The temperature of the xenon gas in the balloon is approximately 276 K.
We can use the Ideal Gas Law to solve for the moles of xenon gas present in the balloon:
PV = nRT
where P is pressure, V is volume, n is number of moles, R is gas constant, and T will be the temperature in Kelvin.
Converting the given values to the correct units:
P = 954 Torr = 954/760 atm
= 1.2553 atm
V = 2.37 L
n = 0.115 mol (given)
R = 0.08206 L·atm/mol·K (gas constant)
T = ? (unknown)
Substituting the values and solving for T:
T = PV/nR = (1.2553 atm)(2.37 L)/(0.115 mol)(0.08206 L·atm/mol·K)
≈ 276 K
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How many moles are there in 5.6x1015 particles of hydrogen peroxide?
Answer:
0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex]
Explanation:
[tex]OH^-[/tex]: 5.6 x 10^(15) (brainly doesn't allow exponents greater than 9)
This number of particles can also be represented as 5.6e15.
'e' in this case means 'times 10 to the n' where n is the number that follows e.
Use stoichiometry to convert between different units.
[tex]\frac{5.6e15 particles}{1 sample} *\frac{1 mole}{6.022 e22 particles}= 0.9299 e -7 moles[/tex]
So in that sample of particles, there are 0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex].
How many grams of NH3
form when 22.3 L
of H2(g)
(measured at STP) reacts with N2
to form NH3
according to this reaction?
N2(g)+3H2(g)→2NH3(g)
Answer:
11.2823 grams of NH3 are produced
Explanation:
No. of moles for H2 = 22.3/22.4 = 0.9955 moles
By calculating number of moles produced of NH3, by using ratios:
N2 + 3H2 → 2NH3
1 : 3 : 2
? : 0.9955: ?
part value = 0.9955/3 = 0.33183
No. of moles for NH3 = 2 * 0.33183 = 0.6637 moles
mass of produced NH3 (Molar mass = 17 g/mol) = 0.6637*17 = 11.2823 grams
I am mixing vinegar and baking soda in a bottle. If I want to be sure that Conservation of Mass is followed, what should I make sure to do?
Law of conservation of mass was crucial to progression of chemistry, as it helped scientists understand that substances did not disappear as result of reaction.
What is conservation of mass?Law of conservation of mass explains that in chemical reaction mass is neither created nor destroyed.
To ensure Conservation of Mass is followed when mixing vinegar and baking soda in a bottle, you should make sure to do the following:
Weigh the bottle and its contents before adding vinegar and baking soda. This will give the initial mass of system.
Carefully measure the amounts of vinegar and baking soda you add to bottle.
Quickly and securely cap the bottle after adding baking soda to avoid any gas from escaping.
Weigh the bottle and its contents again after reaction has completed and the gas has stopped escaping. This will give the final mass of the system.
Compare the initial and final masses of system. They should be equal within experimental error.
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Two elements, and , combine to form two binary compounds. In the first compound, 23. 3 g of combines with 3. 00 g of. In the second compound, 7. 00 g of combines with 4. 50 g of. Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is , what is the formula of the first compound?
Compound I:
The formula for the first Compound I is likely A2B, or O2N.
To show that the data are in accordance with the law of multiple proportions, we need to calculate the ratios of the masses of element B that combine with a fixed mass of element A in each compound. If these ratios are in simple whole-number ratios, then the law of multiple proportions is upheld.
For Compound I:
Mass of A (23.3 g) / Mass of B (3.00 g) = 7.77
For Compound II:
Mass of A (7.00 g) / Mass of B (4.50 g) = 1.56
These ratios are not equal, indicating that the two compounds have different ratios of A and B. However, we can simplify the ratio for Compound II by dividing both masses by the mass of B:
Mass of A (7.00 g / 4.50 g) = 1.56
This suggests that Compound II has a 2:3 ratio of A to B.
Using this information, we can determine the formula of Compound II. Let x be the atomic mass of A and y be the atomic mass of B:
(2x) + (3y) = 4.50 g
Solving for y gives us y = 1.00 g/mol. Since the formula of Compound II is AB2, we know that the atomic mass of A is 2 g/mol. Therefore, A is likely oxygen (atomic mass 16 g/mol).
For Compound I, we know that A is oxygen (atomic mass 16 g/mol). Using the same approach as above, we can determine that B has an atomic mass of 14 g/mol. Therefore, the formula for Compound I is likely A2B, or O2N.
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To earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units.
In 2013, there were 2.6 x 106 people living in Paris. If 7.34 x 104 babies were born what was the crude birth rate?
The birth rate is 28.2 births per year
What is the birth rate?The number of births per 1,000 persons in a particular population over a given time period is commonly used to determine the birth rate.
The following is the formula that can be used to calculate the birth rate:
(Number of births / Population) x 1,000 is the birth rate.
The birth rate can be obtained from;
Birth rate = (Number of births / Population) x 1,000
We know that the birth rate can be obtained from;
7.34 x 10^4 / 2.6 x 10^6 * 1000
= 28.2 births per year
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How many molecules are contained in
1357 mL of O2 gas at −14◦C and 1437 torr?
Answer in units of molec.
There are approximately 6.031 x 10^23 molecules of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr.
we can use the ideal gas law:
PV = nRT
where, P = pressure of the gas in torr,
V = volume of the gas in liters,
n = number of moles of gas,
R = ideal gas constant (0.08206 L·atm/mol·K),
T = temperature of the gas in Kelvin.
the volume of the gas from milliliters (mL) to liters (L):
V = 1357 mL / 1000 mL/L
V = 1.357 L
Now to convert the temperature of the gas from Celsius (°C) to Kelvin (K):
T = -14°C + 273.15
T = 259.15 K
Substituting the given values:
(1437 torr) (1.357 L) = n (0.08206 L·atm/mol·K) (259.15 K)
n = (1437 torr x 1.357 L) / (0.08206 L·atm/mol·K x 259.15 K)
n = 1.0008 mol
the number of moles of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr is 1.0008 mol. To find the number of molecules,
we can use Avogadro's number:
1 mol of O2 gas contains 6.022 x 10^23 molecules
So, the number of molecules in 1.0008 mol of O2 gas is:
(1.0008 mol) x (6.022 x 10^23 molecules/mol) = 6.031 x 10^23 molecules
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When an antacid tablet dissolves in water, the fizz is due to a reaction between sodium hydrogen carbonate (sodium bicarbonate, NaHCO3) and citric acid (H₂CH₂O7).
3 NaHCO3(aq) + H₂C6H₂O7(aq) →3 CO₂(g) + 3 H₂O(l) + Na3CH₂O₂(aq)
How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved?
Therefore, 0.00723 moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved.
What is balanced chemical reaction?The balanced chemical equation shows that 3 moles of NaHCO3 react with 1 mole of H2C6H6O7 to produce 1 mole of Na3C6H5O7. Therefore, the number of moles of Na3C6H5O7 produced is directly proportional to the number of moles of NaHCO3.
If one tablet containing 0.0217 mol of NaHCO3 is dissolved, then according to the balanced chemical equation, the number of moles of Na3C6H5O7 produced is:
(0.0217 mol NaHCO3) x (1 mol Na3C6H5O7 / 3 mol NaHCO3) = 0.00723 mol Na3C6H5O7
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An aerosol deodorant can has a pressure of 3.00 atm at 25 °C. What is the pressure inside the can at a temperature of 845 °C? This example illustrates why you shouldn’t incinerate aerosol cans.
The pressure inside the aerosol can at 845°C is 33.8 atm. This is why it is extremely dangerous to incinerate aerosol cans, as they can explode when exposed to high temperatures.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature.
We are given the following:
Initial pressure P1 = 3.00 atm
Initial temperature T1 = 25°C = 298 K
We need to find the final pressure P2 at T2 = 845°C = 1118 K.
Since the can is sealed, volumes V1 and V2 remain the same.
Plugging these values into the combined gas law, we get:
(P1 x V1) / T1 = (P2 x V2) / T2
(3.00 atm x V1) / 298 K = (P2 x V1) / 1118 K
Simplifying this equation, we get the following:
P2 = (3.00 atm x V1 x 1118 K) / (298 K x V1)
P2 = 33.8 atm
Therefore, the pressure inside the aerosol can at 845°C is 33.8 atm, which is significantly higher than at room temperature. This demonstrates why it is extremely dangerous to incinerate aerosol cans, as they can explode when exposed to high temperatures.
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how can enzymes speed up chemical reactions? a.they raise the activation energy needed for the reaction. b.they increase the ph of the reaction. c.they increase the amount of substrate in the reaction. d.they lower the activation energy needed for the reaction.
Enzymes speed up chemical reactions by lowering the activation energy needed for the reaction. The correct option is d.
Enzymes are biological molecules, typically proteins, that act as catalysts for chemical reactions. Catalysts are substances that can speed up a chemical reaction without being consumed in the process.
Enzymes work by lowering the activation energy needed for a chemical reaction to occur. Activation energy is the energy required to break the bonds of the reactants and initiate the chemical reaction. By lowering the activation energy, enzymes make it easier for reactants to come together and form products.
Enzymes achieve this by binding to the reactants, or substrates, and bringing them into close proximity to each other. This allows the substrates to interact more easily and lowers the energy barrier for the reaction to occur. Enzymes also stabilize the transition state of the reaction, further reducing the activation energy needed for the reaction to proceed.
Therefore, the correct answer is d) they lower the activation energy needed for the reaction.
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6) What is the vapor pressure of water at 100°C?
Answer: The vapor pressure of pure water at 100°C is 760mm of Hg.
Explanation: We know tat 100 degree Celsius the water will convert into gas phase. At boiling point the vapor pressure of any liquid is 1 atmosphere and if we boil the water at 100° Celsius it means 1 atmosphere . So, 1 atmosphere = 760mm of Hg.
How many g of water are needed to create a 4 molal solution with 9 moles of NaOH?
The grams of water needed to create a 4 molal solution with 9 moles of NaOH is 2250 grams.
How to calculate grams of water?Molality is defined as moles of solute per kilogram of solvent. Changing the values of moles and molality in the equation will provide the kg of solvent. 4=9/kg of solvent2.25 kilograms per kilogram of solventThe term "total moles of a solute contained in a kilogram of a solvent" is used to define molality. Molality is often referred to as molal concentration. It gauges the amount of solutes in a solution. Solute and solvent are the two parts that make up the solution. which is equivalent to 2250 grams of water.Molality, often known as molal concentration, is the product of the solute's mass and the solvent's mass: Molality = nsolute / msolvent = msolute / (Wsolute msolvent), where: nsolute is the quantity of the solute (in moles)For more information on molality kindly visit to
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What do the red-colored blocks indicate?
The red-colored blocks indicate non metals in the periodic table. Nonmetals are located on the right side of the periodic table, in the p-block.
Non-metals are composed of a variety of elements, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium. These elements are generally non-reactive, but some of them can form compounds with other elements. They are also used in various industries, such as the production of plastics, fertilizers, and explosives. Non-metals are divided into two categories: metalloids and non-metalloids. Nonmetals are characterized by their lack of luster and their low thermal conductivity.
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what does the NaBr + CI2 in the reaction?
NaBr + CI2 -> NaCI + Br2
A. Reactants
B. States of matter
C. Products
D. Yields
Answer:- NaBr and Cl2 are reactants .
The atoms/molecules/ions on RHS of the reaction which react to give products are called reactants.
So here Sodium bromide and chlorine are the reactants.
Option A is the correct choice.
Additional information:-
Law of conservation of Mass :-
According to this law , the mass of reactants is equal to the mass of the products . Take a chemical reaction ,
C + O2 ==> CO2
Now suppose that if 12g of carbon reacts with 16g of oxygen to form carbon dioxide, then what will be the mass of carbon dioxide? So by law of conservation of Mass we can say that mass of carbon dioxide will be equal to mass of the reactants that will be 12g + 16g = 28g
With this I am leaving a sample problem for you to solve,
Question: Consider the following reaction .
2C + O2 ==> 2CO
If the mass of carbon taken is 24g and the amount of carbon monoxide formed is 56g , find the amount of oxygen used in the reaction.
Answer:D. Yields
Explanation:
what is the mass of 29.3 L of carbon monoxide at STP?
hey guys.. show. work.. i have no idea whats going on
Answer:
33.67g
Explanation:
To calculate the mass of carbon monoxide, we can use the ideal gas law, which relates the pressure, volume, number of moles, and temperature of a gas:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 273.15 K. The ideal gas constant is R = 0.08206 L atm/(mol K).
To find the number of moles of carbon monoxide in 29.3 L at STP, we can rearrange the ideal gas law to solve for n:
n = PV/(RT)
n = (1 atm)(29.3 L)/(0.08206 L atm/(mol K) * 273.15 K)
n = 1.203 mol
The molar mass of carbon monoxide (CO) is 28.01 g/mol. Therefore, the mass of 1.203 mol of CO is:
mass = n * molar mass
mass = 1.203 mol * 28.01 g/mol
mass = 33.67 g
Therefore, the mass of 29.3 L of carbon monoxide at STP is approximately 33.67 grams.
If a 100.0g sample of water at 27.8 degrees Celsius is added to a 100.0g sample of water at 73.7 degrees Celsius determine the final temperature of the water assume no heat is lost to the surroundings
The final temperature of the water is 32.3°C.
If 500.0 g of water at 80.0°C is mixed with 300.0 g of water at 20.0°C, what is the final temperature of the mixture assuming no heat is lost to the surroundings?The final temperature of the mixture is 53.3°C.
How much heat is lost by a 50.0 g piece of copper initially at 200.0°C when it is placed in 100.0 g of water initially at 25.0°C? The final temperature of the copper and water is 50.0°C.The heat lost by the copper is 4.19 kJ.
To determine the final temperature of the water, we can use the principle of conservation of energy. The total heat gained by the cooler water is equal to the total heat lost by the hotter water. The heat gained or lost by a substance can be calculated using the formula:
Q = mcΔT
where Q is the heat gained or lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Let's assume that the final temperature of the water is T. Then, the heat lost by the hotter water is:
Q1 = mcΔT = (100.0 g) x (4.184 J/g°C) x (73.7°C - T)
The heat gained by the cooler water is:
Q2 = mcΔT = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)
Since the total heat gained is equal to the total heat lost, we can equate Q1 and Q2:
(100.0 g) x (4.184 J/g°C) x (73.7°C - T) = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)
Simplifying the equation:
3134.4 - 41.84T = 418.4T - 11702.72
459.24T = 14837.12
T = 32.3°C
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The particles in.......... can be separated from
heterogeneous mixtures by passing the mixture through a filter.
-suspension
-solution
-colloid
-pure substance
The particles in suspension can be separated from heterogenous mixtures by passing the mixture through a filter. Option 1.
Particles in a suspensionThe particles in suspension can be separated from heterogeneous mixtures by passing the mixture through a filter.
A suspension is a heterogeneous mixture in which the particles are large enough to settle out over time and can be separated by physical means such as filtration.
Other options such as solution, colloid, and pure substances cannot be separated using a filter.
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HELP MEEE I will give good stuff hahahahhaha, okay help
Answer: Its the bottom one
Name the following formula: BF2 (hint: treat boron like a nonmetal)
A. Boron fluoride
B. Monoboron difluoride
C. Boron difluoride
D. Boron (II) fluoride
E. Best Friends Forever
The name of the formula BF2 is : C.) Boron difluoride. The number of atoms of each element in a compound is known by chemical formula.
What is meant by chemical formula?Chemical formula is an expression that shows elements in a compound and relative proportions of those elements. If only one atom of specific type is present, then no subscript is used. For atoms that have two or more of a specific type of atom present, then a subscript is written after the symbol for that atom.
Chemical formula contains the symbols of atoms of the elements present in the compound and also how many there are for each element in the form of subscripts.
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if a given amount of gas has a pressure of 787.0mmHg and a volume of 970.0mL what would its final volume be at 897.0mmHg and keeping the temperature constant
Final volume of the gas would be 850.5 mL when the pressure is increased from 787.0 mmHg to 897.0 mmHg while keeping the temperature constant.
What is Boyle's law?Boyle's Law explains that when temperature of given mass of confined gas is constant, then the product of its pressure and volume is also constant.
Given, P1 = 787.0 mmHg ; V1 = 970.0 mL; P2 = 897.0 mmHg
V2 = ?
As P1V1 = P2V2
V2 = P1V1/ P2
V2 = (787.0 mmHg x 970.0 mL) / 897.0 mmHg
V2 = 850.5 mL
Therefore, the final volume of the gas would be 850.5 mL when the pressure is increased from 787.0 mmHg to 897.0 mmHg while keeping the temperature constant.
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which process could result in the net movement of a substance into a cell, if the substance is more concentrated in the cell than in the surroundings? group of answer choices
The process that could result in the net movement of a substance into a cell, if the substance is more concentrated in the cell than in the surroundings is called osmosis.
Osmosis is a passive transport process where water molecules move from an area of high concentration to an area of low concentration through a selectively permeable membrane. In this process, a solute moves from a region of high concentration to a region of low concentration. A selectively permeable membrane is a type of biological membrane that allows certain molecules or ions to pass through it by diffusion and occasionally specialized "facilitated diffusion" and passive or active transport processes, while preventing other molecules or ions from passing through it. Therefore, the correct answer is the option C - Osmosis.
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What is the percent composition of MgSO4 in a solution if 18.6 grams MgSO4 is dissolved in 229 g water ?
Percent of water of crystallisation in MgSO4⋅7H2O=2467×18×100=51. 2 %.
How can you tell what proportion of the composition is water?Divide by 100 the mass of the hydrate and the volume of water lost. The amount of water in one mole of the hydrate must be multiplied by 100 after being divided by the hydrate's molar mass in order to determine the theoretical (actual) percent hydration (percent water) using the formula.
Hence, this ratio might be represented by one magnesium sulfate formula unit to seven water molecules. Since MgSO47H2O is the chemical formula for magnesium sulfate hydrate, the value of x must be seven. The value of x in the chemical formula for magnesium sulfate hydrate is thus seven.
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Zinc hydroxide, Zn(OH)2, is precipitated from the tailings ponds of zinc mining operations before the water is released into local rivers. This reduces the concentration of Zn2+ ions in the wastewater. 5.00 kg of sludge containing zinc hydroxide is titrated against HCl solution and 1.50 L of 2.0 M acid is required to reach the endpoint and neutralize the zinc hydroxide. What mass of zinc is contained in the 5.00 kg sludge?
Answer:
First, we need to find the number of moles of HCl used in the titration:
moles HCl = M x V = 2.0 mol/L x 1.50 L = 3.00 mol
Since zinc hydroxide and HCl react in a 1:2 molar ratio according to the balanced chemical equation:
Zn(OH)2 + 2 HCl → ZnCl2 + 2 H2O
we know that twice as many moles of HCl are required to react with each mole of Zn(OH)2. Therefore, the number of moles of zinc hydroxide in the 5.00 kg sludge can be calculated as follows:
moles Zn(OH)2 = 1/2 x moles HCl = 1/2 x 3.00 mol = 1.50 mol
Finally, we can use the molar mass of Zn(OH)2 to convert the number of moles to mass:
mass Zn(OH)2 = moles Zn(OH)2 x molar mass Zn(OH)2
= 1.50 mol x 99.39 g/mol
= 149.1 g
Therefore, the mass of zinc contained in the 5.00 kg sludge is 149.1 grams.
Explanation:
Please help and write full solution
The pH of the solution is 1.8. Option C is the right answer
How The answer was obtainedFirst, we need to calculate the moles of LiOH and HNO3:
Moles of LiOH = 0.1 mol/L × 0.025 L = 0.0025 mol
Moles of HNO3 = 0.1 mol/L × 0.035 L = 0.0035 mol
Next, we need to determine which of the reactants will be limiting. LiOH and HNO3 react in a 1:1 stoichiometric ratio, so whichever reactant is present in the smaller amount will be limiting. In this case, LiOH is limiting because it has fewer moles than HNO3.
The balanced chemical equation for the reaction between LiOH and HNO3 is:
LiOH + HNO3 → LiNO3 + H2O
Since LiOH is limiting, all of it will react with HNO3. This means that all of the moles of HNO3 will be consumed, and there will be some excess LiOH remaining.
Moles of LiOH remaining = Moles of LiOH - Moles of HNO3 = 0.0025 mol - 0.0035 mol = -0.0010 mol
Note that the result is negative, which means that all of the HNO3 has been consumed, and there is still some LiOH remaining.
The concentration of LiOH in the final solution is:
[LiOH] = Moles of LiOH remaining / Total volume of solution = -0.0010 mol / (0.025 L + 0.035 L) = -0.010 mol/L
Again, the result is negative, which is not physically meaningful. This indicates that our assumption that LiOH is limiting is incorrect.
To correct this, we can assume that HNO3 is limiting and repeat the calculations. In this case, all of the HNO3 will react with LiOH, and there will be some excess HNO3 remaining.
Moles of HNO3 remaining = Moles of HNO3 - Moles of LiOH = 0.0035 mol - 0.0025 mol = 0.0010 mol
The concentration of HNO3 in the final solution is:
[HNO3] = Moles of HNO3 remaining / Total volume of solution = 0.0010 mol / (0.025 L + 0.035 L) = 0.01 mol/L
The balanced chemical equation for the reaction between HNO3 and LiOH is:
HNO3 + LiOH → LiNO3 + H2O
The stoichiometry of this reaction tells us that one mole of HNO3 reacts with one mole of LiOH to produce one mole of water. Therefore, the moles of water produced in the reaction are equal to the moles of HNO3 remaining:
Moles of water = 0.0010 mol
The volume of the final solution is:
Volume = 0.025 L + 0.035 L = 0.06 L
The molarity of the water in the final solution is:
Molarity of water = Moles of water / Volume of solution = 0.0010 mol / 0.06 L = 0.0167 mol/L
The pH of water is 7.0, and the pH of a solution is related to the concentration of H+ ions in the solution. Since water is neutral and does not contribute any H+ ions, the pH of the final solution is:
pH = 7.0 - log[H+] = 7.0 - log(0.0167) ≈ 1.8
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Determine the pH of the solution when 25ml of 0.1mLiOH is added to 35ml of 0.1m nitric acid
(A) 0.23
(B) 0.47
(C) 1.8
(D) 7.0
Find the volume in liters of a 1. 80 m solution of potassium chloride is required to prepare
0. 100 l of a 0. 600 m solution
the volume of a 1.80 M solution of potassium chloride that is required to prepare 0.100 L of a 0.600 M solution is 0.0333 L, or 33.3 mL.
To determine the volume of a 1.80 M solution of potassium chloride that is required to prepare 0.100 L of a 0.600 M solution, we can use the formula:
M1V1 = M2V2
where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
Let's use this formula to solve the problem:
M1 = 1.80 M (since we are starting with a 1.80 M solution)
V1 = ? (what we are trying to find)
M2 = 0.600 M (since we want to prepare a 0.600 M solution)
V2 = 0.100 L (since we want to prepare 0.100 L of the final solution)
Substituting these values into the formula, we get:
1.80 M x V1 = 0.600 M x 0.100 L
Simplifying, we get:
V1 = (0.600 M x 0.100 L) / 1.80 M
V1 = 0.0333 L, or 33.3 mL
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At the carnival, a baby was given a helium balloon whose pressure equaled the
atmospheric pressure at the carnival which was 102. 7 kPa. However, the baby wasn't
paying attention and the balloon floated away into the troposphere where the
atmospheric pressure is 97. 8 kPa. What is the positive difference between the
pressure in the balloon and the pressure of the troposphere in atm?
atm
The positive difference between the
pressure in the balloon and the pressure of the troposphere is 0.048 kPa .
The balloon is being compressed by atmospheric force. The balloon is trying to inflate owing to gas pressure. The atmospheric pressure (outside pressure) in a fully inflated balloon is lower than the internal gas pressure.
An inflated balloon has a higher internal pressure than its surrounding air. Because the contracting force produced by the rubber's surface tension balances the expanding force caused by the pressure differential, the balloon remains stable.
Because to the air pressure on the walls, a balloon's surface feels tighter when it is inflated. The internal air pressure gives the balloon its shape. The balloon will therefore be more pressurized after being inflated.
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Is the pattern of atomic radius absolute or general (always true or generally true)?
Answer:
Generally true.
Explanation:
As you go down the columns of the Periodic Table, the radius of the atom increases.
As you go across the Periodic Table (left to right), the radius of the atoms decrease.
Therefore, the second element on the table, Helium, has the smallest radius and element 87, Francium has the largest radius.
There are a few exception scattered throughout the table, such as the lanthanides and actinides, but generally speaking the radius increases as you travel from right to left and top to bottom.
Show how to carry out the following transformation in the highest yield possible. Select the appropriate reagents and/or draw the correct organic product at each step. Use an expanded octet on sulfur to minimize formal charges
Factors that make the higher yield of crop possible are as follows: enough water for irrigation. access of organic manure of high quality . Fertilizers are a factor in the higher yields of high-cost farming.
Fertilizer is used to ensure good vegetative growth (leaves, branches and flowers), giving rise to healthy plants. They are artificially made but have a rapid response. Overuse of fertilisers can cause negative effects like loose soil fertility. There's a risk with any bond that the issuing company might not be able to meet its obligations.
However, the risks of default are typically higher for companies that issue high-yield bonds. Interest rate . If the octet is expanded with preferred number of bonds, formal charge = 0. The S-atom will gain two electrons in order to complete its octet.
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an impure sample of table salt that weighed 0.8421 g when dissolved in water and treated with excess agno3 formed 2.044 g of agcl. what percentage of nacl is in the impure sample?
The percentage of NaCl in the impure sample is 76.25%.
The given weight of an impure sample of table salt is 0.8421 g, and the weight of AgCl formed is 2.044 g. The percentage of NaCl in the impure sample can be determined as follows:
Calculations: Gram molecular weight of NaCl = 23 + 35.5 = 58.5 g
Number of moles of AgCl = weight of AgCl / gram molecular weight of AgCl= 2.044 / 143.5 = 0.0142 mol
The equation of the reaction between NaCl and AgNO3 is given as follows:
NaCl + AgNO3 → NaNO3 + AgCl
It can be seen from the above equation that 1 mole of NaCl gives 1 mole of AgCl.So, the number of moles of NaCl present in the sample is 0.0142 mol.
Percentage of NaCl in the sample = number of moles of NaCl present in the sample / number of moles of the impure sample × molar mass of NaCl × 100= (0.0142 / (0.8421 / 58.5)) × 100= 76.25%
Therefore, the percentage of NaCl in the impure sample is 76.25%.
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(d) If 48.0 g of NaCl react with 19.0 g of H₂SO4, what mass of Na2SO4 will be produced?
Answer:
the mass of Na2SO4 produced is 27.6 g.
Explanation:
determine the balanced chemical equation for the reaction between NaCl and H₂SO4, and then use stoichiometry to calculate the mass of Na2SO4 produced.
The balanced chemical equation for the reaction is:
2 NaCl + H₂SO4 → Na2SO4 + 2 HCl
This equation tells us that 2 moles of NaCl react with 1 mole of H₂SO4 to produce 1 mole of Na2SO4.
First, we need to determine the number of moles of NaCl and H₂SO4 we have:
moles of NaCl = mass / molar mass = 48.0 g / 58.44 g/mol = 0.821 mol
moles of H₂SO4 = mass / molar mass = 19.0 g / 98.08 g/mol = 0.194 mol
Since H₂SO4 is the limiting reactant (it is present in less amount than required for complete reaction), we need to use the number of moles of H₂SO4 to calculate the number of moles of Na2SO4 produced:
moles of Na2SO4 = moles of H₂SO4 / 1 x (1 mole Na2SO4 / 1 mole H₂SO4) = 0.194 mol x (1/1) = 0.194 mol
Finally, we can use the molar mass of Na2SO4 to calculate the mass of Na2SO4 produced:
mass of Na2SO4 = moles of Na2SO4 x molar mass = 0.194 mol x 142.04 g/mol = 27.6 g
Therefore, the mass of Na2SO4 produced is 27.6 g.
is the diamond cubic structure close-packed? explain your rationale. note: a close-packed structure is one where you can find a plane of atoms in that structure where all the atoms touch. for example, fcc and hcp are close- packed structures.
Yes, the diamond cubic structure is close-packed. In a close-packed structure, you can find a plane of atoms where all the atoms touch. To understand why the diamond cubic structure is close-packed, follow these steps:
1. Identify the structure: The diamond cubic structure consists of two interpenetrating face-centered cubics (fcc) lattices with a relative shift of 1/4 along the space diagonal.
2. Locate the planes: In the diamond cubic structure, there are several planes where atoms touch each other, forming a hexagonal close-packed (hcp) arrangement. For instance, the (111) plane in one of the fcc sublattices is close-packed.
3. Examine neighboring atoms: In these close-packed planes, the atoms are arranged so that each atom touches its neighboring atoms. This close arrangement of atoms maximizes the packing efficiency.
So, based on the presence of close-packed planes and the neighboring atoms touching each other, the diamond cubic structure is considered a close-packed structure.
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