The flow velocity in the meter is 0.7958 in/min
How to determineThe flow meter attached to the main line in a hydraulic system measures the flow rate at 10 gpm. The line has an inside diameter of 2 in.
The flow velocity in the meter can be calculated using the formula:
Velocity = (Flow rate) / (Cross-sectional area)
The cross-sectional area of the line can be calculated as:
Area = π × (diameter/2)²
Substituting the given values, we get:
Area = π × (2/2)²
Area = π × 1
Area = π
Therefore, the velocity in the meter is:
Velocity = (10 gpm) / (π in²)
Simplifying the units, we get:
Velocity = (10 gal/min) / (π × (2 in)²)
Velocity = (10 gal/min) / (π × 4 in²)
Velocity = (10/4π) in/min
Velocity ≈ 0.7958 in/min
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state which parties will be responsible for the following task in a construction of an earthfall dam for irrigation:
1.Providing labour.
2.Funding the construction of the dam. 3. Approving the drawings
4.Overall coordination of the project.
5.Setting up coordinates and levels for back-filling
The parties in the construction of an earthfall dam for irrigation who will be responsible for the following services are given below.
What is the justification for the above response?Providing labor: The responsibility for providing labor in the construction of an earthfill dam for irrigation will typically fall on the contractor or construction company that has been awarded the contract for the project. The contractor is usually responsible for hiring and managing all the necessary labor, including skilled and unskilled workers, to complete the construction of the dam.
Funding the construction of the dam: The responsibility for funding the construction of the earthfill dam will usually lie with the party or parties that have commissioned the project. In most cases, this will be a government agency or a private company that is investing in the construction of the dam.
Approving the drawings: The responsibility for approving the drawings for the earthfill dam will typically fall on the government agency or private company that is commissioning the project. The drawings will need to be approved by the relevant regulatory bodies and local authorities to ensure that the dam meets all the necessary safety and environmental standards.
Overall coordination of the project: The responsibility for the overall coordination of the project will usually fall on the project manager or project team that has been appointed by the commissioning party. The project manager will be responsible for overseeing all aspects of the project, including managing the budget, scheduling, and ensuring that the construction work is completed to the required standards.
Setting up coordinates and levels for back-filling: The responsibility for setting up the coordinates and levels for back-filling will typically fall on the engineering team that is responsible for the design and construction of the dam. The engineering team will be responsible for surveying the site and determining the best locations for the dam, as well as setting the appropriate coordinates and levels for the back-filling process.
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Answer:
project manager
Explanation:
3–109E A 0. 083-in-diameter electrical wire at 90°F is covered by 0. 02-in-thick plastic insulation (k = 0. 075 Btu/h·ft·°F). The wire is exposed to a medium at 50°F, with a combined convection and radiation heat transfer coefficient of 2. 5 Btu/h·ft2·°F. Determine if the plastic insulation on the wire will increase or decrease heat transfer from the wire. Answer: It helps
The heat transfer rate with insulation is significantly higher than the heat transfer rate without insulation, as can be shown by comparing the two heat transfer rates.
Which has the greatest rate of heat transfer?The table shows that solids (s) generally conduct heat at rates that are significantly higher than those of liquids (l) and gases (g).
The following equation can be used to determine the heat transfer rate without insulation under the conditions of steady-state heat transmission and little heat generation in the wire:
A = pidL A = pi0.0831 = 0.26 square inches. Q = hA(T wire - T inf).
Q = 2.50.26(90 - 50) = 26 Btu/h without insulation R = 0.02 / (0.075×0.26) = 0.98 hrft2°F/Btu
Copper, which is frequently used for electrical cables, has a thermal conductivity of roughly 223 Btu/hft°F. Inputting the values provided yields:
R total = 1 / (2230.26pi×0.0832 / 4) = 0.14 hours/feet/degrees Fahrenheit/Btu
We obtain the following by substituting the above values: q with insulation = (90 - 50) / 0.14 = 286 Btu/h
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What are the advantages of regenerative cycle over simple Rankine cycle?
The regenerative Rankine cycle has a number of advantages over the simple Rankine cycle, such as Higher thermal efficiency, Lower exhaust, and Smaller physical size, Shorter startup time.
Higher thermal efficiency as the steam is recycled back to the boiler, resulting in higher efficiency and better fuel economy. Lower exhaust steam pressure and temperature, making it more suitable for applications with lower temperature differences between the heat source and the sink. Shorter startup time as the turbine does not require as much steam to reach operating conditions. Smaller physical size, as the high pressure and temperature equipment, is not necessary.
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There are three car manufacturing factories A,B and C and they are producing the same type of cars.they are employing 1000,2000, and 3000 men and producing 10,15, and 25 cars per month respectively.find the labour productivity of each form and the production of each form per year
Answer:
A: 0.010 cars/man·month, 120 cars/year
B: 0.0075 cars/man·month, 180 cars/year
C: 0.0083 cars/man·month, 300 cars/year
Explanation:
You have factories A, B, C employing 1000, 2000, 3000 men and producing 10, 15, 25 cars per month. You want to know the productivity and annual production of each factory.
ProductivityProductivity is output per input. In this case, the input is measured in man·months. The output is measured in cars.
A: 10 cars/(1000 man·months) = 0.010 cars/man·month
B: 15 cars/(2000 man·months) = 0.0075 cars/man·month
C: 25 cars/(3000 man·months) ≈ 0.0083 cars/man·month
ProductionThe annual production rate is 12 times the monthly production rate, assuming each factory works 12 months per year.
A: 10 cars/mo · 12 mo/yr = 120 cars/yr
B: 15 cars/mo · 12 mo/yr = 180 cars/yr
C: 25 cars/mo · 12 mo/yr = 300 cars/yr
assume variables (a, b, c, and max) have been declared. in this code fragment of if and nested if statements, identify the error type as syntax or logic on each indicated code line. if(a > b) {
Here is the corrected code with comments explaining the changes made to address the syntax and logic errors:
if (a > b) {
max = a;
} else {
max = b; // max variable is now initialized or updated properly
}
if (a < 100) {
if (b < 100) {
System.out.printf("a and b are both greater than 100\n"); // corrected newline character inside double quotes
}
}
a = 1; // set a to a positive integer to avoid division by zero error
c = b / a;
if (a == b) { // use double equal signs to compare a with b
System.out.printf("a and b are equal\n");
}
// added closing curly brace for the outer if statement
The synthesis errors in the code fragment are:
Logic error: Max variable is not initialized or updated properly if a is not greater than b.Syntax error: curly brace is not closed for the inner if statement.Syntax error: missing closing curly brace for the outer if statement.Syntax error: newline character should be inside double quotes in the printf() statement.Logic error: division by zero will occur since a has been set to 0 before the calculation.Logic error: assignment should use double equal signs to compare a with b.Syntax error: missing closing curly brace for the outer if statement.Learn more about programming:
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Question complete:
Assume variables (a,b,c, and max) have been declared. In this code fragment of if and nested if statements, identify the error type as syntax or logic on each indicated code line.
if (a>b)
{
Max=a;//1
}
if(a<100)
{
if (b<100)
{
System.out.printf("gna and b are both greater than1008n"); // \}
}
a=0;
c=b/a;//
if (a=b)
{
System.out.printf("ona and b are equalzn");
a=a+1;