Answer:
c) 6 m/s²
Explanation:
What is the input distance for a claw hammer if the output distance is 2.0 cm and the mechanical advantage is 5.5?
Answer:
0.36cm
Explanation:
Given parameters:
Output distance = 2.0cm
M.A = 5.5
Unknown:
Input distance = ?
Solution:
The mechanical advantage is the value of the force multiplier.
M.A = Output distance / Input distance
Input distance = Output distance / mechanical advantage
Input distance = [tex]\frac{2.0cm}{5.5}[/tex] = 0.36cm
Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg
Answer:
(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) Un satélite de 1,200 kg pesará allí 264 N.
Explanation:
(a) Cada punto del espacio tiene un valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:
[tex]g=G*\frac{m}{r^{2} }[/tex]
donde m será masa, r la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]
En este caso:
m= 6*10²⁴ kgr=42,370 km= 42,370,000 mReemplazando:
[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]
Resolviendo, obtenes:
g= 0.22 [tex]\frac{m}{s^{2} }[/tex]
La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria. Esto se expresa matemáticamente como:
F= m*a
en donde F es fuerza neta , m la masa y a la aceleración.
El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:
P=m*g
En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].
Reemplazando:
P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]
Resolviendo:
P= 264 N
Un satélite de 1,200 kg pesará allí 264 N.
NEED HELP IS THERE SOMEONE CAN HELP ME PLS :)
A 3.0-kg meatball is moving with a speed of 6.0 m/s directly toward a 2.0 kg meatball which is at rest. The two meatballs collide and stick together. What is their velocity immediately after the (inelastic) collision?
18 m/s
3.6 m/s
6 m/s
5 m/s
Answer:
Their common velocity after collision is 3.6 m/s
Explanation:
Given;
mass of the first meatball, m₁ = 3.0 kg
initial velocity of the first meatball, u₁ = 6.0 m/s
mass of the second meatball, m₂ = 2.0 kg
initial velocity of the first meatball, u₂ = 0 m/s
let their common velocity after collision = v
Apply the principle of conservation of linear momentum for inelastic collision ;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(3 x 6) + (2 x 0) = v( 3 + 2)
18 = 5v
v = 18 / 5
v = 3.6 m/s
Therefore, their common velocity after collision is 3.6 m/s
Question 3 of 10
Which sentence best explains the difference between potential energy and
kinetic energy?
A. Potential energy is related to an object's motion, and kinetic
energy is related to its position.
B. Potential energy is related to an object's position, and kinetic
energy is related to the arrangement of its particles.
C. Potential energy is related to an object's shape, and kinetic energy
is related to its position.
D. Potential energy is related to an object's position, and kinetic
energy is related to its motion.
SUBMIT
Answer
D
Explanation:
Potential energy is related to an object's position, and kinetic
energy is related to its motion.
What tool of dream analysis says that feelings and urges are hidden inside an event? condensation symbolism projection displacement
Answer:
Condensation
Explanation:
Answer:
Condensation! Hope this helps!!!
Explanation:
A circus performer walked up and to the right for a total displacement of 10\,\text m10m10, start text, m, end text along a diagonal tightrope angled 30 \degree30°30, degree above the ground.
Answer: 5m
(10m) sin 30
=5m
The vertical displacement of the circus performer in m is 5m.
What is displacement?The displacement is the shortest distance travelled by the particle. It is the vector quantity which represents both the magnitude and direction.
A circus performer walked up and to the right for a total displacement of 10 m along a diagonal tightrope angled 30° above the ground.
We know the hypotenuse is 10m (diagonal) and the angle above the ground is 30°
The displacement will be sin (30) of hypotenuse.
Displacement = 10 sin (30)
d = 5m
Thus, the vertical displacement of the circus performer is 5 m.
Learn more about displacement.
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Please help me! Yes, I know the quality SUCKS I have an old Android lol
Answer:
top to 2\
next to top
then to up one
next to up
Explanation:
Two students are discussing gravity. One student says that there is a gravitational attraction between the two
of them. The other student thinks this cannot be true, because he cannot feel any gravitational attraction to
the other student. Which student is correct, and why?
The student says that there is a gravitational attraction between the two of them. This student is correct.
What is gravitational force?The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.
The gravitational force is weak unless there are massive masses involved. As compared to Earth, humans have relatively low masses, which results in a very small and negligible gravitational force. As a result, although it is tiny and imperceptible, gravitational force exists between two people seated near to one another.
Hence, the student, who says that there is a gravitational attraction between the two of them, is correct.
Learn more about gravitational force here:
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how can you differentiate between fast motion and slow motion
Use the formula, F = ma, which is the basic equation of motion in classical mechanics. A slow motion will tend to have lower acceleration and vice versa
What is the power output of an electric motor that
lifts a 2.0-kilogram block 15 meters vertically in 6.0
seconds? PLEASE SHOW WORK
1. 5.0 J
2. 5.0 W
3. 49 J
4. 49 W
Answer:
Power = 49 W
Explanation:
power = work / time (J/t or watt)
Joule or J = kg*[tex]m^{2}[/tex]/[tex]s^{2}[/tex]
watt or W = J/s
given:
mass = 2.0 kg
height = 15 m
g = 9.81 m/s2 (assumed)
t = 6 seconds
work = mass*g*h
work = 2.0*9.81*15 = 294.3 kg*[tex]m^{2}[/tex]/[tex]s^{2}[/tex] = 294.3 J
Power = 294.3 J / 6 seconds = 49.1 J/s = 49 W
A giant treasure chest is sitting in the sand, when two rival groups of pirates (the sharks and the squids) come upon it at the same time from opposite directions. Both groups run forward and each pirate grabs a side. On the shark’s side, they have one pirate pulling with 20N, one with 30N, one with 50N, and one with 10N. On the squid’s side, they have one pirate pulling with 10N, one with 25N, one with 30N, and one with 40N.
Which team is able to pull harder?
What is the net force experienced by the chest?
If the chest weighs 100 kg, how fast is it accelerating?
Answer: if you search this up there is a video saying the answer
Explanation:
A Student walks 2 km in 30 minutes
Answer:
1 km / 15min
Explanation:
The average speed is calculated by simply doing space divided by time so:
2km / 30min that becomes 1km / 15min
Have a good day.
While sitting in class, your body exerts a force of 600 N on your chair. How much work do you do?
Answer:
1000 N
Explanation:
What is mean by speed?
Answer:
Speed is acceleration or a high rate of motion
Answer:
the rate at which something or someone moves or operates or is able to move or operate .
How old is the earth? PLEASE HELP ME WITH THIS QUESTION BANANAFANART
I’LL GIVE U BRAINLIEST BANANAFANART PLEASE ANSWER IT :(
Answer:
The earth is 4 billion years old.
Explanation:
Name all errors and type it again
EZ POINTS CMON
Answer:
you need to capitalize
Explanation:
When Grandpa Joe comes to visit, he tells us stories about when he was in the army with Colonel Jack S. Anderson.
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?
Answer:
(a) 5.62 m/s²
(b) 5.46 m/s²
Explanation:
The given values are:
mass,
m = 50 kg
angle
= 35°
(a)
If friction neglected,
⇒ [tex]F_x=mgSin \theta=ma[/tex]
⇒ [tex]a_x=gSin \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}[/tex]
[tex]=5.62 \ m/s^2[/tex]
(b)
If friction present,
⇒ [tex]F_x=mgCos \theta[/tex]
⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]
⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]
[tex]=5.46 \ m/s^2[/tex]
A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg. The robot pushes on the doll with a force of 1 N. The magnitude of the acceleration of the robot is
Answer:
1.43m/s²Explanation:
According to newtons second law.
F = mass * acceleration
If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg
Force applied = 1N
acceleration = Force/mass
Substitute the values and get acceleration
acceleration = 1/0.7
acceleration = 1.43m/s²
Hence the magnitude of the acceleration of the robot is 1.43m/s²
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
Answer:
The angular velocity of the propeller is 2.22 rad/s.
Explanation:
The angular velocity (ω) of the propeller is:
[tex] \omega = \frac{\Delta \theta}{\Delta t} [/tex]
Where:
θ: is the angular displacement = 10.6 revolutions
t: is the time = 30 s
[tex] \omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s [/tex]
Therefore, the angular velocity of the propeller is 2.22 rad/s.
I hope it helps you!
Given:
Angular displacement,
[tex]\Theta = 10.6[/tex]Diameter,
3 mTime,
[tex]\Delta t = 30 \ s[/tex]Now,
The angular velocity will be:
→ [tex]\omega = \frac{\Delta \Theta}{\Delta t}[/tex]
By putting the values, we get
[tex]= \frac{10.6\times \frac{2 \pi rad}{1 \ rev} }{30 \ s}[/tex]
[tex]= 2.22 \ rad/s[/tex]
Thus the response above is right.
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Give three reasons why gravity is important.
Answer:
It allows people to not float around in the air, it allows earth to orbit, and it holds down the air from the atmosphere so that we could breathe
Answer:
gravity is important bc we cant live without it. The sun's gravity keeps earth in orbit around it. It holds down our atmosphere and air we need to breath.
Explanation:
A baseball player’s bat applies an average force of 220. newtons to a tennis ball for 0.03 second. The average force exerted on the racket by the tennis ball is
Answer:
98
Explanation:
what was his starting velocity???
Answer:
Vo = 18.3 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} -a*t[/tex]
Vf = final velocity = 0 (the bike stops)
Vo = initial velocity [m/s]
a = desacceleration = 6.42 [m/s²]
t = time = 2.85 [s]
Note: the negative sign in the above equation means that the motorcyclist decrease his velocity.
0 = Vo - (6.42*2.85)
Vo = 18.3 [m/s]
please help!!! give me a summary on why human population is either good or bad!! thank youu
Which of the following cannot be transmitted through a
vacuum?
a. ocean waves
b. UV rays
C. Laser
d. X-rays
e. microwave
This man proposed that all matter was composed of atoms
Answer:
John Dalton
Explanation:
Can you hear sounds from space or not? Why or Why not?
an athlete running 2.6m/ increases his velocity to 3.7m/s in 2.7s. what is the acceleration of the runner
A 5.0kg concrete block accelerates down a 34 degree slope at 4.2 m/s^2. Find the Coefficient of friction between the block and the slope.
Answer:
The coefficient of friction between the block and the slope is 0.16.
Explanation:
We can find the coefficient of friction between the block and the slope by using Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex]P_{x} -\mu N = ma[/tex]
[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex] (1)
Where:
m: is the mass of the block = 5.0 kg
a: is the acceleration = 4.2 m/s²
θ: is the angle = 34°
μ: is the coefficient of friction =?
g: is the gravity = 9.81 m/s²
By entering the above values into equation (1) we have:
[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]
[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]
Therefore, the coefficient of friction between the block and the slope is 0.16.
I hope it helps you!
All of the following are good conductors of heat exept
a. Wood
b. Aluminum
c. Copper Silver
(Sorry if its the wrong subject, Im not sure which science this is.)