direction of the force on a positive test charge.
The strength of the Electric field at a point can also be checked by the density of electric field lines present at that point.
The S.I unit of the Electric field is Newton per columb.
The S.I unit of force is Newton.
[tex]F = E \ q_{0}[/tex]
F= electrostatic force
E= electric field
[tex]q_{0}[/tex] = test charge
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figure 22-47 shows two paral- lel nonconducting rings with their central axes along a common line. ring 1 has uniform charge q1 and ra- dius r; ring 2 has uniform charge q2 and the same radius r. the rings are separated by distance d 3.00r.the net electric field at point p on the common line, at distance r from ring 1, is zero.what is the
The value of the force P at which the space between the polyethylene bar and the steel tube will be closed is 88,120 lbf.
What is Poisson's ratio?Poisson's ratio is a measure of the relationship between the longitudinal and transverse strains in a material. It is defined as the ratio of the change in the width per unit width (transverse or lateral strain) to the change in length per unit length (longitudinal or axial strain) caused by an applied load. The ratio typically ranges between 0 and 0.5 for most materials.
The value of the force P at which the space between the polyethylene bar and the steel tube will be closed can be calculated using the formula P = (π/4) * E * (d1^4 - d2^4)/(d1^4)
Given that E = 200 ksi and d1 = 4.0 in, d2 = 4.01 in
P = (π/4) * 200000 * (4.0^4 - 4.01^4)/(4.0^4)
P = 8.812 * 10^4 lbf
So the value of the force P at which the space between the polyethylene bar and the steel tube will be closed is 88,120 lbf.
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A 0.76 kg ball is dropped from a height of 22 m. It strikes the ground with an impact speed of 15.6 m/s. The acceleration of gravity is 9.8 m/s². How much mechanical energy is lost to non- conservative forces? Answer in units of J. Answer in units of J.
Answer:
71 J
Explanation:
You want the energy lost to non-conservative forces when a 0.76 kg ball is dropped from a height of 22 m and impacts the ground at 15.6 m/s.
Potential energyThe potential energy of the ball is ...
PE = mgh
PE = (0.76 kg)(9.8 m/s²)(22 m) = 163.856 J
Kinetic energyThe kinetic energy the ball has when it strikes the ground is ...
KE = 1/2mv²
KE = 1/2(0.76 kg)(15.6 m/s)² = 92.4768 J
Lost EnergyThe energy lost during the fall is ...
PE -KE = lost energy
163.856 -92.4768 = 71.3792 . . . joules
About 71 joules of mechanical energy is lost.