3
Extremist groups typically mix radical beliefs or values with anger over some aspect of society.
OA. True
OB. False

Answers

Answer 1
A) true
Extremist groups typically mix radical beliefs or values with anger over some aspect of society"
Answer 2
True.
Because Extremist groups often mix radical beliefs or values with anger over some aspect of society. They may believe that their group or ideology is under threat, and they may use violence or other extreme measures to defend their beliefs or advance their cause. Extremist groups can be found on the far right, far left, or in religious or cultural movements, and their tactics can range from peaceful protests to terrorism.

Related Questions

A hurricane travels a distance of 20 miles in 1 hour. Determine the hurricanes velocity.

Answers

Answer:

the answer is 20mi/hr

Explanation:

What two things can be considered to be substances?

Answers

Answer:Classification of Matter According To Composition

When you think about classifying matter, you likely think of the three states of matter: solid, liquid, and gas. But, thinking back to the donut metaphor, we can also classify matter according to what it is made of (aka its chemical composition)! So, what makes up matter? Well, on a molecular level, all matter is made up of atoms that can form elements, compounds, and molecules! Even with all these different components, matter can be split into two broad categories based on its composition: pure substances and mixtures. We will spend most of our time on pure substances, but briefly cover mixtures! So, let’s dive into pure substances!

We will go into more detail on all the components of matter, but for a more thorough review, check out Atomic Structure!

Definition of Pure Substances

A simple way to think about pure substances is as something that is made up of only one type of matter that always has the same properties, such as melting point, boiling point, density, etc.

Pure substances are matter that has a fixed chemical composition and properties that do not change.

Can you guess what are pure substances in your day-to-day life? I bet you may have salt (NaCl) and tin cans (Sn) in your pantry! These are perfect examples of pure substances because salt is made up of purely NaCl molecules, and tin is made up of only tin atoms.

But wait, you may have noticed a difference between salt and tin and asked how exactly salt is only made up of one type of matter when it’s two different atoms bonded together?

Pure substances can be further divided into two classes: elements and compounds.

Pure Substance Examples

We are going to spend some time looking at elements and compounds separately and some common examples of each!

Elements

If you think elements sound familiar, you are correctly thinking of the 118 organized in the periodic table. Tin is an example of an element!

Explanation:

In which stage is the individual willing to modify their behavior and their
environment to overcome the problem, as they are ready to change and take
the proper steps to make change happen?
OA. Maintenance
OB. Precontemplation
C. Action
D. Contemplation
SUBMIT

Answers

In C. Action stage is the individual willing to modify their behavior and environment to overcome problem, as they are ready to change and take proper steps to make change happen

Five phases of behaviour modification are identified as per phases of modification model. Precontemplation, Contemplation, Preparation, Action, and Maintenance are the phases. The person has made a commitment to change and is actively making changes to their surroundings and behaviour to address the issue in the Action stage.

In this mode, people have a strategy in place, and are generally moving in the right direction. Since it involves making significant changes to behaviour, attitudes, and lifestyle, the action stage is the most labor-intensive. In addition to having the tools and assistance they require for success, the person must be motivated and dedicated to making the change.

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 1.What did Ruskin write about Nocturne in Black and Gold: Falling Rocket?

2. How did Whistler defend his work in court? ( You need to mention the two paintings he brought with him to court.)

3. What was the outcome of the trial?

4. Why do you think the lawsuit was important in the history of art?

Answers

Answer:

Ruskin wrote a scathing review of James McNeill Whistler's painting Nocturne in Black and Gold: Falling Rocket, describing it as "flinging a pot of paint in the public's face." He criticized the painting for not being representative enough and lacking in artistic skill.Whistler defended his work in court by stating that he was not interested in creating a realistic depiction of the subject, but rather capturing the mood and atmosphere of the scene. He brought two other paintings, Nocturne in Blue and Silver and Harmony in Blue and Gold, to demonstrate his artistic style and prove that his intention was not to deceive the public.The outcome of the trial was a victory for Whistler, but he was only awarded a farthing in damages. The judge ruled that Ruskin's review did damage Whistler's reputation but only to a very small extent.The lawsuit was important in the history of art because it highlighted the changing attitudes towards art in the 19th century. Whistler's defense challenged the traditional idea of what art should be, which was based on realism and technical mastery. It paved the way for the emergence of modern art, which emphasized imagination and individual expression.

Additionally, the trial drew attention to the importance of art criticism and the power of critics to influence public perception of art.

Consider the circuit in the diagram below.

Circuit diagram showing a battery on the left leg, with the positive terminal towards the top. Across the top leg of the circuit, a switch is positioned to the left of center in the open or off position. On the right leg of the circuit, there is a capacitor. On the bottom leg of the circuit, there is a lightbulb to the right of center. Running vertically through the center of the circuit, there is another branch connecting the top leg and bottom leg. In the center of this leg, there is a switch in the open or off position.

If the switch at the top is moved to the closed or on position, what would best describe the flow of the conventional current?

The electricity would flow from the positive terminal of the battery in a clockwise direction.
The electricity would flow from the negative terminal of the battery in a counterclockwise direction.
The electricity would flow from the bottom of the capacitor around in a clockwise direction.
The electricity would flow from the top of the capacitor around in a counterclockwise direction.

Answers

If the switch at the top is moved to the closed or on position, the best description of the flow of conventional current would be " The electricity would flow from the positive terminal of the battery in a clockwise direction." The correct option is A.

This is because in a circuit, the conventional current flows from the positive terminal of the battery to the negative terminal of the battery. In this circuit, the positive terminal of the battery is connected to the top leg of the circuit, and the negative terminal is connected to the bottom leg of the circuit. When the switch at the top is closed, the current would flow from the positive terminal of the battery, through the switch, and down through the top leg of the circuit in a clockwise direction.

Option B is not true because the conventional current flows from the positive terminal to the negative terminal of the battery, not the other way around.

Option C is not true because the current would not flow through the capacitor until it is charged. At the moment the switch is closed, the capacitor is uncharged and acts like an open circuit, so the current would not flow through it.

Option D is not true because the current would flow from the positive terminal of the battery, through the switch, and down through the top leg of the circuit in a clockwise direction. It would not flow around the capacitor in a counterclockwise direction.

Hence,  the correct answer is option A.

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Which of the following is most likely the caption for the illustration that was scratched out of the textbook?

A. An electrically-charged object can attract an uncharged object with magnetic properties.

B. An electrically-charged object is stronger than a magnet.

C. A dry cell battery has magnetic properties.

D. An electric circuit can only have one dry cell battery.

IMAGE DOWN BELOW OR UP

Answers

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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In the figure the current in resistance 6 is i_{6} = 1.41A and the resistances are R_{1} = R_{2} = R_{3} = 2.34f , R_{4} = 17.2 Q, R_{5} = 7.55Omega and R_{6} = 4 Q. What is the emf of the ideal battery?

Answers

The emf of the ideal battery is 50.57 volts.

∵ The resistors R5 and R6 are in series,

∴ Current through R5 = Current through R6 = 1.41 A

Now, voltage across R4 resistor = voltage across R5 and R6

                                                     = 1.41 × (7.55 + 4.44)     {as V=IR}

                                                     = 16.9 v

Now current through R4 resistor = V/R

                                                      = 16.9/17.2

                                                      = 0.982 A

Using Kirchoff's Current law,

Current in R2 = Current in R4 + current in R5, R6 branch.

                      = 0.982 + 1.41

                      = 2.392 A

Using Kirchoff's voltage law, in the loop containing resistances R2, R3, and R4,

I×2.34 - 2.392×2.34 - 0.982 × 17.2 = 0,

where "I" is the current across R3.

⇒ I = 9.61 A

Again, using Kirchoff's current law,

Current through R1 = Current through R2 + current through R3

                                = 9.61 + 2.392

                                = 12.002 A

Now calculating the resistance across the battery,

R5 and R6 are in series,

∴ their equivalent Req1 = R5 + R6 = 7.55 + 4.44

                                               = 11.99

Req1 and R4 are in parallel,

∴ Their equivalent Req2 = 11.99 × 17.2/(11.99+17.2)

                                         = 7.06

Again, R2 and Req2 are in series,

so, their equivalent Req3 = 7.06 + 2.34

                                          = 9.4

Req3 and R3 are in parallel,

So, their equivalent, Req4 = 2.34 × 9.4/(2.34+9.4)

                                            = 1.87

R1 and Req4 are in series

So, their equivalent = 2.34+1.87 = 4.21

So, the resistance across the battery = 4.21 ohms

But current across battery = current across R1(series) = 12.002 A

∴ EMF across battery = IR = 12.002 × 4.21 = 50.57 v

Hence, the emf of the ideal battery is 50.57 volts.

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A 150kg diver jumps off a diving board and hits the water at 40 m/s
What is the kinetic energy of the diver entering the water?

Answers

When the diver enters the water, the kinetic energy is 120,000 J.

This is an exercise in kinetic energy, which is a form of energy associated with the movement of an object and its speed. It is important in many areas of physics, from classical mechanics to modern physics. This form of energy can be transformed into other forms of energy, such as thermal energy, sound energy or electrical energy. The formula for calculating kinetic energy is KE = m * v^2/2, where m is the mass of the object and v is its speed.

Kinetic energy is a fundamental concept in classical mechanics. It is used to analyze the movement of objects and calculate the amount of work required to stop them. When an object is in motion, it has kinetic energy, which is equal to half its mass times its speed squared. If the object collides with another object, some of its kinetic energy is transferred to the second object in the form of work or heat.

Kinetic energy is also important in modern physics. In Einstein's theory of special relativity, the mass of a moving object increases with its speed, which means that its kinetic energy also increases. In fact, the kinetic energy of a moving object is a form of energy that is included in Einstein's famous equation E=mc^2, where E is the energy, m is the mass of the object, and c is the speed of light. . This equation shows how the mass of an object and its energy are related.

Kinetic energy is also important in quantum physics. In quantum mechanics, particles have a property called momentum, which is a measure of their motion. Momentum and kinetic energy are related, and experiments in quantum physics often measure the momentum and kinetic energy of particles.

It tells us that the diver has a mass of 150 kg, and that he jumps from a diving board into the water at a speed of 40 m/s.

They ask us what is the kinetic energy of the diver who enters the water?

We know that the formula for kinetic energy is:

KE = m * v^2/2. We should not do the formula clearance, because we are going to calculate the kinetic energy.

We already know our data from the formula, now we substitute and solve, then

KE = (m × v²)/2

KE = (150 kg × (40 m/s)²)/2

KE = (150 kg × 1600 m²/s²)/2

KE = 120000 J

When the diver enters the water, the kinetic energy is 120,000 J.

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KINETIC ENERGY

Answer:

The kinetic energy of the diver entering the water is 120,000 Joules.

Explanation:

The kinetic energy (KE) of an object is given by:

[tex]\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * m * v^2[/tex]

where:

m is the mass of the objectv is its velocity.

Plugging in the given values, we get:

[tex]\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * (40\: m/s)^2[/tex]

[tex]\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * 1600\: m^2/s^2[/tex]

[tex]\sf\qquad\dashrightarrow KE = \boxed{\bold{\:\:120,000\: J\:\:}}[/tex]

Therefore, the kinetic energy of the diver entering the water is 120,000 Joules.

Given the equation X=10m+(5m/s^2) t^2, find the change in positiin at t1=1s, t2=2s

Answers

To find the change in position between t1=1s and t2=2s, we need to calculate the displacement (change in position) caused by acceleration between these two times.

First, we can find the position at t1=1s:

X1 = 10m + (5m/s^2) (1s)^2 = 15m

Next, we can find the position at t2=2s:

X2 = 10m + (5m/s^2) (2s)^2 = 30m

The change in position between t1 and t2 is simply the difference between X2 and X1:

ΔX = X2 - X1 = 30m - 15m = 15m

Therefore, the change in position between t1=1s and t2=2s is 15 meters.

The specific heat values for solid gold and solid iron are listed below:
J/8°C
gold

= 0.129

J/8°C

iron

= 0.449

If a 10g sample of gold and a 10g sample of iron were exposed to the same heat source for 1 minute, which sample would have a higher final
temperature? Why?
O The gold sample contains fewer atoms, therefore its final temperature is higher
O The gold sample contains fewer atoms, therefore its final temperature is lower
O The gold sample contains more atoms, therefore its final temperature is higher
O The gold sample contains more atoms, therefore its final temperature is lower

Answers

The gold sample contains fewer atoms, therefore its final temperature is higher

Does iron have a higher specific heat capacity than gold?

The specific heat capacity of a substance is defined as the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius.

The specific heat capacity of gold is 0.129 J/g°C, while the specific heat capacity of iron is 0.449 J/g°C. This means that it takes less heat energy to raise the temperature of one gram of iron by one degree Celsius compared to gold . Therefore, iron can absorb more heat energy before it reaches the same temperature as gold .

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Question 1 1 point possible (graded) In a laboratory, scientists often study neurons in isola living creature, in a dish. In this setting, one can have control over the local ionic environment in which the c we can control the makeup of the solution - the 'medi This situation is a bit like replacing the extracellular flu normally be bathed in with some other fluid. There are a variety of different kinds of media that sci different purposes. Let's consider a few standard one Dulbecco's Modified Eagle's Medium (DMEM) and de The table below lists the ionic concentrations for thes intracellular column lists the concentrations inside a p concentrations below are in mm (millimolar). lon K+ Na+ CI- Ca²+ 87 mV -87 mV -25 mV 25 mV Intracellular -60 mV 140 10 12 0.0001 DMEM 5.3 154 119 1.8 "de me Based on this chart, what is the Nernst potential for K bathed in DMEM at 37°C? 55 105 119 1.8​

Answers

Nernst potential for K+ ions bathed in DMEM at 37°C is  55 mV. The correct option is A.

The Nernst potential for K+ ions bathed in DMEM at 37°C is a measure of the equilibrium potential for K+ ions across a cell membrane in a solution of DMEM. It is calculated using the Nernst equation, which takes into account the concentration gradient of K+ ions across the membrane, as well as the valence of K+ ions and the temperature of the solution.

The Nernst potential for an ion at a given temperature is calculated using the Nernst equation:

E = (RT/zF) * ln([ion]out/[ion]in)

Where:

E is the Nernst potential (in mV)

R is the gas constant (8.314 J/K/mol)

T is the temperature (in Kelvin)

z is the valence of the ion

F is the Faraday constant (96,485 C/mol)

[ion]out is the concentration of the ion outside the cell (in mM)

[ion]in is the concentration of the ion inside the cell (in mM)

ln is the natural logarithm function

Using the values from the table given in the question, we can calculate the Nernst potential for K+ ions bathed in DMEM at 37°C:

Plugging in the values for K in DMEM:

E = (RT/zF) * ln([K+]out/[K+]in)

E = (8.314 * 310.15)/(1 * 96485) * ln(5.3/140)
E≈ 0.055 V

E ≈ 55 mV

Therefore, The correct option is A.

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What is the primary difference between outlaw motorcycle gangs and social motorcycle groups?
O A.
OB.
O C.
O D.
being a structured group with roles
having a group leader
their group activities and behavior
having group rules

Answers

Answer:

The primary difference between outlaw motorcycle gangs and social motorcycle groups is their group activities and behavior. Outlaw motorcycle gangs are typically involved in criminal activities, such as drug trafficking, extortion, and violence. They often have a hierarchical structure and strict rules for membership and behavior. In contrast, social motorcycle groups are primarily focused on riding motorcycles and socializing with other riders. They do not engage in criminal activities and do not have a strict hierarchy or rules for membership. While both types of groups may have some level of structure, such as having a group leader or group rules, the main difference lies in their group activities and behavior.

The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.

Answers

Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

You are pushing a 30-kg wooden crate across the floor. The force of sliding friction on the crate is 90 N. How much force must you exert on the crate to keep it moving with a constant velocity.

Answers

To keep the crate moving with a constant velocity, the force you need to exert on it is the force of kinetic friction, which in this case is 90 N. This is the minimum force required to overcome the force of sliding friction and maintain a constant velocity.

When an object is moving across a surface, there is a force of friction that opposes its motion. This is known as the force of kinetic friction. In the case of the wooden crate being pushed across the floor, the force of sliding friction is 90 N.

In order to keep the crate moving at a constant velocity, the force being applied to it must be equal and opposite to the force of sliding friction. This is because if the applied force is less than the force of sliding friction, the crate will slow down and eventually come to a stop. If the applied force is greater than the force of sliding friction, the crate will accelerate.

The force you need to exert on the crate is:

Force = Force of kinetic friction = 90 N

Note that the mass of the crate is not needed to calculate the force you need to exert, only the force of sliding friction acting on it.

Therefore, the force you must apply to the crate in order to maintain its constant velocity is the force of kinetic friction, which in this instance is 90 N. This is the bare minimum force necessary to overcome sliding friction and preserve constant speed.

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A2 kg iron sphere is heated to 130 °C. It is then dropped into a bath of 4 kg of water at 25 °C.

Specific heat of iron-0.444 kJ/kg C
Specific heat of water-4.186 kJ/kg"C
Calculate the final temperature of the iron-water system in degrees Celsius. Round your answer to one decimal place.

Answers

A2 kg iron sphere is heated to 130 °C. It is then dropped into a bath of 4 kg of water at 25 °C then ,the final temperature of the iron-water system is 30.3°C.

First, let's calculate the heat transferred from the iron sphere to the water

Heat lost by iron sphere = m * c * ΔT

Where m is the mass, c is the specific heat, and ΔT is the change in temperature.

Heat lost by iron sphere = 2 kg * 0.444 kJ/kg°C * (130°C - T)

Heat gained by water = m * c * ΔT

Where m is the mass, c is the specific heat, and ΔT is the change in temperature.

Heat gained by water = 4 kg * 4.186 kJ/kg°C * (T - 25°C)

Since heat is conserved, we can equate the two equations

2 kg * 0.444 kJ/kg°C * (130°C - T) = 4 kg * 4.186 kJ/kg°C * (T - 25°C)

Solving for T

2 * 0.444 * (130 - T) = 4 * 4.186 * (T - 25)

0.888 * (130 - T) = 16.64 * (T - 25)

115.44 - 0.888T = 16.64T - 416

17.528T = 531.44

T = 30.32°C

Therefore, the final temperature of the iron-water system is 30.3°C.

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3) Vector A is 2.8 cm at 60° above the positive x-axis. Vector B is 1.90 cm at 60° below the
positive x-axis. Use components to find the following:
a) A + B
b) A -B
c) B-A

Answers

a) A + B: 3.9 cm, 0°

b) A - B: 0.9 cm, 60°

c) B - A: 0.9 cm, 240°

Two balloons with charges of 8.37 µC and unknown one repel each other with a force of 0.5 Newton in the distance of 30mm. Determine the unknown charge.

Answers

The electrostatic force between two charged objects is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant (9 x 10^9 N*m^2/C^2), q1 and q2 are the charges of the two objects, and r is the distance between them.

In this case, we have two balloons with charges of 8.37 µC and q2 (unknown), separated by a distance of 30 mm, and experiencing a repulsive force of 0.5 N.

We can plug in the given values and solve for q2:

0.5 N = (9 x 10^9 N*m^2/C^2) * (8.37 µC * q2) / (0.03 m)^2

Simplifying:

q2 = (0.5 N * 0.03 m^2) / (9 x 10^9 N*m^2/C^2 * 8.37 µC)

q2 = 2.05 µC

Therefore, the unknown charge is 2.05 µC.

Ice of mass 14.6 kg at 0°C is placed in an ice chest. The ice chest has 3.5 cm thick walls of thermal conductivity 0.01 W/m x K and a surface area of 1.21 m^2. Express your answers with appropriate mks units.
(a) How much heat must be absorbed by the ice during the melting process?
(b) If the outer surface of the ice chest is at 36° C, how long will it take for the ice to melt?

Answers

The heat absorbed by the melting ice is Q = 4,875,600 J.

How to solve

a, Given mass (m) = 14.6 kg, then the heat absorbed by the melting ice is Q = 4,875,600 J.

This can be determined using Q = 14.6 kg × 334,000 J/kg.

b. By utilizing the equation P = (0.01 W/m × K × 1.21 m^2 × 36 K) / 0.035 m, we can determine that P equals 12.396 watts.

To discover how long it will take for the ice to melt, we can use another formula: t = Q / P.

With the given value of Q as 4,875,600 joules and P is equal to 12.396 watts, we find that t evaluates to roughly 393,292 seconds.

In order to transform this result into hours, simply divide by 3600 which leads us to t ≈ 109.25 hours.

Therefore, it is predicted that the ice will melt in approximately 109.25 hours.

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Question 1
2. Can 120 g of KNO3 (potassium nitrate) dissolve in 100 mL of water at 60°C?
Provide evidence from the graph to support your answer.
Edit View Format Table
12pt
Paragraph
BI U A
✓ T²V
4
1 pts
PAR

Answers

We can now see that 120 g of KNO3 (potassium nitrate) can not dissolve in 100 mL of water at 60°C.

What is the solubility?

Solubility is the ability of a substance, called the solute, to dissolve in a solvent to form a hom--ogeneous mixture called a solution.

The saturated solution of potassium nitrate will hold about 110 g of dissolved salt per 100 mL of water at 60∘C . Thus we can say that the solubility of the KNO3 at 60°C is 110g of the salt per  100 g of water.

Solubility is an important concept in chemistry and is used in various applications such as in the preparation of solutions.

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PLEASE HELP!


The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.20 mA out of the page, and is at distance d₁ = 2.58 cm from a surface. Wire 2. which is parallel to wire 1 and also long, is at horizontal distance d-5.05 cm from wire 1 and carries a current of 6.88 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1?

Answers

Answer: I think The correct Answer is 41.5pN/m

How do i solve E=MC^2

Answers

Answer:

Calculating E = mc^2 for any object tells you how much energy would result if the entire object disappeared. Weigh the object you will perform the calculation for with a mass balance scale. Record its mass. Convert the mass to kg, if necessary. To convert from g to kg, for example, divide by 1,000. Square the speed of light.

Explanation:

1. Single Choice
The higher the frequency of a wave, ( )
A:The smaller its speed
B:The shorter its wavelength
C:The greater its amplitude
D:The larger its period

Answers

B:The shorter its wavelength.
The answer is B shorter is wavelength

Drag the answer in order from most potential energy (at the top) to least potential energy (at the bottom).
Source:
Position D on the roller coaster
A person standing on the ground
Position A on the roller coaster
B
A person in an airplane in the sky
A
Target

Answers

A person in an airplane in the sky has the greatest potential energy, while a person standing on the ground has the least potential energy.

What is gravitational potential energy?

Gravitational potential energy is the energy that an object possesses due to its position above the ground.

Mathematically, the formula for gravitational potential energy is given as;

PE = mgh

Where;

m is the mass of the objectg is the acceleration due to gravityh is the height of the object

The greater the height or distance of an object above the ground, the greater the gravitational potential energy.

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A proton is accelerated from rest through a potential difference of 91 V. Calculate the final speed of this proton.

Answers

Answer: v = 4.17 x 10^5 m/s

Explanation:

The potential difference (ΔV) is given as 91 V. The charge of the proton is given by q = 1.6 x 10^-19 C.The mass of the proton is given by m = 1.67 x 10^-27 kg. The acceleration due to gravity is given by g = 9.81 m/s^2. The final speed of the proton can be calculated as follows:

The potential energy gained by the proton (ΔU) can be calculated using the formula:

ΔU = qΔV

where

q = charge of the proton

ΔV = potential difference

Substituting the given values, we get:

ΔU = (1.6 x 10^-19 C) x (91 V) = 1.456 x 10^-17 J

The kinetic energy gained by the proton (K) can be calculated using the formula:

K = (1/2)mv^2

where

m = mass of the proton

v = final speed of the proton

The kinetic energy gained by the proton is equal to the potential energy gained by the proton. Therefore, we have:

K = ΔU = 1.456 x 10^-17 J

Substituting the given values, we get:

1.456 x 10^-17 J = (1/2) x (1.67 x 10^-27 kg) x v^2

Simplifying the equation, we get:

v^2 = (2 x 1.456 x 10^-17 J) / (1.67 x 10^-27 kg)

v^2 = 1.743 x 10^10 m^2/s^2

Taking the square root of both sides, we get:

v = 4.17 x 10^5 m/s

Therefore, the final speed of the proton is 4.17 x 10^5 m/s.

When a proton is accelerated from rest through a potential difference of 91 V then final speed of this proton is

A proton is a stable subatomic particle with a +1 e (elementary charge) positive electric charge. It has a little lower mass than a neutron and a mass that is 1,836 times that of an electron (the proton-to-electron mass ratio). Protons and neutrons, each with a mass of around one atomic mass unit, are referred to collectively as "nucleons" (particles found in atomic nuclei).

Potential energy of the proton gets converted into kinetic energy.

i.e. 1/2 mv² = qV

Where m is mass of the proton, v is velocity of the proton and q is charge on proton, V is potential difference.

Given,

mass of the proton m = 1.6 × 10⁻²⁷ kg

charge on proton q =1.6 × 10⁻¹⁹ C

P.D. V = 91 V

putting values in equation,

1/2× 1.6 × 10⁻²⁷ kg × v² = 1.6 × 10⁻¹⁹ C × 91 V

0.8 × 10⁻²⁷ v² = 145 × 10⁻¹⁹ C

v = 1.34 × 10⁵ m/s

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The same collision as in Question 5 takes place, only this time the car and the truck bounce off each other completely elastically What are the final velocities of the car and truck just after the collision?

Answers

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

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One long wire lies along an x axis and carries a current of 36 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0,5.8 m, 0), and carries a current of 73 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 2.0 m, 0)?

Answers

The magnetic field at the point (0, 2.0 m, 0) due to the two long wires is 6.8 x 10⁻⁶T (tesla) in the positive y direction.

To find the magnetic field at the given point, we can use the Biot-Savart law, which gives the magnetic field produced by a current-carrying wire at a point in space. For the wire along the x-axis, the magnetic field at the point (0, 2.0 m, 0) is zero, since the wire is parallel to the y-axis and there is no component of the magnetic field along the y-axis.

For the wire perpendicular to the xy-plane, the magnetic field at the point (0, 2.0 m, 0) can be found using the Biot-Savart law as follows:

dB = (μ0 / 4π) * (I / r²) * dl x r

where dB is the magnetic field produced by a small length element of the wire, I is the current in the wire, r is the distance from the length element to the point where the magnetic field is being calculated, and dl x r is the vector cross product of the length element and the distance vector.

Integrating over the entire length of the wire, we can find the total magnetic field at the point (0, 2.0 m, 0). Using vector addition, we can find the magnitude and direction of the resulting magnetic field. Finally, we can substitute the given values into the equation to obtain the answer of 6.8 x 10⁻⁶ T in the positive y direction.

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*Calculation
An intensity level change of 1 dB correspond
s to what percentage change in intensity?

Answers

Answer:

An intensity level change of 1 dB corresponds to a 10% change in intensity.

1. Which type of subatomic particle is not found in the nucleus?(1 point)

a. proton
b. quark
c. electron
d. neutron

Answers

Answer:

(c) electron - they are found in the outer "shells" of atoms

An object has a mass of 25 kilograms: to. How much is the potential energy if the height is 30 m. b. How much is the kinetic energy at a height of 30 m. If the object is in repose?​

Answers

The potential energy of the object is 7,350 J.

The kinetic energy is zero.

What is the potential energy of the object?

The potential energy of an object at the given position is calculated by applying the following formula.

P,.E = mgh

Where;

g  is the acceleration due to gravityh is height m is mass

P.E = 25 x 9.8 x 30

P.E  = 7,350 J

If the object is at rest (not moving), then its kinetic energy is zero, sice kinetic energy of a nergy of a body in motion.

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How do I measure luminous intensity? Are there specific devices that measure it in candelas? Is there a possibility to measure Luminous intensity using an analogue system like radiant intensity?

Answers

Luminous intensity is measured in candelas (cd) and can be measured using a photometer, which is a device that measures the intensity of light as perceived by the human eye.

Photometers can measure luminous intensity directly in candelas, or they can measure illuminance in lux and distance in meters to calculate luminous intensity using the formula: Luminous Intensity = Illuminance x Distance².

Radiant intensity is a different physical quantity than luminous intensity, and they cannot be measured using the same system. Radiant intensity is measured in watts per steradian (W/sr), while luminous intensity is measured in candelas (cd).

Therefore, it is not possible to measure luminous intensity using an analogue system designed to measure radiant intensity.
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