The oxygen content of something like a metal oxide matching the composition MO is 19.66%. The element M is represented by the Zn symbol.
What are metals and an example of one?The elements with boiling and melting temperatures and glossy crystalline solids are known as metals. Metals are efficient heat and electrical conductors. Metals like iron, aluminium, nickel, silver, and tin, for instance, are utilized frequently in our daily lives.
Who made the metal?Native Metals were originally discovered and used by ancient man around 5000 BC. In the following two thousand years, up until the beginning of the Bronze Age, humankind perfected the techniques for discovering, working with, and using these local metals. Gold nuggets were frequently the simplest to locate and utilize.
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Acetylene gas (C2H2) used in welding, produces an extremely hot flame when it burns
in pure oxygen according to the reaction
2 C₂H₂(g) +5 O₂(g) → 4CO₂(g) + 2 H₂O(g).
How much H₂O is produced when 40000 g of
C₂H₂ burns completely?
Answer in units of g.
The mass of H₂O produced when 40000 g of C₂H₂ burns completely is 27692.3 g.
What is the mass of water produced when 40000 g of C₂H₂ burns completely in the air?The mass of water produced when 40000 g of C₂H₂ burns completely in the air is determined from the mole ratio as given in the equation of the reaction as follows;
Equation of reaction: 2 C₂H₂(g) + 5 O₂(g) → 4 CO₂(g) + 2 H₂O(g)
The molar mass of C₂H₂ = 26 g
The molar mass of water = 18 g
The mole ratio of C₂H₂ to H₂O is 1 : 1
The mass of water produced = 40000/26 * 18 g
The mass of water produced = 27692.3 g
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Name TWO things chemical and nuclear reactions have IN COMMON/SHARE.
Answer:
Both chemical and nuclear reactions involve changes in the arrangement of atoms or subatomic particles.
Both chemical and nuclear reactions result in the release or absorption of energy.
Chemical and nuclear reactions are both types of reactions that involve a change in the composition of matter. Here are two things that they have in common/share:
1. Conservation of mass: Both chemical and nuclear reactions follow the law of conservation of mass. This means that the total mass of the reactants is equal to the total mass of the products. In other words, mass cannot be created or destroyed during a chemical or nuclear reaction.
2. Energy changes: Both chemical and nuclear reactions involve a release or absorption of energy. Chemical reactions typically involve the breaking and forming of chemical bonds, which releases or absorbs energy. Nuclear reactions involve the splitting or combining of atomic nuclei, which releases or absorbs much larger amounts of energy. In both cases, the energy change can be measured and analyzed.
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Please help on 1.15!!
The equation, in its most basic form, asserts that energy and mass (matter) are interchangeable; they are various manifestations of the same thing. Both energy and mass can become one another under the correct circumstances.
The universe contains how much matter and energy?Dark energy, which makes up the remaining 68.5 percent of the universe, is a mystery factor that appears to be speeding up the universe's expansion.The equation, in its most basic form, asserts that energy and mass (matter) are interchangeable; they are various manifestations of the same thing. Both energy and mass can become one another under the correct circumstances.Dark energy, which makes up the remaining 68.5 percent of the universe, is a mystery factor that appears to be speeding up the universe's expansion.The equation, in its most basic form, asserts that energy and mass (matter) are interchangeable; they are various manifestations of the same thing. Both energy and mass can become one another under the correct circumstances.The complete question is,
"Mass times light speed squared equals energy."
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Does the phrase “you are what you eat” make scientific sense according to your knowledge of enzymes and transport?
The phrase “you are what you eat” does not make scientific sense according to the knowledge of enzymes and transport because foods are broken down by enzymes into small subunits which are common to all biomolecules.
What is the role of enzymes in the digestive system?The role of enzymes in the digestive system is based on breaking down food into smaller components during metabolic activities.
Therefore, with this data, we can see that the role of enzymes in the digestive system is to degrade biomolecules that are ingested into common subunits.
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for each pair of elements, first write the ions that they form. then predict the ionic compound formed when combined.
The ionic compound that occurs between each pair of elements has the following formula:
[tex]Al_2} S_{3}[/tex]AIN [tex]k_{2} o[/tex]MgO [tex]BaF_{2}[/tex][tex]Be_{3} N_{2}[/tex]The formula of the ionic compound of each pair is:
(a)Aluminum and Sulfur:
Aluminum sulfide, commonly known as [tex]Al_{2} S_3}[/tex], is created when aluminum and sulfur are combined. Its molar mass is 150.158 g/mol. Al has an oxidation state of +3, while the sulfur in [tex]Al_{2} S_{3}[/tex]is in a -2 oxidation state.
[tex]Al_2} S_{3}[/tex] = [tex]Al^{+3}[/tex] + [tex]S^{-2}[/tex]
(b) Aluminum and Nitrogen:
Solid aluminum nitride is known as aluminum nitride (AlN). It's an electrical insulator with a high thermal conductivity of up to 321 W/. (mK).
AlN = [tex]Al^{+3}[/tex] + [tex]N^{+3}[/tex]
(c) Potassium and oxygen
When potassium and oxygen combine, a substance known as potassium oxide is created. The chemical name for it is [tex]K_{2} O[/tex]. Due to its high level of reactivity, potassium is never found in its free form. It is straightforward for it to react with oxygen atoms to produce [tex]K_{2} O[/tex]because of its +1 valency.
( K₂ )⁺¹ + O²⁻ → K₂O
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The complete question follows
Write a formula for the ionic compound that forms between each pair of elements.
An experiment at Sandia National Labs in New Mexico is performed at 758.7 mm Hg. What is this pressure in atm?
40 points
Answer:
0.9997 atm.
Explanation:
To convert pressure from millimeters of mercury (mm Hg) to atmospheres (atm), you can use the conversion factor 1 atm = 760 mm Hg.
To convert 758.7 mm Hg to atm, you can divide the pressure in mm Hg by 760:
758.7 mm Hg / 760 mm Hg/atm = 0.9997 atm
So the pressure in atm is approximately 0.9997 atm.
According to the unit conversion of pressure, the pressure in atmospheres is 0.998 atmospheres.
What is pressure?Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.
There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .
It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.
As 1 atmosphere= 760 mm Hg , thus, 758.7 ×1/760=0.998 atmospheres.
Thus, the pressure in atmospheres is 0.998 atmospheres.
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Explain why the formula shown below is incorrect for the compound potassium chloride:
Formula: KCL
The formula KCL is not the correct formula for the compound potassium chloride. Potassium chloride is a compound made up of potassium and chlorine ions, and its chemical formula is KCl.
What volume of a 25% (W/V) solution of HNO3
The volume of a 25% solution of HNO3 that is needed to contain 12.6g of HNO3 is: 50.4 ml .
How to find the volume of a 25% solution of HNO3?Based on the information given the 25%(w/v) implies that 25 g of HNO3 contains in 100 ml of the solution.
Now let find the volume of a 25%(w/v) solution of HNO3 that is needed to contain 12.6 g HNO3
Volume needed = 12,6×100/25
Volume needed = 50.4 ml of solution required
Therefore we can conclude the volume needed is 50.4ml .
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The complete question is:
What volume of a 25% solution of HNO3 is needed to contain 12.6g of HNO3?
Which of the following are correct procedures for
handling microorganisms? Check all of the boxes
that apply.
Touch the microorganisms with your bare
hands.
Use aseptic techniques.
Wash your hands frequently.
Use disinfectants to clean lab surfaces.
The correct procedure for handling microorganisms is to wash your hands frequently to make preventive doings. For the safest reason, using Personal Protective Equipment is recommended.
What is Personal Protective Equipment?
Personal Protective Equipment (PPE) is equipment that must be used when working, according to the potential hazards and work risks on the job. This is used to maintain the safety of the workers themselves and those around them. Personal Protective Equipment must be in accordance with the type of work so that the safety and health of workers can be guaranteed.
Activities in the microbiology laboratory will always be closely related to the following things
Biological substanceChemical substancePhysics substanceThe tool used in assisting the examination or identification of microorganisms can be in the form of a Bunsen which uses spirit, which has flammable properties. If the test tube is not used carefully, it can break and can injure the limbs.
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Answer:
Use aseptic techniques, Wash your hands frequently, and use disinfectants to clean lab surfaces.
Explanation:
Which of the following statements correctly reflect the relationship between the volume and external pressure of a gas at constant temperature? Select all that apply. a. As pressure decreases, volume will increase. b. Pressure and volume are inversely proportional.c. Volume and pressure are independent of each other. d. The external pressure increases as volume increases.
The correct statements that reflect the relationship between the volume and the external pressure of the gas at the constant temperature is a) As pressure decreases, volume will increase. b) Pressure and volume are inversely proportional.
The ideal gas equation is given as :
P V = n R T
where,
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
As the pressure will decreases, the volume will increase and the Pressure and the volume are inversely proportional to each other. The number of mole is the ratio between the mass divided by the molar mass.
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Exercise 1. Calculate the volume of a sample of ammonia (NH3) at 0°C and 1.00 atm if the sample occupies a volume of 0.25 L at 27°C and 0.850 atm.
The volume of a sample of ammonia at 0°C and 1.00 atm is approximately 0.232 L.
How to find the volume of a sample of ammonia (NH3)?
The relationship between the volume and temperature of a gas is described by Charles's law, which states that the volume of a gas is proportional to its temperature, provided that the pressure and number of moles of the gas remain constant.
Mathematically, this can be expressed as:
V1 / T1 = V2 / T2
Where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
Given:
Initial volume = 0.25 L
Initial temperature = 27°C = 27 + 273.15 = 300 K
Initial pressure = 0.850 atm
Final temperature = 0°C = 273.15 K
Final pressure = 1.00 atm
To convert from one pressure to another, we can use the ideal gas law:
P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Rearranging, we can find the final volume:
V2 = P1V1 / P2
V2 = (0.850 atm) * (0.25 L) / (1.00 atm)
V2 = 0.213 L
Finally, using Charles's law, we can find the volume of the sample at 0°C and 1.00 atm:
V2 / T2 = V1 / T1
V2 / 273.15 = V1 / 300
V1 = (V2 * 300) / 273.15
V1 = (0.213 L) * (300 K) / (273.15 K)
V1 = 0.232 L
So, the volume of a sample of ammonia at 0°C and 1.00 atm is approximately 0.232 L.
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Write a balanced chemical equation to represent the following chemical reaction.
potassium iodide + lead(II) nitrate âLead(II) iodide + potassium nitrate
Answer:
KI + Pb(NO3)2 -> PbI2 + KNO3
Explanation:
The balanced chemical equation for the reaction of potassium iodide with lead(II) nitrate to form lead(II) iodide and potassium nitrate is:
KI + Pb(NO3)2 -> PbI2 + KNO3
In this equation, the coefficients in front of the compounds indicate the number of moles of each substance that are needed to balance the equation. This means that there are equal numbers of atoms of each element on both sides of the equation.
Please match each word with the correct description. (Lesson 1.01)
First layer of the
atmosphere
Layer that contains the
Ozone Layer
The layer of the atmosphere that has the least molecules
atmosphere that has the
least molecules
1. Troposphere
2. Stratosphere
3. Exosphere
Answer:
First layer of the atmosphere = Troposphere
Layer that contains the Ozone Layer = Stratosphere
The layer of the atmosphere that has the least molecules atmosphere that has the least molecules = Exosphere
Explanation:
You need a KOAc solution at pH 5, which is 3 M in K+. Such a solution is used in bacterial plasmid DNA isolation. How many moles of KOAc and acetic acid (HOAc) do you need to make 500 mL of this solution?
1.73/2 approximately 0.86 moles of acetic acid must be added. KOAc should be used at a ratio of 3/2, or 1.5 moles.
Is acetic acid poisonous to people?Effects on People Acetic acid is a potent irritant to the skin, upper respiratory tract, eyes, and mucous membranes when inhaled as vapor. Sodium acetate mixtures of 80% or over can be corrosive when in contact with skin or eyes, severely burning any exposed tissue.
Using the Henderson-Hasselbalch equation, determine the quantity of acetic acid (x) required to produce a pH-5.0 solution that contains
3MK+(3 M KOAc). The pK of acetic acid is 4.76 (Table 2-4).
[tex]$$\begin{aligned}\mathrm{pH} & =\mathrm{p} K+\log \frac{[\mathrm{KOAc}]}{[\mathrm{HOAc}]} \\5 & =4.76+\log \frac{3}{x} \\0.24 & =\log 3-\log x \\0.24-0.48 & =-\log x \\0.24 & =\log x \\x & =1.73 \mathrm{M}\end{aligned}$$[/tex]
Therefore, for a 500 mL solution, the amount of acetic acid added should be 1.73/2 or 0.86 moles. The amount of KOAc should be 3/2 or 1.5 moles.
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metal x replaces the ions of metal y from solution, but it cannot replace the ions of metal z from solution. the order these metals should have in the activity series (from top to bottom) is
The order these metals should have in the activity series (from top to bottom) is z,x,y.
An activity series is a list of elements in order of decreasing reactivity. Elements at the top of the activity series are more reactive than those at the bottom. Since metal x can replace the ions of metal y from solution but not those of metal z, it means that metal x is more reactive than metal y but less reactive than metal z. Therefore, the order of these metals in the activity series would be z (most reactive), y (least reactive), x (more reactive).
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What is the similarities of polar covalent bonds and nonpolar covalent bonds?
Answer:
Explanation:
Polar covalent bonds and nonpolar covalent bonds are similar in that they both involve the sharing of electrons between atoms in a covalent bond. In both types of bonds, the atoms involved share electrons in order to achieve a full valence electron shell, which gives the bond its stability.
Both polar and nonpolar covalent bonds have a covalent character, meaning they are formed by the sharing of electrons between atoms, as opposed to the transfer of electrons which is seen in ionic bonds. Also, both type of bonds are strong chemical bonds, which means they have a high bond energy, meaning they require a lot of energy to break.
Covalent bond formation depends on the ability of atoms to...
a) share electrons with other atoms
b) donate electrons to other atoms
c) receive electrons from other atoms
d) share electrons with ions
e) capture electrons from gases
The correct answer is a) share electrons with other atoms.
Covalent bond formation occurs when atoms share electrons in order to achieve a stable electron configuration, also known as a full outermost electron shell. This is known as a covalent bond. In this type of bond, atoms share electrons in order to achieve a stable electron configuration. This is different from ionic bond formation, where atoms transfer electrons to each other in order to achieve a full outermost electron shell. Atoms collaborate with other atoms to form stable electron configurations in covalent bonds. In covalent bond, atoms share electrons with other atoms in order to achieve a stable electron configuration.
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What functional group is found in an aldehyde?
O A. Carbonyl
OB. Hydroxyl
O C. Ester
O D. Amino
Answer:
The answer is A. Carbonyl.
Carbonyl functional group is found in an aldehyde. Therefore, option (A) is correct.
What are the functions of carbonyl groups?A functional group with the formula C=O that is composed of a carbon atom double-bonded to an oxygen atom and is divalent at the C atom is known as a carbonyl group in organic chemistry.
The function of the carbonyl group is to break up the bonds in the carbon chain. The electronegative oxygen molecule will in general draw in additional electrons than the carbon it is attached to inside the carbonyl gathering.
There are many aromatic carbonyl compounds. Substances which incorporate carbonyls incorporate the compound answerable for the smell of vanilla and cinnamon.
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If a person practicing yoga for one hour burns 285 kilocalories (kcal),
how many joules (J) of energy have they burned?
Using unit conversion, One hour of yoga can result in 285 kilocalories burned (kcal) 1192440 j of energy were burned.
Unit conversion is what?It involves changing a value stated in one unit of measurement into an equivalent value expressed in a different unit of measurement that is of the same kind.
The same attribute is expressed using a unit conversion, but in a different unit of measurement. For instance, time can be expressed in minutes rather than hours, and distance can be expressed in kilometers, feet, or any other measurement unit instead of miles.
We must convert the units using the provided data in order to solve this challenge.
information regarding the issue:
energy is equal to 285 kcal (kcal)
Energy measured in joules (j) equals.
A calorie (kcal) is equal to 4184 joules (j)
Kilocalories (kcal) are converted to joules (j), which gives us:
1 kcal = 285 kcal * 4184 j of energy.
1192440 j = energy
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19. Radioactive copper-64 decays with a half-life of 12.8 days.
a. What is the value of k in s-¹?
b. A sample co rains 28.0 mg 64-Cu. How many decay events will be produced in the first second? Assume the atomic mass of 64-Cu is 64.0 u.
c. A chemist obtains a fresh sample of 64-Cu and measure radioactivity. She then determines that to do an experiment, the radioactivity cannot fall below 25% of the initial measured value. How long does she have to perform the experiment?
The chemist has 14.4 days to perform the experiment.
What is the value of k in s-¹?The value of k in s-¹ is 0.0530.The number of decay events in the first second is 5.5 x 1012.The value of k in s-¹ is equal to the natural logarithm of two (ln2) divided by the half-life (T1/2) of 12.8 days. Therefore, k = ln2/12.8 days = 0.04968 s⁻¹.The number of decay events produced in the first second can be calculated using the equation N = N0e^(-kt), where N0 is the initial number of atoms of the radioactive isotope, k is the decay constant, and t is the time interval in seconds.Since the atomic mass of 64-Cu is 64.0 u and the mass of the sample is 28.0 mg, the number of atoms in the sample can be calculated by dividing the mass of the sample by the atomic mass of the isotope, which gives us N0 = 28.0 mg/64.0 u = 0.4375 x 10^24 atoms.Substituting this value for N0 and the value for k (0.04968 s⁻¹), we get N = 0.4375 x 10^24 e^(-0.04968s⁻¹) = 0.4375 x 10^24 e^(-0.04968) = 4.355 x 10^23. Therefore, the number of decay events produced in the first second is 4.355 x 10^23.The chemist has to perform the experiment before the radioactivity of the sample falls below 25% of the initial measured value. This can be calculated by rearranging the equation N = N0e^(-kt) to get t = (ln(N/N0))/k.Substituting the initial number of atoms (N0) and the decay constant (k) and solving for t, we get t = (ln(0.25N0))/0.04968 = (ln(0.25 x 0.4375 x 10^24))/0.04968 = 15.6 days. Therefore, the chemist has 15.6 days to perform the experiment.To learn more about half-life experiment refer to:
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what molecule is most consistent with the following? what molecule is most consistent with the following? i ii iii iv v
The molecule in question is C12H22O2. This can be determined by using the information provided about the number of carbon, hydrogen, and oxygen atoms present in the molecule.
The chemical formula for the molecule is determined by listing the elements present in the molecule and their respective number of atoms.
The chemical formula for this molecule is C12H22O2. Using this information, it is possible to determine that the molecule is composed of 12 carbon atoms, 22 hydrogen atoms, and 2 oxygen atoms. The molecule with this chemical formula is known as "dodecanoic acid" and it is a straight-chain carboxylic acid.
It is also known as Lauric acid, which is found in many natural fats and oils and is a common ingredient in soaps and cosmetics. It is a white, waxy solid with a faint, characteristic odor. It is used in the manufacture of a wide variety of products, such as soaps, lubricants, and surfactants.
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The complete question is:
What is the chemical formula and structure of the molecule that is composed of 12 carbon atoms, 22 hydrogen atoms, and 2 oxygen atoms?
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consider the following two substances and their vapor pressures at 298 k . substance vapor pressure ( mmhg ) a 275 b 459 based on this information, compare the characteristics of the two substances. d
The characteristics of the two substances :
Substance A:
It has a higher boiling point.
It has higher heat of vaporization
Substance B:
It has the weaker intermolecular forces.
It is a gas at 300 mmHg
1) The substance A has the vapor pressure of 275 mmHg . It has low vapor when compared to the substance B . It has the higher boiling point and has the higher heat of vaporization.
2) The substance B has the vapor pressure of the 459 mmHg and it has the weaker intermolecular forces when compared to the substance A and also it is a gas at 300 mmHg.
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ammonium dihydrogen phosphate, formed from the reaction of phosphoric acid with ammonia, is used as a crop fertilizer as well as a component of some fire extinguishers. what are the mass percentages of nitrogen and phosphorus in the compound? round each of your answers to significant figures.
The mass percentage of the nitrogen is 24.34 % and the mass percentage of phosphorus is 26.95 %.
The formula for the ammonium dihydrogen phosphorus is NH₆PO₄.
The molar mass of ammonium dihydrogen phosphate = 115 g/mol
The molar mass of nitrogen = 28 g/mol
The molar mass of phosphorus = 31 g/mol
The mass percentage of nitrogen = (1 × 28 / 115 ) × 100 %
= 24.34 %
The mass percentage of phosphorus = ( 1 × 31 / 115 ) × 100 %
= 26.95 %
Thus, the mas percentage of nitrogen is 24.34 % and phosphorus is 26.95 %.
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C3H8 + 5O2 --> 3CO2 + 4H2O
Assume if we combust 1.3L of propane(C3H8). How much CO2 will be produced?
4.5 L
3.9 L
2.7 L
22.4 L
The amount of carbondioxide that will be produced if 1.3L is combusted is 3.9L (option B).
How to calculate volume using stoichiometry?Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).
According to this question, propane gets combusted in air to produce carbondioxide and water as follows:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Based on the above equation, 1 mole of propane produces 3 moles of carbondioxide.
This suggests that 1.3L of propane will produce 3.9L of carbondioxide.
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based on the pie chart, which of the following approaches would likely yield the biggest benefits for reducing nitrogen inputs into the chesapeake bay?
Based on the pie chart, Local governments work with farmers to implement strategies to minimize nitrogen runoff from farm fields would likely yield the biggest benefits for reducing nitrogen inputs into the chesapeake bay.
In order to control the transport of nitrogen from source regions to surface waters, managing agriculture and other human activities on the landscape usually entails reducing nitrogen applications and/or making changes to improve the efficiency of natural elimination of nitrogen. The transfer of nitrogen in particle form from the land surface to surface waters may be restricted by management techniques intended to reduce runoff and soil losses, such as riparian buffers, contour tillage, or manure or fertiliser injection.
The efficiency of management strategies for lowering nitrogen transfer from the land surface to surface waters is constrained by a number of factors and mechanisms. In anoxic riparian areas, nitrate may be converted to nitrogen gas, although it frequently moves past riparian areas to reach locations where streams discharge . Nitrogen losses may be significant where a thin surficial aquifer restricts groundwater to shallow flow paths, but minimal where a thicker surficial aquifer permits deeper groundwater flow. Variable hydrogeologic conditions on the Eastern Shore contribute to variable nutrient retention in riparian buffers.
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Based on the pie chart, which of the following approaches would likely yield the biggest benefits for reducing nitrogen inputs into the Chesapeake Bay?
surface chemists design metal alloys for specific functions in everyday life. which of the following does not demonstrate a benefit of using an alloy? A. Goldd is mixed with copper or silver to make a less expensive form that can be used in jelwery. B. Smalleer atoms of one metal are incorporated into the structure of larger metal atoms to reduce malleability andimprove strength of the structure. C. Densities of metals are closely matched to increase desirable properties without increased cost. D. The canductivity has been eliminated due to the stronger bonding of the different types od metals.
The statement that does not demonstrate a benefit of using an alloy is the conductivity has been eliminated due to the stronger bonding of the different types of metals. The answer is D.
Alloys are mixtures of two or more metals that are designed to have specific properties for a particular application. A common example of alloy used in jewelry is where gold is mixed with copper or silver to create a less expensive material with the same appearance as pure gold.
Another example for the use of alloy is where smaller atoms of one metal are incorporated into the structure of larger metal atoms to reduce malleability and improve strength of the structure. Another benefit of alloy is that the densities of metals are closely matched to increase desirable properties without increased cost. In most of the alloys, the conductivity is retained or even increased due to the combined properties of the different types of metals.
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Your question seems to be missing, but I suppose the question was:
"surface chemists design metal alloys for specific functions in everyday life. which of the following does not demonstrate a benefit of using an alloy?
A. Gold is mixed with copper or silver to make a less expensive form that can be used in jewelry.
B. Smaller atoms of one metal are incorporated into the structure of larger metal atoms to reduce malleability and improve strength of the structure.
C. Densities of metals are closely matched to increase desirable properties without increased cost.
D. The conductivity has been eliminated due to the stronger bonding of the different types of metals."
Step 1:?(slow)Step 2:NO3(g)+CO(g)→NO2(g)+CO2(g (fast)Overall:NO2(g)+CO(g)→NO(g)+CO2(g)A two-step reaction mechanism is proposed for a gas-phase reaction, as represented above. Which of the following correctly identifies both the chemical equation for step 1 and the rate law for the overall reaction?
The step that determines rate is the one that moves most slowly in a series of non-elementary reactions.
Reaction of CO(g) with NO2(g)
CO(g) + NO2(g) ? NO(g) + CO2(g)
At low temperatures, the experimentally determined rate law expression is:
Rate = k [NO2]2
A two step reaction mechanism is suggested
Step 1 SLOW NO2(g) + NO2(g) ? NO3(g) + NO(g)
Step 2 FAST CO(g) + NO3(g) ? CO2(g) + NO2(g)
CO(g) + NO2(g) ? NO(g) + CO2(g)
The step that determines rate is the one that moves most slowly in a series of non-elementary reactions. The rate-determining step is the initial reaction since it happens slowly. We can get the rate law from this.
Additionally, because the specie is not present in the overall reaction equation, it can only be an intermediate that was created in step 1 and depleted in step 2.
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Calculate the value of Dell H Kj upon kg for the following reaction using the list thermochemical reaction equation 2N2 + O2 form 2n2o DELLH equals to?second equation to end to 2NH3 + 3 N 2 O forM 4N2 + 3h2o DELL H equals to -1010KJ third equation for 4NH3 + 3 O2 form 2 N2 + 6h2oh DELL H equals to -1531 kj
The enthalpy for the reaction, N[tex]_2[/tex](g) + 1/2 O[tex]_2[/tex](g) →N[tex]_2[/tex]O(g) is +81.5. among all the given options, the correct option is option A.
What is enthalpy?The amount of heat inside a system is measured as enthalpy. This heat is used to cause a process to occur. Enthalpy is indeed a thermodynamic quantity since every system that involves heat is referred to be a thermodynamic system.
Additionally, it is important to remember that each system has a number of players. These individuals each have their own pressure and volume. We already know that the ratio of a system's pressure to its volume is constant.
N[tex]_2[/tex](g) + 1/2 O[tex]_2[/tex](g) →N[tex]_2[/tex]O(g)
i)2 NH[tex]_3[/tex](g) + 3 N[tex]_2[/tex]O(g) → 4N[tex]_2[/tex](g) + 3 H[tex]_2[/tex]O(l) ∆H°/kJ= -1010 KJ
ii)4 NH[tex]_3[/tex](g) + 3 O[tex]_2[/tex](g) → 2 N[tex]_2[/tex](g) + 6 H[tex]_2[/tex]O(l) ∆H°/kJ = -1531 KJ
Multiply second equation with 4 and first equation with 2. Now substract third equation from fourth equation.
N[tex]_2[/tex](g) + 1/2 O[tex]_2[/tex](g) →N[tex]_2[/tex]O(g) ΔH=+81.5
Therefore, the enthalpy for the reaction, N[tex]_2[/tex](g) + 1/2 O[tex]_2[/tex](g) →N[tex]_2[/tex]O(g) is +81.5.
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using figures 5.21, 5.22, and the text, describe the structure and function of g-protein coupled receptors and ligand-gated ion channels.
TheThe function of GPCRs is highly diverse, recognizing a wide range of ligands, including photons, small molecules, and proteins. Ion channels are pores in the cellular membrane that allow ions to pass in and out of the celThe function of GPCRs is highly diverse, recognizing a wide range of ligands, including photons, small molecules, and proteins. Ion channels are pores in the cellular membrane that allow ions to pass in and out of the cell.
The function of GPCRs is highly diverse, recognizing a wide range of ligands, including photons, small molecules, and proteins. Ion channels are pores in the cellular membrane that allow ions to pass in and out of the cell.GPCRs contain seven transmembrane helices (gray), three extracellular loops (ECLs) and an amino terminus (orange), and three intracellular loops (ICLs) and a carboxyl terminus (purple).The transmembrane domain consists of the transmembrane helices, as well as the extracellular and intracellular loops.Ligand-gated ion channels (LGICs) are integral membrane proteins that contain a pore which allows the regulated flow of selected ions across the plasma membrane. Ion flux is passive and driven by the electrochemical gradient for the permeant ions.To know more about Proteins:-
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Consider the composition. information from the SDS. What is a possible name of this compound?
A. Glycine
B. Glycogen
C. Glycerol
This substance may also be known as glycol. Each chemical's characteristics, potential physical, mental, and environmental health risks, as well as safety precautions, are all covered in the SDS.
What do a compound and an element mean?Atoms of various elements are chemically mixed in compounds in a predetermined ratio. A pure chemical compound made of the same type of atom is referred to as an element. Composition. Different elements are found in compounds in a predetermined ratio, organized by chemical bonds in a predetermined way.
Which best explains a compound?A substance that has been chemically linked by the joining of two or more distinct components. Saltwater (NaCl), which is derived from the components sodium and chloride, and water (H2O), which is created from the elements and oxygen, are two examples of compounds.
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