A projectile is launched from ground level with an initial velocity of feet per second. Neglecting air​ resistance, its height in feet t seconds after launch is given by . Find the​ time(s) that the projectile will​ (a) reach a height of 192 ft and​ (b) return to the ground when 112 feet per second.

Using the quadratic equation the distance of point B from the ground level is D. 3 units

An equation is a mathematical function that shows the relationship between two variables.

Since an archway is modeled by the equation y = -2x² + 8x.

A rod is to be placed across the archway at an angle defined by the equation x − 2.23y + 10.34 = 0.

If the rod is attached to the archway at points A and B, such that point B is at a higher level than point A, we desire to find the distance of point be from the ground. To do this , we proceed as follows.

Since we have the equations

Substituting y into the second equation, we have

x - 2.23y + 10.34 = 0

x - 2.23(-2x² + 8x) + 10.34 = 0

x + 4.46x² - 17.84x + 10.34 = 0

4.46x² - 16.84x + 10.34 = 0

To find the points a and B, we solve for x where both equations intersect.

So, using the quadratic formula, we solve for x

[tex]x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}[/tex] where a = 4.46, b = -16.84 and c = 10.34

So, substituting the values of the variablers into the equation, we have that

[tex]x = \frac{-(-16.84) +/-\sqrt{(-16.84)^{2} - 4\times4.46\times10.34} }{2\times4.46}\\= \frac{16.84 +/-\sqrt{283.5856 - 184.4656} }{8.92}\\= \frac{16.84 +/-\sqrt{99.12} }{8.92}\\= \frac{16.84 +/-9.96 }{8.92}\\x = \frac{16.84 + 9.96 }{8.92} or x = \frac{16.84 - 9.96 }{8.92}\\x = \frac{26.8}{8.92} or x = \frac{6.88}{8.92}\\x = 3.004 or x = 0.771[/tex]

Since B is higher, we take the higher value x = 3.

So, the distance of point B from the ground level is D. 3 units

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Using the quadratic equation the distance of point B from the ground level is D. 3 units

An equation is a mathematical function that shows the relationship between two variables.

Since an archway is modeled by the equation y = -2x² + 8x.

A rod is to be placed across the archway at an angle defined by the equation x − 2.23y + 10.34 = 0.

If the rod is attached to the archway at points A and B, such that point B is at a higher level than point A, we desire to find the distance of point be from the ground. To do this , we proceed as follows.

Since we have the equations

Substituting y into the second equation, we have

x - 2.23y + 10.34 = 0

x - 2.23(-2x² + 8x) + 10.34 = 0

x + 4.46x² - 17.84x + 10.34 = 0

4.46x² - 16.84x + 10.34 = 0

To find the points a and B, we solve for x where both equations intersect.

So, using the quadratic formula, we solve for x

[tex]x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}[/tex] where a = 4.46, b = -16.84 and c = 10.34

So, substituting the values of the variablers into the equation, we have that

[tex]x = \frac{-(-16.84) +/-\sqrt{(-16.84)^{2} - 4\times4.46\times10.34} }{2\times4.46}\\= \frac{16.84 +/-\sqrt{283.5856 - 184.4656} }{8.92}\\= \frac{16.84 +/-\sqrt{99.12} }{8.92}\\= \frac{16.84 +/-9.96 }{8.92}\\x = \frac{16.84 + 9.96 }{8.92} or x = \frac{16.84 - 9.96 }{8.92}\\x = \frac{26.8}{8.92} or x = \frac{6.88}{8.92}\\x = 3.004 or x = 0.771[/tex]

Since B is higher, we take the higher value x = 3.

So, the distance of point B from the ground level is D. 3 units

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Answer:

y = 1/3x +2

Step-by-step explanation:

when x =o, y=2

when x= -6, y=0

so slope is always the difference between the Ys divided by diff b/w the Xs

so the slope is (2-0)/(0-(-6)) =  1/3

the intercept by definition is when x=0, so it's 2

so Y = 1/3 X +2

Sarah's profit, given the shirts sold, the cost of the shirts, and the shirts returned, can be found to be $ 126

First, find Sarah's cost :

= Cost to buy the shirts + cost to return the shirts

= ( 37 x 9 ) + ( 7 x 3)

= 333 + 21

= $ 354

The revenue made from selling the shirts was :

= 30 x 16 per shirts

= $ 480

Sarah's profit is therefore:

= 480 - 354

= $ 126

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The sum of the angles formed on the same side of the transversal which are inside the two parallel lines is always equal to 180°

What exactly is the degree formula?

Yes, we can use the radian-to-degree formula to convert a negative radian to a degree. Degrees = Radians 180 / is the formula, and it may be used for both positive and negative values. Parallel lines are lines that are always the same distance apart in a plane. Parallel lines never cross. Perpendicular lines are those that connect at a straight angle (90 degrees).

These are referred to as parallels. A circle of latitude is an imaginary ring that connects all places that share a parallel. The Equator is the 0 degree latitude line. Each parallel is one degree north or south of the Equator, with 90 degrees north and 90 degrees south respectively.

Hence, The sum of the angles formed on the same side of the transversal which are inside the two parallel lines is always equal to 180°

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Answer:

honestly, I got no idea. I can tell you though - go us Desmos kid. it'll help you more than any person in this platform.

don't thank me

Step-by-step explanation:

Desmos

use Desmos

The equation when making x the subject is X = -2 - 6y

To do this, we would have to take the values that are in the left hand side to the right hand side. When we do this, the signs on the left hand side would have to change

X+6y=-2

we have to take +6y to the right hand side.

When the positive sign crosses the equal sign it becomes negative

X = -2 - 6y

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X+6y=-2 show ur work make x the subject

The equation of the line passing through the point (8, 4) and having a slope of 0 is y = 4.

What is the slope intercept?

The slope-intercept form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).

The line passing through the point (8, 4) and having a slope of 0 is a horizontal line which is parallel to the x-axis. The slope (m) of this line is 0.

The point-slope form of this line would be:

(y - 4) = 0(x - 8)

Simplifying this, we get:

y = 4

Hence, the equation of the line passing through the point (8, 4) and having a slope of 0 is y = 4.

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Answer:

1.44

Step-by-step explanation:

11.52/8=1.44

Answer:

As a whole, the piece first measured 38 inches. No matter how many times you cut it, all of the pieces will still add up to 38 inches. You know that 19 inches is the length of one of the two pieces, so all you need to find is the other unknown piece. Add the two together, with m being the unknown length.

19+m=38

If you want to solve the equation, just subtract 19 from both sides.

19+m=38

m=19

If the sun is 69° above the horizon, the length of the shadow cast by a building 91 ft tall

You should understand that the length of the shadow is the distance between a point to the foot of the tenth

This makes an angle of depression, with 69 degrees

Remember that the angle on top of the tenth is 90-69 = 21 degrees

therefore, using the trigonometrical ratio

We have Tan∅ = opposite of adjacent

Tan 21⁰ = x/9

x= 9*tan 21⁰

x = 9*0.3839

The distance is 3.45

Therefore the length of the shadow cast by a building is approximately 3.5 feet long

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The volume of the solid is equal to 96 cubic units.

V= Integral (from x=2 to x=-4) of (8-x^2-2x)^2 dx = ∫(8-x^2-2x)^2 dx

= 1/3*∫(24-6x^2-12x)dx

= 1/3*[24x-2x^3-6x^2] from x=2 to x=-4

= 1/3*[(-6)-(-140)-(-136)]

= 1/3*(288)

= 96 cubic units

Set up an integral to compute the volume of the solid.

V= Integral (from x=2 to x=-4) of (8-x^2-2x)^2 dx

Rewrite the integral with a function of x in terms of a single power of x.

V= Integral (from x=2 to x=-4) of (8-x^2-2x)^2 dx = ∫(8-x^2-2x)^2 dx

= 1/3*∫(24-6x^2-12x)dx

Integrate the function.

= 1/3*[24x-2x^3-6x^2] from x=2 to x=-4

Evaluate the integral to find the volume of the solid.

= 1/3*[(-6)-(-140)-(-136)]

= 1/3*(288)

= 96 cubic units

The volume of the solid is equal to 96 cubic units.

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Answer:

Step-by-step explanation:

[tex]\sf 8-3(4-4)+2*4*6[/tex]

[tex]\sf 8-(3)(0)+(2)(4)(6)[/tex]

[tex]\sf 8-0+(2)(4)(6)[/tex]

[tex]\sf 8+(2)(4)(6)[/tex]

[tex]\sf 8+(8)(6)[/tex]

[tex]\sf 8+48[/tex]

[tex]\sf 56[/tex]

Equivalent equations are algebraic equations that are having identical roots or solutions

Equations in algebra with the same roots or solutions are said to be equivalent. An analogous equation is one that is created by adding or removing the identical number, symbol, or expression from both sides of an equation. We can also get an equivalent equation by multiplying or dividing both sides of an equation by the same nonzero value.

Expressions that are equivalent do the same thing even when they have distinct appearances. When we enter the same value(s) for the variable, two algebraic expressions that are equivalent have the same value (s).

To determine which complex expression is the simple expression's equivalence:

Give any coefficients a distribution:

a(bx±c)=abx±ac

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The Numerical Expressions answers are shown below:

Integers come in three types:

Given:

1. 7-6+ 5

= 7 -1

= 6

So, the value of 7-6+ 5 is 6.

2. 31 +19 -8

= 31 + 11

= 42

So, the value of 31 +19 -8 is 42.

3. 64-8+21

= 56 + 21

= 77

So, the value of 64-8+21 is 77.

4. 17+34-2

= 51-2

= 49

So, the value of 17+34-2 is 49.

5. 28+ 89 -67

= 117-67

= 50

So, the value of 28+ 89 -67 is 50.

6. (8+1) x 12- 13

= 9 x 12 -13

= 108 - 13

= 95

So, the value of (8+1) x 12- 13 is 95.

7. 63/9 +8

= 7 +8

= 18

So, the value of 63/9 +8  is 18.

8. 5 x 6 -(9-4)

= 5x 6 - 5

= 30- 5

= 25

So, the value of 5 x 6 -(9-4)  is 25.

9. 13x 4 -72 /8

= 13 x 4 - 9

= 52- 9

= 43

So, the value of 13x 4 -72 /8  is 43.

10. 16/2 + 8 x 3

= 8 + 8 x 3

= 8+24

= 32

So, the value of 16/2 + 8 x 3  is 32.

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The additional fact that would prove that

EFGH is a square is D) IFLEH ~ LFGH.

A quadrilateral is a plane figure with four edges and four corners, also known as vertices. The quadrilateral's four vertices or corners all have angles.

If a quadrilateral is a rhombus, that means opposite sides are congruent, but it does not mean that all angles are congruent. In order to prove that EFGH is a square, we need to show that all angles are congruent. The statement "IFLEH ~ LFGH" implies that all angles in the quadrilateral are congruent, since it states that opposite angles are congruent, which is one of the defining characteristics of a square. Therefore, statement D is the correct answer.

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Diya could earn 72 marks out of 80 after getting the extra credits.

Teachers employ extra credit for a variety of reasons. For example, it may be felt that students who are highly capable may benefit from an additional challenge that might not be suitable as required work for all students. Extra credit may also be used as a way to allow a student to improve their grade after a weak performance earlier in a course. In both of these cases, extra credit can promote differentiated instruction by factoring in optional work in the assessment of student performance.

Given here: Diya scores 36 out of 80 on a test.

Also, her teacher gives her extra credit with which she could double her marks.

If Diya doubles her marks then her total marks would be 72

Therefore the increase in her marks is 72-36=36

She could earn another 36 credits.

Thus her score after the extra credit is equal to 72

Hence, Diya could earn 72 marks out of 80 after getting the extra credits.

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After 180 miles both the cars' tanks contain same amount of gas.

Graph is a mathematical representation of a network and it describes the relationship between lines and points. A graph consists of some points and lines between them. The length of the lines and position of the points do not matter.

Given that, Ann and Leila are driving separate cars to New York. They begin the trip with full gas tanks.

From the given  graph,

After 360 miles Ann's car has 2 gallons of gas.

After 180 miles both the cars' tanks contain same amount of gas.

When they travelled less than 180 miles, Leila's car has more gas.

Therefore, after 180 miles both the cars' tanks contain same amount of gas.

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Answer:

7/12 of salt.

1/4 + 1/3 =

1/3 + 1/4 =

4/12 + 3/12 = 7/12.

Step-by-step explanation:

Hope it helps! =D

Answer:

Step-by-step explanation:

36

(

x

+

3

)

2

(

x

−

3

)

2

The rate at which the water flow from the given volume is 21.72 in³/sec

To find the rate at which water is being drained from the container, we first need to find the rate at which the water level is falling and then use that to calculate the volume of water being drained per unit of time.

We know that the surface level is falling at a rate of 0.9 inches per second and that the container has the shape of an inverted right circular cone. The volume of a cone is given by the formula:

V = (1/3) * π * r^2 * h

Where V is the volume, π is pi (approximately 3.14), r is the radius of the base, and h is the height of the cone.

We can use this formula to find the volume of the container when the water level is 8 inches. The radius at this point is 6 * (8/10) = 4.8 inches and the height is 8 inches.

V = (1/3) * π * (4.8 inches)^2 * 8 inches = 193.02 inches³

Now that we know the volume of the container when the water level is 8 inches, we can use the rate at which the water level is falling (0.9 inches per second) to find the rate at which the water is being drained.

The rate at which water is being drained = rate of change of volume / rate of change of height = dV/dt = dV/dh * dh/dt = -dV/dh * dH/dt

Where dV/dh is the derivative of volume with respect to height, dH/dt is the rate of change of height.

-dV/dh = -(1/3) * π * (4.8 inches)^2 = -24.13 in³

dH/dt = -0.9 inches/sec

The rate at which water is being drained = -dV/dh * dH/dt = -24.13 * -0.9 inches/sec = 21.72 in³/sec

So the rate at which water is being drained from the container is 21.72 in³/sec

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In a plane, intersecting lines are any two or more lines that cross each other. The point of intersection is the common point shared by all intersecting lines.

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The movie theater will have 50 shows in 6 days

To find the total number of shows in 6 days, we need to calculate the number of shows for each type of day (4 days per week with 7 shows per day and 2 days per week with 11 shows per day) and then add them together.

First, let's calculate the number of shows for the 4 days per week with 7 shows per day:

4 days per week x 7 shows per day = 28 shows per week

Next, let's calculate the number of shows for the 2 days per week with 11 shows per day:

2 days per week x 11 shows per day = 22 shows per week

Now, we can add the number of shows for each type of day together to find the total number of shows in 6 days:

28 shows per week + 22 shows per week = 50 shows in 6 days

We used multiplication to calculate the number of shows per week for each type of day (by multiplying the number of days by the number of shows per day) and then added the two results together to find the total number of shows in 6 days.

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Answer: To find the price of the 3-year old car, we need to determine how much less it is than the new car, which is 23% of the price of the new car.

We can start by finding the value of 23% of the price of the new car, which is: $12,400 x 0.23 = $2,832

Now we know that the price of the 3-year old car is $2,832 less than the price of the new car. To find the price of the 3-year old car, we subtract $2,832 from the price of the new car: $12,400 - $2,832 = $9,568

So the price of the 3-year old car is $9,568.

Step-by-step explanation:

Answer:

You are correct

Step-by-step explanation:

You are correct sir. They want the answer in feet, so everything on that triangle has to be converted into feet.

There are 12 inches in a foot. If we do 108/12 we get 9 feet.

728 kilograms of sugar is used in this month.

percentage, a relative value indicating hundredth parts of any quantity.

Given that a bakery used 30% more sugar this month than last month.

Let us convert 30% to decimal.

Divide 30 by 100

30/100=0.3

the bakery used 560 kilograms of sugar last month we have to find the amount of sugar used this month.

Now multiply 30% of 560

0.3×560

168.

So now 560+168=728 is the amount of sugar used this month.

Hence, 728 kilograms of sugar is used in this month.

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Answer:

59.036

Step-by-step explanation:

tanΘ = opposite/adjacent

Θ =tan⁻¹(opposite/adjacent)

tan⁻¹(10/6) - 59.03624347

Since the longest side cannot be longer than the total of the other two sides, the third side's potential lengths range from 8 to 44.

A triangle's third side must be longer than the difference between the other two sides' lengths and shorter than the total length of the other two sides. The two side lengths in this situation are 18 and 26. The third side must be greater than 8 because the difference between them is 8. The third side must be less than 44 because the total length of the first two sides equals 44. Therefore, the third side length might be any side length between 8 and 44.Since the longest side cannot be longer than the total of the other two sides, the third side's potential lengths range from 8 to 44.

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The complete question is

a triangle has one side length of 26 and another side length of 18. select all of the possible lengths of the third side potential lengths range from 8 to 44?