Answer:
21.86 grams
Explanation:
It is important to note that for every mol of Na3PO4 there is, 3 mols of Na ions are produced.
Na+=1m(0.4l), so mols of Na3PO4= 0.4/3= 0.13333... mols
the molar mass of Na3PO4 is 163.94 grams/mol. 0.1333*163.94=21.86 grams of Na3PO4.
Eating a healthy breakfast gives your body the energy needed to help you start your day.. The girl in the photo is having cereal and orange jucie, both of which habe stored _____ energy, a form of ____________ energy. The girls body breaks down the components of the food to access the energy __________ in them. Later in the day, some of this energy is _______ into _ energy that will alow the girl to study and play sports. Some of this energy is also _________ into ____ energy that keeps her body warm.
Answer:
Words are filled in
Eating a healthy breakfast gives your body the energy needed to help you start your day.. The girl in the photo is having cereal and orange jucie, both of which have stored chemical energy, a form of potential energy. The girls body breaks down the components of the food to access the energy in them. Later in the day, some of this energy is transformed into kinetic energy that will allow the girl to study and play sports. Some of this energy is also transformed into thermal energy that keeps her body warm.
Explanation:
HELPP PLEASE
this is a weird place to ask but does anyone know a good physical science experimental project that the scientific method can be used on? with homemade materials that doesn’t take more than 2 days to do?
Experiment: Does it Dissolve?
Materials Needed:
4 clear, glass jars filled with plain tap waterFlourSalt Talcum or baby powderGranulated sugarStirrerStep 1: Form a question before starting the experiment.
Step 2: Make a hypothesis for each substance.
Step 3: Scoop a teaspoon of each substance in the jars, only adding one substance per jar. Stir it up!
Step 4: Observe whether or not each substance dissolves and record the findings.
The heat of combustion of propane, C3H8 (g) is -2057 kJ/mol. What would be the enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas
Considering the reaction stoichiometry, the enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.
The balanced reaction is:
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l)
The heat of combustion of propane, C₃H₈, is -2057 kJ/mol. This is, 2057 kJ is released for every 1 mol C₃H₈.
So to determine the enthalpy change if enough propane was burned to emit 12 moles of carbon dioxide, you must take into account the stoichiometry of the reaction.
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₃H₈: 1 mole O₂: 5 moles CO₂: 3 moles H₂O: 4 molesThen you can apply the following rule of three: if by stoichiometry 3 moles of CO₂ are produced by 1 mole of C₃H₈, 12 moles of CO₂ are produced by how many moles of C₃H₈?
[tex]amount of moles of C_{3} H_{8} =\frac{12 moles of CO_{2}x1 mole of C_{3} H_{8} }{3 moles of CO_{2}}[/tex]
amount of moles of C₃H₈= 4 moles
So to determine the enthalpy change, you can apply the following rule of three: If for each mole of C₃H₈ 2057 kJ are released, for 4 moles of C₃H₈ how much heat is released?
[tex]Heat released=\frac{4 molesx2057 kJ}{1 mole}[/tex]
Heat released= 8228 kJ
The enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.
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https://brainly.com/question/10936616?referrer=searchResultsbrainly.com/question/16487206?referrer=searchResults brainly.com/question/14446695?referrer=searchResults brainly.com/question/11564309?referrer=searchResults brainly.com/question/4025026?referrer=searchResults brainly.com/question/18650135?referrer=searchResultsA moon orbits in a roughly circular path around a planet with a mass of 8.6 x 1023 kg. The distance from the center of the moon to the center of the planet is 7.04 x 106 meters. Calculate the speed of the moon in m/s.
Explanation:
A moon orbits in a roughly circular path around a planet with a mass of 8.6 x 1023 kg. The distance from the center of the moon to the center of the planet is 7.04 x 106 meters. Calculate the speed of the moon in m/s.
a) Explain the changes in the following properties when going across Period 3 from
sodium (Na) to argon (Ar).
i. The element's reactivity towards oxygen
ii. The electrical conductivity of the oxides
Answer:
The ironization energies increase as you go across the period So the electrical conductivity of the oxides is your answer
I need help solving the picture
Answer:
213 kJ-1704 kJ852 kJ (ignore what's on my paper, accidentally added a negative)Explanation:
These problems are pretty easy, you just need to do to the enthalpy what is done to the equation itself. Numbers one and 3 are reversed, so they become positive values. When a coefficient changes in the equation, you multiply the enthalpy by that number. I have attached my work below. Let me know if there is any confusion left.
Hope this helped! :^)
Predict the product of each monosaccharide oxidation reaction.
The complete oxidation of the monosaccharide shown will create a carboxylic acid.
Monosaccharides can be oxidized to carboxylic acids. Recall that monosaccharides have an aldehyde or ketone group at one end and a CH2OH group at the other end.
For the monosaccharide shown, oxidation may lead to the conversion of COH group to acid (-COOH). This confirms the presence of -COH yielding the product C4H8O5.
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can someone tell me how to find moles in acid&base equations (simple explination pls)
Answer:
When the base neutralizes the acid, the number of moles of H+ = the number of moles of OH-. Therefore, the number of moles of H+ = 0.0125 moles. Every mole of HCl will produce one mole of H+; therefore, the number of moles of HCl = number of moles of H+. The concentration of the HCl is 0.25 M
What is the wavelength of a photon that will be emitted when an electron in the hydrogen atom moves from n
Answer:
Use the Rydberg Equation 1/λ = R(1/n²(final) - 1/n²(initial) where R = 109,678 cm⁻¹. Substitute initial orbital number and final orbital number and solve for wavelength (λ).
Explanation:
Example:
Assume an electron transition from n = 5 to n = 2.
1/λ = 109,678cm⁻¹(1/2² - 1/5²) = 109,678(0.25 - 0.04)cm⁻¹ = 23,032cm⁻¹
λ = 1/23,032cm⁻¹ = 4.34 x 10⁻⁵cm x 10⁻²m/cm x 10⁹nm/m = 434nm
what other solvent could have been used?
What other solvent could have been used?
water (universal solvent)acetonemethanolacetic acidethyl acetateWhen comparing an electron's ground state with that of its excited state; which is the
higher entropy and which is the lower entropy? Provide a brief explanation as to why?
HINT: Remember the relationship of the electron to its nucleus!
When comparing an electron's ground state with that of its excited state;
The higher entropy is at its excited state.The lower entropy is at its ground state.Discussion:
Entropy is simply defined as the degree of randomness otherwise termed disorderliness in a system.
Electrons in their ground state are localized and have lower energy. As such, the entropy is lower.
On the contrary; Electrons in their excited state are delocalized and have higher energy. As such, the entropy is higher.
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Which statement best describes a covalent bond?
a
A chemical bond in which no electrons are shared.
b
A chemical bond that involves sharing a pair of electrons between
atoms in a molecule.
с
A chemical bond in which four or more electrons are shared.
A chemical bond in which one atom loses an electron to form a
d positive ion and the other atom gains an electron to form a negative
ion.
Answer:
B
Explanation:
Option B best describes covalent bonds.
One type of sunburn occurs when skin is exposed
to UV light of wavelength in the vicinity of 315 nm.
What is the energy of a photon of this wavelength?
Answer:
E = 6.27 × 10⁻²³ Joules
Explanation:
E = h (Plancks constant) × f (frequency)
(Plancks constant = 6.63 × 10⁻³⁴ J×s)
f = λ × c (used to find frequency so you can satisfy energy equation)
*Have to find wavelength in meters to multiply by speed of light*
1. f = (3.15 × 10⁻⁷ m) × (3 × 10⁸ m/s)
2. f = 9.45 × 10¹⁰ s
3. E = (6.63 × 10⁻³⁴ J×s [Plancks constant]) × (9.45 × 10¹⁰ s)
E = 6.27 × 10⁻²³ Joules
How are mass and weight alike?
A. Both change with gravitational force.
B. Both are measured in pounds.
C. Both depend on how much matter an object has.
D. Both are the same everywhere in the universe.
Answer:
C. Both depend on how much matter an object has.
Explanation:
weight is the gravitational force acting on an object, so it does vary depending on gravity.
Hope it help and if it its correct please give brainliest
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Calculate energy output (ATP production) of full oxidation of saturated fatty acid with 24 carbons in the chain?
..
Explain
Potassium metal reacts with water according to the following balanced equation.
2 K(s) + 2 H2O(l) — 2 KOH(aq) + H, (8)
If one mole of potassium reacts in this manner, how many moles of water are consumed?
Answer: 1 mole
Explanation:
One mole reacts because there is a 1:1 ratio between the potassium and water at the beginning of the equation. 2K+2H2O has a 1 to 1 ratio. If one potassium reacts there is one h2o that also reacts.
Taking into account the reaction stoichiometry, if one mole of potassium reacts, 1 mole of water are consumed.
Reaction stoichiometryIn first place, the balanced reaction is:
2 K + 2 H₂O → 2 KOH + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
K: 2 moles H₂O: 2 moles KOH: 2 moles H₂: 1 moleMoles of water consumedThe amount of water consumed is calculated from the following rule of three: if by stoichiometry 2 moles of K react with 2 moles of H₂O, 1 mole of K react with how many moles of H₂O?
[tex]amount of moles of H_{2} O=\frac{1 mole of Kx2 moles ofH_{2} O }{2 moles of K}[/tex]
amount of moles of H₂O= 1 mole
In summary, if one mole of potassium reacts, 1 mole of water are consumed.
Learn more about the reaction stoichiometry:
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How many atoms are in mercury phosphate
Answer:
There are 95 atoms in mercury phosphate
Explanation:
You just add the atomic number for both elements
Place the events of a fight or flight situation in the correct order.
Question 3 options:
You spring into action
Your heart and lungs prepare to fight or run
You see the bear
Your brain sends signals to you adrenal and pituitary glands
Answer:
you see le bear
you brain sends signals
your heart and lungs receive said signals
spring to action
Stems are important plant structures because they _________.
A.
are the main sites of photosynthesis for plants
B.
are the only site of water and nutrient transport
C.
allow plants to absorb water and nutrients from the soil
D.
give the plant structure and support
Answer:
c
Explanation:
allow plants to absorb water and nutrients from the soil
what is another extraction that uses gravity filtration and describe it
Answer -ˋˏ ༻༺ ˎˊ-
A common use for gravity filtration is for separating anhydrous magnesium sulfate (MgSO4) from an organic solution that it has dried (Figure 1.68b). Anhydrous magnesium sulfate is powdery, and with swirling in an organic solvent creates a fine dispersal of particles like a snow globe.
45.0 g of CaCl2 are dissolved in enough water so that the molarity of the solution is 1.15 M. What is the volume in mL of the solution?
Answer:
[tex]\boxed {\boxed {\sf 353 \ mL}}[/tex]
Explanation:
We are asked to find the volume in milliliters of a solution, given the mass of solute and molarity of the solution.
Molarity is a measure of concentration in moles per liter.
[tex]molarity = \frac {moles \ of \ solute}{liters \ of \ solution}[/tex]
1. Moles of SoluteWe are given the mass of the solute. We must convert the mass to moles using the molar mass (the mass of 1 mole of a substance). These values are found on the Periodic Table. They are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.
Look up the molar masses of the individual elements in calcium chloride.
Ca: 40.08 g/mol Cl: 35.45 g/molThe chemical formula, CaCl₂, has a subscript of 2. There are 2 moles of chlorine in 1 mole of calcium chloride. We must multiply chlorine's molar mass by 2 before adding calcium's molar mass.
Cl₂ = 35.45 *2 = 70.9 g/mol CaCl₂= 40.08 + 70.9 = 110.98 g/molSet up a conversion factor using the molar mass.
[tex]\frac {110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2}[/tex]
Multiply by 45.0 grams of calcium chloride.
[tex]45.0 \ g \ CaCl_2 *\frac {110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2}[/tex]
Flip the conversion factor so the units of grams of calcium chloride cancel.
[tex]45.0 \ g \ CaCl_2 *\frac{1 \ mol \ CaCl_2} {110.98 \ g \ CaCl_2}[/tex]
[tex]45.0 \ *\frac{1 \ mol \ CaCl_2} {110.98}[/tex]
[tex]\frac {45.0}{110.98} \ mol \ CaCl_2= 0.405478465 \ mol \ CaCl_2[/tex]
2. Liters of SolutionNow we can find the liters of solution.
[tex]molarity = \frac {moles \ of \ solute}{liters \ of \ solution}[/tex]
molarity = 1.15 mol CaCl₂/L moles of solute = 0.405478465 mol CaCl₂liters of solution =xSubstitute the values into the formula.
[tex]1.15 \ mol \ CaCl_2/L = \frac{0.405478465 \ mol \ CaCl_2}{x}[/tex]
Cross multiply.
[tex]\frac {1.15 \ mol \ CaCl_2 /L}{1}= \frac{0.405478465 \ mol \ CaCl_2}{x}[/tex]
[tex]{1.15 \ mol \ CaCl_2 /L}*x= {0.405478465 \ mol \ CaCl_2} * 1[/tex]
Divide both sides of the equation by 1.15 moles of calcium chloride to isolate the variable x.
[tex]\frac {1.15 \ mol \ CaCl_2/L *x}{1.15 \ mol \ CaCl_2 /L}= \frac{0.405478465 \ mol \ CaCl_2 * 1 }{1.15 \ mol \ CaCl_2/L }[/tex]
[tex]x=\frac{0.405478465 \ mol \ CaCl_2 * 1 }{1.15 \ mol \ CaCl_2 /L}[/tex]
The units of moles of calcium chloride cancel.
[tex]x=\frac{0.405478465 }{1.15 \ L }[/tex]
[tex]x=0.35258997 \ L[/tex]
3. Convert to millilitersThere are 1000 milliliters in 1 liter.
[tex]\frac {1000 \ mL}{1 \ L}[/tex]
[tex]0.35258997 \ L * \frac{1000 \ mL}{ 1 \ L}[/tex]
[tex]0.35258997 * 1000 \ mL=352.58997 \ mL[/tex]
The original measurements of mass and molarity have 3 significant figures, so our answer must have the same. For the number we found, that is the ones place. The 5 in the tenth place tells us to round the 2 up to a 3.
[tex]353 \ mL[/tex]
The volume of the solution is approximately 353 milliliters.
List key terms associated with the carbon cycle
The main parts of the carbon cycle are photosynthesis, respiration, diffusion, absorption, fossil fuel burning, and land use.
Describe the experiment that Chadwick conducted which led to his discovery of the neutron.
Answer:
James Chadwick conducted an experiment where he assailed the element Beryllium with alpha particles that came from the radioactive decay of Polunium. The experiment results showed highly penetrating radiation emitted from the Beryllium. In this, Chadwick proposed that radiation consisted of uncharged particles, which were later founded as neutrons.
Which of the following statements is true?
Select one:
a. All the answers are right
b. Aerobic and anaerobic bacteria don’t decompose organic matter
c. Aerobic bacteria produce bad smelling compounds
d. Anaerobic bacteria produce oxygen as one of their decomposition products
e. Anaerobic bacteria function in the absence of oxygen
What equipment is generally used to make lyophilized medications suitable for administering to the patient? a) Test tubes or sterile ampules b) Petri dishes and sterile droppers c) Sterile syringes or graduated cylinders d) Measuring cups and clean, warm water
Answer:
The answer is B
B = Petri dishes and sterile droppers
Explanation:
I. Indicate whether the following statements are true or false 1. The entropy of a fixed amount of an incompressible substance increases in every process for which temperature increase. A: True B: False 2. A closed system can experience a decrease in entropy only when there is heat transfer from the system to its surroundings during the process. A: True B: False 3. Entropy is produced in every internally reversible process of a closed system. A: True B: False 4. In an adiabatic and internally reversible process of a closed system the entropy remains constant A: True B: False 5. The entropy of a fixed amount of an ideal gas increases in every isothermal process A: True B: False 6. The energy of an isolated system must remain constant, but the entropy can only decrease A: True B: False 7. The entropy change of a closed system during a process can be greater than, equal to, or less than zero. A: True B: False
A gas has a volume of 1140 ml at 37 ºC and 620 mm Hg pressure. Calculate its volume at STP.
1.900
2.800
3.819
4.1000
Answer:
3. 0.819L (819 mL)
Explanation: Before we go about solving this, we need to do some conversions prior to using the gas law, the gas law is as follows...
P(atm)*V(L)=n(mol)*r(constant)*T(in kelvin)
So here are all the conversions you need.
620 mm Hg -> 0.816 atm
1140 mL -> 1.14 L
37 C -> 310.15 K
After plugging in our new converted values, we will proceed to solve the number of moles of the gas present, our n value, so our equation will look like this...(Note: Constant r in this case is 0.08206 L*atm/K*mol)
(0.816 atm)(1.14 L) = n(0.08206)(310.15)
Solving for n we get 0.03653 moles.
Now our second part is to figure out the volume AT STP (standard temperature/pressure). In the STP conditions, your temperature defaults to 0 C (273.15 K) and 1 atm. Now there is an easier way to do this, but I'll also show the more comprehensive way. Here is the easier method...
Since 1 mole of every gas occupies 22.4 L at STP, we can simply multiply this by our number of moles. So (22.4L)(0.3653 mol) to give us 0.818272.
However, a more accurate answer can be given like this...
Plugging n back into the same equation and this time resetting pressure to 1 atm and temperature to 273.15 K and conserving our number of moles we get...
(1 atm)(v) = (0.03653 mol)(0.08206)(273.15 K)
v = (0.03653)(0.08206)(273.15)
v = 0.8188 L = 0.819 L or 819 mL
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How many moles of NO₂ would be required to produce 2.30 moles of HNO₃ in the presence of excess water in the following chemical reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)
Answer:
Stoichiometric Calculation:
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)
2 moles of HNO₃ is produced from 3 moles of NO₂.
Therefore, By unitary method:
2.30 moles of HNO₃ produced from the moles of NO₂ = [tex] \dfrac{3}{2} \times 2.30 = \bf{3.45 mol}[/tex]
The number of moles of NO₂ that would be required to produce 2.30 moles of HNO₃ in the presence of excess water in the chemical reaction is 3.45 moles
The balance equation is as follows:
3NO₂(g) + H₂O (l) → 2HNO₃(g) + NO(g)
Water molecules is in excess. Therefore, the limiting reagent is Dinitrogen oxide.
The limiting reagent will determine the amount of product produced.
Therefore,
2 moles of HNO₃ needs 3 moles of NO₂
2.30 moles of HNO₃ will need ? moles of NO₂
cross multiply
number of moles of NO₂ = 2.30 × 3 / 2
number of moles of NO₂ = 6.9 / 2
number of moles of NO₂ = 3.45 moles
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Each of the following sets of quantum numbers is supposed
to specify an orbital. Which of the following sets of quantum
numbers contains an error?
A) n = 2, l = 1 , ml = -1
B) n = 4, l = 2, ml =0
C) n = 3, l =3 , ml = -2
D) n = 1, l = 0, ml =0
E) n = 3, l = 0, ml =0
Answer:
C
Explanation:
The azimuthal quantum number can take values from 0 to (n-1)
So in answer C n= 3, l can take values between 0
and 2.
l can't be 3.
ml can take values from -l to +l.
Hope you understood