2.5 x 10^3 times what number is equal to 5 x 10^6?

Step-by-step explanation:

hope it will help you and please mark the answer as brillant please.

The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

The formula of the volume of a sphere is given below

⇒ Formula:

⇒ Where:

From the question, There are two spheres.

If the radius of the bigger sphere is two times the radius of the smaller sphere.

⇒ Where

For the bigger sphere

⇒ Substitute these values into equation 1

  For the smaller sphere,

⇒ Comparing equation 2 and equation 3

Hence, The volume of the bigger sphere is 8 times larger than the volume of the smaller sphere.

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Answer:

85m

Step-by-step explanation:

Perimeter of a rectangle = 2(l+b)

b=72m, l=?

perimeter =314m

314=2(l+72)

314/2= l+72

157=l+72

l=157-72

l=85m

The equation in slope-intercept form that represents the situation is y = 3x + 12

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let x be the calf's age in month and y be the weight.

A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs. Hence it can be represented by:

(2, 18) and (8, 36). The equation is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-18=\frac{36-18}{8-2}(x-2) \\\\y=3x+12[/tex]

The equation in slope-intercept form that represents the situation is y = 3x + 12

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Answer:

-90

Step-by-step explanation:

it's right

Answer:

The first one.

Step-by-step explanation:

I took the quiz and got a 100, hope this helps :))

Answer:

Nick will have to pay $63.56 for the shoes.

Step-by-step explanation:

f the original cost of the shoes is $56.75 and the markup is 12% greater than the original price, the final price would be $63.56.

$56.75 • 0.12 = $6.81

$56.75 + $6.81 = $63.56

$56.75 + 12% = $63.56

Answer:

Nick will have to pay $63.56 for the shoes.

Answer:

292.6

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]x - 0.20x \: = 1480[/tex]

[tex]0.8x = 1480[/tex]

[tex]x = 1480 \div 0.8[/tex]

I'm not sure if this is correct, but I got this

Last year’s computer models are discounted 20%. If a computer is on sale for $1,480, what is the original price of the computer rounded to the nearest dollar?

20% = 0.2

1,480 x 0.2 = 296

1,480 + 296 = 1,776

Answer: 1,776

Again, I don't know if this is correct, so don't be 100% sure with my response.

Answer:

x = 65

Step-by-step explanation:

2x + 2(2x-15) = 360

2x + 4x - 30 = 360

6x = 390

x = 65

a) The equation is therefore; x³ + 3x² + 2x = 336

b) Solving for the length, we get the length to be; x = 6.

c) All workings are as shown below;

According to the question;

In essence, the volume of the original prism is;

Since, the original prism had a length, width, and height of consecutive integers, increasing in that order.

a) The equation is therefore;

b) Solving for the length, x is as follows;

By testing values and checking;

c) All workings are as shown above.

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The Lateral Surface Area of the cylindrical oil storage tank is [tex]2486.9\text{ sq.ft}[/tex]

The Total Surface Area of the cylindrical oil storage tank is [tex]5526.4\text{ sq.ft}[/tex]

If the height and base radius of the cylindrical oil storage tank are represented by [tex]h[/tex] and [tex]r[/tex] respectively, then

The Lateral Surface Area, also known as the Curved Surface Area, of the cylindrical oil storage tank has the formula

[tex]L=2\pi rh[/tex]

The Total Surface Area of the cylindrical oil storage tank has the formula

[tex]T=2\pi rh+2\pi r^2\\T=2\pi r(h+r)[/tex]

The values for the height and base radius are [tex]18ft[/tex] and [tex]22ft[/tex] respectively.

Calculate the Lateral Surface Area

[tex]L=2\pi rh\\=2\times 3.14\times 22\times 18\\\approx 2486.9\text{ sq.ft}[/tex]

Calculate the Total Surface Area

[tex]T=2\pi r(h+r)\\=2\times 3.14\times22(18+22)\\=5526.4\text{ sq.ft}[/tex]

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Answer:

pic?

Step-by-step explanation:

send me the picture please

Answer:

x > 2

Step-by-step explanation:

-1+6(-1-3x)>-39-2x

-1-6 - 18x > -39 - 2x

-7 - 18x + 2x > -39 - 2x + 2x

-7 - 16x + 7 > -39 + 7

16x / 16 > -32 / 16

x > 2

Answer: 40

Step-by-step explanation: yes make me brainlist (its the crown)

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]

Answer:

(-5,-3)

(1,3)

Step-by-step explanation:

Solving with substitution

Set both equations to y =  ...

y = x^2 + 5x - 3

----------------

y - x =2

y = x + 2

----------------

Substitute one of the Y's with the other Y = equation.

x + 2 = x ^2 + 5x -3

Set one side to 0

0 = x^2 + 4x -5

x^2 + 4x - 5 = 0

Simplify by factoring

(x-1) (x+5)

Get your X values

x-1 = 0

x = 1

x+5 = 0

x = -5

Plug in each X into one of the equations to get your Y value.

1st X

y = x + 2

y = 1 + 2

y = 3

When X = 1, Y = 3

2nd X

y = x + 2

y = -5 + 2

y = -3

When X = - 5, Y = -3

Your answers are (1,3) and (-5,-3)

The sequences A and E are the same sequences.

Sequences are set of numbers where the numbers are arranged in a specific order. Some of the common types of sequences are Arithmetic sequences and Geometric sequences.

A) f(x) = 6x + 4 for x = {1, 2, 3, ....}

f(1) = 10, f(2) = 16, f(3) = 22, ....

B) f(x) = 10x + 4 for x = {1, 2, 3, ...}

f(1) = 14, f(2) = 24, f(3) = 34, ....

C) a₁ = 6 and aₙ₊₁ = aₙ + 4 for n = {1, 2, 3, ...}

a₁ = 6, a₂ = a₁ + 4 = 10, a₃ = a₂ + 4 = 14, ....

D) a₁ = 10 and aₙ₊₁ = aₙ + 4 for n = {1, 2, 3, ...}

a₁ = 10, a₂ = a₁ + 4 = 14, a₃ = a₂ + 4 = 18, .....

E) a₁ = 10 and aₙ₊₁ = aₙ + 6 for n = {1, 2, 3, ...}

a₁ = 10, a₂ = a₁ + 6 = 16, a₃ = a₂ + 1 = 22, ....

A and E are the same sequences with a common difference 6 and the first term 10.

Hence A and E have the same sequence 10, 16, 22, .....

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Answer:

2.8

Step-by-step explanation:

Answer:

Step-by-step explanation:

2.8 units

Answer:

y=

x

​

−2

y=−

x

​

−2, x≥0

​

y=−

x−2, x≥0

​

Step-by-step explanation:

6x+3y=13

6x+3y-13=13--13

6x+3y-13=0

Answer:

x = 20

Hope you could get an idea from here.

Doubt clarification - use comment section

Step-by-step explanation:

x = the first number of the sequence

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519

6x + 1 + 2 + 3 + 4 + 5 = 519

6x = 504

x = 84

so, the third number is x+2 = 84 + 2 = 86

Answer:

x = 7 & y = 8

Step-by-step explanation:

We know that

Mean = Sum of terms/Total terms

=> Mean = 4 + 6 + x + y + 10/5

=> Mean = 20 + x + y/5

Now,

Median = (n + 1)/2

=> Median = (5 + 1)/2

=> Median = 6/3

=> Median = 3rd term = x

So,

x = 20 + x + y/5

x × 5 = 20 + x + y

5x = 20 + x + y

5x - x = 20 + y

4x = 20 + y

Since x and y are in order so,

Possible outcomes will be 7,8 & 9

(7,8) & (8,9) & (7,9)

Taking x = 7 and y = 8

4(7) = 20 + 8

28 = 28

Hence,

x = 7 and y = 8

Answer:

y=7 x=8

Step-by-step explanation: hope you do well in school

Answer:

As per graph the rate of Printer A is 15 pages per minute.

Missing words are:

(a) greater than

(b) greater than

(c) 15

The rate for Printer B is greater than the rate for Printer A because the rate of 25 pages per minute is greater than the rate of 15 pages per minute for Printer A.

or

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

Step-by-step explanation: it's either greater than or more than

From the graph of the printing rate of Printer A, we can see that;

At 1 minute, number of pages printed = 15

At 2 minutes, number of pages printed = 30 minutes

At 3 minutes, number of pages printed = 45

Thus printing rate for printer A is; 15/1 = 30/2 = 45/3 = 15 pages per minutes

Since printer B can print 25 pages per minute, we can conclude that;

The printing rate for Printer B is 10 pages more than the rate of printer A because the rate of 25 pages per minute is 10 pages more than the rate 15 pages per minute for Block A

EXPLANATION:

Given that

sin θ = 1/2

We know that

sin 3θ = 3 sin θ - 4 sin³ θ

⇛sin 3θ = 3(1/2)-4(1/2)³

⇛sin 3θ = (3/2)-4(1/8)

⇛sin 3θ = (3/2)-(4/8)

⇛sin 3θ = (3/2)-(1/2)

⇛sin 3θ = (3-1)/2

⇛sin 3θ = 2/2

⇛sin 3θ = 1

and

cos 2θ = cos² θ - sin² θ

⇛cos 2θ = 1 - sin² θ - sin² θ

⇛cos 2θ = 1 - 2 sin² θ

Now,

cos 2θ = 1-2(1/2)²

⇛cos 2θ = 1-2(1/4)

⇛cos 2θ = 1-(2/4)

⇛cos 2θ = 1-(1/2)

⇛cos 2θ = (2-1)/2

⇛cos 2θ = 1/2

Now,

The value of sin 3θ /(1+cos 2θ

⇛1/{1+(1/2)}

⇛1/{(2+1)/2}

⇛1/(3/2)

⇛1×(2/3)

⇛(1×2)/3

⇛2/3

Answer : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.

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Answer:

x = -7

Step-by-step explanation:

The 2 horizontal lines are parallel as given ion the problem.

The x + 97 angle is congruent to the right angle.

x + 97 = 90

x = -7

Answer:

To find area of the square you'll need to square one side

(3X)^2 = 81

9(X)^2 = 81

(x)^2 = 81/9

x^2 = 9

X = (9)^1/2

X = 3

[tex]\left(3+\sqrt{-16} \right) \left(5-\sqrt{-25} \right)\\\\=\left(3+\sqrt{-1} \cdot \sqrt{16} \right) \left(5- \sqrt{-1} \cdot \sqrt{25} \right)\\\\=(3+4i)(5-5i)~~~~~~~~~~~~~~;\left[i=\sqrt{-1} \right]\\\\=15-15i + 20i - 20i^2\\\\=15+5i -20(-1)~~~~~~~~~~~~;[i^2 =-1]\\\\=15+5i +20\\\\=35+5i[/tex]