Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.
A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function of its horizontal position x.
Part A
Find the net work done on the box as it moves from x = 0 m to x = 8.0 m. .
Part B
Apply concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m. Assume the box started from rest.
From the graph, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
From the question, these are the given parameters;
Mass M = 5.5 KgPosition X = 0 to X = 8mPart A
The net work done will be the area under the graph.
From position X = 2m to X = 8m gives us the shape of a trapezium.
A = 1/2( a + b )h
A = 1/2( 2 + 6 ) x 8
A = 8 x 4
A = 32 Nm
From X = 0 to X = 2 gives us the shape of a triangle.
A = 1/2bh
A = 1/2 x 2 x (-4)
A = -4 x 1
A = -4 Nm
Net Work done = 32 - 4
Net work done = 28 Nm
Part B
Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m
Net Work done = 1/2m[tex]V^{2}[/tex]
Substitute all the necessary parameters
28 = 1/2 x 5.5 x [tex]V^{2}[/tex]
5.5[tex]V^{2}[/tex] = 56
[tex]V^{2}[/tex] = 56/5.5
[tex]V^{2}[/tex] = 10.18
V = [tex]\sqrt{10.1818}[/tex]
V = 3.19 m/s
Therefore, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
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Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation:
anything that has mass and occupies space is called
Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
Describe your acceleration if you ride your bike up a hill,then ride down the other side.
Answer:
first negative and then positve
Two forces that act on very small distances (smaller than you can see ) are
3. A(n)______ is someone who travels to new places or does new things. A. explorer B. thrill C. expedition D. research
Answer:
explorer
Explanation:
Answer:
a) EXPLORER
Explanation:
An explorer is someone who travels to new places or does new things.
Question:
The US Navy is developing a railgun that uses magnetic field repulsion. The railgun can propel a 981 N projectile at seven times the speed of sound. How much energy is stored in this magnetic field? Assume a complete conversion of energy and a speed of sound of 340 m/s.
Answer choices:
A. 119 MJ
B. 283 MJ
C. 578 MJ
D. 2780 MJ
The relation of the kinetic energy allows to find the correct result for the energy stored in the electromagnet is:
B) 283 MJ
Kinetic energy is the energy due to the movement of bodies.
K = ½ m v²
Where K is the kinetic energy, m is the mass and v the spped.
They indicate that the weight of the bodye is W = 981 N and its final velocity is v = 7 [tex]v_s[/tex].
W = m g
Since the projectile starts from rest, its initial velocity is zero, therefore the change in energy is
ΔK = [tex]K_f - K_o = K_f[/tex]
we substitute
ΔK = ½ 981 / 9.8 (7 340) ²
ΔK = 2.835 10⁸ J
They indicate that all the energy of the electromagnet is transformed into the energy of the projectile,
Em = K
When reviewing the results, the correct one is:
B) 283 MJ
In conclusion, using the relationship of kinetic energy we can find the correct result for the energy stored in the electromagnet is:
B) 283 MJ
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Grass, trees, shrubs, worms, birds, and deer that live in a certain area is known as what?
Answer:they live in grass land also called forests hope the answer helps
Explanation:
a body of mass 10 kg is moving with velocity of 10ms-1.a force acts for 5 seconds to reduce its velocity to 2ms-1.find the momentum of the body before and after application of the force on it
Answer:
momentum before: 100kgm/s
momentum after: 20kgm/s
Explanation:
initial velocity: 10
final velocity: 2
p=mv
before: 10kg×10m/s
after:10kg×2m/s
I'm not 100% sure btw
If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21
First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,
3x10^30. 5x10 to the 19 power
_______.
6x10^10
The answer is c
If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.
What is speed?Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit time . Thus, mathematically it is the ratio of distance to the time.
If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.
Here the spaceship travels 6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:
1 year - 6 × 10¹⁰ km
? - 3 × 10³⁰ km
Cross multiply them we get, 3 × 10³⁰ km/ 6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.
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bow long does it take earth to rotate once on its axis
Answer:
23 hours, 56 minutes
Can someone please give me the (Answers) to this? ... please ...
Explanation:
1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.
2. The reaction force is the force of arrow on bowstring.
3. Forward force of fish on water and vice versa?
4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.
5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.
6. The reaction force will also decreases as both forces are equal in magnitude.
7 im nt sure sorry Ahahah
A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.
Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.
S = I(fsd) / V(fsd).
S = 4.0 / 25
S = 0.16 mA/Ω
Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)
(S(new)) = 50 mA / V(fsd)
(S(new)) = 50 / 0.16
(S(new)) = 312.5 Ω
Add External Resistor:
Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter
(R(internal) = 25 Ω:
R(ext) = R(new) - R(internal)
R(ext) = 312.5 Ω - 25 Ω
R(ext) = 287.5 Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.
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What is number 10 for this?
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
A truck moves 60 kilometers east from point A to point B. At point B, It turns back west and stops 15 kllometers away from point A. What are the
total distance and total displacement of the truck?
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation:
what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
plssssss look at the picture i need it right hurry pls
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
Calculate the speed of light in a medium whose refractive index is 2.4
Answer:
Approximately [tex]1.3\times 10^{8}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the speed of light in vacuum: [tex]c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}[/tex]. Denote the speed as [tex]c[/tex].
If the speed of light in a medium is [tex]v[/tex], the refractive index of that medium would be:
[tex]\displaystyle n = \frac{c}{v}[/tex].
Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.
Rearrange this equation to find the speed of light [tex]v[/tex] in this medium:
[tex]\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}[/tex].
A 2 kg wagon is being pulled by a kid with a force of 0.1 N to the right. Determine the acceleration of the wagon
Answer:
0.2 m/s^2
Explanation:
a = fm
a = 2 x .1
a = 0.2 m/s^2
Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30
Answer:
here's your answer below
Explanation:
sorry something went wrong
.
why we use light-years in space verses other units of distance?
Answer:
The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.
Which form can solutions come in?
liquid
gas
solid
all of the above
Answer:
liquid
Explanation:
leave a thanks if helped !
plssss helppppppppppp i need it
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragster? Answer to the nearest hundredth
a boulder sitting on a 45 m tall cliff has a potential energy of 7,100 J. the acceleration due to gravity is 9.8 m/s^2. what is the mass of the boulder
The mass of the boulder is equal to 16.10 kilograms.
Given the following data:
Height of cliff = 45 mPotential energy = 7,100 JoulesAcceleration due to gravity = 9.8 [tex]m/s^2[/tex]To determine the mass of the boulder:
Mathematically, potential energy (P.E) is calculated by using the following formula:
[tex]P.E = mgh[/tex]
Where:
m is the mass of object. g is the acceleration due to gravity. h is the height of an object.Making m the subject of formula, we have:
[tex]m = \frac{P.E}{gh}[/tex]
Substituting the given parameters into the formula, we have;
[tex]m=\frac{7100}{9.8 \times 45} \\\\m=\frac{7100}{441}[/tex]
Mass, m = 16.10 kg
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A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.
The position on the meter mark where Ari catches up with Amanda is 19.3 m.
The given parameters:
Range of the number line, = 0 to 30Position of the closed circles, = 6 and 25The ratio between the initial position and final position of Ari = 7:3The distance between 6 m mark and 25 m mark is calculated as follows;
[tex]d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m[/tex]
The distance traveled by Ari before catching up with Amanda is calculated as follows;
total ratio = 7 + 3 = 10
[tex]distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m[/tex]
The position of Ari from the 6 m mark is calculated as follows;
[tex]position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m[/tex]
Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.
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Answer:
The above answer is correct! The answer is 19.3 meters :)
Explanation:
adding a ss for proof!
hope this helps :D
ii. Which of these has a heating element with a low melting point?
a, electric bell
c. electric iron
b. fuse
d. all of these
what depth would a submarine have to submerge so that it would not be swayed by surface waves wwith a wavelength of 30 meters
Answer:
Explanation:
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The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Which law was used to determine the relationship between the volume and the number of moles in this equation? Boyle’s law Charles’s law Avogadro’s law Gay-Lussac’s law.
The relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
Avogadro's law:
It states that at constant temperature and pressure, gases with same volume has the same number of molecules.
For an ideal gas with with constant temperature and pressure, the volume of the gas is directly proportional to the amount or number of molecules.
Charle's law states that at constant pressure, volume (V) and temperature (T) are directly proportional.Boyle's law states that at constant temperature, the volume of gas is inversely proportional to the gas pressure.Gay-Lussac's law states that pressure (P) and absolute temperature (T) of the gas are directly proportional.Therefore, the relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
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Answer:
Avogadro's law
Explanation:
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
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