25.0g of iron is heated to 100.0 and then placed in 50.0 g of water in a insulated calorimeter. the initial temperature of the water is 38.00. the specific heat of water is 4.181j/g and the specific heat if iron is 0.45j/g. what is the final temp of the water and the iron?

Answers

Answer 1

Answer:

Approximately [tex]41.2\; {\rm ^{\circ} C}[/tex].

Explanation:

Let [tex]t\; {\rm ^{\circ} C}[/tex] be the final temperature of the water and the iron.

Temperature of the water would be increase by [tex](t - 38.00)\; {\rm ^{\circ} C}[/tex].

Temperature of the iron would be reduced by [tex](100.0 - t)\; {\rm ^{\circ} C}[/tex].

Let [tex]c[/tex] denote the specific heat of each material. Let [tex]m[/tex] denote the mass of the material. For a temperature change of [tex]\Delta t[/tex], the energy change involved would be:

[tex]Q = c\, m \, \Delta t[/tex].

The energy that the water need to absorb would be:

[tex]\begin{aligned}& Q(\text{water, absorbed}) \\ =\; & c(\text{water}) \, m(\text{water})\, \Delta t (\text{water}) \\ =\; & 4.181\; {\rm J \cdot g^{-1} \cdot K^{-1}} \times 50\; {\rm g} \times (t - 38.00)\; {\rm ^{\circ} C} \\ =\; & (209.05\, t - 7943.9)\; {\rm J} \end{aligned}[/tex].

The energy that the iron would need to release would be:

[tex]\begin{aligned}& Q(\text{iron, released}) \\ =\; & c(\text{iron}) \, m(\text{iron})\, \Delta t (\text{iron}) \\ =\; & 0.45\; {\rm J \cdot g^{-1} \cdot K^{-1}} \times 25.0\; {\rm g} \times (100.0 - t)\; {\rm ^{\circ} C} \\ =\; & (1125 - 11.25 \, t)\; {\rm J} \end{aligned}[/tex].

Since this calorimeter is insulated, the energy that the iron had released would be equal to the energy that the water had absorbed:

[tex]Q(\text{water, absorbed}) = Q(\text{iron, released})[/tex].

[tex]209.05\, t - 7943.9 = 1125 - 11.25\, t[/tex].

[tex]t \approx 41.2[/tex].

Thus, the final temperature of the water and the iron would be approximately [tex]41.2\; {\rm ^{\circ} C}[/tex].


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Answer:

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Explanation:

Answer:

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Answers

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

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Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

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Answer:

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Answer:

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Answer: 23.53g

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Answer:

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Answer:

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Explanation:

...

Answer:

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Explanation:

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Whether it conducts heat or electricity,if it is attracted by a magnet , high density high melting point

The question that will best help the student to classify the material is; "is the material malleable or ductile?"

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Answer:

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Answer:

5 significant figures

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The zeros as considered when they are in between or after numbers greater than zero.

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Answers

The density of the gas is obtained as  0.55 g/L.

We can find the density of the gas using the relation;

PM = dRT

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Answers

Considering the rule of three and molar mass of O, the mass of O²⁻ ions in 3 mol of alumina Al₂O₃ is 96 grams.

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So, in 1 mole of Al₂O₃, you have 2 ions of O²⁻.

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Answers

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According to this question, silver reacts with hydrochloric acid to form silver chloride and hydrogen gas as follows:

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Based on this balanced equation, 2 moles of silver (Ag) produces 2 moles of silver chloride (AgCl).

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Answers

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