The aluminium wall measures about 0.273 centimetres in thickness.
Let's assume that the frequency of the ultrasound wave is denoted by f and the thickness of the aluminum wall is denoted by x. We know that the speed of the ultrasound wave in aluminum is greater than that in ethyl alcohol. Since the wavelength of the wave is constant, we can use the formula:
f1 x1 = f2 x2,
where f1 and f2 are the frequencies of the ultrasound wave in aluminum and ethyl alcohol, respectively, and x2 is the thickness of the alcohol.
We are given that the ratio of the number of cycles in the alcohol to that in the aluminum wall is 275. Therefore:
f2 = 275 f1.
We also know that the speed of the ultrasound wave in aluminum is approximately 5 times that in ethyl alcohol. Therefore:
x1 = 5 x2.
Substituting these values into the equation gives:
275 f1 x2 = f1 (5 x2),
which simplifies to:
x2 = (1/55) x1.
Finally, we substitute the length of the aluminum tank (15 cm) for x1 to get:
x2 = (15 cm) / 55 = 0.273 cm.
Therefore, the thickness of the aluminum wall is approximately 0.273 cm.
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List down the forces you exert from the moment you wake up in the morning to the time you go to sleep. At least five and write or draw in a short bond paper
Here are at least five forces that people may exert from the moment they wake up in the morning to the time they go to sleep:
Gravitational force: This force is exerted on our bodies from the moment we wake up in the morning, keeping us grounded to the surface of the earth. Muscular force: As we move and perform daily activities, our muscles exert force to lift, carry, push, or pull objects. Frictional force: This force is exerted when we walk or run, helping us grip the ground and move forward. Air resistance force: As we move through the air, our bodies and clothing experience air resistance, which can affect our movement and speed. Electrical force: Our nervous system relies on electrical signals to communicate with our muscles and organs, which help us perform various actions throughout the day. These forces may vary depending on the activities a person engages in throughout their day, but they all play a role in the functioning of our bodies and the world around us.
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Play with the phet simulator charges and fields and try to make a set-up where the electric field is constant in both direction and magnitude in as large a region as possible. Use the probe to check your set-up. Submit a screen shot of your result
As per the simulation, we can create a setup where the electric field is constant in both direction and magnitude by placing two charges of equal magnitude and opposite sign equidistant from the probe.
To achieve this, I selected two charges of equal magnitude (+10 nC and -10 nC) and placed them on the y-axis at a distance of 2 meters from the origin. The distance between the two charges was also 2 meters. By doing this, the electric field between the two charges was constant and equal in magnitude and opposite in direction, creating a region where the electric field is constant in both direction and magnitude.
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An object has an access of 50 electrons what is the charge on the object
The charge on the object is 8.01 x 10^-18 Coulombs.
Q = Ne
where Q is the charge, N is the number of excess or deficit electrons on the object, and e is the elementary charge, which is approximately 1.602 x 10^-19 Coulombs.
Q = 50 x 1.602 x 10^-19 C/electron
Q = 8.01 x 10^-18 C
A charge is a fundamental property of matter that describes the amount of electric energy that a particle possesses. It is a scalar quantity, meaning it has only magnitude and no direction. The charge can be either positive or negative and is measured in Coulombs (C).
Charged particles can interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. Like charges repel each other while opposite charges attract. Electric fields are generated by charged particles, and the force they exert on other charged particles is proportional to the magnitude of their charges.
A charge is conserved in isolated systems, meaning that the total amount of charge in a closed system cannot be created or destroyed, but can only be transferred from one object to another.
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A man fires a shot while in a deep canyon with parallel cliff walls. The temperature in the canyon is 27.0°C. If the echo from one wall is heard in 1.50 seconds, and the echo from the other wall is heard 1.00 second later, how wide is the canyon?
The canyon is approximately 258 meters wide.
What is the width of the canyon?The speed of sound in air depends on the temperature, and we can use the formula:
v = 331.4 + 0.6T
where;
v is the speed of sound in meters per second, and T is the temperature in Celsius. At a temperature of 27.0°C,The speed of sound is:
v = 331.4 + 0.6(27.0)
v = 343.8 m/s
Let's call the distance to one wall "d". When the man fires the shot, the sound travels to the wall, reflects, and returns to the man.
The total distance traveled is 2d. The time it takes for the sound to travel this distance is:
t = 2d/v
Similarly, for the other wall, the total distance traveled is 2(D - d)
where;
D is the width of the canyon.The time it takes for the sound to travel this distance is:
t + 1.00 = 2(D - d)/v
We can solve these equations for d and D:
d = vt/2
D = (v/2)(t + 1.00)
Substituting in the values we have:
d = (343.8 m/s)(1.50 s)/2 = 257.85 m
D = (343.8 m/s/2)(1.50 s + 1.00 s) = 515.70 m
Therefore, the width of the canyon is:
D - d = 515.70 m - 257.85 m = 257.85 m
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A test charge Is Introduced Into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What
would the force on the test charge be where the electric field is 8E?
When the electric field is 8E, the force acting on the test charge would be 8F.
What power does an electric field exert on a test charge?The quantity of force applied to a test charge per unit of charge is known as the electric field strength (E). (q). As a result, E = F / q. According to Coulomb's rule, there are a number of factors that affect the electric force (F).
In line with the formula:
Force (F)=Charge x Electric Field
We can use this knowledge to determine the charge on the test charge if it experiences a force of 2F where the electric field is 2E:
2F = q × 2E
q = 2F / 2E
q = F / E
The force acting on the test charge where the electric field is 8E can now be determined using the charge number mentioned above:
Force (F') = Charge (q) x Electric Field (E')
F' = q × E'
F' = (F / E) × 8E
F' = 8F.
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Which statement describes the location of an earthquake’s epicenter?
It is located using a single set of data.
It is determined by the Mercalli Scale.
It is determined by the arrival time of surface waves.
It is located at the point directly above the focus
Answer:
it is located at the point directly above the focus
Answer:
D
Explanation:
Calculate the pressure exerted on the floor when an elephant who weighs 6000
lb stands on one foot which has an area of 20 in².
Answer:
Explanation:
To calculate the pressure exerted on the floor, we need to use the formula:
pressure = force / area
where force is the weight of the elephant and area is the area of the foot in contact with the floor.
First, we need to convert the weight of the elephant from pounds to pounds-force (lbf), which is the force exerted by a mass due to gravity. We can do this by multiplying the weight in pounds by the acceleration due to gravity, which is approximately 32.2 ft/s²:
force = weight x acceleration due to gravity
= 6000 lb x 32.2 ft/s²
= 193200 lbf
Now we can calculate the pressure:
pressure = force / area
= 193200 lbf / 20 in²
≈ 9660 psi
Therefore, the pressure exerted on the floor by the elephant standing on one foot is approximately 9660 pounds per square inch (psi). This is a very high pressure and could cause damage to some types of flooring.
Can someone answer this question:
What is a period on the periodic table?
Answer:
A period in the periodic table is a row of chemical elements
Explanation:
Don't forget to follow me
Answer:
Horizontal rows in a periodic table are called periods
Explanation:
There are 7 periods in the periodic tableIn periods, chemical properties of elements changeIn periods, physical properties of elements remain the samePeriod number also indicates number of shells an element will have.For example: Na (sodium) is in the third period, hence it will have 3 shells
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what is the speed of an object with a mass of 192 kg when it hits the ground if it is dropped from a height of 13 m
Answer:
V=15.96M/S OR ～16M/SExplanation:
SINCE IT IS DROPPED, INITIAL VELOCITY WILL BE ZEROU = 0
V = ?
S = 13M
ACCELERATION DUE TO GRAVITYA = 9.8m/s²
USING KINEMATIC FORMULA[tex]v {}^{2} = u {}^{2} + 2as[/tex]
[tex]v { }^{2} = 0 + 2(9.8)(13) \\ v {}^{2} = 254.8 \\ v = 15.96m/s[/tex]
A rectangular block with dimensions 6.0 cm x 8.0 cm x 12.0 cm is made of aluminium of density 2700 kg m¹. Find the maximum pressure it can exert when placed on one of its faces on a horizontal surface.
The maximum pressure the rectangular block can exert on a surface when placed on one of its faces on a horizontal surface is 317.71 Pa.
What is the maximum pressure of the block?The maximum pressure the rectangular block can exert on a surface occurs when it is placed on one of its smallest faces.
To calculate the maximum pressure, we need to find the weight of the block, which is equal to its mass multiplied by the acceleration due to gravity. The mass of the block can be calculated as follows:
mass = density x volume
The volume of the block is:
volume = length x width x height
volume = 6.0 cm x 8.0 cm x 12.0 cm
volume = 576 cm³
Converting to meters:
volume = 0.006 m x 0.008 m x 0.12 m
volume = 5.76 x 10^-5 m³
Therefore, the mass of the block is:
mass = density x volume
mass = 2700 kg/m³ x 5.76 x 10^-5 m³
mass = 0.1555 kg
The weight of the block is:
weight = mass x acceleration due to gravity
weight = 0.1555 kg x 9.81 m/s²
weight = 1.526 N
When the block is placed on one of its smallest faces, the area of contact with the surface is:
area = length x width
area = 6.0 cm x 8.0 cm
area = 48 cm²
Converting to meters:
area = 0.06 m x 0.08 m
area = 0.0048 m²
Therefore, the maximum pressure the block can exert on the surface is:
pressure = weight / area
pressure = 1.526 N / 0.0048 m²
pressure = 317.71 Pa
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a simple machine is able to move a 400N load a distance of 20cm when a force of 20N is moved through a distance of 5m calculate work input
The work input required is 180 J.
The formula gives the work input:
Work input = Force x Distance
In this instance, a force of 20 N is used, and 5 m is moved. As a result, the force's work is:
Work done by force = 20 N x 5 m = 100 J
A 400 N weight can be moved by the machine 20 cm (or 0.2 m) away.
Using the following formula, we can estimate the work performed by the machine:
Work done by machine = Load x Distance moved by the load
Work done by machine = 400 N x 0.2 m = 80 J
As a result, the amount of work needed to move the load with the machine is:
Work input = Work done by force + Work done by machine
Work input = 100 J + 80 J = 180 J
Therefore, the work input required is 180 J.
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A fan turns a rate 900 rpm. Find the angular speed of any point on one of the fan blades and find the tangential speed of the tip of a blade if the distance from the center to the tip is 20 cm.
a. 15 rad/s & 3 m/s
b. 15 rad/s & 30 m/s
c. 94.2 rad/s & 18.8 m/s
d. 900 rad/s & 180 m/s
At 900 rpm, a fan spins. angular speed of the any point on a fan blade and tangential speed of a blade's tip if there is a 20 cm gap between the centre and the tip. 9.4 rads and 18.8 m/s.
Correct option is, C.
What is the formula for angular velocity?A amount or angle rotated (and angular displacement) by a rotating body in a given length of time is known as the angular velocity of the body. The symbol for it is omega (). The formula for angular velocity is rad/s = dtd. Radian per second serves as its SI unit.
What is the SI unit for angular momentum?The product of a moment of inertia (I) as well as the angular velocity () of the an object in rotation is the angular momentum. A vector quantity is angular momentum. Kg. m2 is the SI unit for angular momentum.
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3. show your calculations for the following quantities for 1.5 v. include formula and show all your work.
The calculation for the quantity for 1.5 V is simple: 1.5V = 1.5 x 1 = 1.5. The formula for this calculation is V = Voltage x 1, where V is the quantity. The calculation for 1.5V is shown below:
1.5V = 1.5 x 1 = 1.5, By multiplying 1.5 with 1, we get 1.5. This is the calculation for 1.5V.
To understand the calculation of 1.5V better, it is important to first understand the basic unit of electricity - volts. Volts measure the force of electricity in a circuit. It is the amount of electricity that flows through the circuit and is measured in terms of voltage. The higher the voltage, the more electricity is available in the circuit.
To calculate the quantity of electricity for 1.5V, we need to multiply 1.5 with 1. This is the calculation for 1.5V. By multiplying 1.5 with 1, we get 1.5, which is the quantity of electricity for 1.5V.
In conclusion, the calculation for the quantity of electricity for 1.5V is 1.5 x 1 = 1.5. This calculation can be represented using the formula V = Voltage x 1, where V is the quantity.
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The speed of a wave is equal to the frequency multiplied by... what?
Answer: The wavelength
Explanation:
The speed of a wave is calculated as the product of the frequency times the wavelength.
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Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint of the distance is marked to make it easier to see how the locations compare. Assume the spaceship has the same mass throughout the trip (that is, it is not burning any fuel). Rank the five positions of the spaceship from left to right based on the strength of the gravitational force that Earth exerts on the spaceship, from strongest to weakest. The following diagrams are the same as those from Part A. This time, rank the five positions of the spaceship from left to right based on the strength of the gravitational force that the Moon exerts on the spaceship, from strongest to weakest. The following diagrams show five pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d= 2 is twice as large as a distance of d = 1. Rank each pair from left to right based on the strength of the gravitational force attracting the asteroids to each other, from strongest to weakest.
A: The gravity between Earth and the spaceship decreases, B: Gravity obeys the inverse square law, C: d=2; m=2; m=2, d=1; m=1; m=2, d=1; m=1; m=1, d=2; m=1; m=2, d=2; m=1; m=1.
What is the gravitational equivalent of the inverse square law?According to Newton's inverse square law, the force of gravity acting between any two objects is inversely equal to the square of the distance between their centres. Altering the separation distance (d) results in a modification in the force of gravity acting between the objects.
How did Newton arrive at the inverse square law?The third law of planetary motion, which states that "the square of the time taken for a planet to orbit the sun is directly proportional to the cube of the semi-major axis of the orbit," is where Newton actually got the idea for his inverse square law.
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#10. When the weightlifter in question #9 stands, his feet make contact with the floor over an area of 250 square centimeters. What is the area of contact between his feet and the floor in *square meters (picture of question 9 for reference)
The weight is 1372 N
How do we calculate the weight of an object on earth?The weight of an object on Earth can be calculated by using the following formula:
Weight = Mass x Acceleration due to Gravity
Where:
Weight is measured in Newtons (N)
Mass is measured in kilograms (kg)
Acceleration due to Gravity is a constant value
Weight = mass * acceleration due to gravity
Weight = 140 Kg * 9.8
= 1372 N
To calculate the weight of an object on Earth, you need to know its mass.
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how much voltage is available to operate an overvoltage relay 59g when connected across the grounding resistor? what is the multiple of pickup if 59g minimum operating value is 5.4 v.
The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. The multiple of pickup if 59G minimum operating value is 5.4 V is 10.
An overvoltage relay is a type of protective relay that is used to detect overvoltage conditions on an electrical network. The purpose of this relay is to detect if the voltage on the network exceeds a certain level, which could result in damage to equipment or electrical systems connected to the network. The overvoltage relay is connected to the electrical network in such a way that it monitors the voltage level on the network and is capable of tripping a circuit breaker or other protective device if the voltage level exceeds a preset value.
The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. This is because the grounding resistor limits the voltage to a maximum of 54 volts. If the voltage level on the network.
The multiple of pickup if 59G minimum operating value is 5.4 V is 10. This means that the overvoltage relay will trip if the voltage on the network exceeds 54 volts. If the voltage level on the network is between 5.4 volts and 54 volts, the overvoltage relay will not trip, since the voltage is below the pickup level. However, if the voltage level on the network exceeds 54 volts, the overvoltage relay will trip and disconnect the circuit.
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Simple Pendulum Shows Uniform or Non uniform Motion. Explain?
The speed of the bob in a simple pendulum changes every time from A to B. So, its motion can't be a uniform motion. Therefore, the motion of the bob in a simple pendulum is a non-uniform motion.
A simple pendulum is a weight (or bob) suspended from a string or rod, which is free to swing back and forth under the influence of gravity. It is an idealized model used to study the behavior of more complex pendulum systems and has been studied extensively in physics due to its simplicity and ubiquity in everyday life.
The motion of a simple pendulum can be described by a number of variables, including the length of the string, the mass of the bob, the angle at which the pendulum is released, and the amplitude and period of the pendulum's oscillations.
In the absence of friction, the motion of a simple pendulum is governed by the laws of conservation of energy and conservation of momentum.
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Which property of the Sun most affects the
strength of gravitational attraction between
the Sun and Earth?
A mass
B radius
C shape
D temperature
Answer:
mass
Explanation:
The first part of the graph is a straight diagonal line and the second part of the graph is a straight horizontal line. The slope of the first part of the graph is positive, indicating that the cart increased in speed, and was therefore accelerating for the first four seconds. After the fourth second, the slope of the line is zero, indicating that the cart moved at a constant speed and did not accelerate any more because the fan was turned off.
Answer:
This description is likely referring to a graph that shows the velocity of a cart over time. The first part of the graph shows a positive slope, indicating that the velocity is increasing over time, and the second part of the graph shows a horizontal line, indicating that the velocity is constant. The fact that the slope of the first part of the graph is positive means that the cart is accelerating, since acceleration is defined as a change in velocity over time. The fact that the slope of the second part of the graph is zero means that the cart is not accelerating, since its velocity is not changing. The explanation suggests that the change in velocity is due to a fan being turned on and then off, which is causing the cart to accelerate and then move at a constant velocity.
A runner with a mass of 90 kg accelerates from 0 to 8 m/s in 4 s. Find the net force on the runner using the alternate form of newton's second law
Answer: 180 Newtons.
Explanation:
The alternate form of Newton's second law states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m x a
In this problem, the mass of the runner (m) is 90 kg, and the acceleration (a) can be found by dividing the change in velocity (8 m/s) by the time interval (4 s):
a = (8 m/s) / (4 s) = 2 m/s^2
Substituting the values into the equation for force:
F = 90 kg x 2 m/s^2
F = 180 N
Therefore, the net force on the runner is 180 Newtons.
What is the unknown mass of the second box shown in the collision below?
Before collision: v= 6 m/s, 7kg
stationary: m
After collision: v= 2 m/s, 7 kg, m
Answer:
We can use conservation of momentum to solve for the unknown mass of the second box. The total momentum before the collision is equal to the total momentum after the collision.
Before collision:
p = m1v1 = (7 kg)(6 m/s) = 42 kg m/s
After collision:
p = m1v1 + m2v2 = (7 kg)(2 m/s) + m(2 m/s)
Setting the two expressions for momentum equal to each other, we can solve for m2:
42 kg m/s = (7 kg)(2 m/s) + m(2 m/s)
42 kg m/s = 14 kg m/s + 2m kg m/s
28 kg m/s = 2m kg m/s
m = 14 kg
Therefore, the mass of the second box is 14 kg
The reactants of a chemical equation have 1 S atom and 4 O atoms. Which set of atoms must also be founding the equations products so that the equation models the law of conservation of mass
A. 1 S and 4 O
B. 1 S and 1 O
C. 4 S and 1 O
D. 4 S and 4O
The set of atoms must also be founding the equations products so that the equation models the law of conservation of mass is option (A) 1 S and 4 O
The law of conservation of mass is a fundamental principle in chemistry that states that the mass of the reactants in a chemical reaction must be equal to the mass of the products. This principle is based on the fact that atoms cannot be created or destroyed in a chemical reaction, and therefore, the number of atoms of each element on both sides of the equation must be the same.
In order to balance a chemical equation and satisfy the law of conservation of mass, it is necessary to adjust the coefficients of the reactants and products to ensure that the number of atoms of each element is equal on both sides of the equation.
Therefore, the correct option is (A) 1 S and 4 O
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Compute the resistance of a 90-cm length of copper wire with a 0. 020 -cm^2 cross-sectional area. ( = 1. 8 x 10-6 ohm-cm)
R = ______ ohms
The resistance of a 90-cm length of copper wire with a 0. 020 -cm^2 cross-sectional area is 81 ohms.
The resistance of a wire is given by:
R = (rho * L) / A
where rho is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
In this case, we are given that the length of the copper wire is 90 cm, the cross-sectional area is 0.020 cm^2, and the resistivity of copper is 1.8 x 10^-6 ohm-cm.
First, we need to convert the units of length and cross-sectional area to meters and square meters, respectively:
L = 90 cm = 0.9 m
A = 0.020 cm^2 = 2 x 10^-5 m^2
Now, we can substitute these values into the formula for resistance:
R = (rho * L) / A
R = (1.8 x 10^-6 ohm-cm * 0.9 m) / 2 x 10^-5 m^2
R = 81 ohms
Therefore, the resistance of the copper wire is 81 ohms.
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a proton is near a charged plate and feels a force of 4.5x10^-16 N if the oroton is 1.3x1^-6 m away from the charged plate what is the charge of the plate
10. You weigh yourself on a scale and find that your weight is about 126 pounds.
a) Multiply your weight in pounds times 4.45. This is your weight in Newtons.
b) What is your mass in kilograms?
c) If you went to the moon, how much would you weigh?
(a) Your weight in Newtons is 560.7 N.
(b) Your mass in kilograms is 57.12 kg.
(c) Your weight on the moon is 93.45 N.
What is the measure of your weight in Newtons?a) To convert your weight from pounds to Newtons, we can use the conversion factor that 1 pound is equal to 4.45 Newtons.
Therefore, your weight in Newtons would be:
126 pounds x 4.45 Newtons/pound = 560.7 Newtons
b) To find your mass in kilograms, we can use the formula:
mass (kg) = weight (N) / acceleration due to gravity (m/s²)
The acceleration due to gravity on Earth is approximately 9.81 m/s². Therefore, your mass in kilograms would be:
mass (kg) = 560.7 N / 9.81 m/s² = 57.12 kg
c) The gravitational force between two objects depends on their masses and the distance between them. The gravitational force on the moon is about 1/6th the gravitational force on Earth.
Therefore, if you went to the moon, your weight would be about 1/6th of what it is on Earth.
Your weight on the moon would be:
126 pounds / 6 = 21 pounds
To convert this to Newtons, we can use the conversion factor:
1 pound = 4.45 Newtons
So your weight on the moon in Newtons would be:
21 pounds x 4.45 Newtons/pound = 93.45 Newtons
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A string attached to an airborne kite has a eastward horizontal vector of 72 m. The kite also has a northward vertical vector of 150 m. What is the resultant vector of the actual kite string?
Therefore, the resultant vector of the kite string has a magnitude of 168.5 meters and makes an angle of 65.5 degrees with the horizontal axis.
What is vector?In physics, a vector is a quantity that has both magnitude and direction. It can be represented graphically as an arrow, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector. Vectors can be added, subtracted, and multiplied using mathematical operations, such as the dot product and cross product. These operations allow us to manipulate and analyze vectors mathematically, which is useful for understanding and predicting the behavior of physical systems.
Here,
To find the resultant vector of the kite string, we can use the Pythagorean theorem and trigonometric functions. First, we can find the magnitude of the resultant vector using the Pythagorean theorem:
magnitude = √((72 m)² + (150 m)²)
magnitude = 168.5 m
Next, we can find the angle that the resultant vector makes with the horizontal axis using trigonometric functions.
tan(theta) = opposite / adjacent
tan(theta) = (150 m) / (72 m)
theta = tan⁻¹(150 m / 72 m)
theta = 65.5 degrees
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Help fast please…………
The answer is (c) N north-east 76.
What is a vector quantity?A vector quantity is a physical quantity with magnitude as well as direction. Vector quantities include things like displacement, velocity, acceleration, force, and momentum. A vector is typically represented graphically as an arrow, with the length of the arrow representing the magnitude and the direction of the arrow representing the vector's direction.
To find the vector V, we need to combine its X and Y components. Using the given values:
X component = 44 N east
Y component = 62 N north
We can represent this as a vector V with the notation V = (44 N east) + (62 N north).
To find the magnitude of the resultant R, we can use the formula R = √(Rx² + Ry²), where Rx and Ry are the X and Y components of the resultant vector. In this case:
Rx = 44 N east
Ry = 62 N north
So, R = √((44 N east)² + (62 N north)²) = √(1936 N² + 3844 N²) = √(5780 N²) = 76 N.
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The wires in a piano vibrate, but fractions of the wire also vibrate at different frequencies than the whole wire. What is the term
for the softer notes produced by these different frequencies? (1 point)
O interference
O pitch
O resonance
Oharmonics
the answer to the question is pitch
what is the magnitude of the force between two wires separated by 9.30 cm and each carrying 128 a? one wire is very long and the other is 35.0 m long
The magnitude of the force between the wires is 0.00156 N
The magnitude of the force between two parallel wires can be calculated using the formula:
F = (μ₀ * I₁ * I₂ * ℓ) / (2 * π * r)
where F is the force
, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A),
I₁ and I₂ are the currents in the wires,
ℓ is the length of the shorter wire, and
r is the separation distance between the wires.
In this case, we have:
I₁ = I₂ = 128 A
ℓ = 35.0 m
r = 9.30 cm = 0.0930 m
So, the force between the wires is:
F = (4π × 10^⁻⁷ T·m/A) * (128 A)² * (35.0 m) / (2 * π * 0.0930 m)
F = 0.00156 N
Therefore, the magnitude of the force between the wires is 0.00156 N.
To learn more about magnetic force:
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