9- Under what circumstances would a vector have components that are equal in
magnitude?
a. if the vector is oriented at 45° from the axes.
b. if the vector is oriented at 90° from the axes.
c. if the vector is oriented at 0° from the X -axis.
d. if the vector is oriented at 0° from the y-axis.
itude of 30 units Vector B is perpendicular to vector A

Answers

Answer 1

Explanation:

c. if the vector is oriented at 0° from the X -axis.


Related Questions

Define the following:
Potential energy
Kinetic energy
Mechanical energy
Chemical energy
Sound energy
Light energy
Nuclear energy

Answers

Define the following:
Potential energy: In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Kinetic energy: In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
Mechanical energy:
Chemical energy: chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic. Reactions that require an input of heat to proceed may store some of that energy as chemical energy in newly formed bonds
Sound energy: In physics, sound energy is a form of energy that can be heard by living things. Only those waves that have a frequency of 16 Hz to 20 kHz are audible to humans. However, this range is an average and will slightly change from individual to individual.
Light energy: Light energy is a kind of kinetic energy with the ability to make types of light visible to human eyes. Light is defined as a form of electromagnetic radiation emitted by hot objects like lasers, bulbs, and the sun. Light contains photons which are minute packets of energy.
Nuclear energy: Nuclear power is the use of nuclear reactions to produce electricity. Nuclear power can be obtained from nuclear fission, nuclear decay and nuclear fusion reactions. Presently, the vast majority of electricity from nuclear power is produced by nuclear fission of uranium and plutonium in nuclear power plants

Answer

potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.

The energy of an object due to its motion or position; the sum of an object's kinetic energy and potential energy is called mechanical energy.

Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic

Sound energy is defined as the movement of vibrations through matter. Sound energy is produced when an object vibrates, which results in noise. The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood, or metal.

Light energy is a kind of kinetic energy with the ability to make types of light visible to human eyes. Light is defined as a form of electromagnetic radiation emitted by hot objects like lasers, bulbs, and the sun. Light contains photons which are minute packets of energy.

Nuclear energy is energy in the nucleus (core) of an atom. ... It can be released from atoms in two ways: nuclear fusion and nuclear fission. In nuclear fusion, energy is released when atoms are combined or fused together to form a larger atom. This is how the sun produces energy.

When the mass of the cylinder increased from 3. 0 kg to 6. 0 kg, what happened to the amount of heat generated in the system? It decreased by a factor of 3. It decreased by a factor of 2. It increased by a factor of 2. It increased by a factor of 3.

Answers

When the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

The given parameters:

Initial mass of the cylinder, m₁ = 3.0 kgFinal mass of the cylinder, m₂ = 6.0 kg

The amount of heat generated in the system is calculated as follows;

Q = mcΔT

where;

m is the massc is the specific heat capacityΔT is the change in temperature

If we keep every other parameters constant and change the mass from 3.0 kg to 6.0 kg, the increase in the heat generated is calculated as follows;

[tex]Q_1 = 3c \Delta T\\\\Q_2 = 6c\Delta T\\\\Q_2 = 2(3c \Delta T)\\\\Q_2 = 2Q_1[/tex]

Thus, when the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

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A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units

Answers

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

please help me! i’ll mark brainliest if you’re correct!

Answers

The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:

[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]

Answer: 3N to the right

Explanation: 2N- 5N= 3N

A diffraction grating is 1.50 cm wide and contains 2000 lines. When used with light of a certain wavelength, a third-order maximum is formed at an angle of 20.0°. What is the wavelength (in nm)?

Answers

Answer:

because of the gravity of the earth

what led scientists to the discovery of the strong nuclear force?

Answers

Answer:

Explanation:

The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.

What happens to all light bulbs in a series circuit when one burns out? How would the situation change when the lights are hooked up in parallel?

Answers

In a series circuit if one light bulb burns out then all of the light bulb would burn out. In a parallel the light bulbs are put in their own pathways so if one burns out the others won't

Which are the most likely products for the following reaction? Zn + CuSO4 --> ?

Answers

Answer:

It's going to be a single displacement reaction

So we'll get ZnSO4 + Cu for the following reaction Zn + CuSO4

Equation:

Zn + CuSO4 ------> Cu + ZnSO4

If the mass of a substance having its volume 80 cm is 68 g. Calculate the density of the substance​

Answers

[tex]\text{Given that,}\\\\\text{Mass}~ m = 68 ~\text{g} = 68 \times 10^{-3}~ \text{kg}\\\\\text{Volume}~ V = 80 ~ \text{cm}^3 = 80 \times 10^{-6}~ \text{m}^3 = 8\times 10^{-5}~ \text{m}^3\\\\\\\text{Density} ~\rho = \dfrac mV = \dfrac{68\times 10^{-3}}{8 \times 10^{-5}} = 8.5 \times 10^2 = 850 ~ \text{kg}~\text{m}^{-3}[/tex]

Please HELP
6. A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed
of 10.0-m/s.


a.
If the rope can only tolerate 400-N of force, what is the maximum speed the bucket can
experience before the rope snaps? {Hint: Let the centripetal force be 400-N and solve for the speed)

Answers

Answer:

Explanation:

hope this helps

The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

What is force?

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the bucket, m = 3.4 kg,

The length of the rope, r = 1 m,

The speed of the bucket, v = 10 m / s,

The force of the rope, F = 400 N,

Calculate the maximum speed by the formula given below,

[tex]F_c = mv^2 / r[/tex]

400 = 3.4 v² / 1

v² = 400 / 3.4

v² = 117.6

v = 10.85 m / s

Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

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An instrument made of brass is an example of which of these?

solid–liquid solution

solid solution

liquid–liquid solution

gas–liquid solution

Answers

Answer:

a solid made of liquid solution

Explanation:

a trumpet for example has intrcuite valves , the only way to do this is by creating a liquid form of the metal to be able to create the solid formed instrument.

Answer:

a solid made of liquid solution

Explanation:

domne

A car takes off from rest takes of from rest and covers a distance of 80m on a straight road in 10s.Calculate the magnitude of its acceleration.​

Answers

Initial velocity (u) = 0 m/s [the car was at rest]Distance (s) = 80 mTime (t) = 10 sLet the magnitude of acceleration be a.By using the equation of motion, [tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]we get,[tex]80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6[/tex]

Answer:

The magnitude of its acceleration is 1.6 m/s^2.

Hope you could get an idea from here.

Doubt clarification - use comment section.

hi my name is coolboy123hillok

Answers

Answer:

you should change that name

please change your name

During which time does Jamal have the greatest momentum?

Answers

Answer:

Momentum Packet Answer KEY - Science Online

YOU WILL SEE THE PDF

why does the earth get more energy from the sun than from all the other stars in the universe combined

Answers

Answer:

Explanation:

The sun is much closer than the other stars

What type of heat does not require matter?

Answers

Radiation is the only method of heat transfer that does not require matter.

Facts about Radiation :

The energy from the sun is received in the form of radiation. It travels in the form of waves. It can be absorbed by substances in its path.Heat Radiation travels through air. Black surfaces are the emitters of heat radiation.Shiny surfaces are the reflectors of heat radiation.Heat transfer by Radiation doesn't require any medium.

i. la protagonista ama a su gata. escribimos, en nuestros cuadernos , las razones por las que pensamos que las personas aman de manera exagerada a sus mascotas. Proponemos un antídoto para la soledad. Lo escribrimos

Answers

Las mascotas son una buena fuente de compañía y socias en la soledad.

La protagonista ama a su gato porque las mascotas son una buena fuente de compañía y es un antídoto para la soledad. Estas mascotas como perros, gatos, loros, etc. dan placer y felicidad a las personas.

La gente tiene mascotas para pasar tiempo con ellas y jugar con ellas para refrescar sus mentes. Tener mascotas es una actividad maravillosa que hace que nuestra mente esté relajada y llena de felicidad, por lo que podemos concluir que las mascotas son una buena fuente de compañía y compañera en la soledad.

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PLZ HELP ME FAST A relationship between two variables is called:
A.
observable
.B.
correlation
.C.
causation
D.
finite.

Answers

Answer:

B- Correlation

Explanation:

Answer:

correlation

Explanation:

what is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds​

Answers

1250 J in 5 sec= 250 Joule(s) per second (1250/5 0

250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)

250 Watts output = 250/0.65 efficiency = 384 Watts input

1 Horsepower = 732 Watts

Motors 1 Horsepower and under are made in certain step sizes like

3/4 , 1/2 , 1/3, 1/4, 1/16 1/20 of a Horsepower.

3/4 Horsepower is 549 Watts

1/2 Horsepower is 366 Watts

so you need to 3/4 horsepower motor to achieve 1250 J of work in 5 seconds.

Which of the following statements cannot be supported by Kepler's laws of planetary motion?


A planet's distance from the sun will not be the same in six months.


A planet's speed as it moves around the sun will not be the same in six months.


The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.


The average distance of Saturn can be calculated using the average distance of Neptune and the orbital period of both planets.

Answers

the second
option is the answer

Look at the diagram of two trains. Calculate the relative speed.

Answers

Answer:speed difference

Explanation:

I need it in the next hour or so!

A sports car with a mass of 650 kg is accelerating at +3 m/s2. The force of friction is 200 N, the forward force from the engine is 3100 N. What must the force of air resistance on the car be? - Show your work - Include a unit with your answer​

Answers

The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is

∑ F = F[a] - F[f] - F[air] = ma

3100 N - 200 N - F[air] = (650 kg) (3 m/s²)

Solve for F[air] :

F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)

F[air] = 3100 N - 200 N - 1950 N

F[air] = 950 N

an airplane flies with a constant speed of 620 miles per hour. how far can it travel in 3 1/2 hours?

Answers

Answer:

hi there !

1 hour -------> 620 miles

3 1/2 ---------> ?

the number of miles the airplane travels in 3 1/2 hours

= 3 1/2 × 620 = "2170" miles

Before Collision:
2,000 kg 4 m/s 4,000kg 0 m/s

After collision: 2,000 kg + 4,000kg Vt = ?

I will give Brainliest to the first person. Please show work

Answers

Answer:

  4/3 m/s

Explanation:

Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:

  (2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)

  Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s

The speed of the combined objects after the collision is 4/3 m/s.

what's the mass of the star rasalas?

Answers

Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.

Explanation:

Answer:

The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.

Explanation:

what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three signficant figures.

Answers

Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

a swimmer experiences a total (absolute) pressure of 117,500 pa in a pool. how far below the surface are they located?

Answers

Answer:

Explanation:

We know that the pressure can be calculated in the following way:

p = d·g·h

with d being the density of the water, g the gravitational acceleration and h the depth.

Also d of the water = 1000 kg/m^3 circa and g = 9.8 m/s^2 circa

117,500 Pa = 1000kg/m³ · 9.8m/s² · h

Therefore h = 11,9 m

In an inelastic collision:

I. only momentum is conserved

II. only kinetic energy is conserved

III. momentum and kinetic energy are both conserved.

IV. neither momentum nor kinetic energy are conserved.

Answers

Hi there!

I. Only momentum is conserved.

An inelastic collision means that there is a LOSS in the KINETIC ENERGY of the system.

However, momentum is ALWAYS conserved for every type of collision unless there is an external force acting on the system.

I think it’s I.
Hope this will help.

The Doppler technique for planet detection has found Earth-like planets around nearby Sun-like stars. (True or False) ____________________

Answers

Answer: false

Explanation:

A rock is lying on a rock ledge that is 3 m high. The rock as 120 J of potential energy. What is the mass of the rock?

Have a great day!

Answers

[tex]\\ \sf\Rrightarrow PE=mgh[/tex]

[tex]\\ \sf\Rrightarrow m(10)(3)=120[/tex]

[tex]\\ \sf\Rrightarrow 30m=120[/tex]

[tex]\\ \sf\Rrightarrow m=4kg[/tex]

Mass=4kg
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