a pharmacy technician measures the mass of a pill. the mass of one pill is . what is the mass in kilograms of pills? write your answer as a decimal.

Answers

Answer 1

The mass of one pill measured was 461 mg and for the same pill, the mass in kilograms of 100 pills will result to 46l*100/100000 => 0.046l kg.  As there are 1 ms = 10^-5 kg.

What is a pharmacy technician? A pharmacy technician is a person in pharma who decides the composition of the chemicals in medicine and the size of medicine from manufacturing.

The mass of one pill is given as 461 mg and the number of pills required is 100So the total mass will be, mass of 1 pill*100 = 461 mg × 100 = 46100mg

one kilogram = 1000 grams, so the mass in kilograms will be, The same mass in kg will be 46100mg / 1000 grams

which results in 0.046l kg.

This simply shows, the mass of 1 pill was 461 mg the mass in kilograms of 100 pills will be 0.046l kg for measurements of the mass in kg of a pill.

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Related Questions

how many watts of power are generated by an object with mass 6 kg that accelerates from rest to 9 m/s in 9 seconds?

Answers

The power generated by the object with a mass 6 kg and accelerate from rest to 9 m/s in 9 seconds is 27 watts.

How do you calculate power in watts?

Power is energy transformed by the device per unit time.

The symbol for power is P and the unit of power is watt.

The formula used to calculate the power is as follows:

Power = [tex]\frac{E}{t}[/tex], which E is kinetic energy and t is time

To calculate the kinetic energy (E), can use the following formula :

[tex]E = \frac{1}{2} mv^{2}[/tex] or [tex]E = \frac{1}{2} m(v2^{2} - v1^{2})[/tex]

By combining both formulas above, here is the new formula that can be applied :

Power = [tex]\frac{\frac{1}{2} m(v2^{2} - v1^{2})}{t}[/tex] = [tex]\frac{\frac{1}{2} 6(9^{2} - 0^{2})}{9}[/tex] = [tex]\frac{\frac{1}{2}x6x81}{9}[/tex] = 27 watts

Thus, as the object has a mass 6 kg and accelerate from rest to 9 m/s in 9 seconds will generate power 27 watts.

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two small conducting point charges, separated by 0.5 m, carry a total charge of 180 c. they repel one another with a force of 120 n. for the universal constant k use the value 8.99 109 n m2/c2. find the charge on the larger of the two point charges:

Answers

The charge on the larger of the two-point charges is 90 coulombs

To determine the charge on the larger point charge, we can use Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the known values of the force (120 N), distance (0.5 m), and the universal constant (8.99 x 10^9 Nm^2/C^2), we can use the equation F = k(q1q2)/r^2 to solve for one of the charges.

By rearranging the equation and substituting the known values, we get q1 = (Fr^2)/k. Then by substituting the given values, we get q1 = (120 N * (0.5 m)^2) / (8.99 x 10^9 Nm^2/C^2) = 90 coulombs.

Since we know the total charge is 180 coulombs and q1 is 90 coulombs, then the charge on the second point charge would also be 90 coulombs.

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Suppose you were to make a three-dimensional model of magnetic force using magnetic field lines and a magnet. Which two characteristics might your model have?
A. The field lines exist only at the top and the bottom of the magnet.
B. The field lines near the magnet are far apart.
C. Arrows on the field lines point from the magnets North Pole to its South Pole.
D. The field lines do not cross paths as they go from one pole of the magnet to the other.

Answers

Answer:

C

Explanation:

it shows how forces are converted from a certain pole to the other

what is the magnitude of the electric force on one of the masses? express your answer with the appropriate units.

Answers

Two 1.6 kg masses are 1.3 m apart (center to center) on a frictionless table. Each has + 9.6 µC of charge.

What is the magnitude of the electric force on one of the masses? Express your answer to two significant figures and include the appropriate units.

ANSWER:

F -0.49N

About electric force

The electric force is the force experienced by a charged object that is in an electric field. The formulation of the electric force is sometimes confused with Coulomb's law, even though the electric force is more general in nature than this law, which only applies to two point charges./ the force possessed by electrically charged objects

Electric force formula

Electric force, as is generally the case, is denoted by the letter F or usually given a small index under E  (electric) or L (electricity).

F=qE

with:

q: is the payload of the object

E : is the electric field

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cold tcs food should be stored at an internal temperature of

Answers

Cold TCS food should be stored at an internal temperature of

41° F or below.

What is TCS food?

TCS full form is Time/Temperature Control for Safety. Foods that typically spoil more quickly than other foods are referred to as TCS. These foods may either have a high initial microorganism load naturally or possess qualities that are ideal for the growth of pathogens.

The TCS food definition makes it clear that any time and temperature control has a significant impact on the foods that fall under this category. Food handlers may find it extremely beneficial to know how TCS foods behave in order to better formulate, prepare, and serve their food products to consumers. In order to avoid causing foodborne illnesses and food waste, this task is a crucial duty of both food managers and food handlers.

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a mass is attached to a vertical spring and set into vibration. the highest point of the motion is point a and the lowest point of the motion is point b. at what position or positions in its motion is the object's potential energy at a maximum? (consider the potential energy of the mass-earth-spring system.)

Answers

Peak A, which is the motion's highest point, and point B, which is its lowest point, are where the object's potential energy is greatest.

Point A, the greatest point of the motion, has the largest potential energy for the item. The mass is now at its maximal potential energy and the spring is fully expanded. The potential energy drops as the mass descends toward point B because the spring contracts and the mass loses potential energy. The potential energy is at its lowest when the mass reaches point B since the spring is entirely compressed and the mass is at its lowest point. The mass subsequently goes back up to point A, and the process is repeated, increasing the potential energy.

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for the tower below, the resultant of the tension in the two cables acts downward. what is the magnitude of this resultant (in units of kn)? the tension force in cable ac is 8 kn.

Answers

The effect of the stress between the two cables acts downward on the tower below. the consequent 11.96 kN's magnitude. 8 kN is the tension force in cable ac.

Tac = 8kN [40/sqrt(402+602) I - 60/sqrt(402+602)]

Tac is equal to 4.438 i-6.656 j kN.

If the tension force in AB is T, then Tab = T is equal to T [- 50 / sqrt(502 + 602) I - 60 / sqrt(502 + 602)].

The resulting Tnet = Tac + Tab = Tab = - 0.64 T I - 0.768 T j k N (4.438 - 0.64T) Since the consequent of I - (6.656 + 0.768 T) j is along j, the component along I will be zero.

magnitude of resultant = 6.656 + 0.768 T = 6.656 + 0.768(6.91) = 11.96 kN 4.438 - 0.64 T = 0 T = 6.91 kN

Simply said, "distance or amount" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an item.

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a certain voltage source provides a constant 6v. the circuit connected to the source draws an exponentially decaying current from the source given by ma, for , where 749ma and 67ms. assuming that for , at what point in time has the source provided 46mj of energy? express your answer in units of ms (milli-seconds).

Answers

At a certain time, by performing the given steps of calculation with appropriate values one can find the point of time at 46mj energy.

To find the point in time at which the source has provided 46mJ of energy, we need to integrate the current over time and set it equal to 46mJ.

The current as a function of time is given by:

i(t) = 749mA * e^(-t/67ms)

The energy provided by the source is given by the integral of the current with respect to time.

E = ∫i(t) dt

To solve the integral, we can use the power rule of integration:

∫e^(ax) dx = e^(ax) / a + C

By substituting the values in the above equation we can get the time at which the source provided 46mJ of energy.

E = ∫(749mA * e^(-t/67ms)) dt

E = 749mA * (e^(-t/67ms) / (-1/67ms)) + C

E = 749mA * (-67ms * e^(-t/67ms)) + C

Solving for t we get t = 67ms * ln(46mJ/(749mA * 67ms))

Therefore, at t = 67ms * ln(46mJ/(749mA * 67ms)) the source has provided 46mJ of energy.

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The velocities of a rollercoaster car at points A and B are shown in the picture. The car has a mass of 25 kg. Apply the Work-Energy theorem to find the net work done by the car between point A and B.

Answers

The work done by the car is equal to the change in kinetic energy.

The work-energy theoremChange in kinetic energy = (1/2)*mass*(velocity A^2 - velocity B^2) Net work done = (1/2)*25*(6^2 - 9^2) Net work done = -225 JThe work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. In the case of a rollercoaster car, the work done can be determined by calculating the change in the car's kinetic energy as it moves from point A to point B.The car's kinetic energy at point A can be calculated by using the equation KE=1/2mv^2, where m is the mass of the car and v is its velocity. We can substitute in the mass (25 kg) and the velocity (20 m/s) at point A to get a kinetic energy of 250 J.We can calculate the car's kinetic energy at point B in the same way. Substituting in the mass (25 kg) and the velocity (30 m/s) at point B yields a kinetic energy of 375 J.The change in the car's kinetic energy is equal to the work done by the car between point A and B. This can be calculated by subtracting the kinetic energy at point A from the kinetic energy at point B. Doing this yields a net work of 125 J. This means that the car does 125 J of work between point A and B.

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Answer:A

Explanation:

is that point to the left of the first two particles, to their right, or be- tween them? (b) should the third particle be positively or negatively charged? (c) is the equilibrium stable or unstable?

Answers

A third charged particle (does not matter whether it is a positive or negative charged particle) can be placed in between -3q and -q at x along .

Is  equilibrium stable or unstable?

Stable equilibrium exists when the object is in its lowest energy condition; metastable equilibrium exists when additional energy (ΔG) must be introduced before the object can reach true stability; unstable equilibrium exists when no additional energy is needed before reaching metastability or stability.

An equilibrium is asymptotically stable when f'(x)<0\ ; that is, the slope of f is negative. It is unstable when f'(x)>0\ . The left two equilibria in the figure are hyperbolic (f'(x) \neq 0), the others are non-hyperbolic because the slope (eigenvalue) is zero.

A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. For example, a marble at the bottom of a bowl will experience a restoring force when displaced from its equilibrium position.

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You are riding a bike with a bag in the front basket. A friend
on the sidewalk watches you ride by, heading south.
Which statement best describes how the bag's motion is
relative to the frame of reference - you and your friend?

Answers

Bag's motion is ,a straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).

Describe a speed example?In a specific direction, accelerate. A 50 mph Eastbound automobile is an illustration. the relationship between an object's motion's distance and time is demonstrated. An object's speed is depicted by the line.An object's velocity is altered by a net force; the acceleration increases with the magnitude of the net force. For an item to accelerate by the same amount as an object that is less massive, more net forces are needed.A straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).        

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a proton is placed in an electric field of intensity 801 n/c. what are the magnitude of the acceleration of the proton due to this field? (e

Answers

When a proton is placed in an electric field of intensity 801 n/c, then the  magnitude of the acceleration of the proton is 7.7 x 10^9 m/s^2.

What is electric field?

The physical field that surrounds electrically charged particles and exerts force on all other charged particles in field (attracting or repelling them) is called electric field.

As we know, a = F/m

where F is force acting and m is its mass.

It is known that, q = 1.6 x 10^-19 C

F = Eq = 801 N/C * 1.6 x 10^-19 C = 1.28 x 10^-17 N

Mass of a proton is approximately 1.67 x 10^-27 kg.

Therefore, acceleration of the proton can be calculated as:

a = F/m = (1.28 x 10^-17 N) / (1.67 x 10^-27 kg) = 7.7 x 10^9 m/s^2

So, the magnitude of acceleration of the proton is 7.7 x 10^9 m/s^2.

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can you receive a shock severe enough to prevent you from releasing the wire from an ordinary outlet with dry hands?

Answers

It is possible to receive a severe electrical shock from an ordinary outlet that would prevent a person from releasing the wire with dry hands, but it is not likely.

What are the factors to judge the severity of an electrical shock?

The severity of an electrical shock depends on several factors, including the amount of current flowing through the body, the duration of the shock, and the path the current takes through the body. In most cases, a person would be able to release the wire from an outlet even if they received a shock. However, it is important to note that any electrical shock can be dangerous and should be avoided.

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The speed of an object undergoing constant acceleration increases from 8.0 meters per second to 16.0 meter per second in 10 seconds. How far does the object travel during the 10 seconds?

Answers

As acceleration increases from 8.0 m/s^2 to 16.0 m/s^2 in 10 seconds, the object travel during this 10 seconds is 84 meters.

To calculate the distance traveled by an object undergoing constant acceleration, we need to use the equation of motion for uniformly accelerated motion, which is given by:

d = v_0t + 0.5 at^2

where d is the distance traveled, v_0 is the initial velocity (8.0 m/s in this case), t is the time interval (10 s in this case), and a is the acceleration. To find the acceleration, we can use the following equation:

v = v_0 + at

Putting the final velocity (16.0 m/s) and the initial velocity (8.0 m/s) and the time interval (10 s), we get:

16 = 8 + a x 10

Solving for acceleration:

a = 0.8 m/s^2

Now that we have the acceleration, we can use the first equation to find the distance traveled:

d = v_0t + 0.5at^2

d = 8 x 10 + 0.5 x 0.8 x 10^2

d = 80 + 4

d = 84 m

So, the object travels 84 meters during the 10 seconds.

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consider the energy consumed by a 300 w light bulb in an hour. how many flights of stairs would you have to climb to equal the work of the lightbulb?

Answers

The number of flights of stairs you would have to climb to equal the work of the lightbulb in this time is approximately 589 stairs.

Given that,

Mass = 88 kg

Height of stairs = 2.1 meters.

Power = 300 Watt

Time = 1 hour

To calculate how many flights of stairs you would need to travel to accomplish the same amount of work as the lightbulb in this period of time:

First, we would figure out how much effort is required to ascend a set of steps that is 2.1 metres high.

Work done, mathematically, is given as,

W = m g h = 88 × 10 × 2.1 = 1848 J

Energy is given by, E = power × time

E = 300 × 3600 = 1080000 J

We can now determine how many flights of stairs you would need to climb to accomplish the same amount of work as the lightbulb in this period:

Flights = Energy/work done = 1080000/1848 = 588.41 ≈ 589 stairs

The given question is incomplete. The complete question is 'Assume your mass if 88 kg and the acceleration of gravity is 10 m/s². How much work do you do against gravity when you climb a flight of stairs that is 2.1 meters high?'

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A 2-kilogram box on a horizontal frictionless surface is acted upon by a 9-newton horizontal force to the left and a 1-newton horizontal force to the right. The acceleration of the box is

(1) 5 m/s^2 to the right
(2) 5 m/s^2 to the left
(3) 4 m/s^2 to the right
(4) 4 m/s^2 to the left

Answers

The acceleration of the box is 4 m/s²  to the left.

option 4 is the correct answer.

What is the acceleration of the box?

The acceleration of the box is calculated by applying Newton's second law of motion as follows;

∑F = ma

where;

∑F is the net forcem is the mass of the boxa is the acceleration of the box

F₁ - F₂ = ma

1 N - 9 N = ( 2 kg ) a

-8 N =  ( 2 kg ) a

divide both sides by 2

- 8 /  ( 2 kg ) = a

- 4 m/s² = a

Thus, the acceleration of the box will be directed to the left which has greater force.

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what are the major examples of functional groups? i. which are polar? which are non-polar? which are charged? how can you tell? be able to identify each one as either polar, non-polar, charged based on its structure

Answers

A polar molecule is usually formed when the one end of the molecule is said to possess more positive charges and whereas the opposite end of the molecule has negative charges, creating an electrical pole.

What is polar molecules?

The unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that a water molecule has two poles -

a positive charge on the hydrogen pole (side) and

a negative charge on the oxygen pole (side).

We say that the water molecule is electrically polar.

What is non -polar molecule?

A nonpolar molecule is one whose charge distribution is spherically symmetric when averaged over time; since the charges oscillate, a temporary dipole moment exists at any given instant in a so-called nonpolar molecule.

These temporary dipole moments fluctuate rapidly in magnitude and direction,…

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What is the net work required to slow down a 5,020kg car from 41.0m/s to 21.0m/s?
a. Wnet = 6.22 · 106J
b. Wnet = 5.02 · 104J
c. Wnet = -3.11· 106J
d. Wnet =-9.85 · 105J

Answers

The net work that has been done is obtained as  5.02 * 10^4J. Option B

What is the net work that is required?

We have to note that the work that is done is defined as the product of the force that has been applied and the acceleration of the object. In this case ,we can see that there is work that has been done as the velolcity of the object is changed.

Hence;

Work done = 1/2mΔv^2

m = mass of the object

v = velocity of the object

Thus;

Work done = 0.5 * 5020 * (21 - 41)^2

Work done =  5.02 * 10^4J

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orbitwheels are a cross between a skateboard and pair of inline skates. riders insert each foot in a large wheel that rotates sideways. orbitwheels differ from a skateboard in that they are self-propelled by the rider's wave-like motion so the need to push off the ground every few feet to get moving is eliminated. the product has been popular among some kids, especially athletic teen boys. athletic teen boys could be described as the

Answers

The sporty teen males here represent a subset of the overall market for skates, which is distinct from the tangential market. Target market is the appropriate response.

What is Target Market ?

The goal of mass marketing is to use the same marketing mix to sell to as many people as possible. In light of this, a mass market is defined as having a sizable number of consumers and is handled as a homogenous aggregate, disregarding segmentation differences. Market aggregation also refers to mass marketing, which involves the sale of standardised commodities to a broad audience. However, the target market also contains a specific market segment or segments on which the product is focused, and the market mix was created to meet the needs of consumers in these categories. In this instance, the target market for the product, for whom the business should create the marketing mix, is sporty teen boys who enjoy using Orbit wheels.

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What things do we need to know to determine how much force was used on an object? Select 2 correct answer(s) Question 5 options: How far it went How much it weighs The object's mass Speed How fast it's moving The object's acceleration

Answers

Answer:

The object's mass

The object's acceleration

Explanation:

To determine how much force was used on an object, we need to know the object's mass and acceleration. The force acting on an object can be calculated using the equation force = mass x acceleration (F = m*a) So, the more massive the object is, the more force is required to accelerate it, and the greater the acceleration is, the greater the force applied to the object.

I need answers, do your thing, I don’t need breakdowns or explanations, just answers.

Answers

a) The gravitational force on the earth is 81 times that on the moon

b) The slope of the graph is the universal gravitational constant

c) The force is  5 * 10^19 N

d) The acceleration due to gravity is the same.

What is gravity?

We know that the term gravity has to do with the force that acts on any object that we can be able to find on the surface of the earth. We know that the larger the mass of the object, the greater the magnitude of the gravitational force on the object.

We can see that in the question the distance between the earth and the moon was halved hence the force would now be one quarter of its initial value hence;

New force = 1/4 * 2 * 10^20

= 5 * 10^19 N

The acceleration  due to gravity does not change hence it is the same both at the surface and near the surface.

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Shilpa found some small creatures moving in the fresh water near her house. What are those small creatures? Do these animals show complete or incomplete metamorphosis in their life cycle

Answers

Without more information about the specific characteristics and appearance of the small creatures that Shilpa found, it is difficult to determine exactly what they are.

However, there are many different types of small aquatic animals that can be found in fresh water, including insects, crustaceans, and mollusks. Some examples of small aquatic creatures that are commonly found in fresh water include:

Aquatic insects: Mayflies, stoneflies, caddisflies, and dragonflies are examples of aquatic insects that can be found in freshwater. These insects typically have a complete metamorphosis, where they go through four distinct stages in their life cycle: egg, larva, pupa, and adult.

Crustaceans: Freshwater crustaceans include crayfish, freshwater shrimp, and freshwater crabs. These animals have a complete metamorphosis, where they go through a series of stages in their life cycle, including a planktonic stage, megalopa stage, and juvenile stage before reaching adulthood.

Mollusks: Freshwater snails, freshwater mussels, and freshwater clams are examples of mollusks that can be found in freshwater. These animals typically have a complete metamorphosis, where they go through different stages in their life cycle, including a planktonic stage, a glochidium stage, and a juvenile stage before reaching adulthood.

It is important to note that without more information about the specific characteristics of the creatures that Shilpa found, it is impossible to determine their exact species and if they show complete or incomplete metamorphosis in their life cycle.

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What makes a thermometer sensitive

Answers

A thermometer sensitive is a bulb with a thin glass wall. so, option (a) is correct.

What is thermometer?

A thermometer is a device that measures temperature. The three most used ways to measure temperature are in degrees Celsius, degrees Fahrenheit, and degrees kelvin. The metric system incorporates the Celsius scale.

What is thermometer sensitive?

The degree of change in a thermometer's thermometric property for a unit change in temperature is referred to as its sensitivity. It speaks of the smallest temperature difference that may be seen or quantified. The difference between the maximum and least temperature is referred to as a thermometer's range.

Therefore, a thermometer sensitive is a bulb with a thin glass wall. so, option (a) is correct.

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cart 1 of mass m moves with a velocity of v toward cart 2 which has a mass of 9m and is at rest. cart 1 collides elastically with cart 2. what is the velocity of both carts after the collision?

Answers

After the collision, cart 1 will have a velocity of v/10, and cart 2 will have a velocity of 9v/10.

The velocity of both carts after the collision can be calculated by using the conservation of momentum principle. In an elastic collision, both momentum and kinetic energy are conserved.

Before the collision, the total momentum of the system is equal to the momentum of cart 1, which is equal to m*v  where the mass of cart 1 is multiplied by its velocity.

After the collision, the total momentum of the system is equal to the combined momentum of the two carts.

Consider the velocity of carts 1 & 2 after the collision as v1 & v2.

The total momentum after the collision is:

mv1 + 9mv2 = m*v (conservation of momentum)

By solving v1 & v2, we get:

v1 = (mv) / (m + 9m) = v / 10

v2 = (9mv) / (m + 9m) = 9v / 10

So after the collision, cart 1 will have a velocity of v/10, and cart 2 will have a velocity of 9v/10.

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what is the maximum elevation above the roof the ball will reach? b) how long will it take to reach that maximum elevation? c) how long will it take to come back to the roof level? d) if the building is 15 m high, how long will it take for the ball to hit the ground after release?

Answers

Equations of motion for constant acceleration to find maximum elevation, time and velocity are as follows :

y = yi + vi*t + (1/2)*a*t^2

vf = vi + a*t

V^2= U^2 + 2 a s

Givens:

vf = 0 m/s (the ball stops at the time in question)

yi = 0 m (or assume whatever initial height you wish, and add to the final answer)

a = -9.8 m/s (we can add more significant digits, but this is close enough)

b) The maximum elevation above the roof the ball will reach can be found by,  y= yi + vi*t + (1/2)*a*t^2

c)Time to reach maximum height can be obtained from v = u + at

     at = v - u

therefore, time required is t = v - u / a

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A 0. 6 kg basketball is thrown straight up at a velocity of 4 m/s. What is the initial kinetic energy of the basketball?

Answers

The initial kinetic energy of the basketball is 8 J.

What do you mean by Kinetic Energy?

Kinetic energy is the energy an object possesses due to its motion. Kinetic energy is proportional to the square of an object's velocity and is expressed as KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity. Kinetic energy is a scalar quantity, meaning it only has magnitude and not direction. When an object slows down or comes to rest, its kinetic energy is converted into other forms of energy, such as heat or potential energy. Kinetic energy is a crucial concept in the fields of mechanics, thermodynamics, and other branches of physics.

The initial kinetic energy of the basketball can be found using the formula:

KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

For the 0.6 kg basketball with a velocity of 4 m/s, the initial kinetic energy is:

KE = 1/2 * 0.6 kg * (4 m/s)^2

KE = 8 J

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Five balls are placed one after the other along a straight line as shown in the figure. Initially, all the balls are at rest. Then the second ball has been projected with speed v0 towards the third ball. Mark the correct statements. (Assume all collisions to be head-on and elastic)
a. total number of collision in the process is 5
b. the velocity of separation between the first and fifth ball after the last possible collision is v0
c. finally, three balls remain stationary
d. all of the above

Answers

All of the given options are correct as the velocity of each ball is transferred via collision

Given,

5 balls are placed one after the other

the velocity of the second ball is V0

if the second ball is given the velocity, it will rebound back and hit the first one. Also, all the other balls will undergo collision due to the velocity given to the second ball.

therefore, 5 collisions will take place

as the second ball collides with the 3rd one, its momentum is transferred to the 4th and will carry on to 5th ball and thus separation velocity of 5th and 1st ball will be the same.

Again, as the collision ends up with only 1st and 2nd ball being separated by velocity V0 , then other 3 balls remain stationary

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while playing ulimate frisbee you run north for 10 m, then eas for 30 m, adn finally 34 m in a direction 37 degrees south of east. what is your total displacememnt (magnitude and direction) during this run?

Answers

The total displacement is 48m in a direction 30° south of east.

What is total displacement?

Total displacement is the vector sum of all individual displacements that an object has undergone during a certain period of time.

To calculate this, we first need to calculate the displacement when running north for 10m. That would be 10m in a direction of 0° (due north).
Next, when running east for 30m, the displacement would be 30m in a direction of 90° (due east).
Finally, when running in a direction 37° south of east for 34m, the displacement would be 34m in a direction of 37° south of east.
Now to calculate the total displacement, we need to add the vector components of each of these three displacement vectors together.
The x component of the total displacement is 10m + 30m + (34m * cos(37°)) = 48m.
The y component of the total displacement is 0m + 0m + (34m * sin(37°)) = 31m.
Using the Pythagorean theorem, we can calculate the magnitude of the displacement vector to be sqrt(48^2 + 31^2) = 59.48m.
To calculate the direction of the displacement vector, we can use the inverse tangent function, arctan(31/48) = 30.14°.
Therefore, the total displacement is 48m in a direction 30° south of east.

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a ball is thrown upward from the ground with an initial speed of 17.2 m/s; at the same instant, another ball is dropped from a building 20 m high. after how long will the balls be at the same height above the ground?

Answers

The balls will be at the same height above the ground at 1.16s.

Equations of motion in physics are equations that explain how a physical system behaves in terms of how its motion changes over time. The behaviour of a physical system is described in more detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables.

Before they collide, the falling ball travels a distance of (20m-h), where h is the height above the earth. We submit

yf= yi + vit - 0.5 gt²

to the falling ball to obtain,

-(20-h)= - 0.5 gt²

Applying yf= yi + vit - 0.5 gt² to the rising ball gives,

h= 17.2t - 0.5gt²

Combining both equations,

t= [tex]\frac{20}{17.2}[/tex] = 1.16 s

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one can tell a raw egg from a boiled one by spinning it on a table. a boiled egg spins for a longer time. explain using fluid mechanics concept.

Answers

A boiled egg rotates for longer time.

While a raw egg contains liquid, a hardboiled egg behaves like a stiff body. The fluid inside the egg flows about as the raw egg is spun, changing its center of gravity or balancing point. Due to centrifugal force, when rotated, the liquid is pushed out from the center. Since raw eggs have more moment of inertia than boiled eggs do, they spin with less angular acceleration because their mass is dispersed farther from the axis in raw eggs than it is in boiled eggs. So, boiling eggs will spin more quickly than raw ones.

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The reason behind the fluids mechanics concept is the moment of inertia.

The tough boiled egg spins for a good deal longer (and quicker) than the uncooked egg. This is due to the fact the inner is stable, so the whole element is one stable mass. The uncooked egg has liquid at the inner, which isn't connected to the shell. The liquid inner it a good deal tougher to spin, and it slows the egg down a good deal quicker. When circled the liquid is driven far from the centre because of centrifugal force. Therefore mass in uncooked egg is sent further from the axis as compared to boiled egg, so moment of inertia for uncooked egg is extra so uncooked egg spin with much less angular acceleration. Therefore, boiled egg will spin quicker than uncooked egg.

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