A 1,000 kg truck is traveling at 3 m/s. Suddenly, the driver sees a herd of cows on the road ahead and applies the brakes. The truck's tires could fail after doing 5,000 J of work to slow the vehicle. Can the truck stop before the tires fail?
A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J.
B. Yes, the tires do not do any work, it is only the brakes that do work.
C. No, the truck had to stop suddenly and the quick change in KE will cause the tires to fail.
D. No, the total KE the tires need to transfer out of the system is more than 5,000 J.
Answers
This question involves the concepts of the law of conservation of energy and kinetic energy.
The correct option is "A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J".
According to the law of conservation of energy:
Loss in Kinetic Energy = Work done by the tires
[tex]\frac{1}{2}mv^2=W[/tex]
where,
W = work done by tires = ?
m = mass of the truck = 1000 kg
v = speed of the truck = 3 m/s
Therefore,
[tex]W=\frac{1}{2}(1000\ kg)(3\ m/s)^2[/tex]
W = 4500 J
Since the failure limit of work done by the tire is 5000 J, which is greater than the actual work done by the tire in this scenario. Hence, the tire will not fail in this case.
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The attached picture explains the law of conservation of energy.
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Answer:
Explanation:
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What happens to the volume of a fixed amount of gas if both the pressure and the absolute temperature are doubled
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Answer: no change in volume
Explanation:
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B. A 10 kg rock at 10°C
C. A6 kg rock at 15°C
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Explanation:
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Answer:
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If a train travels 25 miles in 2 hours 15 minutes, what is its average speed in miles per hour? 11. 1 mph 12. 5 mph 10 mph 9. 1 mph.
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Answer:
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Explanation:
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1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles
The weight of a cart with a mass of 150 kg is ___ N. (Use 9.8
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Answer:
1470 N
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how many tries did it take to invent the lightbulb?
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A force acts on an object. Which option describes an action that could prevent the object from moving
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Answer:
Friction or tension
Explanation:
Friction stops an object from moving in the presence of force
3. If John leaves his house to walk his dog and he walks around the block, what is
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180 Meters
180 Meters
180 Meters
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Answer:
180 meters
Explanation:
How is "speed" defined in terms of physics?
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Explanation:
In everyday use and in kinematics, the speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Anna used a rock to drive a peg into the ground to put up her tent. If the rock applied a 9. 5 N force in 0. 50 s, what is the impulse on the peg? 4. 8 N • s 9. 5 N • s 10 N • s 19 N • s.
Answers
Answer:
4.8 N*s
Explanation:
P = F*t
P = Impulse/ momentum
F = force (Newtons)
t = time (seconds)
P = 9.5N*0.5s
P = 4.75 N*s
Hi there!
[tex]\large\boxed{I = 4.8 N}[/tex]
Impulse = Force (N) × Time (s)
We can also express this as:
I = Δp = Ft
Plug in the given values:
I = 9.5(.50) = 4.75 ≈ 4.8 Ns
Explain why we draw straight lines to show rays of light?
Answers
Answer:
Because light always travels in straight line.
Explanation:
The fact that light travels can be demonstrated by putting an object in its path. If the object is opaque the result is a degree of blackness on the other side of it which is due to the absence of the light. ... As light does appear to travel in straight lines then light is usually modelled as straight lines in drawings.
Hope this helps :)
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A teacher has two radioactive sources, A and B.
Source A has a longer half-life than source B.
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in source B?
Do not refer to isotopes in your answer.
Answers
Answer:
The nuclei of source have greater stability than those of source B.
what is the chemical and physical changes if making a starchs
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Answer:
Chemical modification of starch is based on the chemical reactivity of the constituent glucose monomers which are polyhydroxyl and can undergo several reactions. Starch can undergo reactions such as hydrolysis, esterification, etherification and oxidation.
Explanation:
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1 point
What is the acceleration of a bicyclist moving at a constant speed of 10
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PLEASE HELP HURRY
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Answer:
0
Explanation:
The bicyclist is not speeding up or slowing down so there is no acceleration.
SOMEONE PLEASE HELP ME IM GOING INSANE 4 Select the correct answer. A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 x 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour? O A. -3.77 x 10-2 meters/second OB. -2.77 x 10-3 meters/second OC. -2.62 x 10-2 meters/second D. -5.55 x 103 meters/second
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Hi there!
Since we are dealing with such large distances, we can approximate.
Recall that the equation for speed is:
displacement / time = velocity
OR:
d/t = v
Begin by converting one hour to seconds:
1 hr = 3600 sec
Now, we can solve for velocity:
(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s
Calculate the force applied if 100 N/m² pressure is exerted over the area of 0.2m²
Answers
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Explanation:
What is the correct definition of rarefaction
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Answer:
Explanation:
A decrease in the density of something is rarefaction. ... Most of the time, rarefaction refers to air or other gases becoming less dense. When rarefaction occurs, the particles in a gas become more spread out. You may come across this word in the context of sound waves.
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
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A long-distance runner runs at a constant speed of 4.8 m/s. How long does it take them to run 1.5 km?
Answers
Convert km to meters:
1km = 1000 m
1.5 km x 1000 = 1500 m
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a box takes 350 N to start moving the coefficient of static friction is 0.35. what is the weight of the box?
Answers
Answer:
101.937 kg
Explanation:
The force needed to get the box moving must just cancel the static friction force:
F = µsmg = 0.35•m•9.81 = 350 ---> m = 350 / (0.35•9.81) = 101.937 kg
Again, with units shown, and using 1 N = 1 kg•m/s2:
0.35•m•9.81(m/s2) = 350 N
solving for m:
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______________________
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a
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(i) The maximum vertical height of the two blocks when they stop.
(ii) The time needed for the blocks to reach the bottom of the incline after the moment of impact.
(u = 0.19)
Answers
this is my attachment answer hope it's helpful to you
Part IV Objects on an incline w/ Tension + Friction
1. A small 63 kg sleigh is pulled by a rein attached to horse up a 15'angle hill to the
horizontal. The tension of the rein is 510 N. The coefficient of kinetic friction is
0.25
a. What is the normal force that the sleigh exerts on the hill?
b. What are the magnitude and direction of the sleigh's acceleration?
Answers
(a) The normal force on the sleigh is 596.36 N.
(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.
The given parameters;
mass of the sleigh, m = 63 kginclination of the hill, θ = 15⁰tension on the rein, F = 510 Ncoefficient of friction, μ = 0.25The normal force on the sleigh is calculated as follows;
[tex]F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N[/tex]
The magnitude and direction of acceleration of the sleigh is calculated as follows;
[tex]\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards[/tex]
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Find the velocity of a body of mass 100 g having kinetic energy of 20 J.
Answers
Answer:
Explanation:
Let v be the velocity of object ,
Given that mass of object , m=100 g=
1000
100
kg=0.1 kg
& kinetic energy of object =20 J
K.E =
2
1
mv
2
20=
2
1
×0.1v
2
⟹v
2
=400
⟹v=20 m/s
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Answers
Answer:
Explanation:
BMI= weight/(height × height) ; weight in kilogram and height in metter
= 58kg / (1.61m × 1.61m )
= (58/ 2.5921) kg/[tex]m^{2}[/tex]
= 22.375 kg/[tex]m^{2}[/tex]
≈ 22.4 kg/[tex]m^{2}[/tex]
What mass M will cause this system accelerate e 0.75 m/s²?
Answers
Answer:
5.54 [kg].
Explanation:
1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then
2) it is possible to write: m₁*a=m₁*g-m₂*g, and
3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]
hannah drove 360 mi in 5.2 hours. What was her average speed?
Answers
Explanation:
When you take the number of miles and divide it by the number of hours you get 69.2 (when rounded)
That is how fast she went per hour
help me solve please
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Answer:
please check the image
Explanation:
I hope this image helps you please follow the steps. Thank you
Answer:
1kg/```````2
Explanation:
solution
why the max Static frictional force is a Little bit bigger than the sliding frictional force
Answers
Hope it helps!
Consider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 106°. If the bond length r = 0.103 nm long, locate the center of mass of the molecule. The mass mH of the hydrogen atom is 1.008 u, and the mass mO of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.)
Answers
The definition of the center of mass allows to find the result for the position of the mass center of more than the H₂O molecule is;
[tex]x_{cm} = 0 \ and \ y_{cm} = 6.9 10^{-3 } nm[/tex]
the concept of center of mass of a system is the point where external forces are applied, it is given by the expression
[tex]\frac{x}{y} =\frac{1}{M_{total}} \sum m_i r_i[/tex]
Where M is the total mass of the systemr_i and m_i sums the position and masses of the element i of the system
In the attachment we have a diagram of the system where the axis and coordinates of the molecules are shown, in this case it is indicated that the origin is in the oxygen atom, so its distance is zero.
[tex]r_{cm} = \frac{1}{2 m + M} \ (2 m r )[/tex] )
They indicate the mass of the hydrogen atom m = 1.008 amu, the bond length r = 0.103 nm and there is an angle 106º between the two hydrogens, therefore the angle from the vertical is:
θ = 106/2 = 53º
Let's find the position of the center of mass for each axis.
x-axis
[tex]x_{cm} = \frac{1}{2m+ M} \ ( m x_1 - m x_2)[/tex]
y-axis
[tex]y_{cm} = \frac{1}{2m + M} \ ( m y_1 + m_2)[/tex]
Let's use trigonometry to find the components of the bond length.
cos θ = [tex]\frac{y}{L}[/tex]
sin θ = [tex]\frac{x}{L}[/tex]
y = L cos θ
x = L sin θ
We substitute.
[tex]x_{cm} = \frac{1}{2m+M} \ (mL (sin 53 + sin (-53)) \\y_{cm} = \frac{1}{2m + M} \ ( mL cos 53 + mL sin 53)[/tex]
we use.
sin θ = - sin -θ
cos θ = cos -θ
Let's calculate.
[tex]x_{cm} = 0 \\y_{cm} = \frac{1}{2 \ 1.008 + 15.9999} \ ( 2 \ 1.008 \ 0.103 cos 53)[/tex]
We see that the center of mass is on the x axis and at a distance from the y-axis of 6.9 10-3 nm
In conclusion using the definition of the center of mass we can find the result for the position of the center of mass of the H₂O molecule is;
[tex]x_{cm}=0[/tex] and [tex]y_{cm}[/tex]cm = 6.9 10⁻³ nm
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